In our paper we consider only null-field solutions of Maxwell equations. This means that at every moment of time and at every point in space the following conditions hold:
$$\begin{aligned} \mathbf{E } \cdot \mathbf{B } = 0, \mathbf{E }^2 = \mathbf{B }^2. \end{aligned}$$
(4)
Generally, Maxwell equations do not preserve these conditions, which makes them non-trivial. However, such solutions exist and a procedure of constructing them was described in detail in s.7 of [6]. The simplest solution of this kind is the Ranada’s Hopf solution and we discuss it in Sect. 6.1.
We mainly focus on the following property of null-field solutions. It turns out that one can define self-consistent time evolution of the field lines [7, 8]. Generally, at different moments of time the space is filled with different field lines, due to the electric field evolution according to Maxwell equations. To give a prescription of how a field line deforms and moves in space, one needs to define a velocity vector \(\mathbf{v }\) for each point of a field line. This vector \({\mathbf {v}}\) is normal to the field line at each point. This structure will match the field lines at different moments of time.
However, to define the time evolution of the field lines, a velocity vector field should obey a very special, yet natural condition. The condition requires that any two points of a field line become points of another field line in the further moment of time when moved along the velocity vector field (see Fig. 1). In other words, points of a field lines can not become points of different field lines. Alternatively, one could require that the following curve
$$\begin{aligned} \mathbf{x }^{\prime }(s) = \mathbf{x }(s) + \mathbf{v }(\mathbf{x }(s)) dt \end{aligned}$$
(5)
is a field line that is defined at the moment \(t + dt\).
In case of null-field solutions, the velocity vector \(\mathbf{v }\) can be chosen as the normalized Poynting vector:
$$\begin{aligned} \mathbf{p } = \frac{\mathbf{E } \times \mathbf{B }}{|\mathbf{E }| |\mathbf{B }|} \end{aligned}$$
(6)
Poynting time evolution
In this section we demonstrate that the Poyting vector in a null-field solution induces self-consistent time evolution of the force lines. To do this, we explicitly check the self-consistency of the condition from the previous section.
We consider an electric field line \(\mathbf{x }(s)\) of a null-field solution at the moment t. In this section we fix the parametrization s by the following equation:
$$\begin{aligned} \frac{d \mathbf{x }(s)}{ds} = \mathbf{E }(\mathbf{x }(s), t) \end{aligned}$$
(7)
Then we consider an auxiliary line \(\mathbf{x }^{\prime }(s)\) that is obtained from \(\mathbf{x }(s)\) by a slight shift along the Poynting vector \(\mathbf{p }\):
$$\begin{aligned} \mathbf{x }^{\prime }(s) = \mathbf{x }(s) + \mathbf{p }(\mathbf{x }(s),t) dt \end{aligned}$$
(8)
Note that we shift along the Poynting vector by dt. The main claim is that \(\mathbf{x }^{\prime }(s)\) coincides as geometrical objects with some field line at the moment \(t + dt\). Namely, a tangent vector of the line \(\mathbf{x }^{\prime }(s)\) is collinear to the electric field at the moment \(t + dt\), it means that they define the same field line:
$$\begin{aligned} \frac{d \mathbf{x }^{\prime }(s)}{ds} \ \upuparrows \ \mathbf{E }(\mathbf{x }^{\prime }(s), t + dt) \end{aligned}$$
(9)
We should note that this collinearity holds only in the first order in dt. To explicitly see this, we compute the corresponding cross product:
$$\begin{aligned} \begin{aligned}&\frac{d \mathbf{x }^{\prime }(s)}{ds} \times \mathbf{E }(\mathbf{x }^{\prime }(s), t + dt) = \Biggl ( \mathbf{E } + (\mathbf{E } \cdot \nabla ) \mathbf{p } \, dt \Biggr )\\&\qquad \times \Biggl ( \mathbf{E } + (\mathbf{p } \cdot \nabla ) \mathbf{E } \, dt + \frac{\partial \mathbf{E }}{\partial t} dt + o(dt) \Biggr ) = \\&\quad = dt \, \mathbf{E } \times \Biggl ( (\mathbf{p } \cdot \nabla ) \mathbf{E } - (\mathbf{E } \cdot \nabla ) \mathbf{p } + \frac{\partial \mathbf{E }}{\partial t} \Biggr ) + o(dt) = o(dt) \end{aligned}\nonumber \\ \end{aligned}$$
