1 Introduction

An important problem in nonlinear analysis is to find precise conditions for a local diffeomorphism f between two Banach spaces E, F to be a global one. Many authors have investigated this problem and have obtained results along this line, see [14]. The most famous conclusion among these may be the Hadamard-Levy theorem [2], it states that a continuously differentiable map f between two Banach spaces E and F, which is a local diffeomorphism and satisfies the condition

0 d s ω ( s ) =, [ f ( x ) ] 1 ω ( x ) ,

is a homeomorphism, where ω: R + R + is a continuous increasing mapping.

In 1974, Plastock [3] reduced the global homeomorphism problem to one of finding the conditions for a local homeomorphism to satisfy the ‘line lifting property’. This property was then shown to be equivalent to a limiting condition which was designated by condition (L).

Definition 1.1 (condition (L))

Let D an open connected set of E, the continuous mapping f:DEF satisfies condition (L) if for every continuous function q:[0,1]F with q(0)f(D), and for every x 0 f 1 (0), there exists a continuous function p:[0,b)D with p(0)= x 0 such that f(p(t))=q(t), 0t<b, then there exists a sequence t n b as n such that

lim n p( t n )

exists and is in D.

The powerful generalization of the Hadamard-Levy theorem is as follows.

Theorem 1.1 Let f:EF be a local homeomorphism. Then f is a global homeomorphism of E onto F if and only if f satisfies condition (L).

Theorem 1.1 was employed to prove the global diffeomorphism and the existence and uniqueness of solution of boundary value problems by some authors [36].

Let us consider about the Cauchy problem:

x ˙ (t)=G ( x ( t ) ) ,x(0)= x 0

with

G(x):= f ( x ) 1 ( f ( x ) f ( x 0 ) ) ,

which is equivalent to

f ( x ( t ) ) f( x 0 )= e t ( f ( x ) f ( x 0 ) ) .

In [7], Shen found that the condition (L) could be replaced with x(t) being defined on [0,+). Then the set A of all the x according to x(t) is called the attraction basin of x 0 , which means x will be attracted to x 0 as t+. Thus, Shen presented Theorem 1.2.

Lemma 1.1 [8]

Let x 0 D. Then for any xD, the path-lifting problem

{ f ( γ x ( t ) ) = f ( x 0 ) + e t ( f ( x ) f ( x 0 ) ) , t R , γ x ( 0 ) = x , γ x ( t ) D

has a unique continuous solution t γ x (t) defined on the maximal open interval I x =( t x , t x + ), t x <0< t x + +. Moreover, the set {(x,t)D×R:t I x } is open in D×R and the mapping (x,t) γ x (t) is continuous.

Theorem 1.2 Let f:EF be a local homeomorphism. Then f is a global homeomorphism of E onto F if and only if γ x (t) is defined on R for all xA, namely, γ x (t) can also be extended to −∞. Here A={xD: t x + =+} is the basin of attraction of x 0 .

In 1992, using the nonnegative auxiliary scalar coercive function, that is, continuous mappings k:E R + with k(x)+ as x+, Zampieri [9] also generalized the Hadamard-Levy theorem to show the following situation.

Theorem 1.3 [9]

The mapping f C 1 (E;F) is a global diffeomorphism onto F if

  1. (1)

    f (x)Isom(E,F) xE;

  2. (2)

    sup x r f ( x ) 1 <+ r:0<r<+;

  3. (3)

    there exists a locally Lipschitzian coercive function k:E R + which admits all D V + k(x), and it is such that sup{ D V + k(x):v= f ( x ) 1 u,xE,uF,u=1}<+.

The purpose of this paper is to generalize the above Zampieri [9] theorems by making use of Theorem 1.2 and the attraction basin. In our main Theorem 2.2, in Section 2, we replaced Zampieri’s condition (3) by the conditions:

  1. (3)

    there exists a coercive function k:E R + which admits the directional right derivatives D V + k(x), for arbitrary x, x 0 E, y=f(x)F, v= f ( x ) 1 (yf( x 0 )) and a continuous mapping h: R + R + such that D V + k(x)h(k(x)) and for any r 0 >0, the maximum solution of the initial value problem

    { r = h ( r ) , r ( 0 ) = r 0

is defined on [0,a) and there exists a sequence t n a as n such that lim n r( t n )= r is finite.

