FORMULATION OF THE PROBLEM

During a spacecraft’s flight or, in general, for a material point in the central Newtonian gravitational field of the Earth, the motion of a spacecraft in a nonrotating geocentric geoequatorial coordinate system satisfies the equation

$${{d}^{2}}{\mathbf{r}}{\text{/}}d{{t}^{2}} = \partial {{U}_{0}}{\text{/}}\partial {\mathbf{r}}{\text{*}} = \partial \left( {\mu {\text{/}}r} \right){\text{/}}\partial {\mathbf{r}}{\text{*}} = - \left( {\mu {\text{/}}{{r}^{3}}} \right){\mathbf{r}},$$
(1)

where r (x, y, z) is the radius vector of a point (SC; r = |r|), * is the transposition sign, and μ is the gravitational parameter of the Earth;

$${{U}_{0}}\left( {\mathbf{r}} \right) = \mu {\text{/}}r$$
(2)

is potential of the Earth’s gravity without taking into account the disturbances. System (1) corresponds to Keplerian motions in the gravitational field of a spherical, homogeneous Earth. One of the most important first integrals in this case is the energy integral [1–6]:

$${{V}^{2}} - 2{{U}_{0}} = {{V}^{2}} - 2\mu {\text{/}}r = {{h}_{k}},\,\,\,{{h}_{k}} = - \mu {\text{/}}a,$$
(3)

where V = |V|, V being the geocentric speed of the point; hk is the Keplerian energy constant; and element a in the case of elliptical motion when hk < 0 is the semimajor axis of the orbit. In hyperbolic motion, when hk > 0, a < 0, modulus |a| = α [3] has a geometric sense. Let us consider how integral (3) changes when taking into account the perturbation from the oblateness of the Earth as a body of revolution, as well as its use in the analysis of the orbital motion of a material point.

GENERALIZED INTEGRAL OF ENERGY TAKING INTO ACCOUNT THE OBLATENESS OF THE EARTH

In the simplest case of analyzing motion near the Earth to take into account its oblateness in potential of the Earth U to main member U0, second zonal harmonic U2 is added [2, 3, 5, 6]:

$$U\left( {\mathbf{r}} \right) = {{U}_{0}}\left( {\mathbf{r}} \right) + {{U}_{2}}\left( {\mathbf{r}} \right);$$
(4)
$$\begin{gathered} {{U}_{{\text{2}}}}({\mathbf{r}}) = - \frac{{{\varepsilon }}}{{{{r}^{3}}}}\left( {{{{\sin }}^{2}}{{\varphi }} - \frac{1}{3}} \right) = - \frac{{{\varepsilon }}}{{{{r}^{3}}}}\left( {\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - \frac{1}{3}} \right),~ \\ \varepsilon = \left( {{\text{3/2}}} \right){{J}_{{\text{2}}}}\mu R_{{\text{E}}}^{{\text{2}}}, \\ \end{gathered} $$
(5)

where φ is the geocentric latitude of the spacecraft; J2 = –C20 is the zonal harmonic coefficient of the second order; RE is the average equatorial radius of the Earth, RE ≈ 6378.137 km; J2 ≈ 1082.63 × 10–6 [6]; and ε ≈ 2.63328 × 1010 km5/s2. Equation of motion (1) changes:

$${{{\text{d}}}^{2}}{\mathbf{r}}{\text{/d}}{{t}^{2}} = \partial U{\text{/}}\partial {\mathbf{r}}*,$$
(6)

where U(r) is potential (4), (2), (5). To the main acceleration (1), a disturbing aP, which is the gradient of the function U2 and in rectangular coordinates it will be written in the form [2]:

$$\begin{gathered} {{a}_{{Px}}} = \frac{{{\varepsilon }}}{{{{r}^{4}}}}\left( {5\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - 1} \right)\frac{x}{r};\,\,\,\,{{a}_{{Py}}} = \frac{{{\varepsilon }}}{{{{r}^{4}}}}\left( {5\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - 1} \right)\frac{y}{r}; \\ {{a}_{{Pz}}} = \frac{{{\varepsilon }}}{{{{r}^{4}}}}\left( {5\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - 3} \right)\frac{z}{r}. \\ \end{gathered} $$
(7)

A doubled total mechanical energy of motion of a point of unit mass h(r, V) has the form

$$\begin{gathered} h = {{V}^{2}} - 2U = {{V}^{2}} - 2{{U}_{0}} - 2{{U}_{2}} \\ = {{V}^{2}} - {{2{{\mu }}} \mathord{\left/ {\vphantom {{2{{\mu }}} r}} \right. \kern-0em} r} + \frac{{2{{\varepsilon }}}}{{{{r}^{3}}}}\left( {\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - \frac{1}{3}} \right). \\ \end{gathered} $$
(8)

Theorem. The total mechanical energy of motion of a material point in model (6), where potential U(r) corresponds to (4), (2), and (5), is constant on the trajectory of the point.

