1 Introduction

With the development of boundary value problems for differential equations [15], difference equations [6, 7], and the theory of time scales [812], the existence of solutions for boundary value problems on time scales have attracted many author's attention. Recently in [13], the authors considered positive solutions for boundary value problem of the following second-order dynamic equations on time scales

ϕ u Δ + a ( t ) f ( t , u ( t ) ) = 0 , t ( 0 , T ) ,
(1.1)
u ( 0 ) = i = 1 m - 2 α i u ( ξ i ) ϕ u Δ ( T ) = i = 1 m - 2 β i ϕ u Δ ( ξ i ) ,
(1.2)

where ϕ: RR is an increasing homeomorphism and positive homomorphism and ϕ(0) = 0. Here a projection ϕ: RR is called an increasing homeomorphism and homomorphism, if the following conditions are satisfied:

  1. (i)

    if xy, then ϕ(x) ≤ ϕ(y), ∀x, yR;

  2. (ii)

    ϕ is a continuous bijection and its inverse mapping is also continuous;

  3. (iii)

    ϕ (xy) = ϕ (x)ϕ (y), ∀x, yR.

By using a fixed point theorem, they obtained an existence theorem for positive solutions for this problem. In [14], Han and Jin established existence results of positive solutions for problem (1.1, 1.2) by using fixed point index theory. Sang et al. [15] considered the problem

ϕ u Δ + a ( t ) f ( t , u ( t ) ) = 0 , t ( 0 , T ) ,
(1.3)
ϕ u Δ ( 0 ) = i = 1 m - 2 α i ϕ u Δ ( ξ i ) , u ( T ) = i = 1 m - 2 β i u ( ξ i ) .
(1.4)

By using a fixed point index theorem, the existence results of positive solutions for this problem were established.

However, the nonlinear terms f in [1315] does not depend on the first order delta derivative. It is well-known that many difficulties occur when the nonlinear term f depends on the first order delta derivative explicitly. To the author's best knowledge, positive solutions are not available for the case when the boundary value problem for an increasing homeomorphism and positive homomorphism on a time scale in which the nonlinear term depends on the first order delta derivative. This article will fill this gap in the literature. In this article, we consider the existence of positive solutions for the second-order nonlinear m-point dynamic equation on a time scale with an increasing homeomorphism and positive homomorphism,

ϕ ( u Δ ) + a ( t ) f t , u ( t ) , u Δ ( t ) = 0 , t ( 0 , T )
(1.5)
u ( 0 ) = i = 1 m - 2 α i u ( ξ i ) , ϕ u Δ ( T ) = i = 1 m - 2 β i ϕ u Δ ( ξ i ) o r
(1.6)
ϕ u Δ ( 0 ) = i = 1 m - 2 α i ϕ u Δ ( ξ i ) , u ( T ) = i = 1 m - 2 β i u ( ξ i )
(1.7)

where ξ i T k k for i ∈ {1,2,...,m -2}, T is a time scale.

We will assume that the following conditions are satisfied throughout this:

(H1) α i , β i ∈ [0, +∞) satisfy 0 < i = 1 m - 2 α i < 1 , 0 < i = 1 m - 2 β i < 1 . .

(H2) f ∈ [0, T] × [0, ∞) × R → [0, ∞) is continuous.

Our main results will depend on an application of a fixed point theorem due to Avery and Peterson which deals with fixed points of a cone-preserving operator defined on an ordered Banach space. By using analysis techniques and the Avery-Peterson fixed point theorem, we obtain sufficient conditions for existence of at least three positive solutions of the problems (1.5, 1.6) and (1.5, 1.7).

2 Preliminaries

First we present some basic definitions on time scales which can be found in Atici and Guseinov [8].

A time scale T is a closed nonempty subset of R. For t < sup T and r > inf T, we define the forward jump operator σ and the backward jump operator ρ respectively by

σ ( t ) = inf { τ T | τ > t } T , ρ ( r ) = sup { τ T | τ < r } T ,

for all tT. If σ(t) > t, t is said to be right scattered, and if σ(t) = t, t is said to be right dense. If ρ(t) < t, t is said to be left scattered, and if ρ(t) = t, t is said to be left dense. A function f is left-dense continuous, if f is continuous at each left dense point in T and its right-sided limits exists at each right dense points.

