Abstract
The formal potentials of the Np(VI)/Np(V) couple E f in alkaline solutions were measured potentiometrically. In 1 M LiOH, NaOH, KOH, CsOH, and (CH3)4NOH, the potentials are equal to 0.163⊥0.004, 0.125⊥0.005, 0.112⊥0.005, 0.107⊥0.005, and 0.109⊥0.005 V, respectively. In solutions of MOH+MCl [M=Li, Na, K, Cs, and (CH3)4N] at the ionic strength of 1, the dependence of E f on log[OH−] is a straight line with a slope of 0.118⊥0.010, i.e., two OH− ions participate in the electrochemical reaction between Np(VI) and Np(V). Taking into account the well-known structure of Np(VI), it can be stated that Np(V) in solutions with [OH−]=1 M and less exists in the form of the NpO2(OH) −2 anion. In 2–4 M LiOH and 2–11 M NaOH or KOH, the potential decreases with increasing alkali concentration. In these media, the anion NpO2(OH) 2−3 is formed.
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Original Russian Text © V.P. Shilov, A.B. Yusov, 2006, published in Radiokhimiya, 2006, Vol. 48, No. 1, pp. 22–27.
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Shilov, V.P., Yusov, A.B. Potential of the NP(VI)/Np(V) couple in solutions of various alkalis. Radiochemistry 48, 24–30 (2006). https://doi.org/10.1134/S1066362206010061
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DOI: https://doi.org/10.1134/S1066362206010061