We will use Schwarz alternating method (SAM) [9, 22,23,24,25,26] to solve the problem, as it yields a solution of the problem within the (01) approximation of SAM, which refers to the problem formulated for circular inclusions \(\Omega _{i}^{-\,\left( 0 \right) } \) embedded into the infinite space \(\Omega _{i}^{+\,\left( 0 \right) } \). Note that the convergence of the Schwarz algorithm under fairly general assumptions was proved in [27]. Mikhlin [27] stated the problem of convergence and proved it for a doubly connected domain. He also noticed that the method should work for a multiple connected domain when the holes are far away one from another. The convergence of the Schwarz alternating method in the general case for an arbitrary multiply connected domain was proved in publications summarized in Chapter 3 of [9].
In the latter case, the problem defined on the cell (2.1)–(2.4) can be recast in the fast polar coordinates \(r\,,\;\theta \), and it is governed by the following equations:
$$\begin{aligned}&\displaystyle \frac{\partial ^{2}u_{1}^{- \left( 01 \right) }}{\partial r^{2}}+\frac{1}{r}\cdot \frac{\partial u_{1}^{- \left( 01 \right) }}{\partial r}+\frac{1}{r^{2}}\cdot \frac{\partial ^{2}u_{1}^{- \left( 01 \right) }}{\partial \theta ^{2}}=0\quad \mathrm {in}\,\varOmega _{i}^{- \left( 0 \right) }; \end{aligned}$$
(3.1)
$$\begin{aligned}&\displaystyle \frac{\partial ^{2}u_{1}^{+ \left( 01 \right) }}{\partial r^{2}}+\frac{1}{r}\cdot \frac{\partial u_{1}^{+ \left( 01 \right) }}{\partial r}+\frac{1}{r^{2}}\cdot \frac{\partial ^{2}u_{1}^{+ \left( 01 \right) }}{\partial \theta ^{2}}=0\quad \mathrm {in}\,\varOmega _{i}^{+ \left( 0 \right) }; \end{aligned}$$
(3.2)
$$\begin{aligned}&\displaystyle u_{1}^{+ \left( 01 \right) }=u_{1}^{- \left( 01 \right) };\quad \frac{\partial u_{1}^{+ \left( 01 \right) }}{\partial r}-\lambda \frac{\partial u_{1}^{- \left( 01 \right) }}{\partial r}=\left( \lambda -1 \right) \left( \frac{\partial u_{0}}{\partial x}\cos \theta +\frac{\partial u_{0}}{\partial y}\sin \theta \right) \quad \mathrm {for}\,r=\tilde{a}; \end{aligned}$$
(3.3)
$$\begin{aligned}&\displaystyle u_{1}^{+ \left( 01 \right) }\rightarrow 0; \quad \frac{\partial u_{1}^{+ \left( 01 \right) }}{\partial r}\rightarrow 0\quad \mathrm {for}\,r\rightarrow \infty . \end{aligned}$$
(3.4)
A solution to the coupled problem (3.1)–(3.4) takes the form
$$\begin{aligned}&u_{1}^{-\;\left( {01} \right) } =A_{1}^{\left( {01} \right) } \,r\cos \,\theta +A_{2}^{\left( {01} \right) } \,r\sin \,\theta , \end{aligned}$$
(3.5)
$$\begin{aligned}&u_{1}^{+\;\left( {01} \right) } =\frac{B_{1}^{\left( {01} \right) } }{r}\,\cos \,\theta +\frac{B_{2}^{\left( {01} \right) } }{r}\,\sin \,\theta , \end{aligned}$$
(3.6)
where \(A_{1}^{\left( {01} \right) } \,,\;A_{2}^{\left( {01} \right) } \,,\;B_{1}^{\left( {01} \right) } \,,\;B_{2}^{\left( {01} \right) } \) are arbitrary constants.
It is worthy to mention that representation of the function \(u_{1}^{-\;\left( {01} \right) } \) in the form of (3.5) includes the boundaries of the function governing temperature distribution and its derivation \(\frac{\partial u_{1}^{-\;\left( {01} \right) } }{\partial r}\) (heat stream in radial direction) for \(r=0,\) whereas the function \(u_{1}^{+\;\left( {01} \right) } \) (3.6) satisfies conditions of damping of the latter characteristics for \(r\,\rightarrow \infty \) (3.4).
