Abstract
We consider a system of transmission of the wave equation with Neumann feedback control that contains a distributed delay term and that acts on the exterior boundary. We prove under some assumptions that the solutions decay exponentially in an appropriate energy space. To establish this result, we introduce a suitable energy function and use multipliers technique method and compactness-uniqueness argument.
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Appendix A Proof of the identity (3.10)
Appendix A Proof of the identity (3.10)
We multiply both sides of (1.1) by \(2\,h(x).\nabla y_{i}(x,t)+(divh(x)-\alpha )y_{i}(x,t)\) and integrate over \(\Omega _{i}\times (0,T), i=1,2;\) we have
We sum up (A1) for i, we obtain
Below, we compute the terms on the left-hand side of (A2).
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Term \(2\int _{0}^{T}\int _{\Omega }\partial _{t}^{2}y(x,t)h(x).\nabla y(x,t)dxdt\) Integration by parts in t yields
$$\begin{aligned}&2\int _{0}^{T}\int _{\Omega }\partial _{t}^{2}y(x,t)h(x).\nabla y(x,t)dxdt=2 \left[ \int _{\Omega }\partial _{t}y(x,t)h(x).\nabla y(x,t)dx\right] _{0}^{T} \nonumber \\&-\quad 2\int _{0}^{T}\int _{\Omega }\partial _{t}y(x,t)h(x).\nabla \partial _{t}y(x,t)dxdt \nonumber \\&\quad = 2\left[ \int _{\Omega }\partial _{t}y(x,t)h(x).\nabla y(x,t)dx\right] _{0}^{T}\nonumber \\&\quad -\int _{0}^{T}\int _{\Omega }h(x).\nabla ((\partial _{t}y(x,t))^{2})dxdt. \end{aligned}$$(A3)Applying Green’s theorem to the second integral on the right-hand side of (A3), we obtain
$$\begin{aligned}&2\int _{0}^{T}\int _{\Omega }\partial _{t}^{2}y(x,t)h(x).\nabla y(x,t)dxdt\nonumber \\&\quad =2 \left[ \int _{\Omega }\partial _{t}y(x,t)h(x).\nabla y(x,t)dx\right] _{0}^{T} \nonumber \\&\quad \quad -\int _{0}^{T}\int _{\Gamma }(\partial _{t}y(x,t))^{2}h(x).\nu (x)d\Gamma dt \mathbf {+}\int _{0}^{T}\int _{\Omega }(\partial _{t}y(x,t))^{2}divh(x)dxdt. \end{aligned}$$(A4) -
Term \(\int _{0}^{T}\int _{\Omega }\partial _{t}^{2}y(x,t)(divh(x)-\alpha )y(x,t)dxdt\) Using again integration by parts in t, we obtain
$$\begin{aligned}&\int _{0}^{T}\int _{\Omega }\partial _{t}^{2}y(x,t)(divh(x)-\alpha )y(x,t)dxdt \nonumber \\&\quad = \left[ \int _{\Omega }\partial _{t}y(x,t)(divh(x)-\alpha )y(x,t)dx\right] _{0}^{T}- \int _{0}^{T}\int _{\Omega }(\partial _{t}y(x,t))^{2}div(h(x)-\alpha )dxdt. \end{aligned}$$(A5) -
Term \(2\int _{0}^{T}\int _{\Omega _{1}}a_{1}\Delta y_{1}(x,t))h(x).\nabla y_{1}(x,t)dxdt+2\int _{0}^{T}\int _{\Omega _{2}}a_{2}\Delta y_{2}(x,t))h(x).\nabla y_{2}(x,t)dxdt\) From Green’s theorem, we have,
$$\begin{aligned}&2a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)h(x).\nabla y_{1}(x,t)dxdt\nonumber \\&\quad =2a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\frac{\partial y_{1}(x,t) }{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt \nonumber \\&\quad \quad + 2a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt\nonumber \\&\quad \quad - 2a_{1}\int _{0}^{T}\int _{\Omega _{1}}\nabla y_{1}(x,t).\nabla (h(x).\nabla y_{1}(x,t))dxdt. \end{aligned}$$(A6)Applying the identity
$$\begin{aligned} \nabla w(x).\nabla (h(x).\nabla w(x))=J(x)\nabla w(x).\nabla w(x)+\frac{1}{2} h(x).\nabla \left( \left| \nabla w(x)\right| ^{2}\right) \end{aligned}$$to the last integral on the right hand side of (A6), we find
