Extragradient method for convex minimization problem

Abstract

In this paper, we introduce and analyze a multi-step hybrid extragradient algorithm by combining Korpelevich’s extragradient method, the viscosity approximation method, the hybrid steepest-descent method, Mann’s iteration method and the gradient-projection method (GPM) with regularization in the setting of infinite-dimensional Hilbert spaces. It is proven that, under appropriate assumptions, the proposed algorithm converges strongly to a solution of the convex minimization problem (CMP) with constraints of several problems: finitely many generalized mixed equilibrium problems (GMEPs), finitely many variational inclusions, and the fixed point problem of a strictly pseudocontractive mapping. In the meantime, we also prove the strong convergence of the proposed algorithm to the unique solution of a hierarchical variational inequality problem (over the fixed point set of a strictly pseudocontractive mapping) with constraints of finitely many GMEPs, finitely many variational inclusions and the CMP. The results presented in this paper improve and extend the corresponding results announced by many others.

MSC:49J30, 47H09, 47J20, 49M05.

1 Introduction

Let C be a nonempty closed convex subset of a real Hilbert space H and $P_C$ be the metric projection of H onto C. Let $S:C\to H$ be a nonlinear mapping on C. We denote by $Fix(S)$ the set of fixed points of S and by R the set of all real numbers. A mapping $S:C\to H$ is called L-Lipschitz-continuous (or L-Lipschitzian) if there exists a constant $L\ge 0$ such that

$$\parallel Sx-Sy\parallel \le L\parallel x-y\parallel ,\mathrm{\forall }x,y\in C.$$

In particular, if $L=1$ then S is called a nonexpansive mapping; if $L\in [0,1)$ then S is called a contraction.

A mapping $A:C\to H$ is said to be ζ-inverse-strongly monotone if there exists $\zeta >0$ such that

$$〈Ax-Ay,x-y〉\ge \zeta {\parallel Ax-Ay\parallel }^2,\mathrm{\forall }x,y\in C.$$

It is clear that every inverse-strongly monotone mapping is a monotone and Lipschitz-continuous mapping. A mapping $T:C\to C$ is said to be ξ-strictly pseudocontractive if there exists $\xi \in [0,1)$ such that

$${\parallel Tx-Ty\parallel }^2\le {\parallel x-y\parallel }^2+\xi {\parallel (I-T)x-(I-T)y\parallel }^2,\mathrm{\forall }x,y\in C.$$

In this case, we also say that T is a ξ-strict pseudocontraction. In particular, whenever $\xi =0$, T becomes a nonexpansive mapping from C into itself.

Let $A:C\to H$ be a nonlinear mapping on C. We consider the following variational inequality problem (VIP): find a point $x\in C$ such that

$$〈Ax,y-x〉\ge 0,\mathrm{\forall }y\in C.$$

(1.1)

The solution set of VIP (1.1) is denoted by $VI(C,A)$.

The VIP (1.1) was first discussed by Lions [1]. There are many applications of VIP (1.1) in various fields; see e.g., [2–5]. It is well known that, if A is a strongly monotone and Lipschitz-continuous mapping on C, then VIP (1.1) has a unique solution. In 1976, Korpelevich [6] proposed an iterative algorithm for solving the VIP (1.1) in Euclidean space ${\mathbf{R}}^n$:

$$\{\begin{array}{l}{y}_n=P_C(x_n-\tau A{x}_n),\\ x_{n+1}=P_C(x_n-\tau A{y}_n),\mathrm{\forall }n\ge 0,\end{array}$$

with $\tau >0$ a given number, which is known as the extragradient method. The literature on the VIP is vast and Korpelevich’s extragradient method has received great attention given by many authors, who improved it in various ways; see e.g., [7–19] and references therein, to name but a few.

Consider the following constrained convex minimization problem (CMP):

$$\text{minimize }\{f(x):x\in C\},$$

(1.2)

where $f:C\to \mathbf{R}$ is a real-valued convex functional. We denote by Γ the solution set of the CMP (1.2). If f is Fréchet differentiable, then the gradient-projection method (GPM) generates a sequence $\{x_n\}$ via the recursive formula

$$x_{n+1}=P_C(x_n-\lambda \mathrm{\nabla }f(x_n)),\mathrm{\forall }n\ge 0,$$

(1.3)

or more generally,

$$x_{n+1}=P_C(x_n-{\lambda }_n\mathrm{\nabla }f(x_n)),\mathrm{\forall }n\ge 0,$$

(1.4)

where in both (1.3) and (1.4), the initial guess $x_0$ is taken from C arbitrarily, the parameters, λ or ${\lambda }_n$, are positive real numbers, and $P_C$ is the metric projection from H onto C. The convergence of the algorithms (1.3) and (1.4) depends on the behavior of the gradient ∇f. As a matter of fact, it is well known that if ∇f is strongly monotone and Lipschitzian; namely, there are constants $\eta ,L>0$ satisfying the properties

$$〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉\ge \eta {\parallel x-y\parallel }^2\text{and}\parallel \mathrm{\nabla }f(x)-\mathrm{\nabla }f(y)\parallel \le L\parallel x-y\parallel ,\mathrm{\forall }x,y\in C,$$

then, for $0<\lambda <2\eta /L^2$, the operator $T:=P_C(I-\lambda \mathrm{\nabla }f)$ is a contraction; hence, the sequence $\{x_n\}$ defined by (1.3) converges in norm to the unique solution of the CMP (1.2). More generally, if the sequence $\{{\lambda }_n\}$ is chosen to satisfy the property $0<{lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\lambda }_n\le {lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}{\lambda }_n<2\eta /L^2$, then the sequence $\{x_n\}$ defined by (1.4) converges in norm to the unique minimizer of the CMP (1.2). However, if the gradient ∇f fails to be strongly monotone, the operator T defined by $T:=P_C(I-\lambda \mathrm{\nabla }f)$ would fail to be contractive; consequently, the sequence $\{x_n\}$ generated by (1.3) may fail to converge strongly (see Section 4 in Xu [20]).

Theorem 1.1 (see [[20], Theorem 5.2])

Assume the CMP (1.2) is consistent and let Γ denote its solution set. Assume the gradient ∇f satisfies the Lipschitz condition with constant $L>0$. Let $V:C\to C$ be a ρ-contraction with coefficient $\rho \in [0,1)$. Let a sequence $\{x_n\}$ be generated by the following hybrid gradient-projection algorithm (GPA):

$$x_{n+1}={\alpha }_{n}V{x}_n+(1-{\alpha }_n)P_C(x_n-{\lambda }_n\mathrm{\nabla }f(x_n)),\mathrm{\forall }n\ge 0.$$

(1.5)

Assume the sequence $\{{\lambda }_n\}$ satisfies the condition $0<{lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\lambda }_n\le {lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}{\lambda }_n<2/L$, and, in addition, the following conditions are satisfied for $\{{\lambda }_n\}$ and $\{{\alpha }_n\}\subset [0,1]$: (i) ${\alpha }_n\to 0$, (ii) ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n=\mathrm{\infty }$, (iii) ${\sum }_{n=0}^{\mathrm{\infty }}|{\alpha }_{n+1}-{\alpha }_n|<\mathrm{\infty }$, and (iv) ${\sum }_{n=0}^{\mathrm{\infty }}|{\lambda }_{n+1}-{\lambda }_n|<\mathrm{\infty }$. Then the sequence $\{x_n\}$ converges in norm to a minimizer of CMP (1.2), which is also the unique solution $x^{\ast }\in \Gamma$ to the VIP

$$〈(I-V)x^{\ast },x-x^{\ast }〉\ge 0,\mathrm{\forall }x\in \Gamma .$$

(1.6)

In other words, $x^{\ast }$ is the unique fixed point of the contraction $P_{\Gamma }V$, $x^{\ast }=P_{\Gamma }V{x}^{\ast }$.

On the other hand, let S and T be two nonexpansive mappings. In 2009, Yao et al. [21] considered the following hierarchical variational inequality problem (HVIP): find hierarchically a fixed point of T, which is a solution to the VIP for monotone mapping $I-S$; namely, find $\tilde{x}\in Fix(T)$ such that

$$〈(I-S)\tilde{x},p-\tilde{x}〉\ge 0,\mathrm{\forall }p\in Fix(T).$$

(1.7)

The solution set of the hierarchical VIP (1.7) is denoted by Λ. It is not hard to check that solving the hierarchical VIP (1.7) is equivalent to the fixed point problem of the composite mapping $P_{Fix(T)}S$, i.e., find $\tilde{x}\in C$ such that $\tilde{x}=P_{Fix(T)}S\tilde{x}$. The authors [21] introduced and analyzed the following iterative algorithm for solving the HVIP (1.7):

$$\{\begin{array}{l}{y}_n={\beta }_{n}S{x}_n+(1-{\beta }_n)x_n,\\ x_{n+1}={\alpha }_{n}V{x}_n+(1-{\alpha }_n)T{y}_n,\mathrm{\forall }n\ge 0.\end{array}$$

(1.8)

Theorem 1.2 (see [[21], Theorem 3.2])

Let C be a nonempty closed convex subset of a real Hilbert space H. Let S and T be two nonexpansive mappings of C into itself. Let $V:C\to C$ be a fixed contraction with $\alpha \in (0,1)$. Let $\{{\alpha }_n\}$ and $\{{\beta }_n\}$ be two sequences in $(0,1)$. For any given $x_0\in C$, let $\{x_n\}$ be the sequence generated by (1.8). Assume that the sequence $\{x_n\}$ is bounded and that

• (i) ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n=\mathrm{\infty }$;

• (ii) ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\alpha }_n}|\frac{1}{{\beta }_n}-\frac{1}{{\beta }_{n-1}}|=0$, ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\beta }_n}|1-\frac{{\alpha }_{n-1}}{{\alpha }_n}|=0$;

• (iii) ${lim}_{n\to \mathrm{\infty }}{\beta }_n=0$, ${lim}_{n\to \mathrm{\infty }}\frac{{\alpha }_n}{{\beta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{{\beta }_n^2}{{\alpha }_n}=0$;

• (iv) $Fix(T)\cap intC\ne \mathrm{\varnothing }$;

• (v) there exists a constant $k>0$ such that $\parallel x-Tx\parallel \ge kDist(x,Fix(T))$ for each $x\in C$, where $Dist(x,Fix(T))={inf}_{y\in Fix(T)}\parallel x-y\parallel$.

Then $\{x_n\}$ converges strongly to $\tilde{x}=P_{\Lambda }V\tilde{x}$ which solves the HVIP

$$〈(I-S)\tilde{x},p-\tilde{x}〉\le 0,\mathrm{\forall }p\in Fix(T).$$

Furthermore, let $\phi :C\to \mathbf{R}$ be a real-valued function, $A:H\to H$ be a nonlinear mapping and $\Theta :C\times C\to \mathbf{R}$ be a bifunction. In 2008, Peng and Yao [9] introduced the generalized mixed equilibrium problem (GMEP) of finding $x\in C$ such that

$$\Theta (x,y)+\phi (y)-\phi (x)+〈Ax,y-x〉\ge 0,\mathrm{\forall }y\in C.$$

(1.9)

We denote the set of solutions of GMEP (1.9) by $GMEP(\Theta ,\phi ,A)$. The GMEP (1.9) is very general in the sense that it includes, as special cases, optimization problems, variational inequalities, minimax problems, Nash equilibrium problems in noncooperative games and others. The GMEP is further considered and studied; see e.g., [7, 10, 15, 17, 19, 22–24]. In particular, if $\phi =0$, then GMEP (1.9) reduces to the generalized equilibrium problem (GEP) which is to find $x\in C$ such that

$$\Theta (x,y)+〈Ax,y-x〉\ge 0,\mathrm{\forall }y\in C.$$

It was introduced and studied by Takahashi and Takahashi [25]. The set of solutions of GEP is denoted by $GEP(\Theta ,A)$.

If $A=0$, then GMEP (1.9) reduces to the mixed equilibrium problem (MEP) which is to find $x\in C$ such that

$$\Theta (x,y)+\phi (y)-\phi (x)\ge 0,\mathrm{\forall }y\in C.$$

It was considered and studied in [26]. The set of solutions of MEP is denoted by $MEP(\Theta ,\phi )$.

If $\phi =0$, $A=0$, then GMEP (1.9) reduces to the equilibrium problem (EP) which is to find $x\in C$ such that

$$\Theta (x,y)\ge 0,\mathrm{\forall }y\in C.$$

It was considered and studied in [27, 28]. The set of solutions of EP is denoted by $EP(\Theta )$. It is worth to mention that the EP is a unified model of several problems, namely, variational inequality problems, optimization problems, saddle point problems, complementarity problems, fixed point problems, Nash equilibrium problems, etc.

It was assumed in [9] that $\Theta :C\times C\to \mathbf{R}$ is a bifunction satisfying conditions (A1)-(A4) and $\phi :C\to \mathbf{R}$ is a lower semicontinuous and convex function with restriction (B1) or (B2), where

(A1) $\Theta (x,x)=0$ for all $x\in C$;

(A2) Θ is monotone, i.e., $\Theta (x,y)+\Theta (y,x)\le 0$ for any $x,y\in C$;

(A3) Θ is upper-hemicontinuous, i.e., for each $x,y,z\in C$,

$$\underset{t\to 0^{+}}{lim\hspace{0.17em}sup}\Theta (tz+(1-t)x,y)\le \Theta (x,y);$$

(A4) $\Theta (x,\cdot )$ is convex and lower semicontinuous for each $x\in C$;

(B1) for each $x\in H$ and $r>0$, there exists a bounded subset $D_x\subset C$ and $y_x\in C$ such that, for any $z\in C\setminus D_x$,

$$\Theta (z,y_x)+\phi (y_x)-\phi (z)+\frac{1}{r}〈y_x-z,z-x〉<0;$$

(B2) C is a bounded set.

