1 Introduction

The vector equilibrium problem, which contains vector optimization problems, vector variational inequality problems and vector complementarity problems as special case, has been studied (see [114]). But so far, most papers focused mainly on the existence of solutions and the properties of the solutions, there are a few papers which deal with the optimality conditions. Giannessi et al. [15] turned the vector variational inequalities with constraints into another vector variational inequalities without constraints. They gave the sufficient conditions for the efficient solution and the weakly efficient solution of the vector variational inequalities in finite dimensional spaces. Morgan and Romaniello [16] gave the scalarization and Kuhn-Tucker-like conditions for weak vector generalized quasivariational inequalities in Hilbert space by using the subdifferential of the function. Gong [17] presented the necessary and sufficient conditions for the weakly efficient solution, the Henig efficient solution and the superefficient solution for vector equilibrium problems with constraints under the condition of cone-convexity. Qiu [18] presented the necessary and sufficient conditions for globally efficient solutions of vector equilibrium problems under generalized cone-subconvexlikeness. Gong and Xiong [19] weakened the convexity assumption in [17] and obtained the necessary and sufficient conditions for weakly efficient solutions of vector equilibrium problems. Under the nearly cone-subconvexlikeness, Long et al. [20] obtained the necessary and sufficient conditions for the Henig efficient solution and the superefficient solution to the vector equilibrium problems with constraints. By using the concept of Fréchet differentiability of mapping, Wei and Gong [21] obtained the Kuhn-Tucker optimality conditions for weakly efficient solutions, Henig efficient solutions, superefficient solutions and globally efficient solutions to the vector equilibrium problems with constraints. Ma and Gong [22] obtained the first-order necessary and sufficient conditions for the weakly efficient solution, the Henig efficient solution, and the globally proper efficient solution to the vector equilibrium problems with constraints.

It is well known that the second-order tangent sets and higher-order tangent sets introduced in [23], in general, are not cones and convex sets, there are some difficulties in studying second-order and higher-order optimality conditions for general set-valued optimization problems. Until now, there are some papers to deal with higher-order optimality conditions by virtue of the higher-order derivatives or epiderivatives introduced by the higher-order tangent sets (see [2432]). However, as far as we know the second-order optimality conditions of the solutions remain unstudied in set-valued vector equilibrium problems.

Motivated by the work reported in [22, 24, 2631, 33], we introduce a new second-order derivative called second-order composed contingent epiderivative for set-valued maps and obtain some of its properties. By virtue of the second-order composed contingent epiderivative, we obtain second-order sufficient optimality conditions and necessary optimality conditions for the weakly efficient solution of set-valued vector equilibrium problems.

The rest of the paper is organized as follows. In Section 2, we recall some notions. In Section 3, we introduce second-order composed contingent epiderivatives for set-valued maps and discuss some of its properties. In Section 4, we establish second-order necessary and sufficient optimality conditions for weakly efficient solutions to set-valued vector equilibrium problems.

2 Preliminaries and notations

Throughout this paper, let X, Y, and Z be three real normed spaces, Y and Z be the topological dual spaces of Y and Z, respectively. 0 X , 0 Y and 0 Z denote the origins of X, Y, and Z, respectively. Let CY and DZ be closed convex pointed cones in Y and Z, respectively. Let M be a nonempty subset in Y. The cone hull of M is defined by cone(M)={ty|t0,yM}. Let C be the dual cone of coneC, defined by

C = { y Y : y ( c ) 0 ,  for all  c C } .

Let E be a nonempty subset of X, G:E 2 Z be a set-valued map. The domain, the graph and the epigraph of G are defined, respectively, by

dom ( G ) = { x E | G ( x ) } , graph ( G ) = { ( x , z ) X × Z | x E , z G ( x ) } , epi ( G ) = { ( x , z ) X × Z | x E , z G ( x ) + C } .

Denote

G(E)= x E G(x)and(G z 0 )(x)=G(x){ z 0 }.

Definition 2.1 (see [33, 34])

A set-valued map W:X 2 Y is said to be

  1. (i)

    strictly positive homogeneous if

    W(αx)=αW(x),α>0,xX;
  2. (ii)

    subadditive if

    W( x 1 )+W( x 2 )W( x 1 + x 2 )+C.