Indeed, in this case, the acceleration in (6) is determined by the single-valued scalar force function U = U(r), the motion occurs in a potential field, force function U = U(r) is a potential that does not depend on time. It then follows from the general theorem of mechanics [1, 4] that, on the trajectory of point dh/dt = 0, by virtue of equation of motion (6), h = const. It is possible to show this directly using (6), (1), (7). Therefore, on any trajectory of a point the energy (8) is constant, we have the first integral:

$$h = {{V}^{2}} - \frac{{2{{\mu }}}}{r} + \frac{{2{{\varepsilon }}}}{{{{r}^{3}}}}\left( {\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - \frac{1}{3}} \right) = ~{{h}_{K}} - 2{{U}_{2}} = {\text{const}}.$$
(9)

We will call this integral the “generalized energy integral,” bearing in mind that it generalizes integral (3) to the case of taking into account the Earth’s oblateness when calculating the trajectory of a material point the SC.

Remark 1. It follows from (8), (9) that, in this model of the potential, for a given energy constant h, the movement of a point occurs in the area of space \(h + 2U = h + 2{{U}_{0}} + 2{{U}_{2}}\) = \(h + \frac{{2{{\mu }}}}{r} - \frac{{2{{\varepsilon }}}}{{{{r}^{3}}}}\left( {\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - \frac{1}{3}} \right) = \) \({{V}^{2}} \geqslant 0.\) The difference from the Keplerian case is visible.

Remark 2. This approach can be applied to a more complete model of zonal harmonics. Using the model of the Earth as a body of revolution symmetric about the equatorial plane, for example, and adding a zonal harmonic of the fourth order to potential U in addition to the second one, the generalized energy integral takes the form

$$\begin{gathered} h = {{V}^{2}} - 2U = {{V}^{2}} - 2{{U}_{0}} - 2{{U}_{2}} - 2{{U}_{4}} = {{V}^{2}} - \frac{{2{{\mu }}}}{r} \\ + \,\,\frac{{2{{\varepsilon }}}}{{{{r}^{3}}}}\left( {\frac{{{{z}^{2}}}}{{{{r}^{2}}}} - \frac{1}{3}} \right) - \frac{{2{{\chi }}}}{{{{r}^{5}}}}\left( {\frac{{{{z}^{4}}}}{{{{r}^{4}}}} - \frac{6}{7}\frac{{{{z}^{2}}}}{{{{r}^{2}}}} + \frac{3}{{35}}} \right). \\ \end{gathered} $$

One can also use the entire expansion of the potential in zonal harmonics, which allows one to improve the accuracy and take into account the asymmetry about the equator:

$$U = \frac{{{\mu }}}{r}\left[ {1 - \mathop \sum \limits_{n = 2}^\infty {{J}_{n}}{{{\left( {\frac{{{{R}_{{\text{E}}}}}}{r}} \right)}}^{n}}{{P}_{n}}\left( {\sin {{\varphi }}} \right)} \right].$$

Here, \({{P}_{n}}\left( {{{\sin\varphi }}} \right)\) are nth-order Legendre polynomials. For the Earth, the following coefficients hold after the second order: J3 = –2.53 × 10–6 and J4 = –1.61 × 10–6 [6], i.e., around three orders of magnitude less than J2.

Remark 3. In this case, the potential axisymmetric force field is also the integral of the axial angular momentum of the point [4]: Mz = (ez, [r, V]) = m = const, where ez is the ort along the axis of rotation of the Earth.