(10)
To simplify the formulas, we omit the explicit coordinate and time dependence of the fields meaning \(\mathbf{E } = \mathbf{E }(\mathbf{x }(s), t)\) and \(\mathbf{p } = \mathbf{p }(\mathbf{x }(s), t)\). We compute the expression in the brackets using the following identity for null-field solutions:
$$\begin{aligned} \text {E}_{\beta } \text {p}_{\alpha } - \text {E}_{\alpha } \text {p}_{\beta } = \epsilon _{\alpha \beta \gamma } \text {B}_{\gamma } \end{aligned}$$
(11)
Taking the derivative of (11) and using the Maxwell equations, we obtain the expression of the form:
$$\begin{aligned} (\mathbf{p } \cdot \nabla ) \mathbf{E } - (\mathbf{E } \cdot \nabla ) \mathbf{p } + \frac{\partial \mathbf{E }}{\partial t} = - (\nabla \cdot \mathbf{p }) \mathbf{E } \end{aligned}$$
(12)
The r.h.s is collinear to the electric field \(\mathbf{E }\) that ensures (10). Finally, we conclude that the Poynting vector defines the self-consistent time evolution of the field line. Therefore, we can think of a field line as a strand where each point moves with the velocity vector \(\mathbf{p }\). From now we understand the time dependence of the field lines \(\mathbf{x }(s,t)\) as it is induced by the Poynting vector:
$$\begin{aligned} \frac{d \mathbf{x }(s,t)}{dt} = \mathbf{p }(\mathbf{x }(s,t),t) \end{aligned}$$
(13)
It is evident now why we consider the normalized Poyting vector. If one chooses another normalization for the Poynting vector it will spoil (12).
Examples
For demonstrative purposes let us discuss plane wave null-field solutions of Maxwell equations to analyse the structure of the field lines and its time evolution induced by the Poynting vector.
-
Plane wave with linear polarization
The plane wave with linear polarization has the form:
$$\begin{aligned} \mathbf{E }= & {} \left( \begin{array}{c} E \cos (z - t) \\ 0 \\ 0 \end{array}\right) \mathbf{B } = \left( \begin{array}{c} 0 \\ E \cos (z - t) \\ 0 \end{array}\right) \nonumber \\ \mathbf{p }= & {} \left( \begin{array}{c} 0\\ 0\\ 1 \end{array}\right) \end{aligned}$$
(14)
Note that at a given moment of time the the electric field changes along the z-axis. However, all the electric field lines are straight lines parallel to the x-axis. The field lines fill the whole space except “singular” xy-planes with coordinates \(z = t + \pi /2 + \pi n, n \in {\mathbb {Z}}\). We can write an explicit formula for the electric field line that goes through the point \((y_0, z_0)\) in the yz-plane at the moment \(t_0\):
$$\begin{aligned} \mathbf{x }(s,t) = \left( \begin{array}{c} s \, E \cos (z_0 - t_0) \\ y_0 \\ z_0 + t - t_0 \end{array}\right) \end{aligned}$$
(15)
At each moment of time the tangent vector of the field line is the electric field:
$$\begin{aligned}&\frac{d \mathbf{x }(s,t)}{ds} {=} \mathbf{E }(\mathbf{x }(s,t),t)\nonumber \\&\quad \Leftarrow \left( \begin{array}{c} E \cos (z_0 - t_0) \\ 0 \\ 0 \end{array}\right) {=} \left( \begin{array}{c} E \cos (z_0 {+} t {-} t_0 {-} t) \\ 0 \\ 0 \end{array}\right) \end{aligned}$$
(16)
We note that the tangent vector of the particular field line does not change over time. This is due to the fact \( \nabla \cdot \mathbf{p } = 0\) and we discuss this in Sect. 3.3. The velocity of the points of the field line is the Poynting vector:
$$\begin{aligned} \frac{d \mathbf{x }(s,t)}{dt} = \mathbf{p }(\mathbf{x }(s,t),t) \Leftarrow \left( \begin{array}{c} 0 \\ 0 \\ 1 \end{array}\right) = \left( \begin{array}{c} 0 \\ 0 \\ 1 \end{array}\right) \end{aligned}$$
(17)
The structure of the field lines flows along the z-axis over time as a whole and do not change. This is evident from the coordinate independence of the Poynting vector.
