## 1. Introduction

The stability problem for functional equations is related to the following question originated by Ulam [1] in 1940, concerning the stability of group homomorphisms: Let (G1, .) be a group and let (G2, *) be a metric group with the metric d(., .). Given ε > 0, does there exist δ > 0 such that, if a mapping h : G1→ G2 satisfies the inequality d(h(x.y), h(x) * h(y)) < δ for all x, yG1, then there exists a homomorphism H : G1→ G2 with d(h(x), H(x)) < ε for all xG1?

In 1941, Hyers [2] gave a first affirmative answer to the question of Ulam for Banach spaces. Later, Rassias in [3] provided a remarkable generalization of the Hyers' result by allowing the Cauchy difference to be bounded for the first time, in the subject of functional equations and inequalities. Gǎvruta then generalized the Rassias' result in [4] for the unbounded Cauchy difference.

The functional equation

$f\left(x+y\right)+f\left(x-y\right)=2f\left(x\right)+2f\left(y\right)$
(1.1)

is called quadratic functional equation. Also, every solution (for example f(x) = ax2) of functional Equation (1.1) is said to be a quadratic mapping. A Hyers-Ulam stability problem for the quadratic functional equation was proved by Skof [5] for mappings $f:\mathcal{X}\to \mathcal{Y}$, where $\mathcal{X}$ is a normed space and $\mathcal{Y}$ is a Banach space. Cholewa [6] noticed that the theorem of Skof is still true if the relevant domain $\mathcal{X}$ is replaced by an abelian group. In [7] Czerwik proved the Hyers-Ulam-Rassias stability of the quadratic functional equation. Several functional equations have been extensively investigated by a number of authors (for instances, [810]).

Jun and Kim [11] introduced the functional equation

$f\left(2x+y\right)+f\left(2x-y\right)=2f\left(x+y\right)+2f\left(x-y\right)+12f\left(x\right)$
(1.2)

which is somewhat different from (1.1). It is easy to see that function f(x) = ax3 is a solution of (1.2). Thus, it is natural that Equation (1.2) is called a cubic functional equation and every solution of this cubic functional equation is said to be a cubic function. One year after that, they solved the generalized Hyers-Ulam-Rassias stability of a cubic functional equation f(x + 2y) + f(x - 2y) + 6f(x) = f(x + y) + 4f(x - y) in Jun and Kim [12]. Since then, a number of authors (for details see [13, 14]) proved the stability problems for cubic functional equation.

Recently, Bodaghi et al in [15] proved the superstability of quadratic double centralizers and of quadratic multipliers on Banach algebras by fixed point methods. Also, the stability and the superstability of cubic double centralizers of Banach algebras which are strongly without order had been established in Eshaghi Gordji et al. [16].

In this paper, we remove the condition strongly without order and investigate the generalized Hyers-Ulam-Rassias stability and the superstability by using the alternative fixed point for cubic functional Equation (1.2) and their correspondent cubic multipliers.

## 2. Stability of cubic function equations

Throughout this section, X is a normed vector space and Y is a Banach space. For the given mapping f : XY , we consider

$D\phantom{\rule{0.3em}{0ex}}f\left(x,y\right):=f\left(\mathsf{\text{2}}x+y\right)+f\left(\mathsf{\text{2}}x-y\right)-\mathsf{\text{2}}f\left(x+y\right)-\mathsf{\text{2}}f\left(x-y\right)-\mathsf{\text{12}}f\left(x\right)$

for all x, y ∈ X.

We need the following known fixed point theorem, which is useful for our goals (an extension of the result was given in Turinici [17]).

Theorem 2.1. (The fixed point alternative [18]) Suppose that (Ω, d) a complete generalized metric space and let$\mathcal{J}:\Omega \to \Omega$be a strictly contractive mapping with Lipschitz constant L < 1. Then for each element x ∈ Ω, either$d\left({\mathcal{J}}^{n}x,{\mathcal{J}}^{n+1}x\right)=\infty$for all n ≥ 0, or there exists a natural number n0such that:

(i) $d\left({\mathcal{J}}^{n}x,{\mathcal{J}}^{n+1}x\right)<\infty$for all n ≥ n0;

(ii) the sequence$\left\{{\mathcal{J}}^{n}x\right\}$is convergent to a fixed point y* of$\mathcal{J}$;

