Simulation setting
For the numerical experiments, we consider a phase-space domain \(x \in [-20,20]\), \(p \in [-10, 10]\), and a time domain \(T \in [0,3]\) (recall that we are working in nondimensional variables). The initial position spread is assumed to be \(\delta = 0.8\) and the “spherical wave velocity” is assumed to be \(k_0 = 4\). The two spins are placed at \(x = \pm r\), with \(r = 7\), and the interaction function \(\gamma\) is assumed to have the super-Gaussian shape
$$\begin{aligned} \gamma (x) = \alpha \, \mathrm {e}^{-x^4/2\lambda ^2}, \end{aligned}$$
(20)
with \(\alpha = 2\) and \(\lambda = 0.4\). The above values are chosen so that:
-
1.
the wave has enough time to interact with the two spins and then move away;
-
2.
within the simulation time, the wave has no significant overlap with the border of the computational domain;
-
3.
the reflected waves are small and have not enough time to re-interact with the opposite spin.
Condition 2 implies that the experiments we perform are insensitive to the chosen boundary conditions (incidentally, we impose non re-entry conditions). Condition 3 is very important, since multiple interactions of the reflected waves represent a limitation of the one-dimensional model with respect to the realistic three-dimensional situation, where reflected waves play a negligible role [11].
For the numerical implementation of Eq. (17) we use a simple splitting scheme. Each time step \(\varDelta t\) is divided into two substeps of length \(\varDelta t/2\): In the first one, only the free-transport operator \(-p\partial _x\) is considered and the system evolves according to
$$\begin{aligned} W(x,p,t + \varDelta t/2) = W(x -p \varDelta t/2 ,p,t). \end{aligned}$$
In the second one, only the interaction (second and third terms at the right-hand side of Eq. (17)) operates between \(t+\varDelta t/2\) and \(t + \varDelta t\). Since a pseudo-differential operator is involved, this interaction step is easily implemented by using back and forth Fourier transform. We remark that the present paper is focused on the model and not on the numerical aspects: we just chose a simple numerical method, which is certainly not the most efficient nor the most accurate one.
Dynamics of localization
In Figs. 1 and 2, we can follow the evolution of some of the Pauli components of the Wigner matrix W(x, p, t).
In particular, Fig. 1 displays \(w_{00}\), \(w_{30}\), \(w_{03}\) and \(w_{33}\), which are the only initially non-zero components (see (18)) and which determine the probabilities of the up/down states, according to (15). Each column contains a time snapshot of the four components in the phase space (x, p). Here and in the following figures, the background gray corresponds to the value 0, the lighter gray corresponds to positive values and the darker gray to negative ones. At \(t = 0\) we can see therefore the gray-level representation of \(w_0(x,p)\): note the two counter-moving Gaussians and the central interference fringes. The two Gaussians move freely until they reach the two spins (concentrated around \(x = \pm 7\)) and the interaction begins, turning the spin from up (positive values) to down (negative values). Once the interaction zones have been overcome, the transmitted waves move away freely. Note also the presence of small reflected waves (the reflected portion of the wave is larger when the interaction strength \(\alpha\) is increased).
To interpret these pictures, let us recall that \(w_{00}\) is the Wigner function of the system where the spin degrees of freedom are traced out; hence \(w_{00}\) is the pseudo-distribution in phase space of the emitted particle. Analogously, \(w_{30}\) (respectively, \(w_{03}\)) can be interpreted as the pseudo-distribution in phase space of the value of the z-component of the left (respectively, right) spin. Note that, after the interaction, the state of the left spin is down on the left-hand side and up on the right-hand side. This corresponds to the fact that the left spin is down if the particle will be detected on the left and it is up if the particle will be detected on the right (of course, the symmetrical conclusions can be drawn on the right spin). Therefore, the component \(w_{33}\), which is the pseudo-distribution of the product of the z-component of the two spins, is always negative after the interaction.
Figure 2 shows the evolution of other spin components: Since they are not directly involved in the localization process, we shall limit ourselves to commenting on them briefly in the figure caption.
Let us rather look at Fig. 3, where we plot the Wigner functions
$$\begin{aligned} \begin{aligned}&w_{uu} = w_{00} + w_{30} + w_{03} + w_{33}, \\&w_{ud} =w_{00} + w_{30} - w_{03} - w_{33}, \\&w_{du} = w_{00} - w_{30} + w_{03} - w_{33}, \\&w_{dd} = w_{00} - w_{30} - w_{03} + w_{33}, \end{aligned} \end{aligned}$$
(21)
which, according to (15), can be interpreted as the phase-space quasi-distributions of the uu, ud, du and dd states. It is immediately apparent that at \(t = 0\) only the uu state is populated while, after the interactions, the ud and du states gain the highest probability, and the dd state remains with zero probability. Indeed, computing the integrals over phase space of the four components at \(t = 3\) yields the total probabilities
$$\begin{aligned}&{\Vert {\varPsi _{uu}} \Vert }^2 = 0.1664, \quad {\Vert {\varPsi _{ud}} \Vert }^2 = 0.4168, \quad {\Vert {\varPsi _{du}} \Vert }^2 = 0.4168, \\&\quad {\Vert {\varPsi _{dd}} \Vert }^2 = 0.0000 . \end{aligned}$$
As already mentioned in Sect. 2, such values are the sign of localization: the probability of detecting the particle at both sides is nearly zero, while the larger probability is that of detecting the particle on one of the two sides (with equal probability). There is also a certain probability that the particle is not detected at all, which depends on the interaction strength \(\alpha\). We remark that there might be a tiny nonzero probability of detection at both sides, due to reflected waves (and to the non-perfect locality of the interaction function \(\gamma\)): as already pointed out, the effect of reflected waves is even smaller in the two- or three-dimensional cases.