Observe that relations (3.5), (3.6) include four arbitrary constants, i.e. each two for them stand as the basic functions \(\cos \,\theta \) and \(\sin \,\theta \) (\(A_{1}^{\left( {01} \right) } \,,\;B_{1}^{\left( {01} \right) } \) and \(A_{2}^{\left( {01} \right) } \,,\;B_{2}^{\left( {01} \right) } \), respectively), which are defined through compatibility conditions (3.3). Since the systems of equations which require definition of the integration constants \(A_{1}^{\left( {01} \right) } \,,\;B_{1}^{\left( {01} \right) } \) and \(A_{2}^{\left( {01} \right) } \,,\;B_{2}^{\left( {01} \right) } \) are the same to avoid repetitions, to avoid repetition, we present only one of them:
$$\begin{aligned} \left\{ {\begin{array}{l} A_{1}^{\left( {01} \right) } \,a=B_{1}^{\left( {01} \right) } \,a^{-\,1}, \\ -B_{1}^{\left( {01} \right) } \,a^{-\,2}-\lambda A_{1}^{\left( {01} \right) } =\frac{\partial u_{0} }{\partial x}\,\left( {\lambda -1} \right) . \\ \end{array}} \right. \end{aligned}$$
(3.7)
Solving equations (3.7) allows to find the integration constants
$$\begin{aligned} \left\{ {\begin{array}{l} A_{1}^{\left( {01} \right) } =-\frac{\lambda -1}{\lambda +1}\,\frac{\partial u_{0} }{\partial x}=\frac{\partial u_{0} }{\partial x}\,A^{\left( {01} \right) \,^{*}}, \\ B_{1}^{\left( {01} \right) } =-\frac{\left( {\lambda -1} \right) \,a^{2}}{\lambda +1}\,\frac{\partial u_{0} }{\partial x}=\frac{\partial u_{0} }{\partial x}\,B^{\left( {01} \right) \,^{*}}, \\ \end{array}} \right. \end{aligned}$$
(3.8)
where
$$\begin{aligned} A^{\left( {01} \right) \,^{*}} =-\frac{\lambda -1}{\lambda +1}\,\quad \text{ and }\quad \;\;B^{\left( {01} \right) \,^{*}} =-\frac{\left( {\lambda -1} \right) \,a^{2}}{\lambda +1}. \end{aligned}$$
(3.9)
It is clear that for arbitrary constants \(A_{2}^{\left( {01} \right) } \,\;\text{ and }\;\;B_{2}^{\left( {01} \right) } \) we have
$$\begin{aligned} A_{2}^{\left( {01} \right) } =A_{1}^{\left( {01} \right) } \,\quad \text{ and }\quad \;\;B_{2}^{\left( {01} \right) } =B_{1}^{\left( {01} \right) } \,\,\left( {\frac{\partial u_{0} }{\partial x}\rightarrow \frac{\partial u_{0} }{\partial y}} \right) . \end{aligned}$$
(3.10)
Therefore, the solution of the (01) approximation is as follows:
$$\begin{aligned} { u}_{{1}}^{{- }\left( {01} \right) }{=-}\frac{{\partial }{u}_{{0}}}{\partial {x}}\frac{{\lambda -1}}{{\lambda +1}}{r}\cos {\theta }{-}\frac{{\partial }{u}_{{0}}}{\partial {y}}\frac{{\lambda -1}}{{\lambda +1}}{r}\sin {\theta },\quad {u}_{{1}}^{{+ }\left( {01} \right) }{=-}\frac{{\partial }{u}_{{0}}}{\partial {x}}\frac{{\lambda -1}}{{\lambda +1}}{a}^{{2}}\frac{\cos {\theta }}{{r}}{-}\frac{{\partial }{u}_{{0}}}{\partial {y}}\frac{{\lambda -1}}{{\lambda +1}}{a}^{{2}}\frac{\sin {\theta }}{{r}},\nonumber \\ \end{aligned}$$
(3.11)
or equivalently
$$\begin{aligned} u_{1}^{- \left( 01 \right) }=-\frac{\lambda -1}{\lambda +1}\left( \frac{\partial u_{0}}{\partial x}\xi +\frac{\partial u_{0}}{\partial y}\eta \right) , \quad u_{1}^{+ \left( 01 \right) }=-\frac{\partial u_{0}}{\partial x}\frac{\lambda -1}{\lambda +1}a^{2}\left( \frac{\partial u_{0}}{\partial x}\frac{\xi }{\xi ^{2}+\eta ^{2}}+\frac{\partial u_{0}}{\partial y}\frac{\eta }{\xi ^{2}+\eta ^{2}} \right) . \end{aligned}$$
(3.11')
In what follows, we construct the (02) approximation of the SAM, which refers to the solution of the problem in the cell matrix \(\Omega _{i}^{*} \).
Now, the periodicity conditions (2.4) located on opposite sides of the cell are satisfied, and the compatibility conditions (2.3) are ignored. Since the function \(u_{1}^{\left( {02} \right) } \) should correct errors occurring in the solution \(u_{1}^{+\;\left( {01} \right) } \) on the sizes of the cell, the following boundary value problem holds:
$$\begin{aligned}&\Delta u_{1}^{\left( {02} \right) } =0\quad \text{ in }\,\Omega _{i}^{*} ; \end{aligned}$$
(3.12)
$$\begin{aligned}&\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\xi =1} } \right. =\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\xi =\,-\,1} } \right. , \nonumber \\&{\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) }{\partial \xi }\,\,\left| {\,_{\xi =1} } \right. =\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) }{\partial \xi }\,\,\left| {\,_{\xi =\,-\,1} } \right. ,} \end{aligned}$$
(3.13)
$$\begin{aligned}&\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\eta =1} } \right. =\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\eta =\,-\,1} } \right. , \nonumber \\&\quad {\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) }{\partial \eta }\,\,\left| {\,_{\eta =1} } \right. =\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{1}^{\left( {02} \right) } } \right) }{\partial \eta }\,\,\left| {\,_{\eta =\,-\,1} } \right. }. \end{aligned}$$
(3.14)
We assume
$$\begin{aligned} u_{1}^{\left( {02} \right) } =u_{11}^{\left( {02} \right) } +u_{12}^{\left( {02} \right) } , \end{aligned}$$
(3.15)
where \(u_{11}^{\left( {02} \right) } \) satisfies non-homogenous boundary conditions with regard to \(\xi \) and homogenous boundary condition with regard to \(\eta \). Therefore, the following equations should be satisfied:
$$\begin{aligned}&\Delta u_{11}^{\left( {02} \right) } =0\quad \text{ in }\, \Omega _{i}^{*} ; \end{aligned}$$
(3.16)
$$\begin{aligned}&\left( {u_{1}^{+\;\left( {01} \right) } +u_{11}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\xi =1} } \right. =\left( {u_{1}^{+\;\left( {01} \right) } +u_{11}^{\left( {02} \right) } } \right) \,\,\left| {\,_{\xi =\,-\,1} ,}\right. \nonumber \\&{\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{11}^{\left( {02} \right) } } \right) }{\partial \xi }\,\,\left| {\,_{\xi =1} } \right. =\frac{\partial \,\left( {u_{1}^{+\;\left( {01} \right) } +u_{11}^{\left( {02} \right) } } \right) }{\partial \xi }\,\,\left| {\,_{\xi =\,-\,1} } \right. } , \end{aligned}$$
(3.17)
$$\begin{aligned}&u_{11}^{\left( {02} \right) } \,\left| {\,_{\eta =1} } \right. =u_{11}^{\left( {02} \right) } \,\left| {\,_{\eta =\,-\,1} } \right. \,;\;\;\frac{\partial u_{11}^{\left( {02} \right) } }{\partial \eta }\,\left| {\,_{\eta =1} } \right. =\frac{\partial u_{11}^{\left( {02} \right) } }{\partial \eta }\,\left| {\,_{\eta =\,-\,1} } \right. . \end{aligned}$$
(3.18)
It is obvious that the function \(u_{12}^{\left( {02} \right) } \) can be found in an analogous way simply by using the change: \(\xi \,\,{\begin{array}{*{20}c} \rightarrow \\ \leftarrow \\ \end{array} }\,\,\eta \).
