1 Introduction

Maximizing power output has been the main task for the development of high-power light emitting diode (LED) array applications such as illumination. Due to the performance improvement of the diode, the output power is likely to go up to 5–10 W from a single diode. The heat flux of the high-power LED array has reached 100 W/cm2 [1], however more than half of the power is to be dissipated in form of waste heat within limited area. These will cause that the chip temperature goes up, and the emitted photons quantity is reduced. The efficiency of light is decreased, which will also affect the quality of light source and have a reduction of service life. Consequently, improved thermal management techniques are required for the LED array [2].

The concept of micro-channel heat sink is firstly introduced by Tuckerman and Pease in 1981 [1]. Its superior performances include compact solid structure, high cooling efficiency, and it is easy to integrate with the high-power optoelectronic device and so on. It is a new idea that the microchannel technology is applied in the cooling system of high-power LED array. This design scheme combines the theoretical analysis with simulation, which can effectively decrease the heat dissipation. As long as there is an appropriate coolant, it can step into commercialization stage gradually uniting with the micro-pump technology and dropping the cost.

2 Structure design

As the external heat sink for the LED array, the microchannel structure design is very critical, directly affecting the whole cooling capacity of the system. Conveniently, the structure of straight fin with the rectangular cross section is adopted in the design of microchannel [3] (see Fig. 1). The high-power LED array attached with the microchannel heat sink is shown in Fig. 2. It has five rows of LEDs, which are arranged in parallel in each row. The dies are spaced about 6 mm center-to-center distance across the length of the heat sink. LED dies are solder-bonded to the metal circuit board layer, which is directly connected with the microchannel heat sink. A cover plate is bonded to the substrate to confine the coolant in the channels. The system’s major geometric size is shown in Table 1.

Fig. 1
figure 1

Schematic structure of the microchannel heat sink with straight fins (horizontal section)

Fig. 2
figure 2

Schematic view of high-power LED array integrated with microchannel heat sink

Table 1 Material parameters and size

3 Calculation of thermal resistance

Thermal resistance is a major parameter characterizing the system thermal performance. The smaller is the thermal resistance, the better performance of cooling system. The thermal resistance in this design is comprised of three parts. R = R cond + R conv + R heat, where R cond is the heat conduction from the circuits through the substrate and heat sink interface; R conv is the heat convection from the heat sink to the coolant fluid; R heat is the thermal resistance caused by the heat of coolant absorption [4].

Referring to the thermal resistance definition (R = ∆t/Q) [5], the Fourier heat conduction law and the Newton cooling formula [6], the sum of \( R_{\text{cond}} \) and \( \mathop R\nolimits_{\text{conv}} \) can be obtained:

$$ R_{\text{cond}} + R_{\text{conv}} = \frac{{z_{\text{t}} }}{{\lambda_{\text{fin}} lw}} + \frac{1}{{hA_{\text{s}} }}, $$
(1)

where the channel inner surface area A s = αA = αlw. α is the ratio of total surface area of channel walls in contact with fluid to the area of circuit board layer. zt is the height of the channel top to heat sink surface. R cond can be made very small by locating the heat exchanger (containing the flowing coolant) very near to the heat source. R conv and R heat will be the dominant consideration in high-performance heat sink design.

d is the hydraulic diameter of the channel, defined as d = 4(cross-sectional area)/(perimeter p). For high-aspect ratio rectangular channels, when w c is largely smaller than z c, d is equal to twice as the channel width, expressed as

$$ d = 4 \times \frac{{w_{\text{c}} z_{\text{c}} }}{{2(w_{\text{c}} + z_{\text{c}} )}} \approx 2w_{\text{c}} . $$
(2)

The fluid flow involved in this paper is laminar flow, and as for the laminar flow, Nusselt number is

$$ Nu = 1.86(RePr)^{\frac{1}{3}} \left( \frac{d}{l} \right)^{\frac{1}{3}} \left( {\frac{\mu }{{\mu_{\text{w}} }}} \right)^{0.14} \approx Nu_{\infty } , $$
(3)

where \( Nu_{\infty } \) is a constant situated between 3 and 9, whose precise number is dependent on the shape of the channel [7].