CHANGE IN THE KEPLERIAN ENERGY CONSTANT ON ORBITS OF DEPARTURE TO THE MOON AND PLANETS

Having written out integral (9) for initial point of the trajectory x0 (r0, V0, t0) and for some other point xf (rf, Vf, tf), we obtain the ratio

$$\begin{gathered} h = V_{0}^{2} - \frac{{2{{\mu }}}}{{{{r}_{0}}}} + \frac{{2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {\frac{{z_{0}^{2}}}{{r_{0}^{2}}} - \frac{1}{3}} \right) \\ = V_{f}^{2} - \frac{{2{{\mu }}}}{{{{r}_{f}}}} + \frac{{2{{\varepsilon }}}}{{r_{f}^{3}}}\left( {\frac{{z_{f}^{2}}}{{r_{f}^{2}}} - \frac{1}{3}} \right). \\ \end{gathered} $$
(10)

Let us apply it to the analysis of the spacecraft departure trajectories from the Earth to the Moon and planets.

It follows from (10) that the change in the Keplerian energy constants in accurate analysis satisfies the relationship

$$\begin{gathered} \Delta {{h}_{k}} = {{h}_{{kf}}}-{{h}_{{k0}}} = {\text{2}}{{U}_{{{\text{2}}f}}}-{\text{2}}{{U}_{{{\text{2}}0}}} = -\frac{{2{{\varepsilon }}}}{{r_{f}^{3}}}\left( {\frac{{z_{f}^{2}}}{{r_{f}^{2}}} - \frac{1}{3}} \right) \\ + \,\,\frac{{~2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {\frac{{z_{0}^{2}}}{{r_{0}^{2}}} - \frac{1}{3}} \right), \\ \end{gathered} $$
(11)
$$z{\text{/}}r = \sin \varphi = \sin i\sin u = \sin i\sin \left( {\omega + \theta } \right),$$
(11a)

where i and ω are the inclination and argument of the orbit perigee and u and θ are the latitude argument and true point anomaly.

Remark 4. Energy integral (9) and exact relation (11) for the change in Δhk are valid for any orbit—in particular, for any values of inclination and eccentricity.

If we proceed from Keplerian constant hk to semiaxis a (3) and linearize according to a, then we obtain variation Δa as a first approximation from (11):

$$\Delta a \approx \left( {{{a_{0}^{2}} \mathord{\left/ {\vphantom {{a_{0}^{2}} \mu }} \right. \kern-0em} \mu }} \right)\Delta {{h}_{k}}.$$
(12)

During the spacecraft’s flight to the planet, the departure from the Earth will occur in a hyperbolic orbit (in an osculating approximation). For purposes of assessment, we take the velocity “at infinity” for this orbit as V = 3–4 km/s. In this case, distance rf increases without bound and the penultimate term in (11), 2U2f, tends to zero; therefore, the change in Keplerian energy constants ΔhK tends to limiting value ΔhKl:

$$\Delta {{h}_{K}} \to \Delta {{h}_{{Kl}}} = -{\text{2}}{{U}_{{{\text{2}}0}}} = \frac{{~2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {{\text{si}}{{{\text{n}}}^{2}}{{{{\varphi }}}_{0}} - \frac{1}{3}} \right).$$
(13)

If \({\text{si}}{{{\text{n}}}^{2}}{{{{\varphi }}}_{0}} < \frac{1}{3}\) (|φ0| < \({{\varphi }}_{0}^{*}\) = 35.2644°), then ΔhKl < 0. If \({\text{si}}{{{\text{n}}}^{2}}{{{{\varphi }}}_{0}} > \frac{1}{3},\) then ΔhKl > 0. For a flight to the Moon, we assume that a highly elongated near-parabolic elliptical orbit has a perigee at starting point rπ = r0 ≈ 6578 km; initial distance at apogee rα corresponds to distance to the Moon rM when the spacecraft approaches the Moon; rα ≥ (rM – Δrα); rM ≈ 360 000–405 000 km; and Δrα < 0 is the correction for decreasing rα due to the oblateness of the Earth, Δrα ≈ 2Δa. In (11), distance rf increases in the process of spacecraft motion from r0 to rM < ∞, while the penultimate term in (11) decreases to a small value (~10–6 km2/s2) and the limiting change in Keplerian constant hKl is

$$\Delta {{h}_{{Kl}}} \approx -{\text{2}}{{U}_{{{\text{2}}0}}} = \frac{{~2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {{\text{si}}{{{\text{n}}}^{2}}{{{{\varphi }}}_{0}} - \frac{1}{3}} \right).$$
(14)

For numerical estimates, for the initial point of departure to the Moon and planets from the near-Earth reference orbit, we take, for definiteness, u0 = 0, which is close to the characteristics of interplanetary and lunar flights. In formulas (13), (14), then, φ0 = 0 and z0 = 0, and we obtain

$$\Delta {{h}_{{Kl}}} \approx {{-{\text{2}}\varepsilon } \mathord{\left/ {\vphantom {{-{\text{2}}\varepsilon } {\left( {{\text{3}}r_{0}^{3}} \right)}}} \right. \kern-0em} {\left( {{\text{3}}r_{0}^{3}} \right)}}.$$
(14a)