A general solution of Eq. (3.16) takes the form
$$\begin{aligned}&{u}_{11}^{\left( {02} \right) } ={A}_{0}^{\left( {02} \right) } +{B}_{0}^{\left( {02} \right) } \,\xi +\sum \limits _{{n}=1}^\infty {\left[ {\,\left( {{A}_{\mathrm{n}}^{\left( {02} \right) } \,\cosh \,\uppi {n}\xi + {B}_{\mathrm{n}}^{\left( {02} \right) } \,\sinh \,\uppi {n}\xi } \right) \,\cos \,\uppi {n}\eta } \right. } \nonumber \\&\quad +\left. {\left( {{C}_{\mathrm{n}}^{\left( {02} \right) } \,\cosh \,\uppi {n}\xi + {D}_{\mathrm{n}}^{\left( {02} \right) } \,\hbox {sinh}\,\uppi {n}\xi } \right) \,\sin \,\uppi {n}\eta } \right] , \end{aligned}$$
(3.19)
where \(A_{0}^{\left( {02} \right) } \,,\;B_{0}^{\left( {02} \right) } \,,\;A_{n}^{\left( {02} \right) } \,,\;B_{n}^{\left( {02} \right) } \,,\;C_{n}^{\left( {02} \right) } \,,\;D_{n}^{\left( {02} \right) } \;\left( {n=1\,,\;2\,,\;...} \right) \) are arbitrary constants.
In order to satisfy the boundary conditions (3.17), we recast them considering the (01) approximation of (3.11) to the following form:
$$\begin{aligned} \begin{array}{l} \;u_{11}^{\left( {02} \right) } \,\left| {\,_{\xi =1} } \right. -u_{11}^{\left( {02} \right) } \,\left| {\,_{\xi =\,-\,1} } \right. =\frac{\partial u_{0} }{\partial x}\cdot \frac{2\,a^{2}}{1+\eta ^{2}}\,\frac{\lambda -1}{\lambda +1}, \\ \frac{\partial u_{11}^{\left( {02} \right) } }{\partial \xi }\,\left| {\,_{\xi =1} } \right. -\frac{\partial u_{11}^{\left( {02} \right) } }{\partial \xi }\,\left| {\,_{\xi =\,-\,1} } \right. =-\frac{\partial u_{0} }{\partial y}\cdot \frac{4\,a^{2}\eta }{\left( {1+\eta ^{2}} \right) ^{2}}\,\frac{\lambda -1}{\lambda +1}. \\ \end{array} \end{aligned}$$
(3.20)
The right-hand sides of equations (3.20) are expand into the following Fourier series:
$$\begin{aligned} \begin{array}{l} \frac{1}{1+\eta ^{2}}=\frac{\pi }{4}+\sum \limits _{n=1}^\infty {\,\left[ {e^{-\,\pi n}\,\hbox {Im}\,E_{1} \left( {-\pi n+i\pi n} \right) {-e^{\pi n}\,\hbox {Im}\,E_{1} \left( {\pi n+i\pi n} \right) +\pi e^{-\,\pi n}}} \right] } \cos \,\pi n\eta , \\ \frac{\eta }{\left( {1+\eta ^{2}} \right) ^{2}}=\frac{\pi }{2}\sum \limits _{n=1}^\infty {\,n\,\left[ {e^{\pi n}\,\hbox {Im}\,E_{1} \left( {\pi n+i\pi n} \right) {-e^{-\,\pi n}\,\hbox {Im}\,E_{1} \left( {-\pi n+i\pi n} \right) -\pi e^{-\,\pi n}}} \right] } \,\sin \,\pi n\eta , \\ \end{array} \end{aligned}$$
(3.21)
where \(i=\sqrt{-1} \) and \(E_{1} \) stands for the exponential integral [28].