Definition 2.2 (see [34, 35])

Let EX be a nonempty convex set and G:E 2 Z be a set-valued map with G(x), for all xE. G is said to be D-convex on E, if for any x 1 , x 2 E and λ(0,1),

λG( x 1 )+(1λ)G( x 2 )G ( λ x 1 + ( 1 λ ) x 2 ) +D.

Let X be a normed space supplied with a distance d and K be a subset of X. We denote by d(x,K)= inf y K d(x,y) the distance from x to K, where we set d(x,)=+.

Definition 2.3 (see [23, 36])

Let K be a nonempty subset of X and xK, uX. The contingent cone of K at x is

T(K,x):={vX| t n 0, v n v, such that x+ t n v n K,nN}.

Proposition 2.1 (see [36])

Let KX and xK. The following statements are equivalent:

  1. (i)

    uT(K,x);

  2. (ii)

    there exist sequences { λ n } with λ n + and { x n } with x n K and x n x such that λ n ( x n x)v.

Proposition 2.2 (see [23])

Let KX and xK. Then T(K,x) is a closed cone.

Proposition 2.3 (see [37])

Let KX be a convex set, xK, and uT(K,x). Then

T ( T ( K , x ) , u ) =clcone ( cone ( K x ) u ) .

Let E be a nonempty subset of X, F:E×E 2 Y be a set-valued bifunction, F( x 1 , x 2 ), for all x 1 , x 2 E. We suppose that 0 Y F(x,x), for any xE.

Let x 0 E be given. F x 0 :E 2 Y is the set-valued map defined by

graph( F x 0 )= { ( x , y ) E × Y : y F ( x 0 , x ) } .

The set

epi( F x 0 )= { ( x , y ) E × Y : y F ( x 0 , x ) + C }

is called the epigraph of F x 0 . Denote

F x 0 (E)=F( x 0 ,E)= { y F ( x 0 , x ) : x E } .

Let G:E 2 Z be a set-valued map with G(x), for all xE.

In this paper, we consider the set-valued vector equilibrium problem with unconstraints (USVVEP): find x 0 E such that

F( x 0 ,x)( A 0 )=,for all xE,

where A 0 =A{ 0 Y }, A is a convex cone in Y.

We also consider the set-valued vector equilibrium problem with constraints (CSVVEP): find x 0 K such that

F( x 0 ,x)( A 0 )=,for all xK,

where A 0 =A{ 0 Y }, A is a convex cone in Y, and K:={xE:G(x)(D)}.

Definition 2.4 Let intC.

  1. (i)

    A vector x 0 E is called a weakly efficient solution of (USTVEP) if

    F( x 0 ,E)(intC)=.
  2. (ii)

    A vector x 0 K is called a weakly efficient solution of (CSTVEP) if

    F( x 0 ,K)(intC)=.

3 Second-order composed contingent epiderivatives

Let EX. Let F:E 2 Y be a set-valued map, y 0 F( x 0 ), and (u,v)X×Y. We first recall the definition of the generalized second-order composed contingent epiderivative introduced by Li et al. [24].

Definition 3.1 (see [24])

The generalized second-order composed contingent epiderivative D g ′′ F( x 0 , y 0 ,u,v) of F at ( x 0 , y 0 ) in the directive (u,v) is the set-valued map from X to Y defined by

D g ′′ F( x 0 , y 0 ,u,v)(x)= Min C { y Y | ( x , y ) T ( T ( epi ( F ) , ( x 0 , y 0 ) ) , ( u , v ) ) } .

Now we introduce the following second-order composed contingent epiderivatives of set-valued maps, and then we investigate some of its properties.

Definition 3.2 Let ( x 0 , y 0 )graph(F), (u,v)X×Y. The second-order composed contingent epiderivative D F + ( x 0 , y 0 ,u,v) of F at ( x 0 , y 0 ) in the directive (u,v) is the set-valued map from X to Y defined by

D F + ( x 0 , y 0 ,u,v)(x)= { y Y | ( x , y ) T ( T ( epi ( F ) , ( x 0 , y 0 ) ) , ( u , v ) ) } ,xX.