In this case, for departures from the Earth both to the planet in a hyperbolic orbit and to the Moon in an elongated elliptical orbit, ΔhKl ≈ –0.0617 km2/s2. Numerical calculations have confirmed these estimates [7, 8]. When hK < 0, this change in the Keplerian energy constant (14) corresponds to a change in the semimajor axis of the orbit, in accordance with (12): Δa ≈ –6200 km at a0 = 200 000 km, Δa ≈ –8900 km at a0 = 220 000 km, and Δa ≈ –56 000 km at a0 = 600 000 km. In practice, this change occurs quickly, during the first 3 h or so of the spacecraft’s initial flight from the Earth, with an increase in distance rf up to ~70 000 km.

DEPARTURE SPEED OF THE SPACECRAFT FROM THE NEAR-EARTH REFERENCE ORBIT

The change in the Keplerian energy constants caused by the oblateness of the Earth, within the framework of model (4), (5), leads to a change in the initial velocity of the spacecraft’s departure from the Earth in comparison with the Keplerian model of motion. For the analysis to be correct, let us set a certain value of the Keplerian energy constant for departure orbit hKg (or V, a). Then, in the Keplerian model of spacecraft motion (1), (2), by virtue of integral (3), the initial velocity is

$${{V}_{0}} = {{\left( {{{h}_{{Kg}}} + 2\mu {\text{/}}{{r}_{0}}} \right)}^{{1/2}}}.$$
(15)

Taking into account the oblateness of the Earth, in model (4), (5), under the condition hKf = hKg, by virtue of integral (10), the initial velocity is determined from the relation

$${{V}_{0}} = \sqrt {{{h}_{{Kg}}} + \frac{{2{{\mu }}}}{{{{r}_{0}}}} + 2{{U}_{{20}}} - 2{{U}_{{2f}}}} = \sqrt {{{h}_{{Kg}}} + \frac{{2{{\mu }}}}{{{{r}_{0}}}} + \Delta h} ,$$
(16)

where

$$\begin{gathered} \Delta h = 2{{U}_{{20}}} - 2{{U}_{{2f}}} = \frac{{2{{\varepsilon }}}}{{r_{f}^{3}}}\left( {\frac{{z_{f}^{2}}}{{r_{f}^{2}}} - \frac{1}{3}} \right) \\ - \,\,\frac{{2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {\frac{{z_{0}^{2}}}{{r_{0}^{2}}} - \frac{1}{3}} \right) \approx - \frac{{2{{\varepsilon }}}}{{r_{0}^{3}}}\left( {\frac{{z_{0}^{2}}}{{r_{0}^{2}}} - \frac{1}{3}} \right). \\ \end{gathered} $$

Let us provide numerical estimates for the case z0 = 0. When flying from the Earth to a planet in a geocentric orbit with V = 3–4 km/s, taking into account the Earth’s oblateness in (17), increases initial velocity V0 in comparison with Keplerian case (16) from ~11.410–11.713 to ~11.413–11.716 km/s, i.e., by ~3 m/s. When flying to the Moon, when rα = rM + |Δrα|, rM = 400 000 km, taking into account oblateness increases initial speed V0 from ~10.919 to ~10.922 km/s, i.e., also by ~3 m/s. This leads to an increased initial osculating semimajor axis of the orbit relative to the Keplerian case by ~6500 km, while initial apogee distance rα is increased by ~13 000 km [7, 8] as noted above.

ESTIMATION OF THE CHANGE IN THE KEPLERIAN ENERGY CONSTANT IN THE FIRST APPROXIMATION

When analyzing the spacecraft’s motion in a hyperbolic and highly elongated elliptical orbit, we used the distance to the center of the Earth as a parameter on the trajectory. In the general case, it is more convenient to use true anomaly θ [9], time t, or average anomaly M [10, 11]. We transform relations (11), (12) to use angle θ when determining the change in Keplerian constant ΔhK (or semiaxis Δa) as a first approximation. Then, according to (11), (11a) and taking into account the orbital equation, we obtain