Comparison of the corresponding coefficients in (3.20), accounting for (3.21) yields the (02) approximation coefficients:
$$\begin{aligned}&A_{0}^{\left( {02} \right) } =0\,;\;A_{n}^{\left( {02} \right) } =D_{n}^{\left( {02} \right) } =0\,,\;\;n=1\,,\;2,\ldots ; \nonumber \\&B_{0}^{\left( {02} \right) } =\frac{\partial u_{0} }{\partial x}\,B_{0}^{\left( {02} \right) \,^{*}} ;\;\;B_{n}^{\left( {02} \right) } =\frac{\partial u_{0} }{\partial x}\,B_{n}^{\left( {02} \right) \,^{*}} \,;\;\;C_{n}^{\left( {02} \right) } =\frac{\partial u_{0} }{\partial y}\,C_{n}^{\left( {02} \right) \,^{*}} \,,\;\;n=1\,,\;2\,,\;...\,; \end{aligned}$$
(3.22)
$$\begin{aligned}&B_{0}^{\left( {02} \right) \,^{*}} =\frac{\lambda -1}{\lambda +1}\cdot \frac{\pi a^{2}}{4}; \end{aligned}$$
(3.23)
$$\begin{aligned}&B_{n}^{\left( {02} \right) \,^{*}} =-C_{n}^{\left( {02} \right) \,^{*}} =\frac{\lambda -1}{\lambda +1}\,a^{2}\,S_{n} , \end{aligned}$$
(3.24)
where
$$\begin{aligned} {S}_{\mathrm{n}} =\frac{{e}^{-\,\uppi {n}}\,\hbox {Im}\,{E}_{1} \left( {-\uppi {n+i}\uppi {n}} \right) -{e}^{\uppi {n}}\,\hbox {Im}\,{E}_{1} \left( {\uppi {n}+\hbox {i}\uppi {n}} \right) +\uppi {e}^{-\,\uppi {n}}}{\sinh \,\uppi {n}}. \end{aligned}$$
(3.25)
Consequently, we get
$$\begin{aligned} {u}_{11}^{\left( {02} \right) } =\frac{\partial {u}_{0} }{\partial {x}}\,{B}_{0}^{\left( {02} \right) \,^{*}} \xi +\sum \limits _{{n}=1}^\infty {\,\left( {\frac{\partial {u}_{0} }{\partial {x}}\,{B}_{\mathrm{n}}^{\left( {02} \right) \,^{*}} \sinh \,\uppi {n}\xi \,\cos \,\uppi {n}\eta -\frac{\partial {u}_{0} }{\partial {y}}\,{C}_{\mathrm{n}}^{\left( {02} \right) \,^{*}} \cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } . \end{aligned}$$
(3.26)
Proceeding in an analogous way yields
$$\begin{aligned} u_{12}^{\left( {02} \right) } =u_{11}^{\left( {02} \right) } \;\;\left( {\frac{\partial u_{0} }{\partial x}\,\,{\begin{array}{*{20}c} \rightarrow \\ \leftarrow \\ \end{array} }\,\frac{\partial u_{0} }{\partial y}\,;\;\;\xi \,\,{\begin{array}{*{20}c} \rightarrow \\ \leftarrow \\ \end{array} }\,\,\eta } \right) . \end{aligned}$$
(3.27)
Finally, the (02) order approximation takes the following form:
$$\begin{aligned}&{u}_{1}^{\left( {02} \right) } =\frac{\lambda -1}{\lambda +1}\cdot \frac{\uppi {a}^{2}}{4}\left( {\frac{\partial {u}_{0} }{\partial {x}}\,\xi +\frac{\partial {u}_{0} }{\partial {y}}\,\eta } \right) +\frac{\lambda -1}{\lambda +1}\,{a}^{2}\sum \limits _{{n}=1}^\infty {\,{S}_{\mathrm{n}} \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\uppi {n}\xi \,\cos \,\uppi {n}\eta -} \right. } \right. } \nonumber \\&\quad -\left. {\left. {\cosh \,\uppi {n}\eta \,\sin \,\uppi {n}\xi } \right) +\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi {n}\eta \,\cos \,\uppi {n}\xi -\cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } \right] . \end{aligned}$$
(3.28)
In the (03) order approximation, we should remove the lack of compliance of the function \(u_{1}^{\left( {02} \right) } \) governed by (3.28), on the circular contour of an inclusion with radius \(r=a\). For this purpose, we develop the function \(u_{1}^{\left( {02} \right) } \) into a series regarding polar coordinates \(r\,,\;\theta \); assuming a small radius r of the inclusions, we obtain
$$\begin{aligned}&{B}_{0}^{\left( {02} \right) \,^{*}} \left( {\frac{\partial {u}_{0} }{\partial {x}}\,\xi +\frac{\partial {u}_{0} }{\partial {y}}\,\eta } \right) +\sum \limits _{{n}=1}^\infty {\,{B}_{\mathrm{n}}^{\left( {02} \right) \,^{*}} \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\uppi {n}\xi \,\cos \,\uppi {n}\eta -\cosh \,\uppi {n}\eta \,\sin \,\uppi {n}\xi } \right) } \right. } \\&\quad \left. {+\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi {n}\eta \,\cos \,\uppi {n}\xi -\cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } \right] = B_{0}^{\left( {02} \right) \,^{*}} \left( {\frac{\partial u_{0} }{\partial x}\,r\cos \,\theta +\frac{\partial u_{0} }{\partial y}\,r\sin \,\theta } \right) \\&\quad +2\,\sum \limits _{n=1}^\infty {\,B_{n}^{\left( {02} \right) \,^{*}} \,\left[ {\frac{\partial u_{0} }{\partial x}\,\sum \limits _{k=1}^\infty {\frac{\left( {\pi nr} \right) ^{4k-1}\cos \,\left( {4k-1} \right) \,\theta }{\left( {4k-1} \right) \,!}+\frac{\partial u_{0} }{\partial y}\,\sum \limits _{k=1}^\infty {\frac{\left( {\pi nr} \right) ^{4k-1}\sin \,\left( {4k-1} \right) \,\theta }{\left( {4k-1} \right) \,!}} } } \right] }, \end{aligned}$$
or
$$\begin{aligned}&B_{0}^{\left( {02} \right) \,^{*}} \left( {\frac{\partial u_{0} }{\partial x}\,\xi +\frac{\partial u_{0} }{\partial y}\,\eta } \right) +\sum \limits _{n=1}^\infty {\,B_{n}^{\left( {02} \right) \,^{*}} \left[ {\frac{\partial u_{0} }{\partial x}\,\left( {\sinh \,\pi n\xi \,\cos \,\pi n\eta -\cosh \,\pi n\eta \,\sin \,\pi n\xi } \right) } \right. } \nonumber \\&\quad \left. {+\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi {n}\eta \,\cos \,\uppi {n}\xi -\cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } \right] = B_{0}^{\left( {02} \right) \,^{*}} \left( {\frac{\partial u_{0} }{\partial x}\,r\cos \,\theta +\frac{\partial u_{0} }{\partial y}\,r\sin \,\theta } \right) \nonumber \\&\quad +2\,\sum \limits _{k=1}^\infty \,\frac{\pi ^{4k-1}}{\left( {4k-1} \right) \,!}\left( {\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} n^{4k-1}} } \right) \,\left( \frac{\partial u_{0} }{\partial x}r^{4k-1}\cos \,\left( {4k-1} \right) \,\theta \right. \nonumber \\&\quad \left. +\frac{\partial u_{0} }{\partial y}r^{4k-1}\sin \,\left( {4k-1} \right) \,\theta \right) . \end{aligned}$$
(3.29)
Observe that now the right-hand side of (3.29) is convergent for all values of \(0\le r<\infty \).