Proposition 3.1 Let ( x ˆ , y ˆ )graph(F), ( u ˆ , v ˆ )X×Y, and M:=dom D F + ( x ˆ , y ˆ , u ˆ , v ˆ ). Then

D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x)+C= D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x),xM.
(1)

Proof Let xM, y D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x)+C. Then there exist (x, y ¯ )T(T(epiF,( x ˆ , y ˆ )),( u ˆ , v ˆ )), and cC, such that (x,y)=(x, y ¯ +c). Since (x, y ¯ )T(T(epiF,( x ˆ , y ˆ )),( u ˆ , v ˆ )), there exist sequences ( x n , y n )(x, y ¯ ) and t n 0 + , such that

( u ˆ , v ˆ )+ t n ( x n , y n )T ( epi F , ( x ˆ , y ˆ ) ) ,nN.

Moreover, nN, there exist sequences ( x n k , y n k )( u ˆ , v ˆ )+ t n ( x n , y n ) and t n k 0 + , such that ( x ˆ , y ˆ )+ t n k ( x n k , y n k )epiF, kN. Then we have

y ˆ + t n k y n k F ( x ˆ + t n k x n k ) +C,n,kN.
(2)

Since cC, combine with (2), we have y ˆ + t n k ( y n k + t n c)= y ˆ + t n k y n k + t n k t n cF( x ˆ + t n k x n k )+C, n,kN. That is ( x ˆ , y ˆ )+ t n k ( x n k , y n k + t n c)epi F + , n,kN. Since ( x n k , y n k )( u ˆ , v ˆ )+ t n ( x n , y n ), we have ( x n k , y n k + t n c)( u ˆ , v ˆ )+ t n ( x n , y n +c) as k+. Thus,

( u ˆ , v ˆ )+ t n ( x n , y n +c)T ( epi F , ( x ˆ , y ˆ ) ) ,nN.

Simultaneously, ( x n , y n +c)(x, y ¯ +c), since ( x n , y n )(x, y ¯ ) as n+. Together with (x,y)=( x ¯ , y ¯ +c), we have (x,y)=T(T(epiF,( x ˆ , y ˆ )),( u ˆ , v ˆ )), which implies

y D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x).

So

D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x)+C D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x).

Naturally, D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x) D F + ( x ˆ , y ˆ , u ˆ , v ˆ )(x)+C. Thus (1) holds, and this completes the proof. □

By definitions and Proposition 3.1, we can conclude that the following result holds.

Proposition 3.2 Let F:E 2 Y , ( x 0 , y 0 )graph(F), (u,v)T(epi(F),( x 0 , y 0 )), and xX. Then D g ′′ F( x 0 , y 0 ,u,v)(x)+C D F + ( x 0 , y 0 ,u,v)(x).

Remark 3.1 The inclusion relation

D F + ( x 0 , y 0 ,u,v)(x) D g ′′ F( x 0 , y 0 ,u,v)(x)+C

may not hold.

Now we give the following example to explain Remark 3.1.

Example 3.1 Let C= R + 2 and F(x)={( y 1 , y 2 ) R 2 | y 1 x 2 , y 2 R}, x R + . Let ( x 0 , y 0 )=(0,(0,0)), and (u,v)=(1,(0,1)). Then

T ( T ( epi ( F ) , ( x 0 , y 0 ) ) , ( u , v ) ) = { ( x , ( y 1 , y 2 ) ) R × R 2 | x R , y 1 0 , y 2 R } .

Therefore, for any xR, we have

D g ′′ F( x 0 , y 0 ,u,v)(x)=

and

D F + ( x 0 , y 0 ,u,v)(x)= { ( y 1 , y 2 ) | y 1 0 , y 2 R } .

And then, for any xR, we have

D F + ( x 0 , y 0 ,u,v)(x) D g ′′ F( x 0 , y 0 ,u,v)(x)+C.

Now we discuss some crucial properties of the second-order composed contingent epiderivative.

Proposition 3.3 Let ( x 0 , y 0 )graphF, (u,v)T(epiF,( x 0 , y 0 )) with vC and EX be convex. If F is C-convex on E, then for all xE,

F(x){ y 0 }+C D F + ( x 0 , y 0 ,u,v)(x x 0 u).