$$\begin{aligned}&2a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)h(x).\nabla y_{1}(x,t)dxdt\\&\quad =2a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\frac{\partial y_{1}(x,t) }{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt \\&\quad\quad +2a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt\\&\quad\quad -2a_{1}\int _{0}^{T}\int _{\Omega _{1}}J(x)\nabla y_{1}(x,t).\nabla y_{1}(x,t))dxdt \\&\quad\quad- a_{1}\int _{0}^{T}\int _{\Omega _{1}}h(x).\nabla \left( \left| \nabla y_{1}(x,t)\right| ^{2}\right) . \end{aligned}$$Another use of Green’s theorem yields
$$\begin{aligned}&2a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)h(x).\nabla y_{1}(x,t)dxdt\nonumber \\&\quad =2a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\frac{\partial y_{1}(x,t) }{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt \nonumber \\&\quad\quad +2a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt\nonumber \\&\quad\quad -2a_{1}\int _{0}^{T}\int _{\Omega _{1}}J(x)\nabla y_{1}(x,t).\nabla y_{1}(x,t))dxdt \nonumber \\&\quad \quad-a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt\nonumber \\&\quad \quad-a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt \nonumber \\&\quad \quad+ a_{1}\int _{0}^{T}\int _{\Omega _{1}}\left| \nabla y_{1}(x,t)\right| ^{2}divh(x)dxdt. \end{aligned}$$(A7)For the intgral term \(2\int _{0}^{T}\int _{\Omega _{2}}a_{2}\Delta y_{2}(x,t))h(x).\nabla y_{2}(x,t)dxdt\), we proceed as above to find
$$\begin{aligned}&2a_{2}\int _{0}^{T}\int _{\Omega _{2}}\Delta y_{2}(x,t)h(x).\nabla y_{2}(x,t)d\Omega dt\nonumber \\&\quad =2a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\frac{\partial y_{2}(x,t)}{\partial \nu }h(x).\nabla y_{2}(x,t)d\Gamma dt \nonumber \\&\quad -2a_{2}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{2}(x,t)}{\partial \nu }h(x).\nabla y_{2}(x,t)d\Gamma dt\nonumber \\&\quad -2a_{2}\int _{0}^{T}\int _{\Omega _{2}}J(x)\nabla y_{2}(x,t).\nabla y_{2}(x,t))d\Omega dt \nonumber \\&\quad- a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt\nonumber \\&\quad +a_{2}\int _{0}^{T}\int _{\Gamma _{0}}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt \nonumber \\&\quad +a_{2}\int _{0}^{T}\int _{\Omega _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}divh(x)d\Omega dt. \end{aligned}$$(A8)Summing up (A7) and (A8) yields
$$\begin{aligned}&2\int _{0}^{T}\int _{\Omega }div(a(x)\nabla y(x,t))h(x).\nabla y(x,t) dxdt\nonumber \\&\quad =2a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\frac{\partial y_{1}(x,t)}{ \partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt\nonumber \\&\quad + 2a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)d\Gamma dt\nonumber \\&\quad - 2a_{1}\int _{0}^{T}\int _{\Omega _{1}}J(x)\nabla y_{1}(x,t).\nabla y_{1}(x,t))dxdt \nonumber \\&\quad - a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt\nonumber \\&\quad -a_{1}\int _{0}^{T}\int _{\Gamma _{0}}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt \nonumber \\&\quad + a_{1}\int _{0}^{T}\int _{\Omega _{1}}\left| \nabla y_{1}(x,t)\right| ^{2}divh(x)dxdt\nonumber \\&\quad +2a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\frac{\partial y_{2}(x,t) }{\partial \nu }h(x).\nabla y_{2}(x,t)d\Gamma dt \nonumber \\&\quad - 2a_{2}\int _{0}^{T}\int _{\Gamma _{0}}\frac{\partial y_{2}(x,t)}{\partial \nu }h(x).