The correcting terms of the (03) approximation follow:
$$\begin{aligned}&u_{1}^{-\;\left( {03} \right) } =A_{10}^{\left( {03} \right) } \,r\cos \,\theta +A_{20}^{\left( {03} \right) } \,r\sin \,\theta \nonumber \\&\quad +\sum \limits _{k=1}^\infty {\left( {A_{1k}^{\left( {03} \right) } \,r^{4k-1}\cos \,\left( {4k-1} \right) \,\theta +A_{2k}^{\left( {03} \right) } \,r^{4k-1}\sin \,\left( {4k-1} \right) \,\theta } \right) } ; \end{aligned}$$
(3.30)
$$\begin{aligned}&u_{1}^{+\;\left( {03} \right) } =\frac{B_{10}^{\left( {03} \right) } }{r}\,\cos \,\theta +\frac{B_{20}^{\left( {03} \right) } }{r}\,\sin \,\theta + \sum \limits _{k=1}^\infty {\left( {B_{1k}^{\left( {03} \right) } \,\frac{\cos \,\left( {4k-1} \right) \,\theta }{r^{4k-1}}+B_{2k}^{\left( {03} \right) } \,\frac{\sin \,\left( {4k-1} \right) \,\theta }{r^{4k-1}}} \right) } ,\nonumber \\ \end{aligned}$$
(3.31)
where the constants
$$\begin{aligned}&A_{10}^{\left( {03} \right) } =A_{10}^{{\left( {03} \right) }{*}}\frac{\partial u_{0} }{\partial x}, \quad B_{10}^{\left( {03} \right) } =B_{10}^{{\left( {03} \right) }{*}}\frac{\partial u_{0} }{\partial x}; \\&A_{20}^{\left( {03} \right) } =A_{20}^{{\left( {03} \right) }{*}}\frac{\partial u_{0} }{\partial y}, \quad B_{20}^{\left( {03} \right) } =B_{20}^{{\left( {03} \right) }{*}}\frac{\partial u_{0} }{\partial y} \end{aligned}$$
and
$$\begin{aligned}&A_{1k}^{\left( {03.n} \right) } =A_{1k}^{{\left( {03.n} \right) }{*}}\frac{\partial u_{0} }{\partial x}, \quad B_{1k}^{\left( {03.n} \right) } =B_{1k}^{{\left( {03.n} \right) }{*}}\frac{\partial u_{0} }{\partial x}; \\&A_{2k}^{\left( {03.n} \right) } =A_{2k}^{{\left( {03.n} \right) }{*}}\frac{\partial u_{0} }{\partial y}, \quad B_{2k}^{\left( {03.n} \right) } =B_{2k}^{{\left( {03.n} \right) }{*}}\frac{\partial u_{0} }{\partial y} \end{aligned}$$
are defined through solution of either the following
$$\begin{aligned} \left\{ {\begin{array}{l} A_{m0}^{{\left( {03} \right) }{*}}\,a=\frac{B_{m0}^{{\left( {03} \right) }{*}}}{a} \\ -\frac{B_{m0}^{{\left( {03} \right) }{*}}}{a^{2}}-\lambda \,A_{m0}^{{\left( {03} \right) }{*}}=\left( {\lambda -1} \right) \,B_{0}^{{\left( {02} \right) }{*}} \\ \end{array}} \right. \end{aligned}$$
or the following
$$\begin{aligned} \left\{ {\begin{array}{l} A_{mk}^{{\left( {03.n} \right) }{*}}\,a^{4k-1}=\frac{B_{mk}^{{\left( {03.n} \right) }{*}}}{a^{4k-1}} \\ -\frac{B_{mk}^{{\left( {03.n} \right) }{*}}}{\tilde{{a}}^{4k}}-\lambda \,a^{4k-2}A_{mk}^{{\left( {03.n} \right) }{*}}=\frac{2\,\left( {\lambda -1} \right) \pi ^{4k-1}a^{4k-2}}{\left( {4k-1} \right) \,!}\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} } n^{4k-1} \\ \end{array}} \right. \end{aligned}$$
(3.32)
system of equations. Therefore, we get
$$\begin{aligned}&A_{m0}^{\left( {03} \right) \,^{*}} =-\frac{\lambda -1}{\lambda +1}\,B_{0}^{\left( {02} \right) \,^{*}} =-\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\frac{\pi a^{2}}{4},\;\;B_{m0}^{\left( {03} \right) \,^{*}} =-\frac{\lambda -1}{\lambda +1}\,a^{2}B_{0}^{\left( {02} \right) \,^{*}} =-\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\frac{\pi a^{4}}{4}, \nonumber \\&A_{mk}^{{\left( {03} \right) }{*}}=-\frac{2\,\pi ^{4k-1}}{\left( {4k-1} \right) \,!}\cdot \frac{\lambda -1}{\lambda +1}\,\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} } n^{4k-1}=-\frac{2\,\pi ^{4k-1}a^{2}}{\left( {4k-1} \right) \,!}\cdot \left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\sum \limits _{n=1}^\infty {S_{n} } n^{4k-1}, \end{aligned}$$
(3.33)
$$\begin{aligned}&B_{mk}^{{\left( {03} \right) }{*}}=-\frac{2\,\pi ^{4k-1}a^{8k-2}}{\left( {4k-1} \right) \,!}\cdot \frac{\lambda -1}{\lambda +1}\,\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} } n^{4k-1}=-\frac{2\,\pi ^{4k-1}a^{8k}}{\left( {4k-1} \right) \,!}\cdot \left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\sum \limits _{n=1}^\infty {S_{n} } n^{4k-1}. \end{aligned}$$
(3.34)
In other words, the final form of the (03) approximation governed by (3.30), (3.31), accounting for (3.33), (3.34), is written in the following form:
$$\begin{aligned}&{u}_{1}^{-\;\left( {03} \right) } =-\frac{\lambda -1}{\lambda +1}\,{B}_{0}^{\left( {02} \right) \,^{*}} {r}\,\left( {\frac{\partial {u}_{0} }{\partial {x}}\,\cos \,\theta +\frac{\partial {u}_{0} }{\partial {y}}\,\sin \,\theta } \right) \nonumber \\&\quad -\frac{\lambda -1}{\lambda +1}\,2\,\left( {\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} } n^{4k-1}} \right) \,\sum \limits _{k=1}^\infty {\,\frac{\pi ^{4k-1}\,r^{4k-1}}{\left( {4k-1} \right) \,!}\,\left( {\frac{\partial u_{0} }{\partial x}\cos \,\left( {4k-1} \right) \,\theta +\frac{\partial u_{0} }{\partial y}\sin \,\left( {4k-1} \right) \,\theta } \right) } ;\nonumber \\ \end{aligned}$$
