1 Introduction

Consider the following system of exponents:

{ e i λ n t } n Z ,
(1)

where { λ n }R is a sequence of real numbers, Z is a set of integer numbers. It is the aim of this paper to investigate basis properties (basicity, completeness, and minimality) of the system (1) in Lebesgue space L p t with variable summability index p(t), when { λ n } has the asymptotics

λ n =nαsignn+O ( | n | β ) ,n,
(2)

where α,βR are some parameters.

Many authors have investigated the basicity properties of system of exponents of the form (1), beginning with the well-known result of Paley and Wiener [1] on Riesz basicity. Some of the results in this direction have been obtained by Young [2]. The criterion of basicity of the system (1) in L p L p (π,π), 1<p<+, when λ n =nαsignn, has been obtained earlier in [3, 4].

Recently in connection with consideration of some specific problems of mechanics and mathematical physics [5, 6], interest in the study of the various questions connected with Lebesgue L p t and Sobolev W p t k spaces with variable summability index p(t) has increased [59].

Many questions of the theory of operators (for example, theory of singular operators, theory of potentials and etc.) are studied in spaces L p t [7]. These investigations have allowed one to consider questions of basicity of some system of functions (for example, the classical system of exponents { e i n t } n Z ) in L p t . In [9] the basicity of system { e i n t } n N in L p t has been established. The special case of the system (1) is considered in [1012], when λ n =nαsignn, nZ.

In this paper basis properties of the system (1) in L p t spaces are investigated. Under certain conditions on the parameters α and β equivalence of the basis properties (completeness, minimality, ω-linearly independence, basicity) of the system (2) in L p t are proved.

2 Necessary notion and facts

Let p:[π,π][1,+) be a Lebesgue measurable function. By L 0 we denote the class of all functions measurable on [π,π] with respect to Lebesgue measure. We choose the notation

I p (f) def π π |f(t) | p ( t ) dt.

Let L{f L 0 : I p (f)<+}. Let p =inf vrai [ π , π ] p(t), p + =sup vrai [ π , π ] p(t). For p + <+, with respect to ordinary linear operations of addition of functions and multiplication by number, L turns into a linear space. If we define in L p t the norm

f p t def inf { λ > 0 : I p ( f λ ) 1 } ,

then L is a Banach space and we denote it by L p t . Denote

H ln def { p : p ( π ) = p ( π )  and  C > 0 , t 1 , t 2 [ π , π ] , | t 1 t 2 | 1 2 | p ( t 1 ) p ( t 2 ) | C ln | t 1 t 2 | } .

Throughout this paper, q(t) denotes the function conjugate to function p(t), that is, 1 p ( t ) + 1 q ( t ) 1.

We have Hölder’s generalized inequality,

π π |f(t)g(t)|dtC ( p ; p + ) f p t g q t ,

where C( p ; p + )=1+ 1 p 1 p + .

For our investigation we need some basic concepts of the theory of close bases, given as follows.

We adopt the standard notation: B-space is a Banach space; X is the conjugate to space X; f(x), f X , and xX means the value of functional f on x; L[M] is a linear span of a set M. The system { x n } n N X is called ω-linear independent in B-space X, if n = 1 α n x n =0 true for α n =0, nN.

The following lemma is true.

Lemma 1 Let X be a Banach space with basis { x n } n N X and F:XX be a Fredholm operator. Then the following properties of the system { y n = F x n } n N in X are equivalent:

  1. (1)

    { y n } n N is complete;

  2. (2)

    { y n } n N is minimal;

  3. (3)

    { y n } n N is ω-linear independent;

  4. (4)

    { y n } n N is isomorphic to { x n } n N basis.

We also need the following easily provable lemma.

Lemma 2 Let X be a Banach space with basis { x n } n N and { y n } n N X:card{n: x n y n }<+. Then the expression

Fx= n = 1 x n (x) y n

generates the Fredholm operator F:XX, where { x n } n N X is conjugate to { x n } n N system.

The following lemma is also true.

Lemma 3 Let { x n } n N be complete and minimal in B-space X and { y n } n N X:card{n: x n y n }<+. Then the following properties of system { y n } n N in X are equivalent:

  1. (1)

    { y n } n N is complete;

  2. (2)

    { y n } n N is minimal.

These and other results are obtained in [13, 14].

We will use the following statement, which has a proof similar to the proof of Levinson [15].

Statement 1 Let system { e i λ n t } n Z be complete in L p t . If from the system we remove n any functions and add instead of them n other functions e i μ j t , j=1,,n, where μ 1 ,, μ n are any, mutually different complex numbers not equal to any of numbers λ k , then the new system will be complete.

We shall also need the following theorem of Krein-Milman-Rutman.