Thus Theorem 1.3 is a corollary of our theorem. Our proofs are different from the proofs given by Zampieri [9]. In Section 3, we will apply our theorems to the existence and uniqueness of solutions of the fourth order elliptic boundary value problem.

2 The main theorems

In this paper, we denote E, F, Banach spaces, D is an open subset of E. The following theorem will be employed to prove our main theorems.

Theorem 2.1 [10]

Let U(t,u) be continuous on an open (t,x)-set H and u= u 0 the maximal solution of u (t)=U(t,u), u(0)= u 0 . Let v(t) be a continuous function on [ t 0 , t 0 +b] satisfying the condition v( t 0 ) u 0 , (t,v(t))H, and v(t) has a derivative v (t) on t 0 t t 0 +b such that

v (t)U ( t , v ( t ) ) .

Then, on a common interval of existence of u 0 (t) and v(t)

v(t) u 0 (t).
(2.1)

Now, we will show our main theorems.

Theorem 2.2 Let f:DEF be a C 1 mapping, if

  1. (1)

    f (x)Isom(E,F) xE;

  2. (2)

    sup x r f ( x ) 1 <+ r:0<r<+;

  3. (3)

    there exists a coercive function k:E R + which admits the directional right derivatives D V + k(x) for arbitrary x, x 0 E, y=f(x)F, v= f ( x ) 1 (yf( x 0 )) and a continuous mapping h: R + R + such that D V + k(x)h(k(x)) and for any r 0 >0, the maximum solution of the initial value problem

    { r = h ( r ) , r ( 0 ) = r 0
    (2.2)

is defined on [0,a) and there exists a sequence t n a as n such that lim n r( t n )= r is finite. Then f is a global homeomorphism of D onto F.

Proof Since f (x)Isom(E,F) xE, f ( x ) 1 exists for all xD. Hence f is a local homeomorphism of D. Then, in the light of Theorem 1.2, we only need show that for all xA, γ x (t) can also be extended to −∞. Namely, we need to consider the problem in the opposite direction.

Consider the path-lifting problem of the mapping f

{ f ( γ x ( t ) ) = f ( x 0 ) + e t ( f ( x ) f ( x 0 ) ) , γ x ( 0 ) = x , γ x ( t ) [ 0 , a ) .

It is clear that

γ x (t)= [ f ( γ x ( t ) ) ] 1 e t ( f ( x ) f ( x 0 ) ) .

Let v= f ( γ x ( t ) ) 1 (yf( x 0 )). By the assumption (3), we have D V + k(x)h(k(x)) and the maximum solution r(t) of (2.2) is defined on [0,a) and there exists a sequence t n a as n such that lim n r( t n )= r is finite. It follows that r(t) is continuous on [0,a] and there is a constant M 1 such that |r(t)| M 1 , t[0,a]. By Theorem 2.1, we have

k ( γ x ( t ) ) |r(t)| M 1 ,t[0,a]

as well as γ x (t) M 2 , t[0,a) for some constant M 2 , since k is coercive, and let

M 3 = sup x M 2 f ( x ) 1 <+,xD.

Let t=h, t(a,0], h[0,a), a<0, for t 1 , t 2 (a,0], we have

γ x ( t 1 ) γ x ( t 2 ) = γ x ( h 1 ) γ x ( h 2 ) = h 2 h 1 γ x ( s ) d s = h 2 h 1 f ( γ x ( s ) ) 1 e s f ( x ) f ( x 0 ) d s h 1 h 2 f ( γ x ( u ) ) e u f ( x ) f ( x 0 ) d u M 3 h 1 h 2 f ( x ) f ( x 0 ) e u d u M 3 e a f ( x ) f ( x 0 ) | t 1 t 2 | .

So γ x (t) is Lipschitz continuous on (a,0], γ x (t) can also be extended to −∞, and Theorem 2.2 is proved. □

We find Zampieri’s results (Theorem 1.3) as a consequence of Theorem 2.2.