By comparing Figs. 1 and 3, it is clear from (21) that the prevalence of \(w_{ud}\) and \(w_{du}\), and the smallness of \(w_{dd}\) can be interpreted in terms of constructive/destructive interference among the components \(w_{00}\), \(w_{30}\), \(w_{03}\) and \(w_{33}\). But a more insightful way to understand the phenomenon is in terms of projections and entanglement, which will be treated in the next subsection.
Relationships with entanglement
It will be useful to adopt Dirac’s notation for the spin states. Our initial state can be represented as
$$\begin{aligned} \psi {\vert u \rangle }{\vert u \rangle } \end{aligned}$$
where \(\psi\) is the initial particle wave function, the first \({\vert u \rangle }\) is the initial state of the left spin and the second \({\vert u \rangle }\) is the initial state of the right spin (both are up). The fact that the state is factorized corresponds to the initial independence of the particle and the two spins. The initial particle wave function is the sum of the two wave packets with mean velocities \(-k_0\) and \(+k_0\). So, before the interaction, the state of the system keeps the form
$$\begin{aligned} \psi ^- {\vert u \rangle }{\vert u \rangle } + \psi ^+ {\vert u \rangle }{\vert u \rangle }, \end{aligned}$$
where \(\psi ^\pm\) denote the two counter-moving wave packets as they have moved away from the origin (\(\psi ^-\) and \(\psi ^+\) being approximately localized at \(x<0\) and \(x>0\), respectively). In this situation, the projections \(P_{ud}\), \(P_{du}\) and \(P_{dd}\) (see Eq. (14), where the plus sign corresponds to u and the minus sign corresponds to d) are of course zero. In terms of the Wigner matrix, this situation can be visualized in the first column of Figs. 1, 2 and 3. Then, interactions take place (second and third columns of Figs. 1, 2 and 3), progressively increasing the d-component of the left and right spins. After that (fourth column of Figs. 1, 2 and 3), the state has (schematically) the form
$$\begin{aligned} \left( \psi _u^- {\vert u \rangle } + \psi _d^-{\vert d \rangle }\right) {\vert u \rangle } + {\vert u \rangle } \left( \psi _u^+ {\vert u \rangle } + \psi _d^+{\vert d \rangle }\right) , \end{aligned}$$
(22)
where \(\psi _u^\pm\) and \(\psi _u^\pm\) are position-dependent coefficients. We see therefore that the state is not factorized any longer (indeed, it is an entangled state) but, nevertheless, it is locally, side-wise, factorized. This implies that the \(P_{dd}\) projection of this state is null:
$$\begin{aligned}&P_{dd} \left[ \left( \psi _u^- {\vert u \rangle } + \psi _d^-{\vert d \rangle }\right) {\vert u \rangle } \right. \nonumber \\&\quad \left. + {\vert u \rangle } \left( \psi _u^+ {\vert u \rangle } + \psi _d^+{\vert d \rangle }\right) \right] = \nonumber \\&\quad P_d\left( \psi _u^- {\vert u \rangle } + \psi _d^-{\vert d \rangle }\right) P_d{\vert u \rangle } \nonumber \\&\quad + P_d{\vert u \rangle }\, P_d\left( \psi _u^+ {\vert u \rangle } + \psi _d^+{\vert d \rangle }\right) = 0, \end{aligned}$$
(23)
which explains the smallness of the dd component. Actually, the expression (22) of the final state is just an approximation, because a possible entanglement of the right spin on the left side and of the left spin on the right side arises from reflected waves (and also, but this is of course a negligible effect, form the non-perfect locality of the interaction function (20)). However, our simulations show that such approximation is really good, at least for the chosen values of the parameters. This is illustrated in Fig. 7, which is explained below.
What emerges from the preceding discussion is that two main facts determine the localization process:
-
1.
The two spins and the particle are initially independent;
-
2.
The interactions produce on each side the local entanglement of one spin and preserve the independence of the other one.