(iii) y* is the unique fixed point of$\mathcal{J}$in the set

$\Lambda =\left\{y\in \Omega :d\left({\mathcal{J}}^{{n}_{0}}x,\phantom{\rule{2.77695pt}{0ex}}y\phantom{\rule{2.77695pt}{0ex}}\right)\phantom{\rule{2.77695pt}{0ex}}<\infty \right\};$

(iv) $d\left(y,{y}^{*}\right)\le \frac{1}{1-L}d\left(y,\phantom{\rule{2.77695pt}{0ex}}\mathcal{J}\phantom{\rule{0.3em}{0ex}}y\right)$for all y ∈ Λ.

Theorem 2.2. Let f : X → Y be a mapping with f(0) = 0, and let ψ : X × X → [0, ∞) be a function satisfying

$\underset{n\to \infty }{lim}\frac{\psi \left({2}^{n}x,{2}^{n}y\right)}{{8}^{n}}=0$
(2.1)

and

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}\le \psi \left(x,y\right)$
(2.2)

for all x, yX. If there exists L ∈ (0, 1) such that

$\psi \left(2x,\phantom{\rule{2.77695pt}{0ex}}0\right)\le 8L\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0\right)$
(2.3)

for all xX, then there exists a unique cubic mapping C : X → Y such that

$||f\left(x\right)-C\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \frac{L}{2\left(1-L\right)}\psi \left(x,0\right)$
(2.4)

for all xX.

Proof: We consider the set Ω := {g : XY | g(0) = 0} and introduce the generalized metric on Ω as follows:

$d\left({g}_{1},\phantom{\rule{2.77695pt}{0ex}}{g}_{2}\right):=inf\left\{C\in \left(0,\infty \right):\phantom{\rule{2.77695pt}{0ex}}||{g}_{1}\left(x\right)-{g}_{2}\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le C\psi \left(x,0\right)\phantom{\rule{2.77695pt}{0ex}}\mathsf{\text{for}}\phantom{\rule{2.77695pt}{0ex}}\mathsf{\text{all}}\phantom{\rule{2.77695pt}{0ex}}x\in X\right\}$

if there exists such constant C, and d(g1, g2) = ∞, otherwise. One can prove that the metric space (Ω, d) is complete. Now, we define the mapping $\mathcal{J}:\Omega \to \Omega$ by

$\mathcal{J}\phantom{\rule{0.3em}{0ex}}g\left(x\right)=\frac{1}{8}g\left(2x\right),\phantom{\rule{2.77695pt}{0ex}}\phantom{\rule{2.77695pt}{0ex}}\left(x\in X\right).$

If g1, g2 ∈ Ω such that d(g1, g2) < C, by definition of d and $\mathcal{J}$, we have

$∥\frac{1}{8}{g}_{1}\left(2x\right)-\frac{1}{8}{g}_{2}\left(2x\right)∥\le \frac{1}{8}C\psi \left(2x,\phantom{\rule{2.77695pt}{0ex}}0\right)$

for all xX. By using (2.3), we get

$∥\frac{1}{8}{g}_{1}\left(2x\right)-\frac{1}{8}{g}_{2}\left(2x\right)∥\le C\phantom{\rule{0.3em}{0ex}}L\psi \left(x,0\right)$

for all xX. The above inequality shows that $d\left(\mathcal{J}{g}_{1},\mathcal{J}{g}_{2}\right)\le Ld\left({g}_{1},{g}_{2}\right)$ for all g1, g2 ∈ Ω. Hence, $\mathcal{J}$ is a strictly contractive mapping on Ω with Lipschitz constant L. Putting y = 0 in (2.2), using (2.3), and dividing both sides of the resulting inequality by 16, we have

$∥\frac{1}{8}f\left(2x\right)-f\left(x\right)∥\le \frac{1}{16}\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0\right)\le \frac{1}{2}L\psi \left(\frac{x}{2},0\right)$

for all xX. Thus,$d\left(f,\phantom{\rule{2.77695pt}{0ex}}\mathcal{J}\phantom{\rule{0.3em}{0ex}}f\right)\le \frac{L}{2}<\infty$. By Theorem 2.1, the sequence $\left\{{\mathcal{J}}^{n}f\right\}$ converges to a fixed point C : XY in the set Ω1 = {g ∈ Ω; d(f, g) < ∞}, that is