Corollary 2.1 The mapping f C 1 (E;F) is a global diffeomorphism onto F if

  1. (1)

    f (x)Isom(E,F) xE;

  2. (2)

    sup x r f ( x ) 1 <+ r:0<r<+;

  3. (3)

    there exists a locally Lipschitzian coercive function k:E R + which admits all D V + k(x), and it is such that sup{ D V + k(x):v= f ( x ) 1 u,xE,uF,u=1}<+.

Proof Let

u= y f ( x 0 ) y f ( x 0 ) .

From condition (3) for arbitrary x, x 0 E, yF, v= f ( x ) 1 (yf( x 0 )).

Define

D v + k(x)M.

Let h(t)=M, then the condition (3) of Theorem 2.2 is satisfied, and the corollary is proved. □

3 Applications of the main theorems

Consider the fourth order elliptic boundary value problem

{ Δ 2 u + f ( x , u ) = 0 , u H I  or  H I I ,
(3.1)

where f(x,u) is measurable in x for all u and has continuous partial derivatives in u for almost all x.

Alexiades and Elcart [11] studied the existence of solution of the problem (3.1), and here we will prove the existence and uniqueness of solution of the problem (3.1).

We assume that G is a bounded domain in R n with piecewise smooth boundary ∂G whose principal curvatures are bounded.

Let

H= { u W 2 , 2 W 0 1 , 2 , Δ 2 u L 2 ( G ) }

and note that H is a Hilbert space with norm given by

u 2 = G ( Δ u ) 2 + G ( Δ 2 u ) 2 ,uH,

where W 2 , 2 W 0 1 , 2 (see [[12], Chapter 7]) can be shown to consist of W 2 , 2 limits of smooth functions which vanish on the boundary.

We will first consider the differential operator L defined by

Lu= Δ 2 u+a(x)u,
(3.2)

where a(x) are bounded measurable functions defined in G.

We shall be concerned with the sets of boundary conditions

u= u n =0,on G;
(I)

or

u=Δu=0,on G;
(II)

and we define

H I = { u H , u n = 0 , x G } , H I I = { u H , Δ u W 0 1 , 2 } .

Each of these spaces is a closed subspace of H and the differential operator L is a bounded linear operator from H I or H I I into L 2 (G).

Denote

Ω=inf ( Δ u ) 2 u 2 ,
(3.3)

where the infimum is taken over H I or H I I according to whether (I) or (II) are the boundary conditions in the relevant eigenvalue problem. In fact, Ω is the first eigenvalue in the clamped plate ( Δ 2 φΩφ=0) problem.

Let

m 0 = inf x G a(x), M 0 = sup x G a(x).

Lemma 3.1 If inf x G a(x)>Ω, then L is an invertible operator of H I as well as of H I I onto L 2 (G) and

uC L u 0 ,
(3.4)

where C=2+ Ω ε 2 + 2 M 0 2 ε 2 (ε>0).

Proof Since Ω=inf ( Δ u ) 2 u 2 >0 is the first eigenvalue of Δ 2 φΩφ=0 in H I ( H I I ), it follows that for all u H I ( H I I ), zero is not an eigenvalue of Δ 2 φΩφ=0, so for every u H I ( H I I ), the operator Lu= Δ 2 u+a(x)u is an invertible operator of H I ( H I I ) onto L 2 (G).

For u H I ( H I I ), we have

( Δ u ) 2 +a u 2 =uLu ε 2 u 2 + 1 2 ε ( L u ) 2 ,

for any ε>0 and Ω< m 0 , it follows that

( Δ u ) 2 + m 0 u 2 ε 2 u 2 + 1 2 ε ( L u ) 2 , ( Δ u ) 2 ( ε 2 m 0 ) u 2 + 1 2 ε ( L u ) 2 .

From (3.3), we have

( Δ u ) 2 ( ε 2 Ω + 1 ) ( Δ u ) 2 + 1 2 ε ( L u ) 2 , ( Δ u ) 2 Ω ε 2 ( L u ) 2

and

( Δ 2 u ) 2 = ( L u a u ) 2 2 ( L u ) 2 + 2 ( a u ) 2 ( 2 + 2 a 2 ε 2 ) ( L u ) 2 ( 2 + 2 M 0 2 ε 2 ) ( L u ) 2 .