Proof Since F is C-convex on E, epiF is a convex set. So it follows from Proposition 2.3 that

T ( T ( epi F , ( x 0 , y 0 ) ) , ( u , v ) ) =clcone ( cone ( epi F { ( x 0 , y 0 ) } ) { ( u , v ) } ) .
(3)

Since for every cC, xS and yF(x), one has

( x x 0 u , y y 0 + c ) = ( x x 0 u , y + c + v y 0 v ) { x } × ( F ( x ) + C ) { ( x 0 , y 0 ) } { ( u , v ) } .

Then it follows from (3) that

(x x 0 u,y y 0 )T ( T ( epi F , ( x 0 , y 0 ) ) , ( u , v ) ) .

Thus, by the definition of the second-order composed contingent epiderivative, we have

y y 0 +c D F + ( x 0 , y 0 ,u,v)(x x 0 u),

and then

F(x){ y 0 }+C D F + ( x 0 , y 0 ,u,v)(x x 0 u),xE.

The proof is complete. □

Proposition 3.4 Let ( x 0 , y 0 )graph(F), (u,v)T(epiF,( x 0 , y 0 )). Then

  1. (i)

    D F + ( x 0 , y 0 ,u,v) is strictly positive homogeneous.

    Moreover, if F is C-convex on a nonempty convex set E, then

  2. (ii)

    D F + ( x 0 , y 0 ,u,v) is subadditive.

Proof (i) Let α>0 and xX.

If y D F + ( x 0 , y 0 ,u,v)(x), then there exist sequences { h n } with h n 0 + and {( x n , y n )} with ( x n , y n )T(epiF,( x 0 , y 0 )) such that

( x n , y n ) ( u , v ) h n (x,y),

and then

( x n , y n ) ( u , v ) 1 α h n (αx,αy).

So (αx,αy)T(T(epiF,( x 0 , y 0 )),u,v), and then we can obtain

αy D F + ( x 0 , y 0 ,u,v)(αx).

Thus

α D F + ( x 0 , y 0 ,u,v)(x) D F + ( x 0 , y 0 ,u,v)(x)(αx).
(4)

The proof of

D F + ( x 0 , y 0 ,u,v)(αx)α D F + ( x 0 , y 0 ,u,v)(x)(x)

follows along the lines of (4). So D F + ( x 0 , y 0 ,u,v) is strictly positive homogeneous.

  1. (ii)

    Let x 1 , x 2 X, y 1 D F + ( x 0 , y 0 ,u,v)( x 1 ), y 2 D F + ( x 0 , y 0 ,u,v)( x 2 ). Then one has

    ( x 1 , y 1 )T ( T ( epi F , ( x 0 , y 0 ) ) , ( u , v ) ) ,( x 2 , y 2 )T ( T ( epi F , ( x 0 , y 0 ) ) , ( u , v ) ) .

Since F is C-convex on S, epiF is convex, and then T(T(epiF,( x 0 , y 0 )),(u,v)) is a close and convex cone. Thus we have

( x 1 + x 2 , y 1 + y 2 )T ( T ( epi F , ( x 0 , y 0 ) ) , ( u , v ) ) ,

and then

y 1 + y 2 D F + ( x 0 , y 0 ,u,v)( x 1 + x 2 ).

Thus

D F + ( x 0 , y 0 ,u,v)( x 1 )+ D F + ( x 0 , y 0 ,u,v)( x 2 ) D F + ( x 0 , y 0 ,u,v)( x 1 + x 2 )+C,

and the proof is complete. □

By the proof of Proposition 3.4, we can conclude that the following result holds.

Proposition 3.5 Let ( x 0 , y 0 )graph(F), (u,v)T(epiF,( x 0 , y 0 )), M:=dom D F + ( x 0 , y 0 ,u,v). If F is C-convex on a nonempty convex set E, then D F + ( x 0 , y 0 ,u,v)(M) is a convex cone.

4 Second-order optimality conditions of weakly efficient solutions

Throughout this section, let x 0 K, y 0 = 0 Y F x 0 ( x 0 ), intC, and intD. Firstly, we recall a definition and a result in [25].

Let KX and x 0 K. The interior tangent cone of K at x 0 defined as

IT(K, x 0 )= { u X | δ > 0  such that  x 0 + t u K , t ( 0 , δ ] , u B X ( u , δ ) } ,

where B X (u,δ) stands for the closed ball centered at uX and of radius δ.

