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1 Correction to: Graphs and Combinatorics https://doi.org/10.1007/s00373-020-02194-5
In the original publication of the article, few errors have occurred. The corrections are given below:
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1.
Page 3, Theorem 2:
$$\begin{aligned} gr_k(K_3 : F_9)=gr_k(K_3 : F_{10})= \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : F_9)=gr_k(K_3 : F_{10})= \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
2.
Page 3, Theorem 4 (3):
$$\begin{aligned} k(n-1)+2 \ge gr_k(K_3 : F_{2,n})\ge \left\{ \begin{aligned}&\frac{5n}{2}+k-6,\\&\frac{5n-1}{2}+k-4, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} k(n-1)+2 \ge gr_k(K_3 : F_{2,n})\ge \left\{ \begin{aligned}&\frac{5n}{2}+k-6,&\text{ if } n \text{ is } \text{ even },\\&\frac{5n-1}{2}+k-4,&\text{ if } n \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
3.
Page 4, Theorem 5:
$$\begin{aligned} gr_k(K_3 : F_{12})=gr_k(K_3 : F_{13})= \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : F_{12})=gr_k(K_3 : F_{13})= \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
4.
Page 5, Lemma 2:
$$\begin{aligned} gr_k(K_3 : K_3)= \left\{ \begin{aligned}&5^{k/2}+1,\\&2\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : K_3)= \left\{ \begin{aligned}&5^{k/2}+1,&\text{ if } k \text{ is } \text{ even },\\&2\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
5.
Page 5, Lemma 3:
$$\begin{aligned} gr_k(K_3 : F_9)> \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2},\\&4\cdot 5^{(k-1)/2}, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : F_9)> \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2},&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2},&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
6.
Page 5, Lemma 4:
$$\begin{aligned} gr_k(K_3 : F_{10})\le \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : F_{10})\le \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
7.
Page 5, Proof of lemma 4:
$$\begin{aligned} n= \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} n= \left\{ \begin{aligned}&8\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
8.
Page 6:
$$\begin{aligned} gr_{k-1}(K_3 : K_3)= \left\{ \begin{aligned}&2\cdot 5^{(k-2)/2}+1,\\&5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_{k-1}(K_3 : K_3)= \left\{ \begin{aligned}&2\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
9.
Page 9:
$$\begin{aligned} |V(G_k)|= \left\{ \begin{aligned}&\frac{5n}{2}+k-7,\\&\frac{5n-1}{2}+k-5, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} |V(G_k)|= \left\{ \begin{aligned}&\frac{5n}{2}+k-7,&\text{ if } n \text{ is } \text{ even },\\&\frac{5n-1}{2}+k-5,&\text{ if } n \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
10.
Page 9:
$$\begin{aligned} n_{k}= \left\{ \begin{aligned}&r_2(F_{2,n})+k-2,\\&k+9,\\&k(n-1)+2, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} n_{k}= \left\{ \begin{aligned}&r_2(F_{2,n})+k-2,&\text{ if } n \in \{3,4\} \text{ and } k\ge 1,\\&k+9,&\text{ if } n=5 \text{ and } k\ge 2,\\&k(n-1)+2,&\text{ if } n \ge 6 \text{ and } k\ge 2. \end{aligned} \right. \end{aligned}$$ -
11.
Page 11, Lemma 6:
$$\begin{aligned} gr_k(K_3 : H)> \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2},\\&4\cdot 5^{(k-1)/2}, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : H)> \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2},&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2},&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
12.
Page 11–12, Lemma 7:
$$\begin{aligned} gr_k(K_3 : H)\le \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} gr_k(K_3 : H)\le \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$ -
13.
Page 12, Proof of Lemma 7:
$$\begin{aligned} n= \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,\\&4\cdot 5^{(k-1)/2}+1, \end{aligned} \right. \end{aligned}$$should be
$$\begin{aligned} n= \left\{ \begin{aligned}&9\cdot 5^{(k-2)/2}+1,&\text{ if } k \text{ is } \text{ even },\\&4\cdot 5^{(k-1)/2}+1,&\text{ if } k \text{ is } \text{ odd }. \end{aligned} \right. \end{aligned}$$
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Li, X., Wang, L. Correction to: Gallai–Ramsey Numbers for a Class of Graphs with Five Vertices. Graphs and Combinatorics 36, 1619–1622 (2020). https://doi.org/10.1007/s00373-020-02222-4
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DOI: https://doi.org/10.1007/s00373-020-02222-4