We obtain

u 2 = ( Δ u ) 2 + ( Δ 2 u ) 2 ( 2 + Ω ε 2 + 2 M 0 2 ε 2 ) ( L u ) 2 C L u 0 2 .

Here C=2+ Ω ε 2 + 2 M 0 2 ε 2 .

Now we express (3.1) in the form

F(u)= Δ 2 u+f(x,u)

and (3.1) is equivalent to the operator equation

F(u)=0,u H I ( H I I ).

For any u,φ H I ( H I I ), we have

F (u)(φ)= Δ 2 φ+ f u (x,u)φ.

 □

Theorem 3.1 Assume that

  1. (1)

    inf G × R f u (x,u)>Ω;

  2. (2)

    there exists a coercive function k: R n R + which admits the directional right derivatives D V + k(x) for arbitrary u, u 0 H I ( H I I ), y L 2 (G), v= F ( u ) 1 (yF( u 0 )) and a continuous mapping h: R + R + such that D V + k(u)h(k(u)) and for any r 0 >0, the maximum solution of the initial value problem

    { r = h ( r ) , r ( 0 ) = r 0

is defined on [0,a) and there exists a sequence { t n } such that t n an

lim n r( t n )= r

is finite. Then there is a unique solution of the equation F(u)=0 in H I ( H I I ).

Proof The condition inf G × R f u (x,u)>Ω implies that, for each u, F (u) is invertible as a linear operator from H I ( H I I ) onto L 2 (G). Furthermore, an upper bound for F ( u ) 1 is provided by (3.4) if the coefficient a(x) is identified with f u (x,u). In fact, C=O( M 0 ), where C is the constant in (3.4), implies that

[ F ( u ) ] 1 α sup G | f u (x,u)|+β

for positive constant α, β.

By the above discussion and condition (2), the assumptions of Theorem 2.2 are satisfied, F is a homeomorphism of H I ( H I I ) onto L 2 (G), and the equation F(u)=0 has a unique solution. □

Corollary 3.1 Assume that f satisfies

  1. (1)

    inf G × R f u >Ω;

  2. (2)

    uniformly in x, f u =ω(u), where ω is a continuous map satisfying a d t ω ( t ) =.

Then there is a unique solution of (3.1) in H I ( H I I ).

Proof We have from Lemma 3.1 and (3.4)

[ F ( u ) ] 1 α sup G | f u ( x , u ( x ) ) |+β

for positive constants α, β.

Denote ω 1 (t)=αω(t)+β; clearly, a d t ω 1 ( t ) =.

Let

k(u)= a u d t α sup G | f u ( x , u ) | + β = a u d t ω 1 ( t ) ,

then k(u)+ as u+.

For v= F ( u ) 1 (yF( u 0 )), u 0 H I ( H I I ), y L 2 (G), we have

D v + k ( u ) = lim s 0 + k ( u + s v ) k ( u ) s = 1 α sup G | f u ( x , u ) | + β lim s 0 + u + s v u s = 1 ω 1 ( t ) lim s 0 + u + s v u s 1 F ( u ) v = y F ( u 0 ) = M .

Let h(t)=M, the initial value problem

{ r = h ( r ) , r ( 0 ) = r 0

changes to

{ r = M , r ( 0 ) = r 0 > 0
(3.5)

the solution of equation (3.5) on [0,b) is r(t)=Mt. Hence all the conditions of Theorem 3.1 are satisfied. We get the results of this corollary. □

Corollary 3.2 (Alexiades and Elcrat)

Assume that f satisfies

  1. (1)

    inf G × R f u >Ω;

  2. (2)

    f u =O(u), uniformly in xG.

Then there is a unique solution of (3.1) in H I ( H I I ).

Proof Condition (2) implies that a d t ω ( t ) = holds, and the result of Elcart and Sigillito in [11] becomes a special case of Theorem 3.1. □