Abstract
Stoichiometry of the reaction of Np(VI) with N(CH2COOH)3 (NTA) in a 0.05 M HClO4 solution was studied by spectrophotometry. With excess Np(VI), 1 mol of NTA reduces 2 mol of Np(VI) to Np(V). In 0.05–0.98 M HClO4 solutions (the ionic strength I = 1.0 was maintained by adding LiClO4) containing 5–30 mmol of NTA, at 25–45°С Np(VI) at a concentration of 0.3–2 mM is consumed in accordance with a firstorder rate law until less than 1/3 of Np(VI) remains in the solution. After that, the reaction decelerates. The reaction is first-order with respect to NTA and has an order of–2 with respect to Н+ ions. The activated complex is formed with the loss of two Н+ ions. The activation energy of the reaction is 100 ± 2 kJ mol–1.
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Original Russian Text © V.P. Shilov, A.M. Fedoseev, A.V. Gogolev, 2017, published in Radiokhimiya, 2017, Vol. 59, No. 3, pp. 201–203.
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Shilov, V.P., Fedoseev, A.M. & Gogolev, A.V. Reaction of Np(VI) with nitrilotriacetic acid in perchloric acid solutions. Radiochemistry 59, 229–232 (2017). https://doi.org/10.1134/S1066362217030031
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DOI: https://doi.org/10.1134/S1066362217030031