For u : TR and tT, we define the delta derivative of u(t), uΔ(t), to be the number (when it exists), with the property that for each ε > 0, there is a neighborhood U of t such that

u ( σ ( t ) ) - u ( s ) - u Δ ( t ) ( σ ( t ) - s ) ε σ ( t ) - s ,

for all sU.

For u: TR and tT, we define the nabla derivative of u(t), u(t), to be the number (when it exists), with the property that for each ε > 0, there is a neighborhood U of t such that

| u ( ρ ( t ) ) u ( s ) u ( t ) ( ρ ( t ) s | ε | ρ ( t ) s | ,

for all sU.

We present here the necessary definitions of the theory of cones in Banach spaces and the Avery-Peterson fixed point theorem.

Definition 2.1. Let E be a real Banach space over R. A nonempty convex closed set PE is said to be a cone provided that:

  1. (1)

    auP, for all uP, a ≥ 0;

  2. (2)

    u, -uP implies u = 0.

Definition 2.2. An operator is called completely continuous if it is continuous and maps bounded sets into pre-compact sets.

Definition 2.3. The map α is said to be a nonnegative continuous convex functional on a cone P of a real Banach space E provided that α : P → [0, + ∞) is continuous and

α ( t x + ( 1 - t ) y ) t α ( x ) + ( 1 - t ) α ( y ) , for all x , y P , t [ 0 , 1 ] .

Definition 2.4. The map β is said to be a nonnegative continuous concave functional on a cone P of a real Banach space E provided that β : P → [0, + ∞) is continuous and

β ( t x + ( 1 - t ) y ) t β ( x ) + ( 1 - t ) β ( y ) , for all x , y P , t [ 0 , 1 ] .

Let γ, θ be nonnegative continuous convex functionals on P, α be a nonnegative continuous concave functional on P and ψ be a nonnegative continuous functional on P. Then for positive numbers a, b, c and d, we define the following convex sets:

P ( γ , d ) = { x P | γ ( x ) < d } , P ( γ , α , b , d ) = { x P | b α ( x ) , γ ( x ) d } , P ( γ , θ , α , b , c , d ) = { x P | b α ( x ) , θ ( x ) c , γ ( x ) d } ,

and a closed set

R ( γ , ψ , a , d ) = { x P | a ψ ( x ) , γ ( x ) d } .

Lemma 2.1. [16] Let P be a cone in Banach space E. Let γ, θ be nonnegative continuous convex functionals on P, α be a nonnegative continuous concave functional on P, and ψ be a nonnegative continuous functional on P satisfying

ψ ( λ x ) λ ψ ( x ) , for 0 λ 1 ,
(2.1)

such that for some positive numbers l and d,

α ( x ) ψ ( x ) , x l γ ( x )
(2.2)

for all x P ( γ , d ) ¯ . Suppose T: P ( γ , d ) ¯ P ( γ , d ) ¯ is completely continuous and there exist positive numbers a, b, c with a < b such that

(S 1) { x P ( γ , θ , α , b , c , d ) | α ( x ) > b } and α(Tx) > b for xP(γ, θ, α, b, c, d);

(S2) α(Tx) > b for xP(γ, α, b, d) with θ(Tx) > c;

(S3) 0R ( γ , ψ , a , d ) and ψ(Tx) < a for xR(γ, ψ, a, d) with ψ(x) = a.

Then T has at least three fixed points x 1 , x 2 , x 3 P ( γ , d ) ¯ such that:

γ ( x i ) d , i = 1 , 2 , 3 ; b < α ( x 1 ) ; a < ψ ( x 2 ) , α ( x 2 ) < b ; ψ ( x 3 ) < a .

3 Positive solutions for problem (1.5, 1.6)

Lemma 3.1. [13] Suppose that condition (H1) holds, then the boundary value problem

ϕ u Δ + h ( t ) = 0 , t ( 0 , T ) ,
(3.1)
u ( 0 ) = i = 1 m - 2 α i u ( ξ i ) , ϕ u Δ ( T ) = i = 1 m - 2 β i ϕ u Δ ( ξ i ) ,
(3.2)

has the unique solution

u ( t ) = 0 t ϕ - 1 0 T h ( τ ) τ - A Δ s + B

where

A = - i = 1 m - 2 β i ξ i T h ( τ ) τ 1 - i = 1 m - 2 β i , B = i = 1 m - 2 α i 0 ξ i ϕ - 1 s T h ( τ ) τ - A Δ s 1 - i = 1 m - 2 α i

Lemma 3.2. Suppose that condition (H1) holds, for hC ld [0, T] and h(t) ≥ 0, the unique solution of problem (3.1, 3.2) satisfies

(1)u(t) ≥ 0, t ∈ [0, T].