\nabla y_{2}(x,t)d\Gamma dt \nonumber \\&\quad - 2a_{2}\int _{0}^{T}\int _{\Omega _{2}}J(x)\nabla y_{2}(x,t).\nabla y_{2}(x,t))dxdt \nonumber \\&\quad -a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt\nonumber \\&\quad +a_{2}\int _{0}^{T}\int _{\Gamma _{0}}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt+ \nonumber \\&\quad a_{2}\int _{0}^{T}\int _{\Omega _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}divh(x)dxdt. \end{aligned}$$(A9)We conclude from the boundary conditions (1.3) and (1.5) that
$$\begin{aligned} \nabla y_{1}(x,t)=\frac{\partial y_{1}(x,t)}{\partial \nu }\nu (x)\text { on }\Gamma _{1}\times (0,T), \end{aligned}$$(A10)and
$$\begin{aligned} \nabla (y_{2}(x,t)-y_{1}(x,t))=\frac{\partial (y_{2}(x,t)-y_{1}(x,t))}{ \partial \nu }\nu (x),\text { on }\Gamma _{0}\times (0,T). \end{aligned}$$Then
$$\begin{aligned}&\left| \nabla y_{2}(x,t)\right| ^{2} =\left| \nabla y_{1}(x,t)\right| ^{2}+2\left( \frac{\partial y_{2}(x,t)}{\partial \nu }-\frac{ \partial y_{1}(x,t)}{\partial \nu }\right) \frac{\partial y_{1}(x,t)}{\partial \nu } \nonumber \\&\quad +\left( \frac{\partial y_{2}(x,t)}{\partial \nu }-\frac{\partial y_{1}(x,t)}{ \partial \nu }\right) ^{2} =\left| \nabla y_{1}(x,t)\right| ^{2}+ \left( \frac{\partial y_{2}(x,t)}{ \partial \nu }\right) ^{2}\nonumber \\&\quad - \left( \frac{\partial y_{1}(x,t)}{\partial \nu }\right) ^{2},\text { on }\Gamma _{0}\times (0,T), \end{aligned}$$so on \(\Gamma _{0}\times (0,T),\)
$$\begin{aligned}&2a_{1}\frac{\partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)\nonumber \\&\quad -2a_{2}\frac{\partial y_{2}(x,t)}{\partial \nu }h(x).\nabla y_{2}(x,t)- a_{1}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)\nonumber \\&\quad + a_{2}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)\nonumber \\&\quad =2a_{1}\frac{ \partial y_{1}(x,t)}{\partial \nu }h(x).\nabla y_{1}(x,t)-2a_{2}\frac{ {\partial }y_{2}(x,t)}{\partial \nu }\bigg (\nabla y_{1}(x,t)\nonumber \\&\quad + \left( \frac{ \partial y_{2}(x,t)}{\partial \nu }-\frac{{\partial }y_{1}(x,t)}{ {\partial }\nu }\right) \nu (x)\bigg ).h(x)\nonumber \\&\quad - a_{1}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)+a_{2}\bigg (\left| \nabla y_{1}(x,t)\right| ^{2}\nonumber \\&\quad + \left( \frac{\partial y_{2}(x,t)}{{\partial }\nu }\right) ^{2}-\left( \frac{{\partial }y_{1}(x,t) }{{\partial }\nu }\right) \bigg )h(x).\nu (x)\nonumber \\&\quad =\mathbf {-}2a_{1}\left( \frac{a_{1}}{a_{2}}-1\right) \left( \frac{\partial y_{1}(x,t)}{ \partial \nu }\right) ^{2}h(x).\nu (x)\nonumber \\&\quad\quad + (a_{2}-a_{1})\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)+\bigg (\frac{a_{1}^{2}}{a_{2}}\nonumber \\&\quad -a_{2}\bigg )\left( \frac{ \partial y_{1}(x,t)}{\partial \nu }\right) ^{2}h(x).\nu (x) \nonumber \\&\quad = (a_{2}-a_{1})\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)\nonumber \\&\quad - \frac{(a_{2}-a_{1})^{2}}{a_{2}}\left( \frac{\partial y_{1}(x,t)}{\partial \nu } \right) ^{2}h(x).\nu (x). \end{aligned}$$(A11)Insertion of (A10) and (A11) into (A9) results in