(3.35)
$$\begin{aligned}&u_{1}^{+\;\left( {03} \right) } =-\frac{\lambda -1}{\lambda +1}\,\frac{{B}_{0}^{\left( {02} \right) \,^{*}} }{{r}}\,\left( {\frac{\partial {u}_{0} }{\partial {x}}\,\cos \,\theta +\frac{\partial {u}_{0} }{\partial {y}}\,\sin \,\theta } \right) \nonumber \\&\quad -\frac{\lambda -1}{\lambda +1}\,2\,\left( {\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} } n^{4k-1}} \right) \,\sum \limits _{k=1}^\infty \,\frac{\pi ^{4k-1}a^{8k-2}}{\left( {4k-1} \right) \,!\,r^{4k-1}}\,\left( \frac{\partial u_{0} }{\partial x}\cos \,\left( {4k-1} \right) \,\theta \right. \nonumber \\&\quad \left. +\frac{\partial u_{0} }{\partial y}\sin \,\left( {4k-1} \right) \,\theta \right) . \end{aligned}$$
(3.36)
Reversing the numbering of the series due to k in formulas (3.35), (3.36) yields
$$\begin{aligned}&{u}_{1}^{-\;\left( {03} \right) } =-\frac{\lambda -1}{\lambda +1}\,{B}_{0}^{\left( {02} \right) ^{*}} \left( {\frac{\partial {u}_{0} }{\partial {x}}\,\xi +\frac{\partial {u}_{0} }{\partial {y}}\,\eta } \right) -\frac{\lambda -1}{\lambda +1}\,\sum \limits _{{n}=1}^\infty {{B}_{\mathrm{n}}^{\left( {02} \right) ^{*}} } \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\uppi {n}\xi \,\cos \,\uppi {n}\eta } \right. } \right. \nonumber \\&\quad \left. {\left. {-\cosh \,\uppi {n}\eta \,\sin \,\uppi {n}\xi } \right) +\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi {n}\eta \,\cos \,\uppi {n}\xi -\cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } \right] ; \end{aligned}$$
(3.37)
$$\begin{aligned}&u_{1}^{+\;\left( {03} \right) } =-\,\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\frac{\pi a^{2}}{4}\,\left( {\frac{\partial u_{0} }{\partial x}\,\frac{\xi }{\xi ^{2}+\eta ^{2}}+\frac{\partial u_{0} }{\partial y}\,\frac{\eta }{\xi ^{2}+\eta ^{2}}} \right) \nonumber \\&\quad -\frac{\lambda -1}{\lambda +1}\,\sum \limits _{{n}=1}^\infty {{B}_{\mathrm{n}}^{\left( {02} \right) ^{*}} } \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}-\cosh \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}\,\sin \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}} \right) } \right. \nonumber \\&\quad \left. {+\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}-\cosh \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}\,\sin \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}} \right) } \right] , \end{aligned}$$
(3.38)
i.e., we have
$$\begin{aligned}&{u}_{1}^{-\;\left( {03} \right) } =-\,\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\frac{\uppi {a}^{2}}{4}\left( {\frac{\partial {u}_{0} }{\partial {x}}\,\xi +\frac{\partial {u}_{0} }{\partial {y}}\,\eta } \right) -\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,{a}^{2}\sum \limits _{{n}=1}^\infty {{S}_{\mathrm{n}} } \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\uppi {n}\xi \,\cos \,\uppi {n}\eta } \right. } \right. \nonumber \\&\quad \left. {\left. {-\cosh \,\uppi {n}\eta \,\sin \,\uppi {n}\xi } \right) +\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi {n}\eta \,\cos \,\uppi {n}\xi -\cosh \,\uppi {n}\xi \,\sin \,\uppi {n}\eta } \right) } \right] ; \end{aligned}$$
(3.39)
$$\begin{aligned}&u_{1}^{+\;\left( {03} \right) } =-\,\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,\frac{\pi a^{2}}{4}\,\left( {\frac{\partial u_{0} }{\partial x}\,\frac{\xi }{\xi ^{2}+\eta ^{2}}+\frac{\partial u_{0} }{\partial y}\,\frac{\eta }{\xi ^{2}+\eta ^{2}}} \right) \nonumber \\&\quad -\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\,{a}^{2}\,\sum \limits _{{n}=1}^\infty {{S}_{\mathrm{n}} } \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}-\cosh \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}\,\sin \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}} \right) } \right. \nonumber \\&\quad \left. {+\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}-\cosh \,\frac{\uppi {na}^{2}\xi }{\xi ^{2}+\eta ^{2}}\,\sin \,\frac{\uppi {na}^{2}\eta }{\xi ^{2}+\eta ^{2}}} \right) } \right] . \end{aligned}$$
(3.40)
In the (04) approximation, we proceed in analogous way to remove lack of compliance of the function \(u_{1}^{+\;\left( {03} \right) } \) of (3.40) on the external contour of the matrix.