Lemma 4.1 (see [25])

If KX is convex, x 0 K, and intK, then

IT(intK, x 0 )=intcone(K x 0 ).

Theorem 4.1 Let x 0 be a weakly efficient solution of the problem (USVVEP). Then, for every (u,v)T(epi F x 0 ,( x 0 , y 0 )) with vC, we have

[ D ( F x 0 ) + ( x 0 , y 0 , u , v ) ( x ) + line { v } ] (intC)=,
(5)

for every xdom D ( F x 0 ) + ( x 0 , y 0 ,u,v).

Proof Suppose to the contrary that there exists an xdom D ( F x 0 ) + ( x 0 , y 0 ,u,v) such that (5) does not hold. Then there exist λR and

y D ( F x 0 ) + ( x 0 , y 0 ,u,v)(x)
(6)

such that

y :=y+λvintC.
(7)

Let us consider two possible cases for λ.

Case 1: If λ>0, then it follows from Proposition 3.1 and (6) that y D ( F x 0 ) + ( x 0 , y 0 ,u,v)(x). So

( x , y ) T ( T ( epi F x 0 , ( x 0 , y 0 ) ) , ( u , v ) ) .
(8)

By definition, there exist sequences λ n + and ( u n , v n )T(epiF,( x 0 , y 0 )) such that ( u n , v n )(u,v) and

λ n ( ( u n , v n ) ( u , v ) ) ( x , y ) ,as n+.
(9)

It follows from (9), (7), and vC that there exists N 1 N such that

v n intC,n> N 1 .
(10)

Since ( u n , v n )T(epi F x 0 ,( x 0 , y 0 )), for every nN, there exist a sequence λ n k + as k+ and a sequence ( x n k , y n k )epiF, such that ( x n k , y n k )( x 0 , y 0 ) and

λ n k ( ( x n k , y n k ) ( x 0 , y 0 ) ) ( u n , v n ),as k+.
(11)

It follows from (10) that there exists N 1 (n)N such that

λ n k ( y n k y 0 ) intC,k> N 1 (n),n> N 1 ,

which implies

y n k y 0 intC,k> N 1 (n),n> N 1 .
(12)

Since ( x n k , y n k )epi F x 0 , there exists y ¯ n k F x 0 ( x n k ) such that y n k { y ¯ n k }+C. Then, by (12), we have

y ¯ n k y 0 intC,k> N 1 (n),n> N 1 .

Therefore

F ( x 0 , x n k ) (intC),

which contradicts that ( x 0 , y 0 ) is a weakly efficient solution of the problem (USVVEP).

Case 2: If λ0, then it follows from Proposition vC and (7) that yintC and

(x,y)T ( T ( epi F x 0 , ( x 0 , y 0 ) ) , ( u , v ) ) .

By a similar proof method to case 1, there exist consequences x ¯ n k and N 2 , N 2 (n)N such that

F ( x 0 , x ¯ n k ) (intC),k> N 2 (n),n> N 2 ,

which contradicts that x 0 is a weakly efficient solution of the problem (USVVEP). Thus (5) holds, and the proof is complete. □

Remark 4.1 In Theorem 4.1, we cannot use vintC instead of vC. Since ( x 0 , y 0 ) is a weakly efficient solution of the problem (USVVEP),

F x 0 (x)(intC)=,xE.
(13)

It follows from (u,v)T(epi( F x 0 ),( x 0 , y 0 )), and y 0 =0 that there exist sequences { λ n } with λ n + and ( x n , y n )epi( F x 0 ) with ( x n , y n )( x 0 ,0) such that

λ n ( ( x n , y n ) ( x 0 , 0 ) ) (u,v),as n+.

So, it follows from vintC that there exists NN such that

λ n y n intC,n>N,

which implies

y n intC,n>N.
(14)

Since ( x n , y n )epi( F x 0 ), there exists y ¯ n F x 0 ( x n ) such that y n { y ¯ n }+C. Then, combined with (14), we have

y ¯ n intC,n>N.

Therefore

F x 0 ( x n )(intC), x n E,n>max{N, N 1 },

which contradicts (13).

Next, we give an example to illustrate Theorem 4.1.

