Correction to: New Forests (2022) 53:449–468 https://doi.org/10.1007/s11056-021-09863-0

Some data presented in Table 5 in the original publication are incorrect, and the authors would like to replace Table 5 with the correct version below:

Table 5 Parameter estimates (with standard errors) for shoot biomass Eq. 4
Full size table

The parameter error also flows through to the worked example at the end of the results section. We would like to replace the worked example with the corrected version below.

The author would like to apologise for any inconvenience caused.

Part 1: Uncut component biomasses at age 5.

  1. 1.

    \(m_{cut} = d_{cut} /A_{cut} = 7.5/5 = 1.5\;{\text{cm/yr}}\)

  2. 2.

    \({\text{Uncut}}\;R_{4} /T_{4} = U_{cut} = 0.3116/\sqrt {m_{cut} } = 0.254\quad {\text{Eq}}{.}\;(2)\)

  3. 3.

    \(S = 0.1078g^{1.2173} = 0.1078*\left[ {\frac{\pi }{4}*7.5^{2} } \right]^{1.2173} = 10.851\;{\text{kg}}\quad {\text{Eq}}{.}\;{(4)}\)

  4. 4.

    \(T_{4} = \frac{S}{{1 - R_{4} /T_{4} }} = \frac{10.854}{{1 - 0.254}} = 14.554\;{\text{kg}}\)

  5. 5.

    \(R_{{4}} = U_{cut} T_{4} = 0.254*14.554 = 3.703\;{\text{kg}}\)

  6. 6.

    \(R = \varphi R_{4} = 1.5*3.703 = 5.555\;{\text{kg}}\)

Part 2: Coppice component biomasses at age 3.

  1. 7.

    \(R_{4} /T_{4} = 0.254 + 0.746*\exp \left( { - 2.055*\sqrt {1.5*3/5} } \right) = 0.419\quad {\text{Eq}}{.}\;(2)\)

  2. 8.

    \({\text{Years}}\;{\text{until}}\;R_{4} /T_{4} \;{\text{recovery}}:\;\;Y_{95} = 1.46*5/\sqrt {1.5} = 5.96\;{\text{yrs}}\quad {\text{Eq}}{.}\;(5)\)

  3. 9.

    \(R_{4} /T_{4} \;{\text{at}}\;{\text{recovery:}}\;U_{rec} = 0.05 + 0.95U_{cut} = 0.292\)

  4. 10.

    \( m_{1} = 2m_{{cut}} A_{{cut}} /Y_{{95}} = 2*1.5*5/5.96 = 2.517\;{\text{cm/yr}} \)

  5. 11.

    \( m_{{\text{2}}} = m_{{rec}} \left( {A_{{cut}} /Y_{{95}} + 1} \right) = \left( {0.3116/U_{{rec}} } \right)^{2} \left( {\frac{5}{{5.96}} + 1} \right) = 2.098 \)

  6. 12.

    \(d_{cop} = 3*2.517*\left[ {1 + \left( {1 + \frac{2.098}{{2.517}}} \right)\left( {2*3/5.96 + 1} \right)} \right] = 7.541\;{\text{cm}}\quad {\text{Eq}}{.}\;{(6)}\)

  7. 13.

    \(S = 0.1078g^{1.2173} = 0.1078*\left[ {\frac{\pi }{4}*7.54^{2} } \right]^{1.2173} = 10.998\;{\text{kg}}\quad {\text{Eq}}{.}\;{(4)}\)

  8. 14.

    \( T_{4} = \frac{S}{{1 - R_{4} /T_{4} }} = \frac{{10.998}}{{\left( {1 - 0.419} \right)}} = 18.932\;{\text{kg}} \)

  9. 15.

    \( R_{4} = T_{4} - S = 18.932 - 10.998 = 7.935\;{\text{kg}} \)

  10. 16.

    \(T = S + \varphi R_{4} = 10.998 + 1.5*7.935 = 22.899\;{\text{kg}}\)

  11. 17.

    \(R = T - S = 22.899 - 10.998 = 11.9{02}\;{\text{kg}}\)