Given a positive number $r>0$. Let $T_r^{(\Theta ,\phi )}:H\to C$ be the solution set of the auxiliary mixed equilibrium problem, that is, for each $x\in H$,

$$T_r^{(\Theta ,\phi )}(x):=\{y\in C:\Theta (y,z)+\phi (z)-\phi (y)+\frac{1}{r}〈y-x,z-y〉\ge 0,\mathrm{\forall }z\in C\}.$$

In addition, let B be a single-valued mapping of C into H and R be a multivalued mapping with $D(R)=C$. Consider the following variational inclusion: find a point $x\in C$ such that

$$0\in Bx+Rx.$$

(1.10)

We denote by $\mathrm{I}(B,R)$ the solution set of the variational inclusion (1.10). In particular, if $B=R=0$, then $\mathrm{I}(B,R)=C$. If $B=0$, then problem (1.10) becomes the inclusion problem introduced by Rockafellar [29]. It is known that problem (1.10) provides a convenient framework for the unified study of optimal solutions in many optimization related areas including mathematical programming, complementarity problems, variational inequalities, optimal control, mathematical economics, equilibria, and game theory, etc. Let a set-valued mapping $R:D(R)\subset H\to 2^H$ be maximal monotone. We define the resolvent operator $J_{R,\lambda }:H\to \overline{D(R)}$ associated with R and λ as follows:

$$J_{R,\lambda }={(I+\lambda R)}^{-1},\mathrm{\forall }x\in H,$$

where λ is a positive number.

In 1998, Huang [30] studied problem (1.10) in the case where R is maximal monotone and B is strongly monotone and Lipschitz-continuous with $D(R)=C=H$. Subsequently, Zeng et al. [31] further studied problem (1.10) in the case which is more general than Huang’s one [30]. Moreover, the authors [31] obtained the same strong convergence conclusion as in Huang’s result [30]. In addition, the authors also gave a geometric convergence rate estimate for approximate solutions. Also, various types of iterative algorithms for solving variational inclusions have been further studied and developed; for more details, refer to [12, 24, 32–34] and the references therein.

Motivated and inspired by the above facts, we introduce and analyze a multistep hybrid extragradient algorithm by combining Korpelevich’s extragradient method, the viscosity approximation method, thehybrid steepest-descent method, Mann’s iteration method, and the gradient-projection method (GPM) with regularization in the setting of infinite-dimensional Hilbert spaces. It is proven that under appropriate assumptions the proposed algorithm converges strongly to a solution of the CMP (1.2) with constraints of several problems: finitely many GMEPs, finitely many variational inclusions, and the fixed point problem of a strictly pseudocontractive mapping. In the meantime, we also prove the strong convergence of the proposed algorithm to the unique solution of a hierarchical variational inequality problem (over the fixed point set of a strictly pseudocontractive mapping) with constraints of finitely many GMEPs, finitely many variational inclusions, and the CMP (1.2). Our results represent the supplementation, improvement, extension, and development of the corresponding results in Xu [[20], Theorems 4.1 and 5.2] and Yao et al. [[21], Theorems 3.1 and 3.2].

2 Preliminaries

Throughout this paper, we assume that H is a real Hilbert space whose inner product and norm are denoted by $〈\cdot ,\cdot 〉$ and $\parallel \cdot \parallel$, respectively. Let C be a nonempty closed convex subset of H. We write $x_n\rightharpoonup x$ to indicate that the sequence $\{x_n\}$ converges weakly to x and $x_n\to x$ to indicate that the sequence $\{x_n\}$ converges strongly to x. Moreover, we use ${\omega }_w(x_n)$ to denote the weak ω-limit set of the sequence $\{x_n\}$, i.e.,

$${\omega }_w(x_n):=\{x\in H:x_{n_i}\rightharpoonup x\text{ for some subsequence }\{x_{n_i}\}\text{ of }\{x_n\}\}.$$

The metric (or nearest point) projection from H onto C is the mapping $P_C:H\to C$ which assigns to each point $x\in H$ the unique point $P_{C}x\in C$ satisfying the property

$$\parallel x-P_{C}x\parallel =\underset{y\in C}{inf}\parallel x-y\parallel =:d(x,C).$$

Definition 2.1 Let T be a nonlinear operator with the domain $D(T)\subset H$ and the range $R(T)\subset H$. Then T is said to be

• (i) monotone if

  $$〈Tx-Ty,x-y〉\ge 0,\mathrm{\forall }x,y\in D(T);$$

• (ii) β-strongly monotone if there exists a constant $\beta >0$ such that

  $$〈Tx-Ty,x-y〉\ge \eta {\parallel x-y\parallel }^2,\mathrm{\forall }x,y\in D(T);$$

• (iii) ν-inverse-strongly monotone if there exists a constant $\nu >0$ such that

  $$〈Tx-Ty,x-y〉\ge \nu {\parallel Tx-Ty\parallel }^2,\mathrm{\forall }x,y\in D(T).$$

It is easy to see that the projection $P_C$ is 1-inverse-strongly monotone. Inverse-strongly monotone (also referred to as co-coercive) operators have been applied widely in solving practical problems in various fields, for instance, in traffic assignment problems; see e.g., [35]. It is obvious that if T is ν-inverse-strongly monotone, then T is monotone and $\frac{1}{\nu }$-Lipschitz-continuous. Moreover, we also have, for all $u,v\in D(T)$ and $\lambda >0$,

$$\begin{array}{c}{\parallel (I-\lambda T)u-(I-\lambda T)v\parallel }^2\hfill \\ ={\parallel (u-v)-\lambda (Tu-Tv)\parallel }^2\hfill \\ ={\parallel u-v\parallel }^2-2\lambda 〈Tu-Tv,u-v〉+{\lambda }^2{\parallel Tu-Tv\parallel }^2\hfill \\ \le {\parallel u-v\parallel }^2+\lambda (\lambda -2\nu ){\parallel Tu-Tv\parallel }^2.\hfill \end{array}$$

(2.1)

So, if $\lambda \le 2\nu$, then $I-\lambda T$ is a nonexpansive mapping.

Some important properties of projections are gathered in the following proposition.

Proposition 2.1 For given $x\in H$ and $z\in C$:

• (i) $z=P_{C}x\iff 〈x-z,y-z〉\le 0$, $\mathrm{\forall }y\in C$;

• (ii) $z=P_{C}x\iff {\parallel x-z\parallel }^2\le {\parallel x-y\parallel }^2-{\parallel y-z\parallel }^2$, $\mathrm{\forall }y\in C$;

• (iii) $〈P_{C}x-P_{C}y,x-y〉\ge {\parallel P_{C}x-P_{C}y\parallel }^2$, $\mathrm{\forall }y\in H$.

Consequently, $P_C$ is nonexpansive and monotone.

Definition 2.2 A mapping $T:H\to H$ is said to be

• (a) nonexpansive if

  $$\parallel Tx-Ty\parallel \le \parallel x-y\parallel ,\mathrm{\forall }x,y\in H;$$

• (b) firmly nonexpansive if $2T-I$ is nonexpansive, or equivalently, if T is 1-inverse-strongly monotone (1-ism),

  $$〈x-y,Tx-Ty〉\ge {\parallel Tx-Ty\parallel }^2,\mathrm{\forall }x,y\in H;$$

alternatively, T is firmly nonexpansive if and only if T can be expressed as

$$T=\frac{1}{2}(I+S),$$

where $S:H\to H$ is nonexpansive; projections are firmly nonexpansive.

It can easily be seen that if T is nonexpansive, then $I-T$ is monotone.

Next we list some elementary conclusions for the MEP.

Proposition 2.2 (see [26])

Assume that $\Theta :C\times C\to \mathbf{R}$ satisfies (A1)-(A4) and let $\phi :C\to \mathbf{R}$ be a proper lower semicontinuous and convex function. Assume that either (B1) or (B2) holds. For $r>0$ and $x\in H$, define a mapping $T_r^{(\Theta ,\phi )}:H\to C$ as follows:

$$T_r^{(\Theta ,\phi )}(x)=\{z\in C:\Theta (z,y)+\phi (y)-\phi (z)+\frac{1}{r}〈y-z,z-x〉\ge 0,\mathrm{\forall }y\in C\}$$

for all $x\in H$. Then the following hold:

• (i) for each $x\in H$, $T_r^{(\Theta ,\phi )}(x)$ is nonempty and single-valued;

• (ii) $T_r^{(\Theta ,\phi )}$ is firmly nonexpansive, that is, for any $x,y\in H$,

  $${\parallel T_r^{(\Theta ,\phi )}x-T_r^{(\Theta ,\phi )}y\parallel }^2\le 〈T_r^{(\Theta ,\phi )}x-T_r^{(\Theta ,\phi )}y,x-y〉;$$

• (iii) $Fix(T_r^{(\Theta ,\phi )})=MEP(\Theta ,\phi )$;

• (iv) $MEP(\Theta ,\phi )$ is closed and convex;

• (v) ${\parallel T_s^{(\Theta ,\phi )}x-T_t^{(\Theta ,\phi )}x\parallel }^2\le \frac{s-t}{s}〈T_s^{(\Theta ,\phi )}x-T_t^{(\Theta ,\phi )}x,T_s^{(\Theta ,\phi )}x-x〉$ for all $s,t>0$ and $x\in H$.

Definition 2.3 A mapping $T:H\to H$ is said to be an averaged mapping if it can be written as the average of the identity I and a nonexpansive mapping, that is,

$$T\equiv (1-\alpha )I+\alpha S,$$

where $\alpha \in (0,1)$ and $S:H\to H$ is nonexpansive. More precisely, when the last equality holds, we say that T is α-averaged. Thus firmly nonexpansive mappings (in particular, projections) are $\frac{1}{2}$-averaged mappings.

Proposition 2.3 (see [36])

Let $T:H\to H$ be a given mapping.

• (i) T is nonexpansive if and only if the complement $I-T$ is $\frac{1}{2}$-ism.

• (ii) If T is ν-ism, then for $\gamma >0$, γT is $\frac{\nu }{\gamma }$-ism.

• (iii) T is averaged if and only if the complement $I-T$ is ν-ism for some $\nu >1/2$. Indeed, for $\alpha \in (0,1)$, T is α-averaged if and only if $I-T$ is $\frac{1}{2\alpha }$-ism.

Proposition 2.4 (see [36, 37])

Let $S,T,V:H\to H$ be given operators.

• (i) If $T=(1-\alpha )S+\alpha V$ for some $\alpha \in (0,1)$ and if S is averaged and V is nonexpansive, then T is averaged.

• (ii) T is firmly nonexpansive if and only if the complement $I-T$ is firmly nonexpansive.

• (iii) If $T=(1-\alpha )S+\alpha V$ for some $\alpha \in (0,1)$ and if S is firmly nonexpansive and V is nonexpansive, then T is averaged.

• (iv) The composite of finitely many averaged mappings is averaged. That is, if each of the mappings ${\{T_i\}}_{i=1}^N$ is averaged, then so is the composite $T_1\cdots T_N$. In particular, if $T_1$ is ${\alpha }_1$-averaged and $T_2$ is ${\alpha }_2$-averaged, where ${\alpha }_1,{\alpha }_2\in (0,1)$, then the composite $T_1{T}_2$ is α-averaged, where $\alpha ={\alpha }_1+{\alpha }_2-{\alpha }_1{\alpha }_2$.

• (v) If the mappings ${\{T_i\}}_{i=1}^N$ are averaged and have a common fixed point, then

  $$\bigcap _{i=1}^{N}Fix(T_i)=Fix(T_1\cdots T_N).$$

The notation $Fix(T)$ denotes the set of all fixed points of the mapping T, that is, $Fix(T)=\{x\in H:Tx=x\}$.

We need some facts and tools in a real Hilbert space H which are listed as lemmas below.

Lemma 2.1 Let X be a real inner product space. Then we have the following inequality:

$${\parallel x+y\parallel }^2\le {\parallel x\parallel }^2+2〈y,x+y〉,\mathrm{\forall }x,y\in X.$$

Lemma 2.2 Let H be a real Hilbert space. Then the following hold:

• (a) ${\parallel x-y\parallel }^2={\parallel x\parallel }^2-{\parallel y\parallel }^2-2〈x-y,y〉$ for all $x,y\in H$;

• (b) ${\parallel \lambda x+\mu y\parallel }^2=\lambda {\parallel x\parallel }^2+\mu {\parallel y\parallel }^2-\lambda \mu {\parallel x-y\parallel }^2$ for all $x,y\in H$ and $\lambda ,\mu \in [0,1]$ with $\lambda +\mu =1$;

• (c) if $\{x_n\}$ is a sequence in H such that $x_n\rightharpoonup x$, it follows that

  $$\underset{n\to \mathrm{\infty }}{lim\hspace{0.17em}sup}{\parallel x_n-y\parallel }^2=\underset{n\to \mathrm{\infty }}{lim\hspace{0.17em}sup}{\parallel x_n-x\parallel }^2+{\parallel x-y\parallel }^2,\mathrm{\forall }y\in H.$$

It is clear that, in a real Hilbert space H, $T:C\to C$ is ξ-strictly pseudocontractive if and only if the following inequality holds:

$$〈Tx-Ty,x-y〉\le {\parallel x-y\parallel }^2-\frac{1-\xi }{2}{\parallel (I-T)x-(I-T)y\parallel }^2,\mathrm{\forall }x,y\in C.$$

This immediately implies that if T is a ξ-strictly pseudocontractive mapping, then $I-T$ is $\frac{1-\xi }{2}$-inverse strongly monotone; for further details, we refer to [38] and the references therein. It is well known that the class of strict pseudocontractions strictly includes the class of nonexpansive mappings and that the class of pseudocontractions strictly includes the class of strict pseudocontractions.

Lemma 2.3 (see [[38], Proposition 2.1])

Let C be a nonempty closed convex subset of a real Hilbert space H and $T:C\to C$ be a mapping.