$$\begin{aligned}&2\int _{0}^{T}\int _{\Omega }div(a(x)\nabla y(x,t))h(x).\nabla y(x,t)dxdt\nonumber \\&\quad =a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\left( \frac{\partial y_{1}(x,t)}{ \partial \nu }\right) ^{2}h(x).\nu (x)d\Gamma dt \nonumber \\&\quad- (a_{1}-a_{2})\int _{0}^{T}\int _{\Gamma _{0}}\left| \nabla y_{1}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma \nonumber \\&\quad- \frac{(a_{2}-a_{1})^{2}}{a_{2} }\int _{0}^{T}\int _{\Gamma _{0}}\left( \frac{\partial y_{1}(x,t)}{\partial \nu } \right) ^{2}h(x).\nu (x)d\Gamma dt \nonumber \\&\quad+ 2a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\frac{\partial y_{2}(x,t)}{\partial \nu }h(x).\nabla y_{2}(x,t)d\Gamma dt\nonumber \\&\quad -a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}h(x).\nu (x)d\Gamma dt\nonumber \\&\quad- 2\int _{0}^{T}\int _{\Omega }a(x)J(x)\nabla y(x,t).\nabla y(x,t))dxdt\nonumber \\&\quad +\int _{0}^{T}\int _{\Omega }a(x)\left| \nabla y(x,t)\right| ^{2}divh(x)dxdt. \end{aligned}$$(A12) -
Term \(a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)(divh(x)-\alpha )y_{1}(x,t)dxdt+a_{2}\int _{0}^{T}\int _{\Omega _{2}}\Delta y_{2}(x,t)(divh(x)-\alpha )y_{2}(x,t)dxdt\) It follows from Green’s theorem that
$$\begin{aligned}&a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)(divh(x)-\alpha )y_{1}(x,t)dxdt \\&+\quad a_{2}\int _{0}^{T}\int _{\Omega _{2}}\Delta y_{2}(x,t)(divh(x)-\alpha )y_{2}(x,t)dxdt \\&=\quad a_{1}\int _{0}^{T}\int _{\Gamma _{1}}\frac{\partial y_{1}(x,t)}{\partial \nu }(divh(x)-\alpha )y_{1}(x,t)d\Gamma dt \\&+\quad \quad a_{1}\int _{0}^{T}\int _{\Gamma _{0}} \frac{\partial y_{1}(x,t)}{\partial \nu }(divh(x)-\alpha )y_{1}(x,t)d\Gamma dt\\&-\quad \quad a_{1}\int _{0}^{T}\int _{\Omega _{1}}\left| \nabla y_{1}(x,t)\right| ^{2}(divh(x)-\alpha )dxdt \\&-\quad \quad a_{1}\int _{0}^{T}\int _{\Omega _{1}}y_{1}(x,t)\nabla y_{1}(x,t).\nabla (divh(x)-\alpha )dxdt \\&+\quad \quad a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\frac{\partial y_{2}(x,t)}{\partial \nu }(divh(x)-\alpha )y_{2}(x,t)d\Gamma dt \\&-\quad \quad a_{2}\int _{0}^{T}\int _{\Gamma _{0}} \frac{\partial y_{2}(x,t)}{\partial \nu }(divh(x)-\alpha )y_{2}(x,t)d\Gamma dt \\&-\quad \quad a_{2}\int _{0}^{T}\int _{\Omega _{2}}\left| \nabla y_{2}(x,t)\right| ^{2}(divh(x)-\alpha )dxdt\\&-\quad \quad a_{2}\int _{0}^{T}\int _{\Omega _{2}}y_{2}(x,t)\nabla y_{2}(x,t).\nabla (divh(x)-\alpha )dxdt. \end{aligned}$$Thus from (1.3), (1.5) and (1.6), we conclude that
$$\begin{aligned}&a_{1}\int _{0}^{T}\int _{\Omega _{1}}\Delta y_{1}(x,t)(divh(x)-\alpha )y_{1}(x,t)dxdt\nonumber \\&+\quad a_{2}\int _{0}^{T}\int _{\Omega _{2}}\Delta y_{2}(x,t)(divh(x)-\alpha )y_{2}(x,t)dxdt \nonumber \\&=\quad a_{2}\int _{0}^{T}\int _{\Gamma _{2}}\frac{\partial y_{2}(x,t)}{\partial \nu }(divh(x)-\alpha )y_{2}(x,t)d\Gamma dt \nonumber \\&- \quad \quad \int _{0}^{T}\int _{\Omega }a(x)\left| \nabla y(x,t)\right| ^{2}(divh(x)-\alpha )dxdt \nonumber \\&-\quad \quad \int _{0}^{T}\int _{\Omega }a(x)y(x,t)\nabla y(x,t).\nabla (divh(x)-\alpha )dxdt. \end{aligned}$$(A13)The desired identity follows now from (A2), (A4), (A5), (A12) and (A13).
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Moumen, L., Rebiai, SE. Exponential stability of the transmission wave equation with a distributed delay term in the boundary damping. Rend. Circ. Mat. Palermo, II. Ser 72, 3459–3486 (2023). https://doi.org/10.1007/s12215-022-00834-8
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DOI: https://doi.org/10.1007/s12215-022-00834-8