The cooling fin efficiency η is the ratio of the actual heat dissipating capacity to the heat dissipating capacity assumed the fin surface in rib base temperature [8]. On the same cross section of rectangular fin, η is:

$$ \eta = \frac{\tan H}{H}, $$
(4)
$$ H = \left( {\frac{2h}{{w_{\text{w}} \lambda_{\text{fin}} }}} \right)^{\frac{1}{2}} z_{\text{c}} = \left( {\frac{{Nu_{\infty } \lambda }}{{\lambda_{\text{fin}} }}} \right)^{\frac{1}{2}} \frac{{w_{\text{c}} + z_{\text{c}} }}{{2(w_{\text{c}} \;z_{\text{c}} )^{\frac{1}{2}} }}\alpha . $$
(5)

From (4), it can be observed that \( \eta \) is the monotonically decreasing function of H, which means \( w_{\text{c}} = w_{w} \). There is a maximum for \( \eta \).

The thermal resistance produced by heat absorption of coolant is defined as

$$ R_{\text{heat}} = \frac{1}{{c_{{{\uprho}}} \rho f}}. $$
(6)

According to the thermodynamics formula [9], the coolant fluid velocity in the channel is \( v = {{w_{\text{c}}^{2} \Updelta p} \mathord{\left/ {\vphantom {{w_{\text{c}}^{2} \Updelta p} {12\,\upmu l}}} \right. \kern-0pt} {12\,\upmu l}} \), and the total coolant unit volume flow rate is \( f = n((w_{\text{c}} z_{\text{c}} )v) = {1 \mathord{\left/ {\vphantom {1 2}} \right. \kern-0pt} 2}vww_{\text{c}} \alpha \). The sum of \( R_{\text{conv}} \) and \( R_{\text{heat}} \) can be simplified into:

$$ R = R_{\text{conv}} + R_{\text{heat}} = \frac{2}{{\lambda Nu_{\infty } lw}}(w_{\text{c}} \alpha^{ - 1} \eta^{ - 1} ) + \frac{24\,\upmu l}{{\rho C_{{{\uprho}}} \Updelta pw\alpha w_{\text{c}}^{3} }}. $$
(7)

3.1 Theoretical optimization of the channel width

The size of the heat sink is fixed, and the fin takes the same width as the channel. Then the channel number is n = ((w − w c)/2 w c). Ignoring the heat conduction at the top and bottom of the heat sink channel,

$$ \alpha = \frac{{2nlz_{\text{c}} }}{{nl(w_{\text{c}} + w_{\text{w}} )}} = \frac{{2z_{\text{c}} }}{{(w_{\text{c}} + w_{\text{w}} )}} = \frac{{z_{\text{c}} }}{{w_{\text{c}} }} \Rightarrow z_{\text{c}} = \alpha w_{\text{c}} . $$
(8)

For a practical design, referring to Eq. (5) and setting α = λ fin/(Nu − λ)1/2, we have \( \eta = 0.76 \). Equation (7) is considered as a function of R and \( w_{\text{c}} \) to solve its extreme value and make it equal to zero. Then the optimum solution is got

$$ w_{\text{c}} = 2.29\root{4} \of {{\frac{{\mu \lambda l^{2} Nu_{\infty } }}{{\rho C_{{{\uprho}}} \Updelta p}}}}. $$
(9)

Setting the density of the coolant ρ = 1 g/cm3, the volumetric heat capacity C ρ = 4.2 J/(g·°C), the dynamic viscosity μ = 1.01 × 10−3 Pa·s, the fluid thermal conductivity λ = 0.5 W/(m·°C), Nu  = 6, Re = 730, and the entrance pressure of 30 psi. These are all substituted into Eq. (9), and then, the most ideal channel width is obtained w c = 0.1 mm.

3.2 Theoretical optimization of the fluid velocity

The cooling fluid flow rate is only relevant to R heat, the curve of Eq. (6) is drawn in Fig. 3 with MATLAB.

Fig. 3
figure 3

Relationship curve of thermal resistance and cooling fluid velocity

In Fig. 3, R heat rapidly decreases with the increase of f. After f ≫ 1 × 10−7 m3/s = 0.1 cm3/s, R heat have little change. However, the coolant flow rate cannot unlimitedly increase. The greater the flow velocity, the greater the pressure drop. Synthesizing the above factors, f = 1 × 10−7 m3/s is taken as the best coolant flow rate.