• (i) If T is a ξ-strictly pseudocontractive mapping, then T satisfies the Lipschitzian condition

  $$\parallel Tx-Ty\parallel \le \frac{1+\xi }{1-\xi }\parallel x-y\parallel ,\mathrm{\forall }x,y\in C.$$

• (ii) If T is a ξ-strictly pseudocontractive mapping, then the mapping $I-T$ is semiclosed at 0, that is, if $\{x_n\}$ is a sequence in C such that $x_n\rightharpoonup \tilde{x}$ and $(I-T)x_n\to 0$, then $(I-T)\tilde{x}=0$.

• (iii) If T is ξ-(quasi-)strict pseudocontraction, then the fixed point set $Fix(T)$ of T is closed and convex so that the projection $P_{Fix(T)}$ is well defined.

Lemma 2.4 (see [11])

Let C be a nonempty closed convex subset of a real Hilbert space H. Let $T:C\to C$ be a ξ-strictly pseudocontractive mapping. Let γ and δ be two nonnegative real numbers such that $(\gamma +\delta )\xi \le \gamma$. Then

$$\parallel \gamma (x-y)+\delta (Tx-Ty)\parallel \le (\gamma +\delta )\parallel x-y\parallel ,\mathrm{\forall }x,y\in C.$$

Lemma 2.5 (see [[39], Demiclosedness principle])

Let C be a nonempty closed convex subset of a real Hilbert space H. Let S be a nonexpansive self-mapping on C with $Fix(S)\ne \mathrm{\varnothing }$. Then $I-S$ is demiclosed. That is, whenever $\{x_n\}$ is a sequence in C weakly converging to some $x\in C$ and the sequence $\{(I-S)x_n\}$ strongly converges to some y, it follows that $(I-S)x=y$. Here I is the identity operator of H.

Lemma 2.6 Let $A:C\to H$ be a monotone mapping. In the context of the variational inequality problem the characterization of the projection (see Proposition  2.1(i)) implies

$$u\in VI(C,A)\iff u=P_C(u-\lambda Au),\lambda >0.$$

Let C be a nonempty closed convex subset of a real Hilbert space H. We introduce some notations. Let λ be a number in $(0,1]$ and let $\mu >0$. Associated with a nonexpansive mapping $T:C\to H$, we define the mapping $T^{\lambda }:C\to H$ by

$$T^{\lambda }x:=Tx-\lambda \mu F(Tx),\mathrm{\forall }x\in C,$$

where $F:H\to H$ is an operator such that, for some positive constants $\kappa ,\eta >0$, F is κ-Lipschitzian and η-strongly monotone on H; that is, F satisfies the conditions:

$$\parallel Fx-Fy\parallel \le \kappa \parallel x-y\parallel \text{and}〈Fx-Fy,x-y〉\ge \eta {\parallel x-y\parallel }^2$$

for all $x,y\in H$.

Lemma 2.7 (see [[40], Lemma 3.1])

$T^{\lambda }$ is a contraction provided $0<\mu <\frac{2\eta }{{\kappa }^2}$; that is,

$$\parallel T^{\lambda }x-T^{\lambda }y\parallel \le (1-\lambda \tau )\parallel x-y\parallel ,\mathrm{\forall }x,y\in C,$$

where $\tau =1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}\in (0,1]$.

Remark 2.1 (i) Since F is κ-Lipschitzian and η-strongly monotone on H, we get $0<\eta \le \kappa$. Hence, whenever $0<\mu <\frac{2\eta }{{\kappa }^2}$, we have $\tau =1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}\in (0,1]$.

(ii) In Lemma 2.7, put $F=\frac{1}{2}I$ and $\mu =2$. Then we know that $\kappa =\eta =\frac{1}{2}$, $0<\mu =2<\frac{2\eta }{{\kappa }^2}=4$, and $\tau =1$.

Lemma 2.8 (see [41])

Let $\{a_n\}$ be a sequence of nonnegative real numbers satisfying the property:

$$a_{n+1}\le (1-s_n)a_n+s_n{b}_n+t_n,\mathrm{\forall }n\ge 0,$$

where $\{s_n\}\subset (0,1]$ and $\{b_n\}$ are such that:

• (i) ${\sum }_{n=0}^{\mathrm{\infty }}{s}_n=\mathrm{\infty }$;

• (ii) either ${lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}{b}_n\le 0$ or ${\sum }_{n=0}^{\mathrm{\infty }}|s_n{b}_n|<\mathrm{\infty }$;

• (iii) ${\sum }_{n=0}^{\mathrm{\infty }}{t}_n<\mathrm{\infty }$ where $t_n\ge 0$, for all $n\ge 0$.

Then ${lim}_{n\to \mathrm{\infty }}{a}_n=0$.

Recall that a set-valued mapping $T:D(T)\subset H\to 2^H$ is called monotone if for all $x,y\in D(T)$, $f\in Tx$ and $g\in Ty$ imply

$$〈f-g,x-y〉\ge 0.$$

A set-valued mapping T is called maximal monotone if T is monotone and $(I+\lambda T)D(T)=H$ for each $\lambda >0$, where I is the identity mapping of H. We denote by $G(T)$ the graph of T. It is well known that a monotone mapping T is maximal if and only if, for $(x,f)\in H\times H$, $〈f-g,x-y〉\ge 0$ for every $(y,g)\in G(T)$ implies $f\in Tx$. Next we provide an example to illustrate the concept of a maximal monotone mapping.

Let $A:C\to H$ be a monotone, k-Lipschitz-continuous mapping and let $N_{C}v$ be the normal cone to C at $v\in C$, i.e.,

$$N_{C}v=\{u\in H:〈v-p,u〉\ge 0,\mathrm{\forall }p\in C\}.$$

Define

$$\tilde{T}v=\{\begin{array}{ll}Av+N_{C}v,& \text{if }v\in C,\\ \mathrm{\varnothing },& \text{if }v\notin C.\end{array}$$

Then $\tilde{T}$ is maximal monotone (see [29]) such that

$$0\in \tilde{T}v\iff v\in VI(C,A).$$

(2.2)

Let $R:D(R)\subset H\to 2^H$ be a maximal monotone mapping. Let $\lambda ,\mu >0$ be two positive numbers.

Lemma 2.9 (see [42])

We have the resolvent identity

$$J_{R,\lambda }x=J_{R,\mu }(\frac{\mu }{\lambda }x+(1-\frac{\mu }{\lambda })J_{R,\lambda }x),\mathrm{\forall }x\in H.$$

Remark 2.2 For $\lambda ,\mu >0$, we have the following relation:

$$\parallel J_{R,\lambda }x-J_{R,\mu }y\parallel \le \parallel x-y\parallel +|\lambda -\mu |(\frac{1}{\lambda }\parallel J_{R,\lambda }x-y\parallel +\frac{1}{\mu }\parallel x-J_{R,\mu }y\parallel ),\mathrm{\forall }x,y\in H.$$

(2.3)

In terms of Huang [30] (see also [31]), we have the following property for the resolvent operator $J_{R,\lambda }:H\to \overline{D(R)}$.

Lemma 2.10 $J_{R,\lambda }$ is single-valued and firmly nonexpansive, i.e.,

$$〈J_{R,\lambda }x-J_{R,\lambda }y,x-y〉\ge {\parallel J_{R,\lambda }x-J_{R,\lambda }y\parallel }^2,\mathrm{\forall }x,y\in H.$$

Consequently, $J_{R,\lambda }$ is nonexpansive and monotone.

Lemma 2.11 (see [12])

Let R be a maximal monotone mapping with $D(R)=C$. Then for any given $\lambda >0$, $u\in C$ is a solution of problem (1.5) if and only if $u\in C$ satisfies

$$u=J_{R,\lambda }(u-\lambda Bu).$$

Lemma 2.12 (see [31])

Let R be a maximal monotone mapping with $D(R)=C$ and let $B:C\to H$ be a strongly monotone, continuous, and single-valued mapping. Then for each $z\in H$, the equation $z\in (B+\lambda R)x$ has a unique solution $x_{\lambda }$ for $\lambda >0$.

Lemma 2.13 (see [12])

Let R be a maximal monotone mapping with $D(R)=C$ and $B:C\to H$ be a monotone, continuous and single-valued mapping. Then $(I+\lambda (R+B))C=H$ for each $\lambda >0$. In this case, $R+B$ is maximal monotone.

3 Main results

In this section, we will introduce and analyze a multistep hybrid extragradient algorithm for finding a solution of the CMP (1.2) with constraints of several problems: finitely many GMEPs and finitely many variational inclusions and the fixed point problem of a strict pseudocontraction in a real Hilbert space. This algorithm is based on Korpelevich’s extragradient method, the viscosity approximation method, the hybrid steepest-descent method [43], Mann’s iteration method and the gradient-projection method (GPM) with regularization. Under appropriate assumptions, we prove the strong convergence of the proposed algorithm to a solution of the CMP (1.2), which is also the unique solution of a hierarchical variational inequality problem (HVIP).

Let C be a nonempty closed convex subset of a real Hilbert space H and $f:C\to \mathbf{R}$ be a convex functional with L-Lipschitz-continuous gradient ∇f. We denote by Γ the solution set of the CMP (1.2). Then the CMP (1.2) is generally ill-posed. Consider the following Tikhonov regularization problem:

$$\underset{x\in C}{min}{f}_{\alpha }(x):=f(x)+\frac{1}{2}\alpha {\parallel x\parallel }^2,$$

where $\alpha >0$ is the regularization parameter. Hence, we have

$$\mathrm{\nabla }{f}_{\alpha }=\mathrm{\nabla }f+\alpha I.$$

We are now in a position to state and prove the main result in this paper.

Theorem 3.1 Let C be a nonempty closed convex subset of a real Hilbert space H. Let M, N be two positive integers. Let $f:C\to \mathbf{R}$ be a convex functional with L-Lipschitz-continuous gradient ∇f. Let ${\Theta }_k$ be a bifunction from $C\times C$ to R satisfying (A1)-(A4) and ${\phi }_k:C\to \mathbf{R}\cup \{+\mathrm{\infty }\}$ be a proper lower semicontinuous and convex function with restriction (B1) or (B2), where $k\in \{1,2,\dots ,M\}$. Let $R_i:C\to 2^H$ be a maximal monotone mapping and let $A_k:H\to H$ and $B_i:C\to H$ be ${\mu }_k$-inverse-strongly monotone and ${\eta }_i$-inverse-strongly monotone, respectively, where $k\in \{1,2,\dots ,M\}$, $i\in \{1,2,\dots ,N\}$. Let $T:C\to C$ be a ξ-strictly pseudocontractive mapping, $S:H\to H$ be a nonexpansive mapping and $V:H\to H$ be a ρ-contraction with coefficient $\rho \in [0,1)$. Let $F:H\to H$ be κ-Lipschitzian and η-strongly monotone with positive constants $\kappa ,\eta >0$ such that $0\le \gamma <\tau$ and $0<\mu <\frac{2\eta }{{\kappa }^2}$ where $\tau =1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}$. Assume that $\Omega :={\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)\cap {\bigcap }_{i=1}^N\mathrm{I}(B_i,R_i)\cap Fix(T)\cap \Gamma \ne \mathrm{\varnothing }$. Let $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$, $\{{\alpha }_n\}\subset (0,\mathrm{\infty })$ with ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$, $\{{ϵ}_n\},\{{\delta }_n\},\{{\beta }_n\},\{{\gamma }_n\},\{{\sigma }_n\}\subset (0,1)$ with ${\beta }_n+{\gamma }_n+{\sigma }_n=1$, and $\{{\lambda }_{i,n}\}\subset [a_i,b_i]\subset (0,2{\eta }_i)$, $\{r_{k,n}\}\subset [c_k,d_k]\subset (0,2{\mu }_k)$ where $i\in \{1,2,\dots ,N\}$ and $k\in \{1,2,\dots ,M\}$. For arbitrarily given $x_0\in H$, let $\{x_n\}$ be a sequence generated by

$$\{\begin{array}{l}{u}_n=T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M)T_{r_{M-1,n}}^{({\Theta }_{M-1},{\phi }_{M-1})}(I-r_{M-1,n}{A}_{M-1})\cdots T_{r_{1,n}}^{({\Theta }_1,{\phi }_1)}(I-r_{1,n}{A}_1)x_n,\\ v_n=J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{B}_N)J_{R_{N-1},{\lambda }_{N-1,n}}(I-{\lambda }_{N-1,n}{B}_{N-1})\cdots J_{R_1,{\lambda }_{1,n}}(I-{\lambda }_{1,n}{B}_1)u_n,\\ y_n={\beta }_n{x}_n+{\gamma }_n{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n+{\sigma }_{n}T{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n,\\ x_{n+1}={ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(I-{ϵ}_n\mu F)y_n,\mathrm{\forall }n\ge 0,\end{array}$$

(3.1)

where $\mathrm{\nabla }{f}_{{\alpha }_n}={\alpha }_{n}I+\mathrm{\nabla }f$ for all $n\ge 0$. Suppose that

(C1) ${lim}_{n\to \mathrm{\infty }}{ϵ}_n=0$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n=\mathrm{\infty }$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|=0$;

(C2) ${lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}\frac{{\delta }_n}{{ϵ}_n}<\mathrm{\infty }$, ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|=0$;

(C3) ${lim}_{n\to \mathrm{\infty }}\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C4) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|r_{k,n}-r_{k,n-1}|}{{ϵ}_n{\delta }_n}=0$ for $i=1,2,\dots ,N$ and $k=1,2,\dots ,M$;

(C5) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n-{\lambda }_{n-1}|}{{ϵ}_n{\delta }_n}=0$, ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n{\alpha }_n-{\lambda }_{n-1}{\alpha }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$;

(C6) $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, ${lim}_{n\to \mathrm{\infty }}\frac{{\alpha }_n}{{\delta }_n}=0$ and ${lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\sigma }_n>0$.