$C\left(x\right)=\underset{n\to \infty }{lim}\frac{f\left({2}^{n}x\right)}{{8}^{n}}$
(2.5)

for all xX. By Theorem 2.1, we have

$d\left(f,\phantom{\rule{2.77695pt}{0ex}}C\right)\le \frac{d\left(f,\mathcal{J}\phantom{\rule{2.77695pt}{0ex}}f\right)}{1-L}\le \frac{L}{2\left(1-L\right)}.$
(2.6)

It follows from (2.6) that (2.4) holds for all xX. Substituting x, y by 2 nx, 2 ny in (2.2), respectively, and applying (2.1) and (2.5), we have

$\begin{array}{lll}\hfill ||DC\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}& =\underset{n\to \infty }{lim}\frac{1}{{8}^{n}}||D\phantom{\rule{0.3em}{0ex}}f\left({2}^{n}x,\phantom{\rule{2.77695pt}{0ex}}{2}^{n}y\right)||\phantom{\rule{2em}{0ex}}& \hfill \text{(1)}\\ \le \underset{n\to \infty }{lim}\frac{1}{{8}^{n}}\psi \left({2}^{n}x,\phantom{\rule{2.77695pt}{0ex}}{2}^{n}y\right)=0\phantom{\rule{2em}{0ex}}& \hfill \text{(2)}\\ \hfill \text{(3)}\end{array}$

for all xX. Therefore C is a cubic mapping, which is unique. □

Corollary 2.3. Let p and λ be non-negative real numbers such that p < 3. Suppose that f : XY is a mapping satisfying

$||Df\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}\le \lambda \left(||x|{|}^{p}+||y|{|}^{p}\right)$
(2.7)

for all x, yX. Then, there exists a unique cubic mapping C : XY such that

$||f\left(x\right)-C\left(x\right)||\phantom{\rule{0.3em}{0ex}}\le \frac{{2}^{p}\lambda }{2\left(8-{2}^{p}\right)}||x|{|}^{p}$
(2.8)

for all xX.

Proof: The result follows from Theorem 2.2 by using ψ(x, y) = λ(||x|| p + ||y|| p ). □

Now, we establish the superstability of cubic mapping on Banach spaces.

Corollary 2.4. Let p, q, λ be non-negative real numbers such that p, q ∈ (3, ∞). Suppose a mapping f : XY satisfies

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}\le \lambda ||x|{|}^{q}||y|{|}^{p}$
(2.9)

for all x, yX. Then, f is a cubic mapping on X.

Proof: Letting x = y = 0 in (2.9), we get f(0) = 0. Once more, if we put x = 0 in (2.9), we have f(2x) = 8f(x) for all xX. It is easy to see that by induction, we have f(2 nx) = 8 nf(x), and so $f\left(x\right)=\frac{f\left({2}^{n}x\right)}{{8}^{n}}$ for all xX and n ∈ ℕ. Now, it follows from Theorem 2.2 that f is a cubic mapping. □

Note that in Corollary 2.4, if p + q ∈ (0, 3) and p > 0 such that the inequality (2.9) holds, then by applying ψ(x, y) = λ||x|| p ||y|| q in Theorem 2.2, f is again a cubic mapping.

Theorem 2.5. Let f : XY be a mapping with f(0) = 0, and let ψ : X × X → [0, ∞) be a function satisfying

$\underset{n\to \infty }{lim}{8}^{n}\psi \left(\frac{x}{{2}^{n}},\phantom{\rule{2.77695pt}{0ex}}\frac{y}{{2}^{n}}\right)=0$
(2.10)

and

$||Df\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}\le \psi \left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)$
(2.11)

for all x, yX. If there exists L ∈ (0, 1) such that

$\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0\right)\le \frac{1}{8}L\psi \left(2x,\phantom{\rule{2.77695pt}{0ex}}0\right)$
(2.12)

for all xX, then there exists a unique cubic mapping C : XY such that

$||f\left(x\right)-C\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \frac{L}{16\left(1-L\right)}\psi \left(x,0\right)$
(2.13)

for all xX.