$$\begin{gathered} \Delta {{h}_{k}} = {\text{2}}{{U}_{{{\text{2}}f}}}-{\text{2}}{{U}_{{{\text{2}}0}}} \approx -\frac{{2{{\varepsilon }}}}{{{{p}^{3}}}}{{\left( {1 + e{{\cos\theta }}} \right)}^{3}} \\ \times \,\,\left[ {{\text{si}}{{{\text{n}}}^{2}}i~{\text{si}}{{{\text{n}}}^{2}}\left( {{{\omega }} + {{\theta }}} \right) - \frac{1}{3}} \right]-{{\;}}2{{U}_{{20}}}{{\;}}, \\ \end{gathered} $$
(17)

where the orbital elements are focal parameter p, eccentricity e, i, and ω, which are equal to their initial values p0, e0, i0, and ω0. Change Δa is determined by (12). If the orbit is elliptical, a > 0, and the multiturn motion of the point is considered, then the motion can be averaged. To simplify this procedure, using elementary identical trigonometric transformations, we lead 2U2f to the sum of constant c and several terms of the form (2ε/p3) \({{c}_{j}}\left( {i,{{\;}}e} \right){\text{cos}}({{n}_{j}}{{\omega }} + {{m}_{j}}\theta ),\) where nj and mj are whole numbers:

$$\begin{gathered} {\text{2}}{{U}_{{{\text{2}}f}}} = {{{c}}_{{{\text{0}{\theta }}}}} + \left( {{{{\text{2}}\varepsilon } \mathord{\left/ {\vphantom {{{\text{2}}\varepsilon } {{{p}^{3}}}}} \right. \kern-0em} {{{p}^{3}}}}} \right)\sum\limits_{j = 1}^J {{{c}_{j}}\left( {i,e} \right){\text{cos}}({{n}_{j}}{{\omega }} + {{m}_{j}}\theta )} , \\ ~{{c}_{{{\text{0}{\theta }}}}} = \left( {{{{\text{2}}\varepsilon } \mathord{\left/ {\vphantom {{{\text{2}}\varepsilon } {3{{p}^{3}}}}} \right. \kern-0em} {3{{p}^{3}}}}} \right)\left( {1 - \frac{3}{2}{\text{si}}{{{\text{n}}}^{2}}i} \right)\left( {1 + \frac{3}{2}{{e}^{2}}} \right). \\ \end{gathered} $$

This constant gives the “average” shift of Keplerian energy constant hK due to the oblateness of the Earth according to (17). In this problem, parameter θ is convenient, but it is customary to do averaging over mean anomaly M. Then, after some transformations, we obtain the function value 2U2f that is “average” over M:

$${{c}_{{0{\text{M}}}}} = \left( {{{{\text{2}}\varepsilon } \mathord{\left/ {\vphantom {{{\text{2}}\varepsilon } {3a{{p}^{2}}}}} \right. \kern-0em} {3a{{p}^{2}}}}} \right)\left( {1 - \frac{3}{2}{\text{si}}{{{\text{n}}}^{2}}i} \right){{\left( {1 - {{e}^{2}}} \right)}^{{{1 \mathord{\left/ {\vphantom {1 2}} \right. \kern-0em} 2}}}}.$$

Remark 5. Let the celestial body not fly away from the Earth, but approach it, entering its atmosphere. The change in the Keplerian energy constant with time then occurs in the opposite direction. Moreover, distance from the Earth r decreases with time and the value of potential U2 increases to the final value corresponding to the entry into the atmosphere, r ~ 6478 km.

Remark 6. If a celestial body (spacecraft, asteroid, comet) approaches the Earth, moving at a great distance (r ~ 300 000–400 000 km) from the Earth in an elliptical near-parabolic orbit for which –ΔhK < hK < 0, then, due to the oblateness of the Earth, the Keplerian energy constant can increase to a positive value and this body will approach the Earth in a hyperbolic orbit. Another case is possible in which, under the influence of the Earth’s oblateness, the orbit changes its structure from hyperbolic to elliptical.

CONCLUSIONS

A simplified analysis of the effect of the oblateness of the Earth as a body of revolution—based on the zonal harmonics of the gravitational potential—makes it possible to use the energy integral, which generalizes the energy integral in the Keplerian case. This makes it possible to consider some of the qualitative features of a spacecraft’s motion during flight to the Moon and planets and during the return to the Earth, as well as celestial bodies, asteroids, and comets closely approaching the Earth. Oblateness of the Earth can cause a change in the structure of the orbits of these bodies—from elliptical to hyperbolic and vice versa.