In order to illustrate point 1, let us change our experiment by assuming that the two spins are initially entangled. In particular, let us assume that they initially are in the so-called singlet state
$$\begin{aligned} \frac{{\vert u \rangle }{\vert d \rangle } - {\vert d \rangle }{\vert u \rangle }}{\sqrt{2}}, \end{aligned}$$
corresponding to an initial Wigner matrix (expressed in terms of the Pauli components) of the form
$$\begin{aligned} W(x,p,0) = w_0(x,p) \begin{pmatrix} 1&0&0&0 \\ 0&-1&0&0 \\ 0&0&-1&0 \\ 0&0&0&-1\end{pmatrix}. \end{aligned}$$
(24)
Figures 4 and 5 are the equivalent of Figs. 1 and 3 where the initial Wigner function (18) has been substituted with (24).
We see that the situation is now completely different and localization does not occur. On the contrary, the dd state gains the highest probability. By integration on phase space, we indeed obtain the post-interaction probabilities
$$\begin{aligned}&{\Vert {\varPsi _{uu}} \Vert }^2 = 0.4168, \quad {\Vert {\varPsi _{ud}} \Vert }^2 = 0.0832, \quad {\Vert {\varPsi _{du}} \Vert }^2 = 0.0832, \\&\quad {\Vert {\varPsi _{dd}} \Vert }^2 = 0.4168 . \end{aligned}$$
Coming to point 2, we can check the emergence of entanglement in the system by computing the purity of the spin states. As it follows from the discussion in Sect. 3,
$$\begin{aligned} \rho _k = \int w_{k0}(x,p) \,{\mathrm {d}}p\,{\mathrm {d}}x , \qquad k = 0,1,2,3 \end{aligned}$$
are the Pauli components of the reduced density matrix \(\rho _\textit{red}\) of the left spin (i.e., the density matrix obtained by tracing out the degrees of freedom of the right spin and of the particle). The purity index is defined as
$$\begin{aligned} {{\,\mathrm{tr}\,}}( \rho _\textit{red}^2) = \frac{1}{2}\sum _{k = 0}^3 \rho _k^2. \end{aligned}$$
(25)
If the left spin remains independent, then its reduced density matrix is that of a pure state (characterized by \(\rho _1^2+\rho _2^2+\rho _3^2 = \rho _0^2 = 1\)), and the purity index is 1. If the spin gets entangled, its reduced density matrix is that of a mixed state (characterized by \(\rho _1^2+\rho _2^2+\rho _3^2 < \rho _0^2 = 1\)) and the purity lies between 1/2 and 1. Figure 6 shows the computed evolution in time of the purity index in three cases: the case of the initially independent spins (corresponding to the initial datum (18)), the case of the initially entangled spins (corresponding to the initial datum (24)) and, as a further check, the case of initially independent spins without interaction (corresponding to initial datum (18) and \(\alpha = 0\)). As we can see from the figure, the interaction introduces entanglement in the initially unentangled system.
Let us address the local behaviour of the purity for initially independent spins. In Fig. 7, we plot four time snapshots of the x-dependent quantity
$$\begin{aligned} \Big ( \int w_{00}(x,p)\,{\mathrm {d}}p \Big )^2 - \sum _{k = 1}^3 \Big ( \int w_{k0}(x,p)\,{\mathrm {d}}p \Big )^2, \end{aligned}$$
(26)
which can be interpreted as a “local impurity” index of the left spin (it is zero if the reduced density matrix obtained by tracing out the right spin at fixed x is a that of a pure state). We see that the left spin gets locally entangled (with the particle) at the right-hand side while remaining locally independent on the right-hand side. Of course, the converse is true for the right spin. Figures 6 and 7 confirm the fact that interactions produce on each side local entanglement of one of the two spin, preserving the local independence of the other one, thus creating the conditions under which (23) holds and, therefore, localization takes place.
As a final remark, let us point out that if we had sent from the emitter two independent particles in the two directions, instead of the single particle we have sent, system entanglement and localization would have not occurred. In fact, for an initial state of the form
$$\begin{aligned} \psi \, \varphi \, {\vert u \rangle }{\vert u \rangle } \end{aligned}$$
where now \(\psi\) is the wave function of a left-moving particle and \(\varphi\) is the wave function of another, right-moving, particle, the post-interaction state would have the form
$$\begin{aligned} \left( \psi _u {\vert u \rangle } + \psi _d{\vert d \rangle }\right) \left( \varphi _u {\vert u \rangle } + \varphi _d{\vert d \rangle }\right) , \end{aligned}$$
since each spin has interacted with a different particle. In this case, the post-interaction dd state is given by
$$\begin{aligned} P_{dd} \left[ \left( \psi _u {\vert u \rangle } + \psi _d{\vert d \rangle }\right) \left( \varphi _u {\vert u \rangle } + \varphi _d{\vert d \rangle }\right) \right] = \\ P_d\left( \psi _u {\vert u \rangle } + \psi _d{\vert d \rangle }\right) P_d\left( \varphi _u {\vert u \rangle } + \varphi _d{\vert d \rangle }\right) = \psi _d{\vert d \rangle } + \varphi _d{\vert d \rangle }, \end{aligned}$$
which has a nonzero amount of probability, depending on the efficiency of the spin flip. Indeed, the probability of detecting two particles, one on each side, has no reason to be zero.