Example 4.1 Let F(x)={( y 1 , y 2 ) R 2 | y 1 R, y 2 x 2 }, x R + , ( x 0 , y 0 )=(0,(0,0)), and C= R + 2 . Then T(epi(F),( x 0 , y 0 ))={(u,( v 1 , v 2 ))R× R 2 |x R + , v 1 R, v 2 0}. Take (u,v)=(1,(1,0)). Then

T ( T ( epi ( F ) , ( x 0 , y 0 ) ) , ( u , v ) ) = { ( x , ( y 1 , y 2 ) ) R × R 2 | x R , y 1 R , y 2 0 } .

Therefore, for any xR, we have

D F + ( x 0 , y 0 ,u,v)(x)+line{v}= { ( y 1 , y 2 ) | y 1 R , y 2 0 } .

And then, for any xR, we have

[ D F + ( x 0 , y 0 , u , v ) ( x ) + line { v } ] (intC)=,

which shows that Theorem 4.1 holds.

Theorem 4.2 Let (u,v)T(epi F x 0 ( x 0 , y 0 )) with vC and EX be convex. If F x 0 is C-convex on E, and for all xE,

D ( F x 0 ) + ( x 0 , y 0 ,u,v)(x x 0 u)(intC)=,
(15)

then x 0 is a weakly efficient solution of the problem (USVVEP).

Proof It follows from Proposition 3.3 that

( F x 0 )(x) D ( F x 0 ) + ( x 0 , y 0 ,u,v)(x x 0 u),xE.

Then, from (15), we have

( F x 0 )(x)(intC)=,xE.

So x 0 is a weakly efficient solution of (USVVEP), and the proof is complete. □

Theorem 4.3 Let (u,v,w)T(epi( F x 0 ,G), x 0 , y 0 , z 0 ) with vC and wD. If x 0 is a weakly efficient solution of (CSVVEP), then for any z 0 G( x 0 )(D),

D ( F x 0 , G ) + ( x 0 , y 0 , z 0 , u , v , w + z 0 ) ( x ) cone ( int ( C × D ) + line { ( v , w + z 0 ) } ) { ( 0 Y , 0 Z ) } = ,
(16)

for all xΩ:=dom[ D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )].

Proof To prove the result by contradiction, suppose that there exists an xΩ such that (16) does not hold, that is, there exists a (y,z)Y×Z such that

(y,z) D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )(x)

and

(y,z)cone ( int ( C × D ) + line { ( v , w + z 0 ) } ) { ( 0 Y , 0 Z ) } .
(17)

Then, by the definition of second-order composed contingent epiderivatives, there exist sequences λ n + and ( u n , v n , w n )T(epi( F x 0 ,G),( x 0 , y 0 , z 0 )) such that ( u n , v n , w n )(u,v,w+ z 0 ) and

λ n ( ( u n , v n , w n ) ( u , v , w + z 0 ) ) (x,y,z),as n+.
(18)

It follows from (17) that there exist μ>0, νR, cintC, and dintD such that

y=μ(c+νv),z=μ ( d + ν ( w + z 0 ) ) .
(19)

Let us consider two possible cases for ν.

Case 1: If ν0, then, from (19), vC, and w, z 0 D, we have yintC and zintD. Thus, by (18), there exists N 1 N such that

λ n ( v n v)intC, λ n ( w n ( w + z 0 ) ) intD,n> N 1 .

Thus, it follows from vC and wD that

v n intC, w n intD,n> N 1 .
(20)

Since ( u n , v n , w n )T(epi( F x 0 ,G),( x 0 , y 0 , z 0 )), for every nN, there exist a sequence { λ n k } with λ n k + as k+ and a sequence ( x n k , y n k , z n k )epi( F x 0 ,G), such that ( x n k , y n k , z n k )( x 0 , y 0 , z 0 ) and

λ n k ( ( x n k , y n k , z n k ) ( x 0 , y 0 , z 0 ) ) ( u n , v n , w n ),as k+.
(21)

It follows from (20) and (21) that there exists N 1 (n)N such that

λ n k ( y n k y 0 ) intC, λ n k ( z n k z 0 ) intD,k> N 1 (n),n> N 1 ,

which implies

y n k y 0 intC, z n k z 0 intD,k> N 1 (n),n> N 1 .
(22)

Since ( x n k , y n k , z n k )epi( F x 0 ,G), there exist y ¯ n k F x 0 ( x n k ), z ¯ n k G( x n k ), cC and dD such that y n k = y ¯ n k +c and z n k = z ¯ n k +d. Then, by (22) and y 0 =0, we have

y ¯ n k intC,k> N 1 (n), z ¯ n k intD,n> N 1 .