Then we have:

• (i) ${lim}_{n\to \mathrm{\infty }}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0$;

• (ii) ${\omega }_w(x_n)\subset \Omega$;

• (iii) $\{x_n\}$ converges strongly to a minimizer $x^{\ast }$ of the CMP (1.2), which is a unique solution $x^{\ast }$ in Ω to the HVIP

  $$〈(\mu F-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0,\mathrm{\forall }p\in \Omega .$$

Proof First of all, observe that

$$\begin{array}{rl}\mu \eta \ge \tau & \iff \mu \eta \ge 1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}\\ \iff \sqrt{1-\mu (2\eta -\mu {\kappa }^2)}\ge 1-\mu \eta \\ \iff 1-2\mu \eta +{\mu }^2{\kappa }^2\ge 1-2\mu \eta +{\mu }^2{\eta }^2\\ \iff {\kappa }^2\ge {\eta }^2\\ \iff \kappa \ge \eta \end{array}$$

and

$$\begin{array}{c}〈(\mu F-\gamma S)x-(\mu F-\gamma S)y,x-y〉\hfill \\ =\mu 〈Fx-Fy,x-y〉-\gamma 〈Sx-Sy,x-y〉\hfill \\ \ge \mu \eta {\parallel x-y\parallel }^2-\gamma {\parallel x-y\parallel }^2\hfill \\ =(\mu \eta -\gamma ){\parallel x-y\parallel }^2,\mathrm{\forall }x,y\in H.\hfill \end{array}$$

Since $0\le \gamma <\tau$ and $\kappa \ge \eta$, we know that $\mu \eta \ge \tau >\gamma$ and hence the mapping $\mu F-\gamma S$ is $(\mu \eta -\gamma )$-strongly monotone. Moreover, it is clear that the mapping $\mu F-\gamma S$ is $(\mu \kappa +\gamma )$-Lipschitzian. Thus, there exists a unique solution $x^{\ast }$ in Ω to the VIP

$$〈(\mu F-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0,\mathrm{\forall }p\in \Omega .$$

That is, $\{x^{\ast }\}=VI(\Omega ,\mu F-\gamma S)$. Now, we put

$${\Delta }_n^k=T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k)T_{r_{k-1,n}}^{({\Theta }_{k-1},{\phi }_{k-1})}(I-r_{k-1,n}{A}_{k-1})\cdots T_{r_{1,n}}^{({\Theta }_1,{\phi }_1)}(I-r_{1,n}{A}_1)x_n$$

for all $k\in \{1,2,\dots ,M\}$ and $n\ge 1$,

$${\Lambda }_n^i=J_{R_i,{\lambda }_{i,n}}(I-{\lambda }_{i,n}{B}_i)J_{R_{i-1},{\lambda }_{i-1,n}}(I-{\lambda }_{i-1,n}{B}_{i-1})\cdots J_{R_1,{\lambda }_{1,n}}(I-{\lambda }_{1,n}{B}_1)$$

for all $i\in \{1,2,\dots ,N\}$, ${\Delta }_n^0=I$ and ${\Lambda }_n^0=I$, where I is the identity mapping on H. Then we have $u_n={\Delta }_n^M{x}_n$ and $v_n={\Lambda }_n^N{u}_n$.

In addition, we show that $P_C(I-\lambda \mathrm{\nabla }{f}_{\alpha })$ is ν-averaged for each $\lambda \in (0,\frac{2}{\alpha +L})$, where

$$\nu =\frac{2+\lambda (\alpha +L)}{4}\in (0,1).$$

Indeed, the Lipschitz continuity of ∇f implies that ∇f is $\frac{1}{L}$-ism (see [20] (also [44])); that is,

$$〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉\ge \frac{1}{L}{\parallel \mathrm{\nabla }f(x)-\mathrm{\nabla }f(y)\parallel }^2.$$

Observe that

$$\begin{array}{c}(\alpha +L)〈\mathrm{\nabla }{f}_{\alpha }(x)-\mathrm{\nabla }{f}_{\alpha }(y),x-y〉\hfill \\ =(\alpha +L)[\alpha {\parallel x-y\parallel }^2+〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉]\hfill \\ ={\alpha }^2{\parallel x-y\parallel }^2+\alpha 〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉+\alpha L{\parallel x-y\parallel }^2+L〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉\hfill \\ \ge {\alpha }^2{\parallel x-y\parallel }^2+2\alpha 〈\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y),x-y〉+{\parallel \mathrm{\nabla }f(x)-\mathrm{\nabla }f(y)\parallel }^2\hfill \\ ={\parallel \alpha (x-y)+\mathrm{\nabla }f(x)-\mathrm{\nabla }f(y)\parallel }^2={\parallel \mathrm{\nabla }{f}_{\alpha }(x)-\mathrm{\nabla }{f}_{\alpha }(y)\parallel }^2.\hfill \end{array}$$

Therefore, it follows that $\mathrm{\nabla }{f}_{\alpha }=\mathrm{\nabla }f+\alpha I$ is $\frac{1}{\alpha +L}$-ism. Thus, by Proposition 2.3(ii), $\lambda \mathrm{\nabla }{f}_{\alpha }$ is $\frac{1}{\lambda (\alpha +L)}$-ism. From Proposition 2.3(iii), the complement $I-\lambda \mathrm{\nabla }{f}_{\alpha }$ is $\frac{\lambda (\alpha +L)}{2}$-averaged. Consequently, noting that $P_C$ is $\frac{1}{2}$-averaged and utilizing Proposition 2.4(iv), we find that, for each $\lambda \in (0,\frac{2}{\alpha +L})$, $P_C(I-\lambda \mathrm{\nabla }{f}_{\alpha })$ is ν-averaged with

$$\nu =\frac{1}{2}+\frac{\lambda (\alpha +L)}{2}-\frac{1}{2}\cdot \frac{\lambda (\alpha +L)}{2}=\frac{2+\lambda (\alpha +L)}{4}\in (0,1).$$

This shows that $P_C(I-\lambda \mathrm{\nabla }{f}_{\alpha })$ is nonexpansive. Taking into account that $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$ and ${\alpha }_n\to 0$, we get

$$\underset{n\to \mathrm{\infty }}{lim\hspace{0.17em}sup}\frac{2+{\lambda }_n({\alpha }_n+L)}{4}\le \frac{2+bL}{4}<1.$$

Without loss of generality, we may assume that ${\nu }_n:=\frac{2+{\lambda }_n({\alpha }_n+L)}{4}<1$ for each $n\ge 0$. So, $P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})$ is nonexpansive for each $n\ge 0$. Similarly, since

$$\underset{n\to \mathrm{\infty }}{lim\hspace{0.17em}sup}\frac{{\lambda }_n({\alpha }_n+L)}{2}\le \frac{bL}{2}<1,$$

it is well known that $I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n}$ is nonexpansive for each $n\ge 0$.

We divide the rest of the proof into several steps.

Step 1. We prove that $\{x_n\}$ is bounded.

Indeed, take a fixed $p\in \Omega$ arbitrarily. Utilizing (2.1) and Proposition 2.2(ii) we have

$$\begin{array}{rcl}\parallel u_n-p\parallel & =& \parallel T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{B}_M){\Delta }_n^{M-1}{x}_n-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{B}_M){\Delta }_n^{M-1}p\parallel \\ \le & \parallel (I-r_{M,n}{B}_M){\Delta }_n^{M-1}{x}_n-(I-r_{M,n}{B}_M){\Delta }_n^{M-1}p\parallel \\ \le & \parallel {\Delta }_n^{M-1}{x}_n-{\Delta }_n^{M-1}p\parallel \\ \cdots \\ \le & \parallel {\Delta }_n^0{x}_n-{\Delta }_n^{0}p\parallel \\ =& \parallel x_n-p\parallel .\end{array}$$

(3.2)

Utilizing (2.1) and Lemma 2.10 we have

$$\begin{array}{rcl}\parallel v_n-p\parallel & =& \parallel J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{A}_N){\Lambda }_n^{N-1}{u}_n-J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{A}_N){\Lambda }_n^{N-1}p\parallel \\ \le & \parallel (I-{\lambda }_{N,n}{A}_N){\Lambda }_n^{N-1}{u}_n-(I-{\lambda }_{N,n}{A}_N){\Lambda }_n^{N-1}p\parallel \\ \le & \parallel {\Lambda }_n^{N-1}{u}_n-{\Lambda }_n^{N-1}p\parallel \\ \cdots \\ \le & \parallel {\Lambda }_n^0{u}_n-{\Lambda }_n^{0}p\parallel \\ =& \parallel u_n-p\parallel .\end{array}$$

(3.3)

Combining (3.2) and (3.3), we have

$$\parallel v_n-p\parallel \le \parallel x_n-p\parallel .$$

(3.4)

For simplicity, put $t_n=P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n$ for each $n\ge 0$. Note that $P_C(I-\lambda \mathrm{\nabla }f)p=p$ for $\lambda \in (0,\frac{2}{L})$. Hence, from (3.4), it follows that

$$\begin{array}{c}\parallel t_n-p\parallel \hfill \\ =\parallel P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-P_C(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \hfill \\ \le \parallel P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})p\parallel +\parallel P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})p-P_C(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \hfill \\ \le \parallel v_n-p\parallel +\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})p-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \hfill \\ =\parallel v_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel \hfill \\ \le \parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel .\hfill \end{array}$$

(3.5)

Since $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$ and T is ξ-strictly pseudocontractive, utilizing Lemma 2.4 we obtain from (3.1) and (3.5)

$$\begin{array}{rl}\parallel y_n-p\parallel & =\parallel {\beta }_n{x}_n+{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n-p\parallel \\ =\parallel {\beta }_n(x_n-p)+{\gamma }_n(t_n-p)+{\sigma }_n(T{t}_n-p)\parallel \\ \le {\beta }_n\parallel x_n-p\parallel +\parallel {\gamma }_n(t_n-p)+{\sigma }_n(T{t}_n-p)\parallel \\ \le {\beta }_n\parallel x_n-p\parallel +({\gamma }_n+{\sigma }_n)\parallel t_n-p\parallel \\ \le {\beta }_n\parallel x_n-p\parallel +({\gamma }_n+{\sigma }_n)[\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel ]\\ \le {\beta }_n\parallel x_n-p\parallel +({\gamma }_n+{\delta }_n)\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel \\ =\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel .\end{array}$$

(3.6)

Utilizing Lemma 2.7, we deduce from (3.1), (3.6), $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$, and $0\le \gamma <\tau$ that, for all $n\ge 0$,

$$\begin{array}{c}\parallel x_{n+1}-p\parallel \hfill \\ =\parallel {ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(I-{ϵ}_n\mu F)y_n-p\parallel \hfill \\ =\parallel {ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)-{ϵ}_n\mu Fp+(I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel \hfill \\ \le \parallel {ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)-{ϵ}_n\mu Fp\parallel +\parallel (I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel \hfill \\ ={ϵ}_n\parallel {\delta }_n(\gamma V{x}_n-\mu Fp)+(1-{\delta }_n)(\gamma S{x}_n-\mu Fp)\parallel +\parallel (I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel \hfill \\ \le {ϵ}_n[{\delta }_n\parallel \gamma V{x}_n-\mu Fp\parallel +(1-{\delta }_n)\parallel \gamma S{x}_n-\mu Fp\parallel ]+\parallel (I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel \hfill \\ \le {ϵ}_n[{\delta }_n(\gamma \parallel V{x}_n-Vp\parallel +\parallel \gamma Vp-\mu Fp\parallel )+(1-{\delta }_n)(\gamma \parallel S{x}_n-Sp\parallel +\parallel \gamma Sp-\mu Fp\parallel )]\hfill \\ +\parallel (I-{ϵ}_n\mu F)y_n-(I-{\lambda }_n\mu F)p\parallel \hfill \\ \le {ϵ}_n[{\delta }_n(\gamma \rho \parallel x_n-p\parallel +\parallel \gamma Vp-\mu Fp\parallel )+(1-{\delta }_n)(\gamma \parallel x_n-p\parallel +\parallel \gamma Sp-\mu Fp\parallel )]\hfill \\ +(1-{ϵ}_n\tau )\parallel y_n-p\parallel \hfill \\ \le {ϵ}_n[(1-{\delta }_n(1-\rho ))\gamma \parallel x_n-p\parallel +max\{\parallel \gamma Vp-\mu Fp\parallel ,\parallel \gamma Sp-\mu Fp\parallel \}]\hfill \\ +(1-{ϵ}_n\tau )[\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel ]\hfill \\ ={ϵ}_n(1-{\delta }_n(1-\rho ))\gamma \parallel x_n-p\parallel +{\lambda }_{n}max\{\parallel \gamma Vp-\mu Fp\parallel ,\parallel \gamma Sp-\mu Fp\parallel \}\hfill \\ +(1-{ϵ}_n\tau )\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel \hfill \\ \le {ϵ}_n\gamma \parallel x_n-p\parallel +{ϵ}_{n}max\{\parallel \gamma Vp-\mu Fp\parallel ,\parallel \gamma Sp-\mu Fp\parallel \}+(1-{ϵ}_n\tau )\parallel x_n-p\parallel \hfill \\ =(1-{ϵ}_n(\tau -\gamma ))\parallel x_n-p\parallel +{ϵ}_{n}max\{\parallel \gamma Vp-\mu Fp\parallel ,\parallel \gamma Sp-\mu Fp\parallel \}+{\alpha }_{n}b\parallel p\parallel \hfill \\ =(1-{ϵ}_n(\tau -\gamma ))\parallel x_n-p\parallel +{ϵ}_n(\tau -\gamma )\frac{max\{\parallel \gamma Vp-\mu Fp\parallel ,\parallel \gamma Sp-\mu Fp\parallel \}}{\tau -\gamma }+{\alpha }_{n}b\parallel p\parallel \hfill \\ \le max\{\parallel x_n-p\parallel ,\frac{\parallel \gamma Vp-\mu Fp\parallel }{\tau -\gamma },\frac{\parallel \gamma Sp-\mu Fp\parallel }{\tau -\gamma }\}+{\alpha }_{n}b\parallel p\parallel .\hfill \end{array}$$

By induction, we get

$$\parallel x_{n+1}-p\parallel \le max\{\parallel x_0-p\parallel ,\frac{\parallel \gamma Vp-\mu Fp\parallel }{\tau -\gamma },\frac{\parallel \gamma Sp-\mu Fp\parallel }{\tau -\gamma }\}+\sum _{j=0}^n{\alpha }_{n}b\parallel p\parallel ,\mathrm{\forall }n\ge 0.$$

Thus, $\{x_n\}$ is bounded (due to ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$) and so are the sequences $\{t_n\}$, $\{u_n\}$, $\{v_n\}$ and $\{y_n\}$.