Theorem 1 (Krein-Milman-Rutman [13])

Let X be a Banach space with norm , { x n } n N X be normed basis in X (i.e. x n =1, nN) with conjugate system { x n } n N X , and { y n } n N X be a system satisfying the inequality

n = 1 x n y n < γ 1 ,

where γ= sup n x n . Then { y n } n N also forms a basis isomorphic to the basis { x n } n N in X.

3 Basic results

Before giving the basic results we will prove the following auxiliary theorem.

Theorem 2 Let p H ln and p >1. If the system

{ e i ( n α sign n ) t } n Z ,
(3)

forms a basis in L p t L p t (π,π), then this system is isomorphic to the classical system of exponents { e i n t } n Z , where the isomorphism is given by

Sf= e i α t 0 ( f , e i n x ) e i n t + e i α t 1 ( f , e i n x ) e i n t ,
(4)

where

(f,g)= 1 2 π π π f(t) g ( t ) ¯ dt.

Proof Consider the operator (4). From the basicity of system { e i n t } n Z in L p t it follows that S is a bounded operator on L p t into itself. It is easy to see that KerS=0. Actually, let Sf=0. From the basicity of the system (3) in L p t and from (4) we obtain (f, e i n x )=0, nZ. Also, from the basicity of system { e i n t } n Z in L p t it follows that f=0. We show that for all g L p t , the equation Sf=g in L p t is solved. Let us assume that

f= n Z g n e i n t ,

where { g n } n Z are the biorthogonal coefficients of the function g by the system (3).

It is clear that f L p t , and so

S f = e i α t n = 0 ( f , e i n x ) e i n t + e i α t n = 1 ( f , e i n x ) e i n t = e i α t n = 0 g n e i n t + e i α t n = 1 g n e i n t = g ,

as by the condition of the theorem, the system (3) forms a basis in L p t .

This means that for all g L p t the equation Sf=g is solved in L p t . Then by the Banach theorem the operator S has a bounded inverse. It is obvious that S[ e i n t ]=A(t) e i n t , n0, and S[ e i n t ]=B(t) e i n t , n1. This completes the proof. □

Now we study some basis properties of the system (1). Firstly, we recall the following theorem.

Theorem 3 ([11])

Let p H ln and p >1. If parameter αR satisfies the condition 1 2 p ( π ) <α< 1 2 q ( π ) , then the system { e i μ n t } forms a basis in L p t .

Let the asymptotics (2) occur. Let us assume μ n =nαsignn and δ n = λ n μ n , nZ. It is easy to see that the inequality

| e i λ n t e i μ n t |c|n | β ,n0,
(5)

is fulfilled, where c is some constant. Let us assume that the following inequalities are satisfied:

1 2 p ( π ) <α< 1 2 q ( π ) ,β> 1 p ˜ ,
(6)

where p ˜ =min{ p ;2}. Then, from Theorem 3, the system of exponents { e i μ n t } n Z forms a basis in L p t . By Theorem 1, it is isomorphic to the classical system of exponents { e i n t } n Z in L p t . Therefore the spaces of coefficients of the bases { e i μ n t } n Z and { e i n t } n Z coincide.

Let T: L p t L p t be a natural automorphism

T [ e i μ n t ] = e i n t ,nZ.

For all f L p t , let { f n } n Z be biorthogonal coefficients of f by the system { e i μ n t } n Z , and let g=Tf. Therefore, { f n } n Z are the Fourier coefficients of the function g by the system { e i n t } n Z . From (4) and (5), it directly follows that

n Z e i λ n t e i μ n t p t p ˜ <+.

Consider the following expression:

n ( e i λ n t e i μ n t ) f n .

We have

n Z ( e i λ n t e i μ n t ) f n p t n Z e i λ n t e i μ n t | f n | ( n e i λ n t e i μ n t p t p ˜ ) 1 / p ˜ ( n | f n | q ˜ ) 1 / q ˜ ,

where 1 p ˜ + 1 q ˜ =1. By the Hausdorff-Young theorem [16], we have

( n | f n | q ˜ ) 1 / q ˜ m 1 g p ˜ ,

where m 1 is some constant. From p ˜ p and the continuous embedding L p t L p ˜ , it follows that, m 2 >0,

g p ˜ m 2 g p t m 2 T f p t .

As a result, we obtain

n ( e i λ n t e i μ n t ) f n p t m 1 m 2 T ( n e i λ n t e i μ n t p t p ˜ ) 1 / p ˜ f p t .
(7)

Let us take n 0 N such that

δ= m 1 m 2 T ( | n | > n 0 e i λ n t e i μ n t p t p ˜ ) 1 / p ˜ <1.

Assume that

ω n = { λ n , | n | > n 0 , μ n , | n | n 0 .