Proof: We consider the set Ω := {g : XY | g(0) = 0} and introduce the generalized metric on Ω:

$d\left({g}_{1},\phantom{\rule{2.77695pt}{0ex}}{g}_{2}\right):=inf\left\{C\in \left(0,\infty \right):\phantom{\rule{2.77695pt}{0ex}}||{g}_{1}\left(x\right)-{g}_{2}\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le C\psi \left(x,0\right)\phantom{\rule{2.77695pt}{0ex}}\phantom{\rule{2.77695pt}{0ex}}\forall x\in X\right\}$

if there exists such constant C, and d(g1, g2) = ∞, otherwise. It is easy to show that (Ω, d) is complete. We will show that the mapping $\mathcal{J}:\Omega \to \Omega$ defined by $\mathcal{J}\phantom{\rule{0.3em}{0ex}}g\left(x\right)=8g\left(\frac{x}{2}\right)$; (xX) is strictly contractive. For given g1, g2 ∈ Ω such that d(g1, g2) < C, we have

$∥8{g}_{1}\left(\frac{x}{2}\right)-8{g}_{2}\left(\frac{x}{2}\right)∥\le \frac{1}{8}C\psi \left(2x,\phantom{\rule{2.77695pt}{0ex}}0\right)$

for all xX. By using (2.12), we obtain

$∥8{g}_{1}\left(\frac{x}{2}\right)-8{g}_{2}\left(\frac{x}{2}\right)∥\le CL\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0\right)$

for all xX. It follows from the last inequality that $d\left(\mathcal{J}{g}_{1},\mathcal{J}{g}_{2}\right)\le Ld\left({g}_{1},{g}_{2}\right)$ for all g1, g2 ∈ Ω. Hence, $\mathcal{J}$ is a strictly contractive mapping on Ω with Lipschitz constant L. By putting y = 0 and replacing x by $\frac{x}{2}$ in (2.11) and using (2.12), then by dividing both sides of the resulting inequality by 2, we have

$∥8f\left(\frac{x}{2}\right)-f\left(x\right)∥\le \frac{1}{2}\psi \left(\frac{x}{2},0\right)\le \frac{1}{16}L\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0\right)$

for all xX. Hence, $d\left(f,\mathcal{J}f\right)\le \frac{L}{16}<\infty$. By applying the fixed point alternative, there exists a unique mapping C : XY in the set Ω1 = {g ∈ Ω; d(f, g) < ∞} such that

$C\left(x\right)=\underset{n\to \infty }{lim}{8}^{n}f\left(\frac{x}{{2}^{n}}\right)$
(2.14)

for all xX. Again, Theorem 2.1 shows that

$d\left(f,\phantom{\rule{2.77695pt}{0ex}}C\right)\le \frac{d\left(f,\mathcal{J}\phantom{\rule{0.3em}{0ex}}f\right)}{1-L}\le \frac{L}{16\left(1-L\right)}$
(2.15)

where the inequality (2.15) implies the relation (2.13). Replacing x, y by 2 nx, 2 ny in (2.11), respectively, and using (2.10) and (2.14), we conclude

$\begin{array}{lll}\hfill ||DC\left(x,y\right)||\phantom{\rule{2.77695pt}{0ex}}& =\underset{n\to \infty }{lim}{8}^{n}∥D\phantom{\rule{0.3em}{0ex}}f\left(\frac{x}{{2}^{n}},\frac{y}{{2}^{n}}\right)∥\phantom{\rule{2em}{0ex}}& \hfill \text{(1)}\\ \le \underset{n\to \infty }{lim}{8}^{n}\psi \phantom{\rule{2.77695pt}{0ex}}\left(\frac{x}{{2}^{n}},\phantom{\rule{2.77695pt}{0ex}}\frac{y}{{2}^{n}}\right)=0\phantom{\rule{2em}{0ex}}& \hfill \text{(2)}\\ \hfill \text{(3)}\end{array}$

for all xX. Therefore C is a cubic mapping. □

Corollary 2.6. Let p and λ be non-negative real numbers such that p > 3. Suppose that f : XY is a mapping satisfying

$||D\phantom{\rule{0.3em}{0ex}}f\phantom{\rule{2.77695pt}{0ex}}\left(x,\phantom{\rule{2.77695pt}{0ex}}y\phantom{\rule{2.77695pt}{0ex}}\right)\phantom{\rule{2.77695pt}{0ex}}||\phantom{\rule{2.77695pt}{0ex}}\le \lambda \left(||x|{|}^{p}+||y|{|}^{p}\right)$

for all x, yX. Then there exists a unique cubic mapping C : XY such that

$||f\left(x\right)-C\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \frac{\lambda }{2\left({2}^{p}-8\right)}||x|{|}^{p}$

for all xX.