-
Plane wave with elliptic polarization
This solution has the form:
$$\begin{aligned}&\mathbf{E } = \left( \begin{array}{c} E_x \cos (z - t) \\ E_y \sin (z - t) \\ 0 \end{array}\right) \mathbf{B } = \left( \begin{array}{c} -E_y \sin (z - t) \\ E_x \cos (z - t) \\ 0 \end{array}\right) \nonumber \\&\quad \mathbf{p } = \left( \begin{array}{c} 0\\ 0\\ 1 \end{array}\right) \end{aligned}$$
(18)
This solution of Maxwell equations has a slightly more complicated structure of the field lines, however the time evolution is the same as in the previous example – the field lines move along the z-axis, while the structure of the field lines remains the same. The explicit formula for the field line that goes through the point \((x_0, y_0, z_0)\) at the moment \(t_0\):
$$\begin{aligned} \mathbf{x }(s,t) = \left( \begin{array}{c} x_0 + s \ E_x \cos (z_0 - t_0) \\ y_0 + s \ E_y \sin (z_0 - t_0) \\ z_0 + t - t_0 \end{array}\right) \end{aligned}$$
(19)
The field lines are normal to the z-axis and all field lines on a particular xy-plane are parallel. However, the direction of the field lines at a fixed moment of time is continuously changing along the z-axis. Namely, the direction rotates clockwise or anticlockwise along the z-axis at a fixed moment of time depending on the mutual sign of \(E_x, E_y\).
At each moment of time the tangent vector is the electric field and the velocity is the Poynting vector:
$$\begin{aligned}&\frac{d \mathbf{x }(s,t)}{ds} = \mathbf{E }(\mathbf{x }(s,t),t)\nonumber \\&\quad \Leftarrow \left( \begin{array}{c} E_x \cos (z_0 - t_0) \\ E_y \sin (z_0 - t_0) \\ 0 \end{array}\right) = \left( \begin{array}{c} E_x \cos (z_0 + t - t_0 - t) \\ E_y \sin (z_0 + t - t_0 - t)\\ 0 \end{array}\right) \end{aligned}$$
(20)
$$\begin{aligned}&\frac{d \mathbf{x }(s,t)}{dt} = \mathbf{p }(\mathbf{x }(s,t),t) \Leftarrow \left( \begin{array}{c} 0 \\ 0 \\ 1 \end{array}\right) = \left( \begin{array}{c} 0 \\ 0 \\ 1 \end{array}\right) \end{aligned}$$
(21)
-
Electromagnetic knot
We consider a member of the family of finite energy source-free knot solutions of Maxwell equations [5, 6]. We do not provide the explicit form of the electric and magnetic fields, because its is too complicated. The crucial point is that we use the null-field solution. Instead of formulas we provide a computer simulation. We consider a closed field lines - limit cycles, that represent the trefoil knots. The little yellow knot becomes the big red one under the time evolution (see Fig. 2). The green curves are the trajectories of points and obey equation (13).
We argue that this picture represents general features of the Poynting evolution:
-
1.
The Poynting evolution is well defined. The green trajectories ensure the self-consistency condition.
-
2.
Limit cycles remain limit cycles. It is a strong argument in support of the Poynting evolution, because the time evolution of the limit cycles is well defined without any additional structure. Indeed, generally limit cycles are distinguished field lines, because they are closed. The Poynting time evolution coincides with the evolution of the limit cycles.
-
3.
The topological structure of the limit cycles remains the same. Indeed, in both cases (yellow and red) the knot is the trefoil knot \(3_1\).
Peculiarities of Poynting evolution
In this section we derive the parametrization of the field lines that is suitable for our further analysis of the link invariants. Also we argue that in this parametrization the commutativity of flows along s and t is evident.