Step 2. We prove that ${lim}_{n\to \mathrm{\infty }}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0$.

Indeed, utilizing (2.1) and (2.3), we obtain

$$\begin{array}{c}\parallel v_{n+1}-v_n\parallel \hfill \\ =\parallel {\Lambda }_{n+1}^N{u}_{n+1}-{\Lambda }_n^N{u}_n\parallel \hfill \\ =\parallel J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n+1}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel \hfill \\ \le \parallel J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n+1}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}\parallel \hfill \\ +\parallel J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel \hfill \\ \le \parallel (I-{\lambda }_{N,n+1}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-(I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}\parallel \hfill \\ +\parallel (I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel +|{\lambda }_{N,n+1}-{\lambda }_{N,n}|\hfill \\ \times (\frac{1}{{\lambda }_{N,n+1}}\parallel J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel \hfill \\ +\frac{1}{{\lambda }_{N,n}}\parallel (I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel )\hfill \\ \le |{\lambda }_{N,n+1}-{\lambda }_{N,n}|(\parallel B_N{\Lambda }_{n+1}^{N-1}{u}_{n+1}\parallel +\tilde{M})+\parallel {\Lambda }_{n+1}^{N-1}{u}_{n+1}-{\Lambda }_n^{N-1}{u}_n\parallel \hfill \\ \le |{\lambda }_{N,n+1}-{\lambda }_{N,n}|(\parallel B_N{\Lambda }_{n+1}^{N-1}{u}_{n+1}\parallel +\tilde{M})\hfill \\ +|{\lambda }_{N-1,n+1}-{\lambda }_{N-1,n}|(\parallel B_{N-1}{\Lambda }_{n+1}^{N-2}{u}_{n+1}\parallel +\tilde{M})+\parallel {\Lambda }_{n+1}^{N-2}{u}_{n+1}-{\Lambda }_n^{N-2}{u}_n\parallel \hfill \\ \cdots \hfill \\ \le |{\lambda }_{N,n+1}-{\lambda }_{N,n}|(\parallel B_N{\Lambda }_{n+1}^{N-1}{u}_{n+1}\parallel +\tilde{M})\hfill \\ +|{\lambda }_{N-1,n+1}-{\lambda }_{N-1,n}|(\parallel B_{N-1}{\Lambda }_{n+1}^{N-2}{u}_{n+1}\parallel +\tilde{M})\hfill \\ +\cdots +|{\lambda }_{1,n+1}-{\lambda }_{1,n}|(\parallel B_1{\Lambda }_{n+1}^0{u}_{n+1}\parallel +\tilde{M})+\parallel {\Lambda }_{n+1}^0{u}_{n+1}-{\Lambda }_n^0{u}_n\parallel \hfill \\ \le {\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+\parallel u_{n+1}-u_n\parallel ,\hfill \end{array}$$

(3.7)

where

$$\begin{array}{c}\underset{n\ge 0}{sup}\{\frac{1}{{\lambda }_{N,n+1}}\parallel J_{R_N,{\lambda }_{N,n+1}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel \hfill \\ +\frac{1}{{\lambda }_{N,n}}\parallel (I-{\lambda }_{N,n}{B}_N){\Lambda }_{n+1}^{N-1}{u}_{n+1}-J_{R_N,{\lambda }_{N,n}}(I-{\lambda }_{N,n}{B}_N){\Lambda }_n^{N-1}{u}_n\parallel \}\le \tilde{M}\hfill \end{array}$$

for some $\tilde{M}>0$ and ${sup}_{n\ge 0}\{{\sum }_{i=1}^N\parallel B_i{\Lambda }_{n+1}^{i-1}{u}_{n+1}\parallel +\tilde{M}\}\le {\tilde{M}}_0$ for some ${\tilde{M}}_0>0$.

Utilizing Proposition 2.2(ii), (v), we deduce that

$$\begin{array}{c}\parallel u_{n+1}-u_n\parallel \hfill \\ =\parallel {\Delta }_{n+1}^M{x}_{n+1}-{\Delta }_n^M{x}_n\parallel \hfill \\ =\parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M){\Delta }_n^{M-1}{x}_n\parallel \hfill \\ \le \parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel \hfill \\ +\parallel T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M){\Delta }_n^{M-1}{x}_n\parallel \hfill \\ \le \parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel \hfill \\ +\parallel T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-T_{r_{M,n}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel \hfill \\ +\parallel (I-r_{M,n}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-(I-r_{M,n}{A}_M){\Delta }_n^{M-1}{x}_n\parallel \hfill \\ \le \frac{|r_{M,n+1}-r_{M,n}|}{r_{M,n+1}}\parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}-(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel \hfill \\ +|r_{M,n+1}-r_{M,n}|\parallel A_M{\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel +\parallel {\Delta }_{n+1}^{M-1}{x}_{n+1}-{\Delta }_n^{M-1}{x}_n\parallel \hfill \\ =|r_{M,n+1}-r_{M,n}|[\parallel A_M{\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel +\frac{1}{r_{M,n+1}}\parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\hfill \\ -(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel ]+\parallel {\Delta }_{n+1}^{M-1}{x}_{n+1}-{\Delta }_n^{M-1}{x}_n\parallel \hfill \\ \cdots \hfill \\ \le |r_{M,n+1}-r_{M,n}|[\parallel A_M{\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel +\frac{1}{r_{M,n+1}}\parallel T_{r_{M,n+1}}^{({\Theta }_M,{\phi }_M)}(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\hfill \\ -(I-r_{M,n+1}{A}_M){\Delta }_{n+1}^{M-1}{x}_{n+1}\parallel ]+\cdots +|r_{1,n+1}-r_{1,n}|[\parallel A_1{\Delta }_{n+1}^0{x}_{n+1}\parallel \hfill \\ +\frac{1}{r_{1,n+1}}\parallel T_{r_{1,n+1}}^{({\Theta }_1,{\phi }_1)}(I-r_{1,n+1}{A}_1){\Delta }_{n+1}^0{x}_{n+1}-(I-r_{1,n+1}{A}_1){\Delta }_{n+1}^0{x}_{n+1}\parallel ]\hfill \\ +\parallel {\Delta }_{n+1}^0{x}_{n+1}-{\Delta }_n^0{x}_n\parallel \hfill \\ \le {\tilde{M}}_1\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+\parallel x_{n+1}-x_n\parallel ,\hfill \end{array}$$

(3.8)

where ${\tilde{M}}_1>0$ is a constant such that, for each $n\ge 0$,

$$\begin{array}{c}\sum _{k=1}^M[\parallel A_k{\Delta }_{n+1}^{k-1}{x}_{n+1}\parallel +\frac{1}{r_{k,n+1}}\parallel T_{r_{k,n+1}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n+1}{A}_k){\Delta }_{n+1}^{k-1}{x}_{n+1}-(I-r_{k,n+1}{A}_k){\Delta }_{n+1}^{k-1}{x}_{n+1}\parallel ]\hfill \\ \le {\tilde{M}}_1.\hfill \end{array}$$

Furthermore, we define $y_n={\beta }_n{x}_n+(1-{\beta }_n)w_n$ for all $n\ge 0$. It follows that

$$\begin{array}{c}{w}_{n+1}-w_n\hfill \\ =\frac{y_{n+1}-{\beta }_{n+1}{x}_{n+1}}{1-{\beta }_{n+1}}-\frac{y_n-{\beta }_n{x}_n}{1-{\beta }_n}\hfill \\ =\frac{{\gamma }_{n+1}{t}_{n+1}+{\sigma }_{n+1}T{t}_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n}{1-{\beta }_n}\hfill \\ =\frac{{\gamma }_{n+1}(t_{n+1}-t_n)+{\sigma }_{n+1}(T{t}_{n+1}-T{t}_n)}{1-{\beta }_{n+1}}\hfill \\ +(\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n})t_n+(\frac{{\sigma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\sigma }_n}{1-{\beta }_n})T{t}_n.\hfill \end{array}$$

(3.9)

Since $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$, utilizing Lemma 2.4 and the nonexpansivity of $P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})$ we have

$$\parallel {\gamma }_{n+1}(t_{n+1}-t_n)+{\sigma }_{n+1}(T{t}_{n+1}-T{t}_n)\parallel \le ({\gamma }_{n+1}+{\sigma }_{n+1})\parallel t_{n+1}-t_n\parallel$$

(3.10)

and

$$\begin{array}{rcl}\parallel t_{n+1}-t_n\parallel & =& \parallel P_C(I-{\lambda }_{n+1}\mathrm{\nabla }{f}_{{\alpha }_{n+1}})v_{n+1}-P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n\parallel \\ \le & \parallel P_C(I-{\lambda }_{n+1}\mathrm{\nabla }{f}_{{\alpha }_{n+1}})v_{n+1}-P_C(I-{\lambda }_{n+1}\mathrm{\nabla }{f}_{{\alpha }_{n+1}})v_n\parallel \\ +\parallel P_C(I-{\lambda }_{n+1}\mathrm{\nabla }{f}_{{\alpha }_{n+1}})v_n-P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n\parallel \\ \le & \parallel v_{n+1}-v_n\parallel +\parallel (I-{\lambda }_{n+1}\mathrm{\nabla }{f}_{{\alpha }_{n+1}})v_n-(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n\parallel \\ \le & \parallel v_{n+1}-v_n\parallel +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel .\end{array}$$

(3.11)

Hence it follows from (3.7)-(3.11) that

$$\begin{array}{c}\parallel w_{n+1}-w_n\parallel \hfill \\ \le \frac{\parallel {\gamma }_{n+1}(t_{n+1}-t_n)+{\sigma }_{n+1}(T{t}_{n+1}-T{t}_n)\parallel }{1-{\beta }_{n+1}}\hfill \\ +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|\parallel t_n\parallel +|\frac{{\sigma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\sigma }_n}{1-{\beta }_n}|\parallel T{t}_n\parallel \hfill \\ \le \frac{({\gamma }_{n+1}+{\sigma }_{n+1})}{1-{\beta }_{n+1}}\parallel t_{n+1}-t_n\parallel +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel )\hfill \\ =\parallel t_{n+1}-t_n\parallel +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel )\hfill \\ \le \parallel v_{n+1}-v_n\parallel +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel \hfill \\ +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel )\hfill \\ \le {\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+\parallel u_{n+1}-u_n\parallel +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel \hfill \\ +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel )\hfill \\ \le {\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+{\tilde{M}}_1\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+\parallel x_{n+1}-x_n\parallel \hfill \\ +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel \hfill \\ +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel ).\hfill \end{array}$$

(3.12)

In the meantime, a simple calculation shows that

$$y_{n+1}-y_n={\beta }_n(x_{n+1}-x_n)+(1-{\beta }_n)(w_{n+1}-w_n)+({\beta }_{n+1}-{\beta }_n)(x_{n+1}-w_{n+1}).$$

So, it follows from (3.12) that

$$\begin{array}{c}\parallel y_{n+1}-y_n\parallel \hfill \\ \le {\beta }_n\parallel x_{n+1}-x_n\parallel +(1-{\beta }_n)\parallel w_{n+1}-w_n\parallel +|{\beta }_{n+1}-{\beta }_n|\parallel x_{n+1}-w_{n+1}\parallel \hfill \\ \le {\beta }_n\parallel x_{n+1}-x_n\parallel +(1-{\beta }_n)[{\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+{\tilde{M}}_1\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|\hfill \\ +\parallel x_{n+1}-x_n\parallel +|\frac{{\gamma }_{n+1}}{1-{\beta }_{n+1}}-\frac{{\gamma }_n}{1-{\beta }_n}|(\parallel t_n\parallel +\parallel T{t}_n\parallel )+|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel \hfill \\ +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel ]+|{\beta }_{n+1}-{\beta }_n|\parallel x_{n+1}-w_{n+1}\parallel \hfill \\ \le \parallel x_{n+1}-x_n\parallel +{\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+{\tilde{M}}_1\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|\hfill \\ +\frac{|{\gamma }_{n+1}-{\gamma }_n|(1-{\beta }_n)+{\gamma }_n|{\beta }_{n+1}-{\beta }_n|}{1-{\beta }_{n+1}}(\parallel t_n\parallel +\parallel T{t}_n\parallel )+|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel \hfill \\ +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel +|{\beta }_{n+1}-{\beta }_n|\parallel x_{n+1}-w_{n+1}\parallel \hfill \\ \le \parallel x_{n+1}-x_n\parallel +{\tilde{M}}_0\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+{\tilde{M}}_1\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|\hfill \\ +|{\gamma }_{n+1}-{\gamma }_n|\frac{\parallel t_n\parallel +\parallel T{t}_n\parallel }{1-d}+|{\beta }_{n+1}-{\beta }_n|(\parallel x_{n+1}-w_{n+1}\parallel +\frac{\parallel t_n\parallel +\parallel T{t}_n\parallel }{1-d})\hfill \\ +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|\parallel v_n\parallel +|{\lambda }_{n+1}-{\lambda }_n|\parallel \mathrm{\nabla }f(v_n)\parallel \hfill \\ \le \parallel x_{n+1}-x_n\parallel +{\tilde{M}}_2(\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+|{\gamma }_{n+1}-{\gamma }_n|\hfill \\ +|{\beta }_{n+1}-{\beta }_n|+|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|+|{\lambda }_{n+1}-{\lambda }_n|),\hfill \end{array}$$

(3.13)

where ${sup}_{n\ge 0}\{\parallel x_{n+1}-w_{n+1}\parallel +\frac{\parallel t_n\parallel +\parallel T{t}_n\parallel }{1-d}+\parallel v_n\parallel +\parallel \mathrm{\nabla }f(v_n)\parallel +{\tilde{M}}_0+{\tilde{M}}_1\}\le {\tilde{M}}_2$ for some ${\tilde{M}}_2>0$.

