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A fibre diameter distribution factor (FDDF) for natural fibre composites

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Fig. 1
Fig. 2

Notes

  1. Consequent upon the material presented above, we can substitute the data for jute fibres from Fig. 1 into the natural logarithm model (Eq. 3) to give Eq. 9:

    $$ E_{\text{f}} = 9 8. 8 8 - 17. 28 {\text{ ln (}}d) $$
    (9)

    The modulus of jute fibre at zero diameter is 98.88 GPa when measured assuming the “apparent” diameter for a circular cross section. Using the fibre area correction factor of 1.42 for this batch of jute fibres [33], we can correct this modulus to account for the non-circular cross section (98.88 × 1.42) and derive an elastic modulus of 140 GPa. A value of 140 GPa was estimated for cellulose when using X-ray diffraction to determine the strain [23]. Upper values for the modulus of cellulose I crystals are reported to be in the range 137–143 GPa [14–17, 36–38].

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Acknowledgements

The authors are grateful to Dr Stuart Lane in the School of Biomedical and Biological Sciences at University of Plymouth for advice on aspects of plant growth and ageing processes.

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Authors and Affiliations

  1. Advanced Composites Manufacturing Centre, School of Marine Science and Engineering/Reynolds Building, University of Plymouth, Plymouth, PL4 8AA, United Kingdom

    John Summerscales & Amandeep Singh Virk

  2. Griffith School of Engineering, Gold Coast Campus, Griffith University, Queensland, 4222, Australia

    Wayne Hall

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  1. John Summerscales
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Correspondence to John Summerscales.

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Summerscales, J., Hall, W. & Virk, A.S. A fibre diameter distribution factor (FDDF) for natural fibre composites. J Mater Sci 46, 5876–5880 (2011). https://doi.org/10.1007/s10853-011-5569-6

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