As has been shown in the Sect. 3.1, the tangent vector of the auxiliary line
$$\begin{aligned} \mathbf{x }^{\prime }(s) = \mathbf{x }(s) + \mathbf{p }(\mathbf{x }(s),t) dt \end{aligned}$$
(22)
is not equal to the electric field at the moment \(t + dt\) but only collinear. Graphically it can be shown in the following parallelogram of vectors 3.
This parallelogram is the consequence of the formula (12). As can be seen, the upper vector is a slightly rescaled electric field. This fact can be thought of as the change in the parametrization:
$$\begin{aligned} ds^{\prime } = ds (1 + (\nabla \cdot \mathbf{p }) dt) \end{aligned}$$
(23)
We are free to multiply the electric field by a function \(f(\mathbf{E }^2)\) and the corresponding field lines will remain the same. However, the function f can be chosen in such a way that the parametrization does not change:
$$\begin{aligned} ds^{\prime } = ds \end{aligned}$$
(24)
In other words, the tangent vector of the auxiliary line (the upper vector in the parallelogram) will be equal to the vector \(\mathbf{E } f(\mathbf{E }^2)\) on the shifted line at the moment \(t + dt\). Namely:
$$\begin{aligned} \frac{d \mathbf{x }(s)}{ds}&= \mathbf{E }(\mathbf{x },t) \ f(\mathbf{E }^2(\mathbf{x },t)) \end{aligned}$$
(25)
$$\begin{aligned} \frac{d \mathbf{x }^{\prime }(s)}{ds}&= \mathbf{E }(\mathbf{x }^{\prime },t + dt) \ f(\mathbf{E }^2(\mathbf{x }^{\prime },t + dt)) \end{aligned}$$
(26)
From the last equation in the first order in dt we obtain the following constraint on the function f:
$$\begin{aligned} (\nabla \cdot \mathbf{p }) \left( f + \mathbf{E }^2 \frac{\partial f}{\partial \mathbf{E }^2} \right) = 0 \end{aligned}$$
(27)
Note that if \((\nabla \cdot \mathbf{p }) = 0\), the equation (26) will be satisfied automatically with any function f. Otherwise, if \((\nabla \cdot \mathbf{p }) \not = 0\), the function is determined uniquely:
$$\begin{aligned} f(\mathbf{E }^2) = \frac{1}{\mathbf{E }^2} \end{aligned}$$
(28)
To simplify the formulas, let us introduce the rescaled fields:
$$\begin{aligned} \mathbf{e } \,&{:}{=} \, \mathbf{E } / \mathbf{E }^2 \end{aligned}$$
(29)
Note that the rescaling of the fields does not spoil the null field conditions (4). In these new notations both the analog of the formula (12) and the parallelogram 4 look simpler and do not contain the term with \((\nabla \cdot \mathbf{p })\):
$$\begin{aligned} (\mathbf{p } \cdot \nabla ) \mathbf{e } + \frac{\partial \mathbf{e }}{\partial t} = (\mathbf{e } \cdot \nabla ) \mathbf{p } \end{aligned}$$
(30)
This formula is crucial for our analysis of the topological structure of the field lines. The rescaling of the electric fields does not change the structure of the field lines, however the formulas and calculations in the new notations are much simpler.
As was discussed in the previous Sect. 3.1, each point of the field line moves over time with the velocity \(\mathbf{p }\). Therefore, the system of the equations on the field lines takes the following form:
$$\begin{aligned} \frac{d \mathbf{x }(s,t)}{ds}&= \mathbf{e }(\mathbf{x }(s,t), t) \end{aligned}$$
(31)
$$\begin{aligned} \frac{d \mathbf{x }(s,t)}{dt}&= \mathbf{p }(\mathbf{x }(s,t), t) \end{aligned}$$
(32)
Using the equation (30), we obtain the following property:
$$\begin{aligned} \boxed {\frac{d \mathbf{e }(\mathbf{x }(s,t),t)}{dt} = \frac{d \mathbf{p }(\mathbf{x }(s,t),t)}{ds}} \end{aligned}$$
(33)
This property ensures commutativity of flows along s and t in the chosen parametrization.