On the other hand, we define $z_n:={\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n$ for all $n\ge 0$. Then it is well known that $x_{n+1}={ϵ}_n\gamma z_n+(I-{ϵ}_n\mu F)y_n$ for all $n\ge 0$. Simple calculations show that

$$\{\begin{array}{l}{z}_{n+1}-z_n=({\delta }_{n+1}-{\delta }_n)(V{x}_n-S{x}_n)+{\delta }_{n+1}(V{x}_{n+1}-V{x}_n)\\ \phantom{{}_{n+1}-z_n=}+(1-{\delta }_{n+1})(S{x}_{n+1}-S{x}_n),\\ x_{n+2}-x_{n+1}=({ϵ}_{n+1}-{ϵ}_n)(\gamma z_n-\mu F{y}_n)+{ϵ}_{n+1}\gamma (z_{n+1}-z_n)\\ \phantom{x_{n+2}-x_{n+1}=}+(I-{\lambda }_{n+1}\mu F)y_{n+1}-(I-{\lambda }_{n+1}\mu F)y_n.\end{array}$$

Since V is a ρ-contraction with coefficient $\rho \in [0,1)$ and S is a nonexpansive mapping, we conclude that

$$\begin{array}{rl}\parallel z_{n+1}-z_n\parallel & \le |{\delta }_{n+1}-{\delta }_n|\parallel V{x}_n-S{x}_n\parallel +{\delta }_{n+1}\parallel V{x}_{n+1}-V{x}_n\parallel +(1-{\delta }_{n+1})\parallel S{x}_{n+1}-S{x}_n\parallel \\ \le |{\delta }_{n+1}-{\delta }_n|\parallel V{x}_n-S{x}_n\parallel +{\delta }_{n+1}\rho \parallel x_{n+1}-x_n\parallel +(1-{\delta }_{n+1})\parallel x_{n+1}-x_n\parallel \\ =(1-{\delta }_{n+1}(1-\rho ))\parallel x_{n+1}-x_n\parallel +|{\delta }_{n+1}-{\delta }_n|\parallel V{x}_n-S{x}_n\parallel ,\end{array}$$

which, together with (3.13) and $0\le \gamma <\tau$, implies that

$$\begin{array}{c}\parallel x_{n+2}-x_{n+1}\parallel \hfill \\ \le |{ϵ}_{n+1}-{ϵ}_n|\parallel \gamma z_n-\mu F{y}_n\parallel +{ϵ}_{n+1}\gamma \parallel z_{n+1}-z_n\parallel \hfill \\ +\parallel (I-{ϵ}_{n+1}\mu F)y_{n+1}-(I-{ϵ}_{n+1}\mu F)y_n\parallel \hfill \\ \le |{ϵ}_{n+1}-{ϵ}_n|\parallel \gamma z_n-\mu F{y}_n\parallel +{ϵ}_{n+1}\gamma \parallel z_{n+1}-z_n\parallel +(1-{ϵ}_{n+1}\tau )\parallel y_{n+1}-y_n\parallel \hfill \\ \le |{ϵ}_{n+1}-{ϵ}_n|\parallel \gamma z_n-\mu F{y}_n\parallel +{ϵ}_{n+1}\gamma [(1-{\delta }_{n+1}(1-\rho ))\parallel x_{n+1}-x_n\parallel \hfill \\ +|{\delta }_{n+1}-{\delta }_n|\parallel V{x}_n-S{x}_n\parallel ]+(1-{ϵ}_{n+1}\tau )[\parallel x_{n+1}-x_n\parallel +{\tilde{M}}_2(\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|\hfill \\ +\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+|{\gamma }_{n+1}-{\gamma }_n|+|{\beta }_{n+1}-{\beta }_n|\hfill \\ +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|+|{\lambda }_{n+1}-{\lambda }_n|\left)\right]\hfill \\ \le (1-{ϵ}_{n+1}(\tau -\gamma ))\parallel x_{n+1}-x_n\parallel +|{ϵ}_{n+1}-{ϵ}_n|\parallel \gamma z_n-\mu F{y}_n\parallel +|{\delta }_{n+1}-{\delta }_n|\parallel V{x}_n-S{x}_n\parallel \hfill \\ +{\tilde{M}}_2(\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+|{\gamma }_{n+1}-{\gamma }_n|+|{\beta }_{n+1}-{\beta }_n|\hfill \\ +|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|+|{\lambda }_{n+1}-{\lambda }_n|)\hfill \\ \le (1-{ϵ}_{n+1}(\tau -\gamma ))\parallel x_{n+1}-x_n\parallel \hfill \\ +{\tilde{M}}_3\{\sum _{i=1}^N|{\lambda }_{i,n+1}-{\lambda }_{i,n}|+\sum _{k=1}^M|r_{k,n+1}-r_{k,n}|+|{ϵ}_{n+1}-{ϵ}_n|\hfill \\ +|{\delta }_{n+1}-{\delta }_n|+|{\beta }_{n+1}-{\beta }_n|+|{\gamma }_{n+1}-{\gamma }_n|+|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|+|{\lambda }_{n+1}-{\lambda }_n|\},\hfill \end{array}$$

where ${sup}_{n\ge 0}\{\parallel \gamma z_n-\mu F{y}_n\parallel +\parallel V{x}_n-S{x}_n\parallel +{\tilde{M}}_2\}\le {\tilde{M}}_3$ for some ${\tilde{M}}_3>0$. Consequently,

$$\begin{array}{c}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}\hfill \\ \le (1-{ϵ}_n(\tau -\gamma ))\frac{\parallel x_n-x_{n-1}\parallel }{{\delta }_n}+{\tilde{M}}_3\{\sum _{i=1}^N\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{\delta }_n}\hfill \\ +\sum _{k=1}^M\frac{|r_{k,n}-r_{k,n-1}|}{{\delta }_n}+\frac{|{ϵ}_n-{ϵ}_{n-1}|}{{\delta }_n}+\frac{|{\delta }_n-{\delta }_{n-1}|}{{\delta }_n}+\frac{|{\beta }_n-{\beta }_{n-1}|}{{\delta }_n}\hfill \\ +\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{\delta }_n}+\frac{|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|}{{\delta }_n}+\frac{|{\lambda }_{n+1}-{\lambda }_n|}{{\delta }_n}\}\hfill \\ =(1-{ϵ}_n(\tau -\gamma ))\frac{\parallel x_n-x_{n-1}\parallel }{{\delta }_{n-1}}+(1-{ϵ}_n(\tau -\gamma ))\parallel x_n-x_{n-1}\parallel (\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}})\hfill \\ +{\tilde{M}}_3\{\sum _{i=1}^N\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{\delta }_n}+\sum _{k=1}^M\frac{|r_{k,n}-r_{k,n-1}|}{{\delta }_n}+\frac{|{ϵ}_n-{ϵ}_{n-1}|}{{\delta }_n}+\frac{|{\delta }_n-{\delta }_{n-1}|}{{\delta }_n}\hfill \\ +\frac{|{\beta }_n-{\beta }_{n-1}|}{{\delta }_n}+\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{\delta }_n}+\frac{|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|}{{\delta }_n}+\frac{|{\lambda }_{n+1}-{\lambda }_n|}{{\delta }_n}\}\hfill \\ \le (1-{ϵ}_n(\tau -\gamma ))\frac{\parallel x_n-x_{n-1}\parallel }{{\delta }_{n-1}}+{ϵ}_n(\tau -\gamma )\cdot \frac{{\tilde{M}}_4}{\tau -\gamma }\left\{\frac{1}{{ϵ}_n}\right|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|+\sum _{i=1}^N\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{ϵ}_n{\delta }_n}\hfill \\ +\sum _{k=1}^M\frac{|r_{k,n}-r_{k,n-1}|}{{ϵ}_n{\delta }_n}+\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|+\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|+\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}+\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}\hfill \\ +\frac{|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|}{{ϵ}_n{\delta }_n}+\frac{|{\lambda }_{n+1}-{\lambda }_n|}{{ϵ}_n{\delta }_n}\},\hfill \end{array}$$

(3.14)

where ${sup}_{n\ge 1}\{\parallel x_n-x_{n-1}\parallel +{\tilde{M}}_3\}\le {\tilde{M}}_4$ for some ${\tilde{M}}_4>0$. From conditions (C1)-(C5) it follows that ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n(\tau -\gamma )=\mathrm{\infty }$ and

$$\begin{array}{c}\underset{n\to \mathrm{\infty }}{lim}\frac{{\tilde{M}}_4}{\tau -\gamma }\left\{\frac{1}{{ϵ}_n}\right|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|+\sum _{i=1}^N\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{ϵ}_n{\delta }_n}+\sum _{k=1}^M\frac{|r_{k,n}-r_{k,n-1}|}{{ϵ}_n{\delta }_n}+\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|\hfill \\ +\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|+\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}+\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}+\frac{|{\lambda }_{n+1}{\alpha }_{n+1}-{\lambda }_n{\alpha }_n|}{{ϵ}_n{\delta }_n}+\frac{|{\lambda }_{n+1}-{\lambda }_n|}{{ϵ}_n{\delta }_n}\}=0.\hfill \end{array}$$

Thus, utilizing Lemma 2.8, we immediately conclude that

$$\underset{n\to \mathrm{\infty }}{lim}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0.$$

So, from ${\delta }_n\to 0$ it follows that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel x_{n+1}-x_n\parallel =0.$$

Step 3. We prove that ${lim}_{n\to \mathrm{\infty }}\parallel x_n-u_n\parallel =0$, ${lim}_{n\to \mathrm{\infty }}\parallel x_n-v_n\parallel =0$, ${lim}_{n\to \mathrm{\infty }}\parallel v_n-t_n\parallel =0$ and ${lim}_{n\to \mathrm{\infty }}\parallel t_n-T{t}_n\parallel =0$.

Indeed, utilizing Lemmas 2.1 and 2.2(b), from (3.1), (3.4)-(3.5), and $0\le \gamma <\tau$ we deduce that

$$\begin{array}{c}{\parallel y_n-p\parallel }^2\hfill \\ ={\parallel {\beta }_n{x}_n+{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n-p\parallel }^2\hfill \\ ={\parallel {\beta }_n(x_n-p)+(1-{\beta }_n)(\frac{{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n}{1-{\beta }_n}-p)\parallel }^2\hfill \\ ={\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel \frac{{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n}{1-{\beta }_n}-p\parallel }^2-{\beta }_n(1-{\beta }_n){\parallel \frac{{\gamma }_n{t}_n+{\sigma }_{n}T{t}_n}{1-{\beta }_n}-x_n\parallel }^2\hfill \\ ={\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel \frac{{\gamma }_n(t_n-p)+{\sigma }_n(T{t}_n-p)}{1-{\beta }_n}\parallel }^2-{\beta }_n(1-{\beta }_n){\parallel \frac{y_n-x_n}{1-{\beta }_n}\parallel }^2\hfill \\ \le {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)\frac{{({\gamma }_n+{\sigma }_n)}^2{\parallel t_n-p\parallel }^2}{{(1-{\beta }_n)}^2}-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ ={\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel t_n-p\parallel }^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ \le {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){(\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel )}^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ \le {\beta }_n{(\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel )}^2+(1-{\beta }_n){(\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel )}^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ ={(\parallel x_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel )}^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ \le {(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2,\hfill \end{array}$$

(3.15)

and hence

$$\begin{array}{c}{\parallel x_{n+1}-p\parallel }^2\hfill \\ ={\parallel {ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(I-{ϵ}_n\mu F)y_n-p\parallel }^2\hfill \\ ={\parallel {ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)-{ϵ}_n\mu Fp+(I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel }^2\hfill \\ ={\parallel {ϵ}_n[{\delta }_n(\gamma V{x}_n-\mu Fp)+(1-{\delta }_n)(\gamma S{x}_n-\mu Fp)]+(I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel }^2\hfill \\ =\parallel {ϵ}_n[{\delta }_n(\gamma V{x}_n-\gamma Vp)+(1-{\delta }_n)(\gamma S{x}_n-\gamma Sp)]+(I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\hfill \\ {+{ϵ}_n[{\delta }_n(\gamma Vp-\mu Fp)+(1-{\delta }_n)(\gamma Sp-\mu Fp)]\parallel }^2\hfill \\ \le {\parallel {ϵ}_n[{\delta }_n(\gamma V{x}_n-\gamma Vp)+(1-{\delta }_n)(\gamma S{x}_n-\gamma Sp)]+(I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {[{ϵ}_n\parallel {\delta }_n(\gamma V{x}_n-\gamma Vp)+(1-{\delta }_n)(\gamma S{x}_n-\gamma Sp)\parallel +\parallel (I-{ϵ}_n\mu F)y_n-(I-{ϵ}_n\mu F)p\parallel ]}^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {[{ϵ}_n({\delta }_n\gamma \rho \parallel x_n-p\parallel +(1-{\delta }_n)\gamma \parallel x_n-p\parallel )+(1-{ϵ}_n\tau )\parallel y_n-p\parallel ]}^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2(1-{\delta }_n){ϵ}_n〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ ={[{ϵ}_n(1-{\delta }_n(1-\rho ))\gamma \parallel x_n-p\parallel +(1-{ϵ}_n\tau )\parallel y_n-p\parallel ]}^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {[{ϵ}_n\gamma \parallel x_n-p\parallel +(1-{ϵ}_n\tau )\parallel y_n-p\parallel ]}^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ ={[{ϵ}_n\tau \cdot \frac{\gamma }{\tau }\parallel x_n-p\parallel +(1-{ϵ}_n\tau )\parallel y_n-p\parallel ]}^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {ϵ}_n\frac{{\gamma }^2}{\tau }{\parallel x_n-p\parallel }^2+(1-{ϵ}_n\tau ){\parallel y_n-p\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {ϵ}_n\frac{{\gamma }^2}{\tau }{\parallel x_n-p\parallel }^2+(1-{ϵ}_n\tau )[{(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2]\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {ϵ}_n\frac{{\gamma }^2}{\tau }{(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2+(1-{ϵ}_n\tau )[{(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2\hfill \\ -\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2]+2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉\hfill \\ +2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ =(1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-\frac{{\beta }_n(1-{ϵ}_n\tau )}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-\frac{{\beta }_n(1-{ϵ}_n\tau )}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n\parallel \gamma Vp-\mu Fp\parallel \parallel x_{n+1}-p\parallel +2{ϵ}_n\parallel \gamma Sp-\mu Fp\parallel \parallel x_{n+1}-p\parallel ,\hfill \end{array}$$