  1. (2)

    inft ∈ [0,T]u(t) ≥ δ maxt ∈ [0,T]|u(t)|, where

    δ = i = 1 m - 2 α i ξ i 1 - i = 1 m - 2 α i T + i = 1 m - 2 α i ξ i .
  2. (3)

    max t [ 0 , T ] u ( t ) l max t [ 0 , T ] T k u Δ ( t ) , where

    l = 1 - i = 1 m - 2 α i T + i = 1 m - 2 α i ξ i 1 - i = 1 m - 2 α i .

Proof. Parts (1) and (2) were established in [13]. We give the proof of (3). It is easy to check that

max t [ 0 , T ] u ( t ) = u ( T ) , min t [ 0 , T ] u ( t ) = u ( 0 ) .

For the concavity of u and the boundary condition, we get

1 - i = 1 m - 2 α i u ( 0 ) i = 1 m - 2 α i max u Δ ( t ) .

This together with conclusion (2) ensures that conclusion (3) is satisfied.

Let E be the real Banach space E = CΔ[0, σ(T)] to be the set of all Δ- differential functions with continuous Δ-derivative on [0, σ(T)] with the norm

u ( t ) 1 , T = max u 0 , T u Δ 0 , T k

where

u 0 , T = s u p { u ( t ) : t [ 0 , T ] } , u 0 , T k = s u p u Δ ( t ) : t [ 0 , T ] T k , u E .

We define the cone PE by

P = u E : u ( t ) 0 , u ( 0 ) = i = 1 m - 2 α i u ( ξ i ) , ϕ u Δ ( T ) = i = 1 m - 2 β i ϕ u Δ ( ξ i ) , u  is concave and increasing on[0, T ] E .

Let the nonnegative continuous concave functional α, the nonnegative continuous convex functionals γ, θ and the nonnegative continuous functional ψ be defined on the cone P by

γ ( u ) = max t [ 0 , T ] T k u Δ ( t ) , θ ( u ) = ψ ( u ) = max t [ 0 , T ] u ( t ) , α ( u ) = min t [ 0 , T ] u ( t ) .

By Lemmas 3.3 and 3.4, the functionals defined above satisfy

δ θ ( x ) α ( x ) θ ( x ) = ψ ( x ) , x 1 , T l γ ( x ) .

Therefore condition (2.2) of Lemma 2.1 is satisfied.

Define an operator F : PE by

F u ( t ) = 0 t ϕ - 1 s T f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 β i ξ i T f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 β i Δ s + 1 1 - i = 1 m - 2 α i i = 1 m - 2 α i 0 ξ i ϕ - 1 s T f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 β i ξ i T f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 β i Δ s

To present our main results, we assume there exist constants 0 < a, b, c, d with a < b < d such that

(A1) f ( t , u , v ) ϕ ( d ) 1 - i = 1 m - 2 β i T - i = 1 m - 2 β i ξ i , ( t , u , v ) [ 0 , 1 ] T × [ 0 , l d ] × [ - d , d ] ;

(A2) f ( t , u , v ) > ϕ b 1 - i = 1 m - 2 α i 1 - i = 1 m - 2 β i ϕ i = 1 m - 2 α i ξ i ϕ - 1 ( β i ( T - ξ i ) ) , ( t , u , v ) [ 0 , 1 ] T × [ b , b / δ ] × [ - d , d ] ;

(A3) f ( t , u , v ) < ϕ ( a ) 1 - i = 1 m - 2 β i T - i = 1 m - 2 β i ξ i ϕ T + i = 1 m - 2 α i ξ i 1 - i = 1 m - 2 α i , ( t , u , v ) [ 0 , 1 ] T × [ 0 , a ] × [ - d , d ] .