We define for the function
$$\begin{aligned}&{u}_{11}^{\left( {04} \right) } ={A}_{0}^{\left( {04} \right) } +{B}_{0}^{\left( {04} \right) } \,\xi +\sum \limits _{\ell =1}^\infty \left[ {\,\left( {{A}_{\ell }^{\left( {04} \right) } \,\cosh \,\uppi \ell \xi +{B}_{\ell }^{\left( {04} \right) } \,\sinh \,\uppi \ell \xi } \right) \,\cos \,\uppi \ell \eta +} \right. \\&\quad \left. {\left( {{C}_{\ell }^{\left( {02} \right) } \,\cosh \,\uppi \ell \xi + {D}_{\ell }^{\left( {02} \right) } \,\sinh \,\uppi \ell \xi } \right) \,\sin \,\uppi \ell \eta } \right] \end{aligned}$$
the following boundary conditions for the cell at \(\xi =1\) and \(\xi =-1\):
$$\begin{aligned}&u_{11}^{\left( {04} \right) } \,\left| {\,_{\xi =1} } \right. -u_{11}^{\left( {04} \right) } \,\left| {\,_{\xi =\,-\,1} } \right. =\frac{\partial u_{0} }{\partial x}\,\frac{\lambda -1}{\lambda +1}\,B_{0}^{\left( {02} \right) \,^{*}} \,\frac{2}{1+\eta ^{2}} \nonumber \\&\quad +\frac{\partial {u}_{0} }{\partial {x}}\,\frac{\lambda -1}{\lambda +1}\,2\,\sum \limits _{{n}=1}^\infty {{B}_{\mathrm{n}}^{\left( {02} \right) ^{*}} } \left( {\sinh \,\frac{\uppi {na}^{2}}{1+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\eta }{1+\eta ^{2}}-\cosh \,\frac{\uppi {na}^{2}\eta }{1+\eta ^{2}}\,\sin \,\frac{\uppi {na}^{2}}{1+\eta ^{2}}} \right) ; \end{aligned}$$
(3.41)
$$\begin{aligned}&\frac{\partial u_{11}^{\left( {04} \right) } }{\partial \xi }\,\,\left| {\,_{\xi =1} } \right. -\frac{\partial u_{11}^{\left( {04} \right) } }{\partial \xi }\,\,\left| {\,_{\xi =\,-\,1} } \right. =-\frac{\partial u_{0} }{\partial y}\,\frac{\lambda -1}{\lambda +1}\,B_{0}^{\left( {02} \right) \,^{*}} \,\frac{4\eta }{\left( {1+\eta ^{2}} \right) ^{2}} \nonumber \\&\quad -\frac{\partial u_{0} }{\partial y}\,\frac{\lambda -1}{\lambda +1}\,2\pi a^{2}\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) \,^{*}} n\,} \left[ {\frac{2\eta }{\left( {1+\eta ^{2}} \right) ^{2}}\cosh \,\frac{\pi na^{2}\eta }{1+\eta ^{2}}\,\cos \,\frac{\pi na^{2}}{1+\eta ^{2}}} \right. \nonumber \\&\quad -\frac{1-\eta ^{2}}{\left( {1+\eta ^{2}} \right) ^{2}}\sinh \,\frac{\pi na^{2}\eta }{1+\eta ^{2}}\,\sin \,\frac{\pi na^{2}}{1+\eta ^{2}}-\frac{1-\eta ^{2}}{\left( {1+\eta ^{2}} \right) ^{2}}\sinh \,\frac{\pi na^{2}}{1+\eta ^{2}}\,\sin \,\frac{\pi na^{2}\eta }{1+\eta ^{2}}\nonumber \\&\quad - \left. {\frac{2\eta }{\left( {1+\eta ^{2}} \right) ^{2}}\cosh \,\frac{\uppi {na}^{2}}{1+\eta ^{2}}\,\cos \,\frac{\uppi {na}^{2}\eta }{1+\eta ^{2}}} \right] . \end{aligned}$$
(3.42)
Assuming \(a\ll 1\) and developing the functions standing on the right-hand sides of the formulas (3.41), (3.42) into the Fourier series, allows to define the following coefficients:
$$\begin{aligned}&A_{0}^{\left( {04} \right) } =0\,;\;\;A_{\ell }^{\left( {04} \right) } =D_{\ell }^{\left( {04} \right) } =0; \end{aligned}$$
(3.43)
$$\begin{aligned}&B_{0}^{\left( {04} \right) } =\frac{\partial u_{0} }{\partial x}\,B_{0}^{\left( {04} \right) ^{*}} \,;\;\;B_{\ell }^{\left( {04} \right) } =\frac{\partial u_{0} }{\partial x}\,B_{\ell }^{\left( {04} \right) ^{*}} \,;\;\;C_{\ell }^{\left( {04} \right) } =\frac{\partial u_{0} }{\partial y}\,C_{\ell }^{\left( {04} \right) ^{*}} , \quad \ell =0\,,\;1\,,\;2\,,\;...; \end{aligned}$$
(3.44)