(3.16)

which, together with $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, immediately yields

$$\begin{array}{c}\frac{c(1-{ϵ}_n\tau )}{1-c}{\parallel y_n-x_n\parallel }^2\hfill \\ \le \frac{{\beta }_n(1-{ϵ}_n\tau )}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ \le {(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-{\parallel x_{n+1}-p\parallel }^2+2{ϵ}_n{\delta }_n\parallel \gamma Vp-\mu Fp\parallel \parallel x_{n+1}-p\parallel \hfill \\ +2{ϵ}_n\parallel \gamma Sp-\mu Fp\parallel \parallel x_{n+1}-p\parallel \hfill \\ \le (\parallel x_n-x_{n+1}\parallel +{\alpha }_{n}b\parallel p\parallel )(\parallel x_n-p\parallel +\parallel x_{n+1}-p\parallel +{\alpha }_{n}b\parallel p\parallel )\hfill \\ +2{ϵ}_n{\delta }_n\parallel \gamma Vp-\mu Fp\parallel \parallel x_{n+1}-p\parallel +2{ϵ}_n\parallel \gamma Sp-\mu Fp\parallel \parallel x_{n+1}-p\parallel .\hfill \end{array}$$

Since ${ϵ}_n\to 0$, ${\delta }_n\to 0$, ${\alpha }_n\to 0$, $\parallel x_{n+1}-x_n\parallel \to 0$, and $\{x_n\}$ is bounded, we have

$$\underset{n\to \mathrm{\infty }}{lim}\parallel y_n-x_n\parallel =0.$$

(3.17)

Observe that

$$\begin{array}{rl}{\parallel {\Delta }_n^k{x}_n-p\parallel }^2& ={\parallel T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k)p\parallel }^2\\ \le {\parallel (I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-(I-r_{k,n}{A}_k)p\parallel }^2\\ \le {\parallel {\Delta }_n^{k-1}{x}_n-p\parallel }^2+r_{k,n}(r_{k,n}-2{\mu }_k){\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2\\ \le {\parallel x_n-p\parallel }^2+r_{k,n}(r_{k,n}-2{\mu }_k){\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2\end{array}$$

(3.18)

and

$$\begin{array}{rl}{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2& ={\parallel J_{R_i,{\lambda }_{i,n}}(I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-J_{R_i,{\lambda }_{i,n}}(I-{\lambda }_{i,n}{B}_i)p\parallel }^2\\ \le {\parallel (I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-(I-{\lambda }_{i,n}{B}_i)p\parallel }^2\\ \le {\parallel {\Lambda }_n^{i-1}{u}_n-p\parallel }^2+{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2\\ \le {\parallel u_n-p\parallel }^2+{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2\\ \le {\parallel x_n-p\parallel }^2+{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2\end{array}$$

(3.19)

for $i\in \{1,2,\dots ,N\}$ and $k\in \{1,2,\dots ,M\}$. Combining (3.5), (3.15), (3.18), and (3.19), we get

$$\begin{array}{rcl}{\parallel y_n-p\parallel }^2& \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel t_n-p\parallel }^2-\frac{{\beta }_n}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel t_n-p\parallel }^2\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){(\parallel v_n-p\parallel +{\lambda }_n{\alpha }_n\parallel p\parallel )}^2\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){(\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2\\ =& {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel v_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )]\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel v_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel {\Lambda }_n^i{u}_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel u_n-p\parallel }^2+{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2]\\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel {\Delta }_n^k{x}_n-p\parallel }^2+{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2]\\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel x_n-p\parallel }^2+r_{k,n}(r_{k,n}-2{\mu }_k){\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2\\ +{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2]+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ =& {\parallel x_n-p\parallel }^2+(1-{\beta }_n)[r_{k,n}(r_{k,n}-2{\mu }_k){\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2\\ +{\lambda }_{i,n}({\lambda }_{i,n}-2{\eta }_i){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2]\\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ),\end{array}$$

(3.20)

which immediately leads to

$$\begin{array}{c}(1-{\beta }_n)[r_{k,n}(2{\mu }_k-r_{k,n}){\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2+{\lambda }_{i,n}(2{\eta }_i-{\lambda }_{i,n}){\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2]\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel y_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\hfill \\ \le \parallel x_n-y_n\parallel (\parallel x_n-p\parallel +\parallel y_n-p\parallel )+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ).\hfill \end{array}$$

Since $\parallel x_n-y_n\parallel \to 0$, ${\alpha }_n\to 0$, $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, $\{{\lambda }_{i,n}\}\subset [a_i,b_i]\subset (0,2{\eta }_i)$, $\{r_{k,n}\}\subset [c_k,d_k]\subset (0,2{\mu }_k)$, $i\in \{1,2,\dots ,N\}$, $k\in \{1,2,\dots ,M\}$, and $\{v_n\}$, $\{x_n\}$, $\{y_n\}$ are bounded sequences, we have

$$\underset{n\to \mathrm{\infty }}{lim}\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel =0\text{and}\underset{n\to \mathrm{\infty }}{lim}\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel =0$$

(3.21)

for all $k\in \{1,2,\dots ,M\}$ and $i\in \{1,2,\dots ,N\}$.

Furthermore, by Proposition 2.2(ii) and Lemma 2.2(a) we have

$$\begin{array}{c}{\parallel {\Delta }_n^k{x}_n-p\parallel }^2\hfill \\ ={\parallel T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k)p\parallel }^2\hfill \\ \le 〈(I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-(I-r_{k,n}{A}_k)p,{\Delta }_n^k{x}_n-p〉\hfill \\ =\frac{1}{2}({\parallel (I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-(I-r_{k,n}{A}_k)p\parallel }^2+{\parallel {\Delta }_n^k{x}_n-p\parallel }^2\hfill \\ -{\parallel (I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n-(I-r_{k,n}{A}_k)p-({\Delta }_n^k{x}_n-p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel {\Delta }_n^{k-1}{x}_n-p\parallel }^2+{\parallel {\Delta }_n^k{x}_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n-r_{k,n}(A_k{\Delta }_n^{k-1}{x}_n-A_{k}p)\parallel }^2),\hfill \end{array}$$

which implies that

$$\begin{array}{c}{\parallel {\Delta }_n^k{x}_n-p\parallel }^2\hfill \\ \le {\parallel {\Delta }_n^{k-1}{x}_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n-r_{k,n}(A_k{\Delta }_n^{k-1}{x}_n-A_{k}p)\parallel }^2\hfill \\ ={\parallel {\Delta }_n^{k-1}{x}_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2-r_{k,n}^2{\parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel }^2\hfill \\ +2r_{k,n}〈{\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n,A_k{\Delta }_n^{k-1}{x}_n-A_{k}p〉\hfill \\ \le {\parallel {\Delta }_n^{k-1}{x}_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2+2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel \hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2\hfill \\ +2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel .\hfill \end{array}$$

(3.22)

By Lemma 2.2(a) and Lemma 2.10, we obtain

$$\begin{array}{c}{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2\hfill \\ ={\parallel J_{R_i,{\lambda }_{i,n}}(I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-J_{R_i,{\lambda }_{i,n}}(I-{\lambda }_{i,n}{B}_i)p\parallel }^2\hfill \\ \le 〈(I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-(I-{\lambda }_{i,n}{B}_i)p,{\Lambda }_n^i{u}_n-p〉\hfill \\ =\frac{1}{2}({\parallel (I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-(I-{\lambda }_{i,n}{B}_i)p\parallel }^2+{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2\hfill \\ -{\parallel (I-{\lambda }_{i,n}{B}_i){\Lambda }_n^{i-1}{u}_n-(I-{\lambda }_{i,n}{B}_i)p-({\Lambda }_n^i{u}_n-p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel {\Lambda }_n^{i-1}{u}_n-p\parallel }^2+{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n-{\lambda }_{i,n}(B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel u_n-p\parallel }^2+{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n-{\lambda }_{i,n}(B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel x_n-p\parallel }^2+{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n-{\lambda }_{i,n}(B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p)\parallel }^2),\hfill \end{array}$$

which immediately leads to

$$\begin{array}{c}{\parallel {\Lambda }_n^i{u}_n-p\parallel }^2\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n-{\lambda }_{i,n}(B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p)\parallel }^2\hfill \\ ={\parallel x_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^k{u}_n\parallel }^2-{\lambda }_{i,n}^2{\parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel }^2\hfill \\ +2{\lambda }_{i,n}〈{\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n,B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p〉\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel }^2+2{\lambda }_{i,n}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel \parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel .\hfill \end{array}$$

(3.23)

Combining (3.20) and (3.23) we conclude that

$$\begin{array}{rcl}{\parallel y_n-p\parallel }^2& \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel v_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel {\Lambda }_n^i{u}_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel x_n-p\parallel }^2-{\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel }^2\\ +2{\lambda }_{i,n}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel \parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel ]\\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\parallel x_n-p\parallel }^2-(1-{\beta }_n){\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel }^2\\ +2{\lambda }_{i,n}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel \parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ),\end{array}$$

which yields

$$\begin{array}{c}(1-{\beta }_n){\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel }^2\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel y_n-p\parallel }^2+2{\lambda }_{i,n}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel \parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel \hfill \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\hfill \\ \le \parallel x_n-y_n\parallel (\parallel x_n-p\parallel +\parallel y_n-p\parallel )+2{\lambda }_{i,n}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel \parallel B_i{\Lambda }_n^{i-1}{u}_n-B_{i}p\parallel \hfill \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ).\hfill \end{array}$$

Since $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, $\{{\lambda }_{i,n}\}\subset [a_i,b_i]\subset (0,2{\eta }_i)$, $i=1,2,\dots ,N$, and $\{u_n\}$, $\{v_n\}$, $\{x_n\}$ and $\{y_n\}$ are bounded sequences, we deduce from (3.17), (3.21), and ${\alpha }_n\to 0$ that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel {\Lambda }_n^{i-1}{u}_n-{\Lambda }_n^i{u}_n\parallel =0,\mathrm{\forall }i\in \{1,2,\dots ,N\}.$$

(3.24)

Also, combining (3.3), (3.20), and (3.22) we deduce that

$$\begin{array}{rcl}{\parallel y_n-p\parallel }^2& \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel v_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel u_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel {\Delta }_n^k{x}_n-p\parallel }^2+{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel x_n-p\parallel }^2-{\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2\\ +2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel ]\\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\\ \le & {\parallel x_n-p\parallel }^2-(1-{\beta }_n){\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2\\ +2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ),\end{array}$$

which yields

$$\begin{array}{c}(1-{\beta }_n){\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel }^2\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel y_n-p\parallel }^2+2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel \hfill \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )\hfill \\ \le \parallel x_n-y_n\parallel (\parallel x_n-p\parallel +\parallel y_n-p\parallel )+2r_{k,n}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel \parallel A_k{\Delta }_n^{k-1}{x}_n-A_{k}p\parallel \hfill \\ +{\alpha }_{n}b\parallel p\parallel (2\parallel v_n-p\parallel +{\alpha }_{n}b\parallel p\parallel ).\hfill \end{array}$$

Since $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, $\{r_{k,n}\}\subset [c_k,d_k]\subset (0,2{\mu }_k)$ for $k=1,2,\dots ,M$, and $\{v_n\}$, $\{x_n\}$, $\{y_n\}$ are bounded sequences, we deduce from (3.17), (3.21), and ${\alpha }_n\to 0$ that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel {\Delta }_n^{k-1}{x}_n-{\Delta }_n^k{x}_n\parallel =0,\mathrm{\forall }k\in \{1,2,\dots ,M\}.$$

(3.25)

Hence from (3.24) and (3.25) we get

$$\begin{array}{rl}\parallel x_n-u_n\parallel & =\parallel {\Delta }_n^0{x}_n-{\Delta }_n^M{x}_n\parallel \\ \le \parallel {\Delta }_n^0{x}_n-{\Delta }_n^1{x}_n\parallel +\parallel {\Delta }_n^1{x}_n-{\Delta }_n^2{x}_n\parallel +\cdots +\parallel {\Delta }_n^{M-1}{x}_n-{\Delta }_n^M{x}_n\parallel \\ \to 0\text{as }n\to \mathrm{\infty }\end{array}$$

(3.26)

and

$$\begin{array}{rl}\parallel u_n-v_n\parallel & =\parallel {\Lambda }_n^0{u}_n-{\Lambda }_n^N{u}_n\parallel \\ \le \parallel {\Lambda }_n^0{u}_n-{\Lambda }_n^1{u}_n\parallel +\parallel {\Lambda }_n^1{u}_n-{\Lambda }_n^2{u}_n\parallel +\cdots +\parallel {\Lambda }_n^{N-1}{u}_n-{\Lambda }_n^N{u}_n\parallel \\ \to 0\text{as }n\to \mathrm{\infty },\end{array}$$