Theorem 3.1. Under the assumptions (A1)-(A3), the boundary value problem (1.5)-(1.6) has at least three positive solutions u1, u2, u3 satisfying

max t [ 0 , 1 ] T u i Δ ( t ) d , i = 1 , 2 , 3 ; b < min t [ 0 , 1 ] T u 1 ( t ) ; a < max t [ 0 , 1 ] T u 2 ( t ) , min t [ 0 , 1 ] T u 2 ( t ) max t [ 0 , 1 ] T u 3 ( t ) a . < b ;
(3.3)

Proof.

It is easy to check that problem (1.5), (1.6) has a solution u(t) if and only if u is a fixed

point of operator F.

If u P ( γ , d ) ¯ , then γ ( u ) = max t [ 0 , 1 ] T k u Δ ( t ) d . Thus

f t , u ( t ) , u Δ ( t ) ϕ ( d ) 1 - i = 1 m - 2 β i T - i = 1 m - 2 β i ξ i .

Then,

γ ( T u ) = ϕ - 1 s T f t , u ( t ) , u Δ ( t ) t + i = 1 m - 2 β i ξ i T f t , u ( t ) , u Δ ( t ) τ 1 - i = 1 m - 2 β i = ϕ - 1 1 1 - i = 1 m - 2 β i ϕ - 1 0 T f t , u ( t ) , u Δ ( t ) t - i = 1 m - 2 β i 0 ξ i f t , u ( t ) , u Δ ( t ) t d .

Hence F: P ( γ , d ) ¯ P ( γ , d ) ¯ .

To check condition (S1) of Lemma 2.1, we choose u ( t ) b δ =c. It's easy to see u ( t ) = b δ P ( γ , θ , α , b , c , d ) and α ( b δ ) >b. So { u P ( γ , θ , α , b , c , d | α ( x ) > b ) } .

If uP(γ, θ, α, b, c, d), we have b u ( t ) b δ , u Δ ( t ) d . From assumption (A2), we have

f t , u ( t ) , u Δ ( t ) ϕ b 1 - i = 1 m - 2 α i 1 - i = 1 m - 2 β i ϕ i = 1 m - 2 α i ξ i ϕ - 1 ( β i ( T - ξ i ) ) .

Thus,

α ( F u ) = 1 1 - i = 1 m - 2 α i i = 1 m - 2 α i 0 ξ i ϕ - 1 s T f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 β i ξ i T f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 β i Δ s 1 1 - i = 1 m - 2 α i i = 1 m - 2 α i 0 ξ i ϕ - 1 i = 1 m - 2 ξ i T f τ , u ( τ ) , u Δ ( τ ) 1 - i = 1 m - 2 β i Δ s > b ,

so α(Fu) > b, ∀uP(γ, θ, α, b, b/δ, d).

Second, with (4.1), we have α(Fu) ≥ δθ(Fu) > δb/δ = b for all uP(γ, α, b, d) with θ(Fu) > b/δ. Thus, condition (S2) of Lemma 2.1 is satisfied.

Finally we show that (S3) also holds. Clearly, as ψ(0) = 0 < a, we see 0 ∉ R(γ, ψ, a, d). Suppose that xR(γ, ψ, a, d) with ψ(u) = a, then assumption (A3) holds. then

ψ ( F u ) = F ( u ( T ) ) = 0 T ϕ - 1 0 T f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 β i ξ i T f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 β i Δ s + 1 1 - i = 1 m - 2 α i i = 1 m - 2 α i 0 ξ i ϕ - 1 s T f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 β i ξ i T f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 β i Δ s < a .

So we verify that condition (S3) of Lemma 2.1 is satisfied. Thus, an application of Lemma 2.1 implies that the boundary value problem (1.5)-(1.6) has at least three positive solutions u1, u2, u3 satisfying (3.3).

4 Positive solutions for problem (1.5, 1.7)

In this section, we present the existence of positive solutions for problem (1.5, 1.7).