Proof: It is enough to let ψ(x, y) = λ(||x|| p + ||y|| p ) in Theorem 2.5. □

Corollary 2.7. Let p, q, λ be non-negative real numbers such that p + q ∈ (0, 3) and p > 0. Suppose a mapping f : X → Y satisfies

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)||\phantom{\rule{2.77695pt}{0ex}}\le \lambda ||x|{|}^{q}||y|{|}^{p}$
(2.16)

for all x, yX. Then, f is a cubic mapping on X.

Proof: If we put x = y = 0 in (2.16), we get f(0) = 0. Again, putting x = 0 in (2.16), we conclude that $f\left(x\right)=8f\left(\frac{x}{2}\right)$, and thus $f\left(x\right)={8}^{n}f\left(\frac{x}{{2}^{n}}\right)$ for all xX and n ∈ ℕ. Now, we can obtain the desired result by Theorem 2.5. □

One should remember that if a mapping f : XY satisfies the inequality (2.16), where p, q, λ be non-negative real numbers such that p + q > 3 and p > 0, then it is obvious that f is a cubic mapping on X by putting ψ(x, y) = λ||x|| p ||y|| q in Theorem 2.5.

## 3. Stability of cubic multipliers

In this section, we investigate the Hyers-Ulam stability and the superstability of cubic multipliers.

Definition 3.1. A cubic multiplier on an algebra A is a cubic mapping T : AA such that aT(b) = T(a)b for all a, bA.

The following example introduces a cubic multiplier on Banach algebras.

Example. Let (A, ||·||) be a Banach algebra. Then, we take B = A × A × A × A × A × A = A6. Let a = (a1, a2, a3, a4, a5, a6) be an arbitrary member of B where we define $|\phantom{\rule{0.3em}{0ex}}||a||\phantom{\rule{0.3em}{0ex}}|\phantom{\rule{2.77695pt}{0ex}}={\sum }_{i=1}^{6}||{a}_{i}||$. It is easy to see (B, |||·|||)) is a Banach space. For two elements a = (a1, a2, a3, a4, a5, a6) and b = (b1, b2, b3, b4, b5, b6) of B, we define ab = (0, a1b4, a1b5 + a2b6, 0, a4b6, 0). It is easy to show that B is a Banach algebra. We define T : BB by T(a) = a3 for all aB. It is shown in Eshaghi Gordji et al. [16] that T is a cubic multiplier on A.

Theorem 3.2. Let f : AA be a mapping with f(0) = 0 and let ψ: A4 → [0, ∞) be a function such that

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)+f\left(z\right)w-z\phantom{\rule{0.3em}{0ex}}f\left(w\right)||\phantom{\rule{2.77695pt}{0ex}}\le \psi \left(x,y,\phantom{\rule{2.77695pt}{0ex}}z,\phantom{\rule{2.77695pt}{0ex}}w\right)$
(3.1)

for all x, y, z, wA. If there exists a constant L ∈ (0, 1) such that

$\psi \left(2x,\phantom{\rule{2.77695pt}{0ex}}2y,\phantom{\rule{2.77695pt}{0ex}}2z,\phantom{\rule{2.77695pt}{0ex}}2w\right)\le 8L\psi \left(x,y,\phantom{\rule{2.77695pt}{0ex}}z,\phantom{\rule{2.77695pt}{0ex}}w\right)$
(3.2)

for all x, y, z, wA, then there exists a unique cubic multiplier T on A satisfying

$||f\left(x\right)-T\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \frac{L}{2\left(1-L\right)}\psi \left(x,x,\phantom{\rule{2.77695pt}{0ex}}0,0\right)$
(3.3)

for all xA.

Proof. It follows from the relation (3.2) that

$\underset{n\to \infty }{lim}\frac{\psi \left({2}^{n}x,{2}^{n}y,{2}^{n}z,{2}^{n}w\right)}{{8}^{n}}=0$
(3.4)

for all x, y, z, wA.