So

F x 0 ( x n k ) intC, x n k K,k> N 1 (n),n> N 1 ,

which contradicts that x 0 is a weakly efficient solution of (CSVVEP).

Case 2: If ν>0, then, from (19), we get y=μν( 1 ν c+v) and z=μν( 1 ν d+(w+ z 0 )). So it follows from cintC and dintD that

yintcone ( C + { v } ) ,z=intcone ( D + { w + z 0 } ) .
(23)

Then, by Lemma 4.1 and (23), we get yIT(intC,v) and z=IT(intD,w+ z 0 ). Therefore, there exists δ>0 such that

v+δ y intC, y B Y (y,δ),
(24)
w+ z 0 +δ z intD, y B Z (z,δ).
(25)

For this δ, it follows from (18) that there exists N 2 N such that

δ λ n >1, λ n ( v n v) B Y (y,δ), λ n ( w n ( w + z 0 ) ) B Z (z,δ),n> N 2 .

Then, by (24) and (25), we have

v n ( 1 1 δ λ n ) vintC, w n ( 1 1 δ λ n ) (w+ z 0 )intD,n> N 2 .

Thus, from vC, w, z 0 D, and δ λ n >1, n> N 2 , we have

v n intC, w n intD,n> N 2 .

By a similar proof method to case 1, there exists N 2 (n)N such that

F x 0 ( x n k ) intC, x n k K,k> N 2 (n),n> N 2 ,

which contradicts that x 0 is a weakly efficient solution of (CSVVEP). Thus (16) holds and the proof is complete. □

Theorem 4.4 Let (u,v,w)T(epi( F x 0 ,G), x 0 , y 0 , z 0 ) with vC and wD. If x 0 is a weakly efficient solution of (CSVVEP), then for any z 0 G( x 0 )(D),

D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )(x) ( int ( C × D ) + { ( 0 , z 0 ) } ) =,
(26)

for all xΩ:=dom[ D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )].

Proof To prove the result by contradiction, suppose that there exists an xΩ such that (26) does not hold, that is, there exists (y,z)Y×Z such that

( y , z ) D ( F x 0 , G ) + ( x 0 , y 0 , z 0 , u , v , w + z 0 ) ( x ) , ( y , z ) ( int ( C × D ) + { ( 0 , z 0 ) } ) .
(27)

Then, by the definition of second-order composed contingent epiderivatives, there exist sequences λ n + and ( u n , v n , w n )T(epi( F x 0 ,G),( x 0 , y 0 , z 0 )) such that ( u n , v n , w n )(u,v,w+ z 0 ) and

λ n ( ( u n , v n , w n ) ( u , v , w + z 0 ) ) (x,y,z),as n+.
(28)

It follows from (27) that there exist cintC and dintD such that

y=c,z=(d+ z 0 ).
(29)

Thus, by (28), there exists N 1 N such that

λ n >1, λ n ( v n v)intC, λ n ( w n ( w + z 0 ) ) (intD+ z 0 ),n> N 1 .

Thus, it follows from vC and w, z 0 D that

v n intC, w n intD,n> N 1 .
(30)

Since ( u n , v n , w n )T(epi( F x 0 ,G),( x 0 , y 0 , z 0 )), for every nN, there exist a sequence { λ n k } with λ n k + as k+ and a sequence ( x n k , y n k , z n k )epi( F x 0 ,G), such that ( x n k , y n k , z n k )( x 0 , y 0 , z 0 ) and

λ n k ( ( x n k , y n k , z n k ) ( x 0 , y 0 , z 0 ) ) ( u n , v n , w n ),as k+.
(31)

It follows from (30) and (31) that there exists N 1 (n)N such that

λ n k ( y n k y 0 ) intC, λ n k ( z n k z 0 ) intD,k> N 1 (n),n> N 1 ,

which implies

y n k y 0 intC, z n k z 0 intD,k> N 1 (n),n> N 1 .
(32)

Since ( x n k , y n k , z n k )epi( F x 0 ,G), there exist y ¯ n k F x 0 ( x n k ), z ¯ n k G( x n k ), cC, and dD such that y n k = y ¯ n k +c and z n k = z ¯ n k +d. Then, by (32) and y 0 =0, we have

y ¯ n k intC,k> N 1 (n), z ¯ n k intD,n> N 1 .