Lemma 4.1. [15] Suppose that condition (H1) holds, then boundary value problem

ϕ ( u Δ ) + h ( t ) = 0 , t ( 0 , T ) ,
(4.1)
ϕ u Δ ( 0 ) = i = 1 m - 2 α i ϕ u Δ ( ξ i ) , u ( T ) = i = 1 m - 2 β i u ( ξ i ) ,
(4.2)

has the unique solution

u ( t ) = t T ϕ - 1 0 s h ( τ ) τ - A 1 Δ s + B 1

where

A 1 = - i = 1 m - 2 α i 0 ξ i h ( τ ) τ 1 - i = 1 m - 2 α i , B 1 = i = 1 m - 2 β i ξ i T ϕ - 1 0 s h ( τ ) τ - A 1 Δ s 1 - i = 1 m - 2 β i

Lemma 4.2. Suppose that condition (H1) holds, for hC ld [0,T] and h(t) ≥ 0, the unique solution of problem (4.1, 4.2) satisfies

  1. (1)

    u(t) ≥ 0, t ∈ [0,T]

  2. (2)

    inft ∈ [0,T]u(t) ≥ δ1 maxt ∈ [0,T]|u(t)|, where δ 1 = i = 1 m - 2 β i ( T - ξ i ) /T is a constant.

  3. (3)

    max t [ 0 , T ] u ( t ) γ max t [ 0 , T ] T k u Δ ( t ) , where l 1 =T/ 1 - i = 1 m - 2 β i . is a constant.

Proof. Parts (1) and (2) are established in [15]. It is easy to check that

max t [ 0 , T ] u ( t ) = u ( 0 ) , min t [ 0 , T ] u ( t ) = u ( T ) .

For the concavity of u and the boundary condition, we get

1 - i = 1 m - 2 β i u ( T ) i = 1 m - 2 β i ( T - ξ i ) max u Δ ( t ) .

This together with conclusion (2) ensures that conclusion (3) is satisfied. We define the cone P1E by

P 1 = u E : u ( t ) 0 , ϕ u Δ ( 0 ) = i = 1 m - 2 α i ϕ u Δ ( ξ i ) , u ( T ) = i = 1 m - 2 β i u ( ξ i ) , u  is concave and decreasing on[0, T ] E .

Define an operator G : PE by

G ( u ( t ) ) = t T ϕ - 1 0 s f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 α i 0 ξ i f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 α i Δ s + 1 1 - i = 1 m - 2 β i i = 1 m - 2 β i ξ i T ϕ - 1 0 s f τ , u ( τ ) , u Δ ( τ ) τ + i = 1 m - 2 α i 0 ξ i f τ , u ( τ ) , u Δ ( τ ) τ 1 - i = 1 m - 2 α i Δ s

To present our main results, we assume there exist constants 0 < a1, b1, c 1, d with a1 < b1 < d1 such that

A4) f ( t , u , v ) ϕ ( d 1 ) 1 - i = 1 m - 2 α i T - i = 1 m - 2 α i ( T - ξ i ) , ( t , u , v ) [ 0 , 1 ] T × [ 0 , l 1 d 1 ] × [ - d 1 , d 1 ] ;

A5) f ( t , u , v ) > 1 i = 1 m - 2 α i ξ i ϕ b 1 1 - i = 1 m - 2 β i i = 1 m - 2 β i ( T - ξ i ) , ( t , u , v ) [ 0 , 1 ] T × [ b 1 , b 1 / δ 1 ] × [ - d 1 , d 1 ] ;

A6) f ( t , u , v ) < ϕ 1 - i = 1 m - 2 β i T - i = 1 m - 2 β i ξ i 1 - i = 1 m - 2 α i T + i = 1 m - 2 α i ( T - ξ i ) ϕ ( a 1 ) , ( t , u , v ) [ 0 , 1 ] T × [ 0 , a 1 ] × [ - d 1 , d 1 ] .

Theorem 4.1. Under the assumptions (A4)-(A6), the boundary value problem (1.5), (1.7) has at least three positive solutions u1, u2, u3 satisfying

max t [ 0 , 1 ] T u i Δ ( t ) d 1 , i = 1 , 2 , 3 ; b < min t [ 0 , 1 ] T u 1 ( t ) ; a 1 < max t [ 0 , 1 ] T u 2 ( t ) , min t [ 0 , 1 ] T u 2 ( t ) max t [ 0 , 1 ] T u 3 ( t ) a 1 . < b 1 ;

The proof of Theorem 4.1 is similar with the Theorem 3.1 and is omitted here.