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Area-invariant pedal-like curves derived from the ellipse

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Abstract

We study six pedal-like curves associated with the ellipse which are area-invariant for pedal points lying on one of two shapes: (i) a circle concentric with the ellipse, or (ii) the ellipse boundary itself. Case (i) is a corollary of properties of Steiner’s Curvature Centroid (Krümmungs-Schwerpunkt), proved in 1825. For case (ii) we prove area invariance algebraically. Explicit expressions for all invariant areas are also provided. Finally, we generalize the results for a class of smooth curves.

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Notes

  1. After the actual Talbot’s Curve, shown in Fig. 1 (bottom): the negative pedal curve of an ellipse with respect to its center O.

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Acknowledgements

We would like to thank Robert Ferréol and Mark Helman for their help during this work. We are also grateful to the referee’s corrections and invaluable suggestions for improvement. The second author is fellow of CNPq and coordinator of Project PRONEX/ CNPq/ FAPEG 2017 10 26 7000 508.

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Correspondence to Dan Reznik.

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Appendices

Appendix A: Evolutoids

Some of the results in this section appear in Aguilar-Arteaga (2015); Jerónimo-Castro (2014). Consider a plane curve \({\mathcal {C}}(t)=[x(t),y(t)]\) defined by a support function h, see Eq. (4).

The family of lines passing through \(P(t)=[x(t),y(t)]\) making a constant angle \(\theta \) with \((x^\prime (t),y^\prime (t)) \) is given by:

$$\begin{aligned} {\mathcal {L}}_{\theta }(t):&\cos (\theta -t) \,x - \sin (\theta -t)\, y - h(t) \cos \theta + h'(t) \sin \theta = 0 \end{aligned}$$

Let \({\mathcal {C}}_\theta (t)=(x_\theta ,y_\theta )\) denote the envelope of \({\mathcal {L}}_\theta (t)\). This will be given by:

$$\begin{aligned} x_{\theta }(t)=&\,\frac{1}{2} \left( \cos \left( t-2\,\theta \right) + \,\cos t \right) h \left( t \right) -h'(t)\sin t +\frac{1}{2} \left( \cos \left( t-2\,\theta \right) - \,\cos t \right) h'' \left( t \right) \\ y_{\theta }(t)=&\,\frac{1}{2} \left( \sin \left( t-2\,\theta \right) + \,\sin t \right) h(t) +h'(t)\cos t +\frac{1}{2} \left( \sin \left( t-2\,\theta \right) - \,\sin t \right) h'' (t) \end{aligned}$$

Note that \({\mathcal {C}}_{\pi /2}\) is the evolute of \({\mathcal {C}}\). Let \(h_{\theta }(t)=h(t-\theta )\cos \theta +h'(t-\theta )\sin \theta \). Changing variables \(t=t-\theta \) it follows that the envelope is given by

$$\begin{aligned} x_{\theta }(t-\theta )=&\,h_{\theta }(t)\cos t-h_{\theta }'(t)\sin t\\ y_{\theta }(t-\theta )=&\,h_{\theta }(t)\sin t+h_{\theta }'(t)\cos t \end{aligned}$$

Let S(.) denote the signed area of a curve. Then

$$\begin{aligned} S({\mathcal {C}})=&\,\frac{1}{2} \int _0^{2\pi }( h(t)^2-h'(t)^2) dt\\ S({\mathcal {C}}_{\pi /2})=&\,\frac{1}{2} \int _0^{2\pi }( h'(t)^2-h''(t)^2) dt \end{aligned}$$

Proposition 8

\(S({\mathcal {C}}_\theta )\) is given by

$$\begin{aligned} S({\mathcal {C}}_\theta )= S({\mathcal {C}})\cos ^2\theta +S({\mathcal {C}}_{\pi /2})\sin ^2\theta \end{aligned}$$

Proof

The signed area of the evolute \({\mathcal {C}}_{\pi /2}\) is negative in general, and zero if \({\mathcal {C}}\) is a circle. Integrating Eq. 2 by parts and simplifying it yields the claim. \(\square \)

Let L(.) denote the perimeter of a curve.

Proposition 9

For small \(\theta \), \(L({\mathcal {C}}_{\theta }\)) is given by:

$$\begin{aligned}L({\mathcal {C}}_{\theta } )=L({\mathcal {C}})\cos { \theta } \end{aligned}$$

Proof

Let TN define the tangent and normal axis of the Frenet frame. From Giblin and Warder (2014) we have that

$$\begin{aligned} {\mathcal {C}}_{\theta }(s)={\mathcal {C}}(s)+\frac{\cos \theta \sin \theta }{k(s)}T(s)+\frac{ \sin ^2\theta }{k(s)}N(s).\end{aligned}$$

Differentiating the above and using Frenet equations \(T'={k}N\) and \(N'=-{k}T\), it follows that

$$\begin{aligned} {\mathcal {C}}_{\theta }'(s)=\frac{ k(s) ^{2}\cos {\theta } - k'(s)\sin {\theta }}{ k(s) ^{2}} \left( N(s) \sin {\theta }+T(s) \cos {\theta } \right) \end{aligned}$$

Therefore,

$$\begin{aligned} |{\mathcal {C}}_{\theta }'(s)|= \left| \cos \theta -\frac{k'(s)}{k(s)^2}\sin \theta \right| .\end{aligned}$$

For small \(\theta \) it follows that

$$\begin{aligned} |{\mathcal {C}}_{\theta }'(s)|= \cos \theta -\frac{k'(s)}{k(s)^2}\sin \theta .\end{aligned}$$

Integration leads to the result stated. \(\square \)

Appendix B: Table of symbols

See Table 1.

Table 1 Symbols used

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Reznik, D., Garcia, R. & Stachel, H. Area-invariant pedal-like curves derived from the ellipse. Beitr Algebra Geom 63, 359–377 (2022). https://doi.org/10.1007/s13366-021-00588-x

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