So

F x 0 ( x n k ) intC, x n k K,k> N 1 (n),n> N 1 ,

which contradicts that x 0 is a weakly efficient solution of (CSVVEP). Thus (26) holds and the proof is complete. □

Theorem 4.5 Let EX be a nonempty convex set, z 0 G( x 0 )(D) and (u,v,w)X×(C)×(D). Suppose that the following conditions are satisfied:

  1. (i)

    ( F x 0 ,G) is C×D-convex on E.

  2. (ii)

    x 0 is a weakly efficient solution of (CSVVEP).

Then there exist ϕ C and ψ D , not both zero functionals, such that

inf { ( y , z ) A ϕ ( y ) + ψ ( z ) } =0andψ( z 0 )=0,

where A:= x Ω D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )(x) and Ω:=dom[ D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w+ z 0 )].

Proof Define M=A+( 0 Y , z 0 ). By Proposition 3.5, we see that M is a convex set. By Theorem 4.4, we get

M ( int ( C × D ) ) =.

By the separation theorem of convex sets, there exist ϕ Y and ψ Z , not both zero functionals, such that

ϕ(y)+ψ(z)ϕ( y ¯ )+ψ( z ¯ ),for all (y,z)M,( y ¯ , z ¯ )int(C×D).
(33)

Since intC{ 0 Y } and intD{ 0 Z } are cones, by (33), we have

ϕ( y ¯ )ψ( z ¯ ),for all ( y ¯ , z ¯ )intC×intD,
(34)

and

ϕ(y)+ψ(z)0,for all (y,z)M.
(35)

From (34), we find that ψ is bounded below on intD. Then ψ(z)0, for all zintD. Naturally ψ D .

By a similar line of proof to ψ D , we can obtain ϕ C .

It follows from Proposition 3.5 that ( 0 Y , 0 Z )A, and then, from z 0 D, ψ D , and (35), we obtain

inf { ( y , z ) A ϕ ( y ) + ψ ( z ) } =0andψ( z 0 )=0.

The proof is complete. □

Theorem 4.6 Let EX be a nonempty convex set, (u,v,w)T(epi( F x 0 ,G), x 0 , y 0 , z 0 ) with vC and wD and z 0 G( x 0 )(D). Suppose that the following conditions are satisfied:

  1. (i)

    ( F x 0 ,G) is C×D-convex on E;

  2. (ii)

    there exist ϕ C {0} and ψ D such that

    inf { ( y , z ) V ϕ ( y ) + ψ ( z ) } =0andψ( z 0 )=0,

where U:= x Ω D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w)(x) and V:=dom[ D ( F x 0 , G ) + ( x 0 , y 0 , z 0 ,u,v,w)].

Then x 0 is a weakly efficient solution of (CSVVEP).

Proof To prove the result by contradiction, suppose that x 0 is not a weakly efficient solution of (CSVVEP). Then there exist x K and y F( x 0 , x ) such that y intC. Since x K, there exists z G( x )(D). It follows from assumption (i) and Proposition 3.3 that we have

( y y 0 , z z 0 ) U,

and then, from assumption (ii), we obtain

ϕ ( y y 0 ) +ψ ( z z 0 ) 0.
(36)

Since y y 0 = y intC, ϕ C {0}, ϕ( y y 0 )<0. It follows from z G( x )(D), ψ D , and ψ( z 0 )=0 that ψ( z z 0 )0, thus

ϕ ( y y 0 ) +ψ ( z z 0 ) <0,

which contradicts (36). So x 0 is a weakly efficient solution of (CSVVEP), and this completes the proof. □

5 Conclusions

In this paper, we propose a new concept of a second-order derivative for set-valued maps, which is called the second-order composed contingent epiderivative, and we investigate some of its properties. Simultaneously, by virtue of the derivative, we obtain second-order sufficient optimality conditions and necessary optimality conditions for set-valued equilibrium problems.