$$\begin{aligned}&B_{0}^{\left( {04} \right) ^{*}} =\frac{\lambda -1}{\lambda +1}\,\frac{\pi a^{2}}{4}B_{0}^{\left( {02} \right) ^{*}} +\frac{\lambda -1}{\lambda +1}\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) ^{*}} } \sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi na^{2}} \right) ^{4m-1}}{2^{2m-1}\left( {2m-1} \right) \,\left( {4m-1} \right) \,!}} \nonumber \\&\quad =\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\frac{\pi ^{2}a^{4}}{16}\left( {1+\frac{8}{\pi }\,\sum \limits _{n=1}^\infty {S_{n} } n\sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi n} \right) ^{4m-2}a^{8m-4}}{2^{2m-2}\left( {2m-1} \right) \,\left( {4m-1} \right) \,!}} } \right) ; \end{aligned}$$
(3.45)
$$\begin{aligned}&B_{\ell }^{\left( {04} \right) ^{*}} =-C_{\ell }^{{\left( {04} \right) }^{*}}=\frac{\lambda -1}{\lambda +1}\,a^{2}B_{0}^{\left( {02} \right) ^{*}} S_{\ell } +\frac{\lambda -1}{\lambda +1}\,\sum \limits _{n=1}^\infty {B_{n}^{\left( {02} \right) ^{*}} } \sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi na^{2}} \right) ^{4m-1}}{\left( {2m-1} \right) \,\left( {4m-1} \right) \,!\left( {4m-3} \right) \,!}} \, \nonumber \\&\quad \times \left( {\left( {\pi \ell } \right) ^{4m-2}S_{\ell } +\sum \limits _{k=1}^m {\left( {-1} \right) ^{\ell +k+1}\frac{\left( {4k-3} \right) \,!}{2^{2k-2}}\,\frac{\left( {\pi \ell } \right) ^{4m-4k}}{\sinh \,\pi \ell }} } \right) \nonumber \\&\quad =\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\frac{\pi a^{4}}{4}\,\left[ {S_{\ell } +4\sum \limits _{n=1}^\infty {S_{n} } n\sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi n} \right) ^{4m-2}a^{8m-4}}{\left( {2m-1} \right) \,\left( {4m-1} \right) \,!\left( {4m-3} \right) \,!}} } \right. \nonumber \\&\quad \left. {\times \left( {\left( {\pi \ell } \right) ^{4m-2}S_{\ell } +\sum \limits _{k=1}^m {\left( {-1} \right) ^{\ell +k+1}\frac{\left( {4k-3} \right) \,!}{2^{2k-2}}\,\frac{\left( {\pi \ell } \right) ^{4m-4k}}{\sinh \,\pi \ell }} } \right) } \right] . \end{aligned}$$
(3.46)
Consequently, the (04) approximation takes the following form:
$$\begin{aligned}&u_{1}^{\left( {04} \right) } =\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\frac{\pi ^{2}a^{4}}{16}\left( {1+\frac{8}{\pi }\,\sum \limits _{n=1}^\infty {S_{n} } n\sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi n} \right) ^{4m-2}a^{8m-4}}{2^{2m-2}\left( {2m-1} \right) \,\left( {4m-1} \right) \,!}} } \right) \left( {\frac{\partial u_{0} }{\partial x}\,\xi +\frac{\partial u_{0} }{\partial y}\,\eta } \right) \nonumber \\&\quad +\left( {\frac{\lambda -1}{\lambda +1}} \right) ^{2}\frac{\pi a^{4}}{4}\,\left[ {\sum \limits _{\ell =1}^\infty \, S_{\ell } +4\sum \limits _{\ell =1}^\infty \, S_{\ell } \sum \limits _{n=1}^\infty {S_{n} } n\sum \limits _{m=1}^\infty {\,\frac{\left( {-1} \right) ^{m+1}\left( {\pi ^{2}n\ell } \right) ^{4m-2}a^{8m-4}}{\left( {2m-1} \right) \,\left( {4m-1} \right) \,!\left( {4m-3} \right) \,!}} } \right. \nonumber \\&\quad \left. {+4\sum \limits _{\ell =1}^\infty \, \frac{1}{\sinh \,\uppi \ell }\,\sum \limits _{\mathrm{n}=1}^\infty {{S}_{\mathrm{n}} } {n}\sum \limits _{\mathrm{m}=1}^\infty \,\frac{\left( {-1} \right) ^{\mathrm{m}+1}\left( {\uppi {n}} \right) ^{\mathrm{4m}-2}{a}^{\mathrm{8m}-4}}{\left( {{2m}-1} \right) \,\left( {{4m}-1} \right) \,!\left( {{4m}-3} \right) }\,! \,\sum \limits _{{k}=1}^{\mathrm{m}} \, \frac{\left( {-1} \right) ^{\ell +{k}+1}\,\left( {{4k}-3} \right) \,!\,\left( {\uppi \ell } \right) ^{\mathrm{4m-4k}}}{2^{\mathrm{2k}-2}}} \right] \nonumber \\&\quad \times \left[ {\frac{\partial {u}_{0} }{\partial {x}}\,\left( {\sinh \,\uppi \ell \xi \,\cos \,\uppi \ell \eta -\cosh \,\uppi \ell \eta \,\sin \,\uppi \ell \xi } \right) +\frac{\partial {u}_{0} }{\partial {y}}\left( {\sinh \,\uppi \ell \eta \,\cos \,\uppi \ell \xi -\cosh \,\uppi \ell \xi \,\sin \,\uppi \ell \eta } \right) } \right] .\nonumber \\ \end{aligned}$$
(3.47)