It is clear that the following inequality is satisfied:

n ( e i ω n t e i μ n t ) f n p t δ f p t .
(8)

It follows immediately from (7) that the expression n ( e i ω n t e i μ n t ) f n represents a function from L p t and it can be denoted by T 0 f. Drawing attention to (8) we obtain T 0 δ<1. Thus, the operator F=I+ T 0 is invertible, and it is easy to see that F[ e i μ n t ]= e i ω n t , nZ. Hence, the system { e i ω n t } n Z forms a basis in L p t isomorphic to { e i μ n t } n Z . Systems { e i λ n t } n Z and { e i ω n t } n Z differ in a finite number of elements. Therefore, by Statement 1, the system { e i λ n t } n Z is complete in L p t , if λ i λ j for ij. In the following it is necessary to apply Lemmas 1 and 2.

As a result we obtain the following theorem.

Theorem 4 Let the asymptotics (2) occur and the inequalities

1 2 p ( π ) <α< 1 2 q ( π ) ,β> 1 p ˜ ,
(9)

be fulfilled, where p ˜ =min{ p ;2}. Then the following properties of the system (1) are equivalent in L p t :

  1. (1)

    the system (1) is complete;

  2. (2)

    the system (1) is minimal;

  3. (3)

    the system (1) is ω-linear independent;

  4. (4)

    the system (1) is isomorphic to { e i n t } n N basis;

  5. (5)

    λ i λ j for ij.

Let us consider the case α= 1 2 p ( π ) . In this case, by the results of [11], the system { e i μ n t } n Z is complete and minimal in L p t , but it does not form a basis in it. Then from the previous considerations it follows that the system (1) cannot form a basis in L p t . Because otherwise, by Theorem 2, it will be isomorphic to system { e i n t } n Z in L p t , and as a result the system { e i μ n t } n Z should form a basis in L p t . This gives a contradiction.

By { v n } n Z L q t we denote the system biorthogonal to { e i μ n t } n Z . It is clear that using the estimates from [4], for v n , nZ, we establish that the following relation is true:

γ= sup n v n q t <+.

Let β>1. Then it is clear that the following inequality is satisfied:

n e i λ n t e i μ n t p t <+.

Similarly to the previous case, we can show that the operator

T ˜ f= n v n (f) ( e i λ n t e i μ n t ) ,f L p t ,

is bounded in L p t . Introducing the new system { e i ω n t } n Z in the same manner we establish the completeness of the system (1) in L p t , if λ i λ j for ij. Minimality of the system (1) in L p t follows from Lemma 3. Thus, if λ i λ j for ij and β>1, then the system (1) is complete and minimal in L p t if the condition 1 2 p ( π ) α< 1 2 q ( π ) is satisfied.

Consider the case α[ 1 2 p ( π ) , 1 2 q ( π ) ). Let, for example, α[ 1 2 q ( π ) , 1 2 q ( π ) + 1 2 ). Multiplication of each member of the system (1) by e i t 2 does not affect its basis properties in L p t . After appropriate transformations we obtain the system

e i [ α ˜ + α ˜ 0 ] t { e i λ ˜ n t } n Z ,
(10)

where α ˜ =α 1 2 and

λ ˜ n =n α ˜ signn+O ( | n | β ) ,n.

Denote by α ˜ 0 the member of O(|n | β ) in (2), corresponding to n=0. It is easy to see that condition λ i λ j is equivalent to λ ˜ i λ ˜ j . It is clear that 1 2 p ( π ) α ˜ < 1 2 q ( π ) . Then, by the previous results, the system { e i λ ˜ n t } n Z is complete and minimal in L p t , and therefore the system (10), and at the same time the system (1), is complete, but it is not minimal in L p t . Continuing this process we find that the system (1) is not complete, but it is minimal for α< 1 2 p ( π ) ; and the system (1) is complete, but it is not minimal in L p t for α 1 2 q ( π ) . Thus, the following theorem is proved.

Theorem 5 We have:

  1. (I)

    Let the asymptotics (2) occur and the inequalities (9) be fulfilled, where p ˜ =min{ p ;2}. Then the following properties of the system (1) are equivalent in L p t :

    (1.1) the system (1) is complete;

    (1.2) the system (1) is minimal;

    (1.3) the system (1) is ω-linear independent;

    (1.4) the system (1) is isomorphic to { e i n t } n N basis;

    (1.5) λ i λ j for ij.

  2. (II)

    Let β>1 and α= 1 2 p ( π ) . Then the following properties of the system (1) in L p t are equivalent:

    (2.1) the system (1) is complete;

    (2.2) the system (1) is minimal;

    (2.3) λ i λ j , for ij.

    Moreover, in this case the system (1) does not form a basis in L p t .

  3. (III)

    Let β>1 and λ i λ j , for ij. Then the system (1) is complete and minimal in L p t for 1 2 p ( π ) α< 1 2 q ( π ) , and for α< 1 2 π it is not complete, but it is minimal; and for α 1 2 q ( π ) it is complete, but it is not minimal in L p t .