Abstract
Substitute \(x=1\) and get \(f(2)=1\). Because \(f(1)=2\) and \(f(2)=1,\) by the intermediate value theorem for each \(y\in [1,2]\) there exists \(z\in [1,2]\) such that \(f(z)=y.\)
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Brayman, V., Kukush, A. (2017). 2013. In: Undergraduate Mathematics Competitions (1995–2016). Problem Books in Mathematics. Springer, Cham. https://doi.org/10.1007/978-3-319-58673-1_41
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DOI: https://doi.org/10.1007/978-3-319-58673-1_41
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