4 Simulation analysis

Detailed analysis on the flow field and heat transfer were performed with a computational fluid dynamics (CFD) software FLUENT to optimize the heat sink [10]. The best thermal performance of the high-power LED array is achieved, and the correctness of the theoretical analysis is verified.

Only dies are established without the phosphor and resin in the modeling. The simulation of heat sink is subject to several constraints: (i) Each one of the LED heat source is uniform and plane with a power consumption of 9 W; (ii) The heat flux density 5 × 109 W/m3 calculated by the thermodynamics formula has been imposed on the chip; (iii) The substrate is cooled through the heat conduction and the heat convection, and the coefficient of convective heat transfer is 6 W/(m2·°C) [11]; (iv) The coolant is deionized water with uniform inlet velocity, and the way of the fluid flow is laminar flow; (v) The environment temperature is 25 °C, which is the same as the initial fluid temperature; (vi) The thermal radiation effect is ignored, and the material is assumed that it is homogeneous, isotropic and continuous medium [12].

4.1 Optimize simulation of the channel width

The thermal performance of the high-power LED array with microchannel heat sink is simulated. The rectangular cross section is applied in the simulation, and the channel widths is 1, 0.5, 0.15, 0.1 and 0.08 mm, respectively. The inlet fluid velocity is 1 m/s when the height of the channel is fixed assuming that the chip power consumption is all converted into heat.

Figure 4 shows the temperature distribution of the LED array surfaces in the direction of the flow when the channel widths take on the values 1, 0.1 and 0.08 mm. It can be seen that the temperature in upstream is significantly less than that in downstream along the direction of the flow. In transverse direction of the flow, the temperature of chips in central area is higher than that in the edge. The main reasons of this phenomenon are: (i) The heat in the edge of the LED array can be dissipated from the heat sink side. However the temperature of the center LED chips is affected seriously due to the heat generated by other surrounding chips, which prevented the heat dissipation; (ii) The heat dissipation of the fluid in downstream performs slightly worse after preheating; (iii) The coolant velocity on the flow boundary is slower than that in the center of the coolant.

Fig. 4
figure 4

Temperature distribution nephogram on the surface of the microchannel heat sink (Unit: K)

Figure 5 shows the curve of the average die temperature with the change of the channel width. The smaller is the width of the channel, the greater the cooling area, the higher the cooling efficiency. However the cooling fluid dynamic viscosity increases with the decrease of the channel width, which results in slower velocity and influencing the heat dissipation [13]. When w c = 0.1 mm, the average temperature on the heat sink surface reaches the minimum, and the cooling performance is improved.

Fig. 5
figure 5

Average temperature and thermal resistance versus channel width (v = 1 m/s)

4.2 Optimize simulation of the fluid velocity

Under the condition of the same heat dissipation, the flow rates are respectively taken as 0.5, 1, 1.5, 2 m/s. The influence of the microchannel heat sink temperature distribution caused by the cooling water flow is analyzed. Figure 6 shows the average temperature of the high-power LED array microchannel heat sink with different fluid velocities.

Fig. 6
figure 6

Average die temperature versus flow rate

It can be seen from Fig. 6 that the decrease trend of the temperature of the microchannel heat sink with different channel widths is consistent. The trend of the temperature variation obviously reduced when v > 1 m/s, hence the best fluid velocity is v = 1 m/s. It is f = 1 × 10−7 m3/s when converted to volume flow rate. Figure 7 clearly shows that the flow condition of the laminar state in the channel. When the fluid velocity is 1 m/s, the channel width is 1 mm.

Fig. 7
figure 7

Coolant velocity vector field (w c = 1 mm, v = 1 m/s)

5 Conclusions

The cooling efficiency of the microchannel heat sink can be improved by increasing the channel quantity and reducing the channel diameter. However, the cooling fluid dynamic viscosity will increase with the decrease of the channel width. Considering a compromise, there is a best channel width w c = 0.1 mm achieved through the calculation and simulation.

The relationship between the heat dissipation capacity and the flow velocity are investigated. With the increase of the flow velocity, the average die temperature decreases. It will also cause the increase of the cooling fluid dynamic viscosity. The best flow rate v = 1 m/s should be obtained by the calculation and simulation. Finally, through the calculation and simulation, the minimum of thermal resistance has reached 0.019 W/°C.