Putting y = z = w = 0 in (3.1), we obtain

$||2f\left(2x\right)-16f\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0,0,0\right)$

for all xA. Thus,

$∥\frac{1}{8}f\left(2x\right)-f\left(x\right)∥\le \frac{1}{16}\psi \left(x,\phantom{\rule{2.77695pt}{0ex}}0,0,0\right)$
(3.5)

for all xA.

Now, similar to the proof of theorems in previous section, we consider the set X := {h : AA | h(0) = 0} and introduce the generalized metric on X as:

if there exists such constant C, and d(h1, h2) = ∞, otherwise. The metric space (X, d) is complete, and by the same reasoning as in the proof of Theorem 2.2, the mapping Φ: XX defined by $\Phi \left(h\right)\left(x\right)=\frac{1}{8}h\left(2x\right)$; (xA) is strictly contractive on X and has a unique fixed point T such that $\underset{n\to \infty }{\mathrm{lim}}d\left({\Phi }^{n}f,T\right)=0$, i.e.,

$T\left(x\right)=\underset{n\to \infty }{lim}\frac{f\left({2}^{n}x\right)}{{8}^{n}}$
(3.6)

for all xA. By Theorem 2.1, we have

$d\left(f,\phantom{\rule{2.77695pt}{0ex}}T\right)\le \frac{d\left(f,\Phi \phantom{\rule{0.3em}{0ex}}f\right)}{1-L}\le \frac{L}{2\left(1-L\right)}.$
(3.7)

The proof of Theorem 2.2 shows that T is a cubic mapping. If we substitute z and w by 2 nz and 2 nw in (3.1), respectively, and put x = y = 0 and we divide the both sides of the obtained inequality by 24n, we get

$∥z\frac{f\left({2}^{n}w\right)}{{8}^{n}}-\frac{f\left({2}^{n}z\right)}{{8}^{n}}w∥\le \frac{\psi \left(0,0,{2}^{n}z,{2}^{n}w\right)}{{2}^{4n}}.$

Passing to the limit as n and from (3.4), we conclude that zT(w) = T(z)w for all z, wA. □

Corollary 3.3. Let r, θ be non-negative real numbers with r < 3 and let f : AA be a mapping with f(0) = 0 such that

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)+f\left(z\right)w-z\phantom{\rule{0.3em}{0ex}}f\left(w\right)||\phantom{\rule{2.77695pt}{0ex}}\le \theta \left(||x|{|}^{r}+||y|{|}^{r}+||z|{|}^{r}+||w|{|}^{r}\right)$

for all x, y, z, wA. Then, there exists a unique cubic multiplier T on A satisfying

$||f\left(x\right)-T\left(x\right)||\phantom{\rule{2.77695pt}{0ex}}\le \frac{{2}^{r-1}\theta }{8-{2}^{r}}||x|{|}^{r}$

for all xA.

Proof. The proof follows from Theorem 3.2 by taking

$\psi \left(x,y,z,w\right)=\theta \left(||x|{|}^{r}+||y|{|}^{r}+||z|{|}^{r}+||w|{|}^{r}\right)$

for all x, y, z, wA. □

Now, we have the following result for the superstability of cubic multipliers.

Corollary 3.4. Let r j (1 ≤ j ≤ 4). θ be non-negative real numbers with ${\sum }_{j=1}^{4}{r}_{j}<3$ and let f: AA be a mapping with f (0) = 0 such that

$||D\phantom{\rule{0.3em}{0ex}}f\left(x,\phantom{\rule{2.77695pt}{0ex}}y\right)+f\left(z\right)w-z\phantom{\rule{0.3em}{0ex}}f\left(w\right)||\phantom{\rule{2.77695pt}{0ex}}\le \theta \left(||x|{|}^{{r}_{1}}||y|{|}^{{r}_{2}}||z|{|}^{{r}_{3}}||w|{|}^{{r}_{4}}\right)$

for all x, y, z, wA. Then, f is a cubic multiplier on A.

Proof. It is enough to let $\psi \left(x,y,z,w\right)=\theta \left(||x|{|}^{{r}_{1}}||y|{|}^{{r}_{2}}||z|{|}^{{r}_{3}}||w|{|}^{{r}_{4}}\right)$ in Theorem 3.2. □