(3.27)

respectively. Thus, from (3.26) and (3.27) we obtain

$$\begin{array}{rl}\parallel x_n-v_n\parallel & \le \parallel x_n-u_n\parallel +\parallel u_n-v_n\parallel \\ \to 0\text{as }n\to \mathrm{\infty }.\end{array}$$

(3.28)

On the other hand, note that $\Gamma =VI(C,\mathrm{\nabla }f)$. Then, utilizing Lemma 2.1 and the $\frac{1}{L}$-inverse strong monotonicity of ∇f, we deduce from (2.1) that

$$\begin{array}{rcl}{\parallel t_n-p\parallel }^2& \le & {\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel }^2\\ =& {\parallel v_n-p-{\lambda }_n(\mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p))-{\lambda }_n{\alpha }_n{v}_n\parallel }^2\\ \le & {\parallel v_n-p-{\lambda }_n(\mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p))\parallel }^2\\ -2{\lambda }_n{\alpha }_n〈v_n,(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p〉\\ \le & {\parallel v_n-p\parallel }^2+{\lambda }_n({\lambda }_n-\frac{2}{L}){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\\ +2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel .\end{array}$$

(3.29)

Combining (3.4), (3.20), and (3.29) we obtain

$$\begin{array}{rcl}{\parallel y_n-p\parallel }^2& \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel t_n-p\parallel }^2\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel v_n-p\parallel }^2+{\lambda }_n({\lambda }_n-\frac{2}{L}){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\\ +2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel ]\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel x_n-p\parallel }^2+{\lambda }_n({\lambda }_n-\frac{2}{L}){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\\ +2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel ]\\ \le & {\parallel x_n-p\parallel }^2+(1-{\beta }_n){\lambda }_n({\lambda }_n-\frac{2}{L}){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\\ +2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel ,\end{array}$$

which, together with $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$ and $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, leads to

$$\begin{array}{c}(1-d)a(\frac{2}{L}-b){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\hfill \\ \le (1-{\beta }_n){\lambda }_n(\frac{2}{L}-{\lambda }_n){\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel }^2\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel y_n-p\parallel }^2+2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel \hfill \\ \le \parallel x_n-y_n\parallel (\parallel x_n-p\parallel +\parallel y_n-p\parallel )+2{\alpha }_{n}b\parallel v_n\parallel \parallel v_n-p-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel .\hfill \end{array}$$

Since $\{v_n\}$, $\{x_n\}$, and $\{y_n\}$ are bounded sequences, we deduce from (3.17) and ${\alpha }_n\to 0$ that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel \mathrm{\nabla }f(v_n)-\mathrm{\nabla }f(p)\parallel =0.$$

So, it is clear that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel \mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p)\parallel =0.$$

(3.30)

Again, utilizing Proposition 2.1(iii), from $t_n=P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n$ and $p=P_C(I-{\lambda }_n\mathrm{\nabla }f)p$, we get

$$\begin{array}{c}{\parallel t_n-p\parallel }^2\hfill \\ ={\parallel P_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-P_C(I-{\lambda }_n\mathrm{\nabla }f)p\parallel }^2\hfill \\ \le 〈(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p,t_n-p〉\hfill \\ =\frac{1}{2}({\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel }^2+{\parallel t_n-p\parallel }^2\hfill \\ -{\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p-(t_n-p)\parallel }^2)\hfill \\ =\frac{1}{2}({\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})p-{\lambda }_n{\alpha }_{n}p\parallel }^2+{\parallel t_n-p\parallel }^2\hfill \\ -{\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p-(t_n-p)\parallel }^2)\hfill \\ =\frac{1}{2}({\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})p\parallel }^2\hfill \\ -2{\lambda }_n{\alpha }_n〈p,(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p〉\hfill \\ +{\parallel t_n-p\parallel }^2-{\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p-(t_n-p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel v_n-p\parallel }^2-2{\lambda }_n{\alpha }_n〈p,(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p〉+{\parallel t_n-p\parallel }^2\hfill \\ -{\parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p-(t_n-p)\parallel }^2)\hfill \\ \le \frac{1}{2}({\parallel v_n-p\parallel }^2+2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel +{\parallel t_n-p\parallel }^2\hfill \\ -{\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2),\hfill \end{array}$$

which immediately leads to

$$\begin{array}{rcl}{\parallel t_n-p\parallel }^2& \le & {\parallel v_n-p\parallel }^2+2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \\ -{\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2.\end{array}$$

(3.31)

Combining (3.4), (3.20), and (3.31) we obtain

$$\begin{array}{rcl}{\parallel y_n-p\parallel }^2& \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n){\parallel t_n-p\parallel }^2\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel v_n-p\parallel }^2\\ +2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \\ -{\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2]\\ \le & {\beta }_n{\parallel x_n-p\parallel }^2+(1-{\beta }_n)[{\parallel x_n-p\parallel }^2\\ +2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \\ -{\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2]\\ \le & {\parallel x_n-p\parallel }^2+2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \\ -(1-{\beta }_n){\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2,\end{array}$$

which immediately yields

$$\begin{array}{c}(1-d){\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2\hfill \\ \le (1-{\beta }_n){\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel }^2\hfill \\ \le {\parallel x_n-p\parallel }^2-{\parallel y_n-p\parallel }^2+2{\lambda }_n{\alpha }_n\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel \hfill \\ \le \parallel x_n-y_n\parallel (\parallel x_n-p\parallel +\parallel y_n-p\parallel )+2{\alpha }_{n}b\parallel p\parallel \parallel (I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n-(I-{\lambda }_n\mathrm{\nabla }f)p\parallel .\hfill \end{array}$$

Since $\{v_n\}$, $\{x_n\}$, and $\{y_n\}$ are bounded sequences, we deduce from (3.17) and ${\alpha }_n\to 0$ that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel =0.$$

(3.32)

Observe that

$$\parallel v_n-t_n\parallel \le \parallel v_n-t_n-{\lambda }_n(\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p))\parallel +{\lambda }_n\parallel \mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-\mathrm{\nabla }f(p)\parallel .$$

Thus, from (3.30) and (3.32) we have

$$\underset{n\to \mathrm{\infty }}{lim}\parallel v_n-t_n\parallel =0.$$

(3.33)

Taking into account that $\parallel x_n-t_n\parallel \le \parallel x_n-v_n\parallel +\parallel v_n-t_n\parallel$, from (3.28) and (3.33) we get

$$\underset{n\to \mathrm{\infty }}{lim}\parallel x_n-t_n\parallel =0.$$

(3.34)

Utilizing the relation $y_n-x_n={\gamma }_n(t_n-x_n)+{\sigma }_n(T{t}_n-x_n)$, we have

$$\begin{array}{rl}\parallel {\sigma }_n(T{t}_n-t_n)\parallel & =\parallel {\sigma }_n(T{t}_n-x_n)-{\sigma }_n(t_n-x_n)\parallel \\ =\parallel y_n-x_n-{\gamma }_n(t_n-x_n)-{\sigma }_n(t_n-x_n)\parallel \\ =\parallel y_n-x_n-(1-{\beta }_n)(t_n-x_n)\parallel \\ \le \parallel y_n-x_n\parallel +(1-{\beta }_n)\parallel t_n-x_n\parallel \\ \le \parallel y_n-x_n\parallel +\parallel t_n-x_n\parallel ,\end{array}$$

which, together with (3.17) and (3.34), implies that

$$\underset{n\to \mathrm{\infty }}{lim}\parallel {\sigma }_n(T{t}_n-t_n)\parallel =0.$$

Since ${lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\sigma }_n>0$, we obtain

$$\underset{n\to \mathrm{\infty }}{lim}\parallel t_n-T{t}_n\parallel =0.$$

(3.35)

Step 4. We prove that ${\omega }_w(x_n)\subset \Omega$.

Indeed, since H is reflexive and $\{x_n\}$ is bounded, there exists at least a weak convergence subsequence of $\{x_n\}$. Hence we know that ${\omega }_w(x_n)\ne \mathrm{\varnothing }$. Now, take an arbitrary $w\in {\omega }_w(x_n)$. Then there exists a subsequence $\{x_{n_i}\}$ of $\{x_n\}$ such that $x_{n_i}\rightharpoonup w$. From (3.24)-(3.26), (3.28), and (3.34) we have that $u_{n_i}\rightharpoonup w$, $v_{n_i}\rightharpoonup w$, $t_{n_i}\rightharpoonup w$, ${\Lambda }_{n_i}^m{u}_{n_i}\rightharpoonup w$ and ${\Delta }_{n_i}^k{x}_{n_i}\rightharpoonup w$, where $m\in \{1,2,\dots ,N\}$ and $k\in \{1,2,\dots ,M\}$. Utilizing Lemma 2.3(ii), we deduce from $t_{n_i}\rightharpoonup w$ and (3.35) that $w\in Fix(T)$. Next, we prove that $w\in {\bigcap }_{m=1}^N\mathrm{I}(B_m,R_m)$. As a matter of fact, since $B_m$ is ${\eta }_m$-inverse-strongly monotone, $B_m$ is a monotone and Lipschitz-continuous mapping. It follows from Lemma 2.13 that $R_m+B_m$ is maximal monotone. Let $(v,g)\in G(R_m+B_m)$, i.e., $g-B_{m}v\in R_{m}v$. Again, since ${\Lambda }_n^m{u}_n=J_{R_m,{\lambda }_{m,n}}(I-{\lambda }_{m,n}{B}_m){\Lambda }_n^{m-1}{u}_n$, $n\ge 1$, $m\in \{1,2,\dots ,N\}$, we have

$${\Lambda }_n^{m-1}{u}_n-{\lambda }_{m,n}{B}_m{\Lambda }_n^{m-1}{u}_n\in (I+{\lambda }_{m,n}{R}_m){\Lambda }_n^m{u}_n,$$

that is,

$$\frac{1}{{\lambda }_{m,n}}({\Lambda }_n^{m-1}{u}_n-{\Lambda }_n^m{u}_n-{\lambda }_{m,n}{B}_m{\Lambda }_n^{m-1}{u}_n)\in R_m{\Lambda }_n^m{u}_n.$$

In terms of the monotonicity of $R_m$, we get

$$〈v-{\Lambda }_n^m{u}_n,g-B_{m}v-\frac{1}{{\lambda }_{m,n}}({\Lambda }_n^{m-1}{u}_n-{\Lambda }_n^m{u}_n-{\lambda }_{m,n}{B}_m{\Lambda }_n^{m-1}{u}_n)〉\ge 0$$

and hence

$$\begin{array}{c}〈v-{\Lambda }_n^m{u}_n,g〉\hfill \\ \ge 〈v-{\Lambda }_n^m{u}_n,B_{m}v+\frac{1}{{\lambda }_{m,n}}({\Lambda }_n^{m-1}{u}_n-{\Lambda }_n^m{u}_n-{\lambda }_{m,n}{B}_m{\Lambda }_n^{m-1}{u}_n)〉\hfill \\ =〈v-{\Lambda }_n^m{u}_n,B_{m}v-B_m{\Lambda }_n^m{u}_n+B_m{\Lambda }_n^m{u}_n-B_m{\Lambda }_n^{m-1}{u}_n+\frac{1}{{\lambda }_{m,n}}({\Lambda }_n^{m-1}{u}_n-{\Lambda }_n^m{u}_n)〉\hfill \\ \ge 〈v-{\Lambda }_n^m{u}_n,B_m{\Lambda }_n^m{u}_n-B_m{\Lambda }_n^{m-1}{u}_n〉+〈v-{\Lambda }_n^m{u}_n,\frac{1}{{\lambda }_{m,n}}({\Lambda }_n^{m-1}{u}_n-{\Lambda }_n^m{u}_n)〉.\hfill \end{array}$$

In particular,

$$\begin{array}{rcl}〈v-{\Lambda }_{n_i}^m{u}_{n_i},g〉& \ge & 〈v-{\Lambda }_{n_i}^m{u}_{n_i},B_m{\Lambda }_{n_i}^m{u}_{n_i}-B_m{\Lambda }_{n_i}^{m-1}{u}_{n_i}〉\\ +〈v-{\Lambda }_{n_i}^m{u}_{n_i},\frac{1}{{\lambda }_{m,n_i}}({\Lambda }_{n_i}^{m-1}{u}_{n_i}-{\Lambda }_{n_i}^m{u}_{n_i})〉.\end{array}$$

Since $\parallel {\Lambda }_n^m{u}_n-{\Lambda }_n^{m-1}{u}_n\parallel \to 0$ (due to (3.24)) and $\parallel B_m{\Lambda }_n^m{u}_n-B_m{\Lambda }_n^{m-1}{u}_n\parallel \to 0$ (due to the Lipschitz-continuity of $B_m$), we conclude from ${\Lambda }_{n_i}^m{u}_{n_i}\rightharpoonup w$ and $\{{\lambda }_{i,n}\}\subset [a_i,b_i]\subset (0,2{\eta }_i)$ that

$$\underset{i\to \mathrm{\infty }}{lim}〈v-{\Lambda }_{n_i}^m{u}_{n_i},g〉=〈v-w,g〉\ge 0.$$

It follows from the maximal monotonicity of $B_m+R_m$ that $0\in (R_m+B_m)w$, i.e., $w\in \mathrm{I}(B_m,R_m)$. Therefore, $w\in {\bigcap }_{m=1}^N\mathrm{I}(B_m,R_m)$. Next we prove that $w\in {\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)$. Since ${\Delta }_n^k{x}_n=T_{r_{k,n}}^{({\Theta }_k,{\phi }_k)}(I-r_{k,n}{A}_k){\Delta }_n^{k-1}{x}_n$, $n\ge 1$, $k\in \{1,2,\dots ,M\}$, we have

$$\begin{array}{r}{\Theta }_k({\Delta }_n^k{x}_n,y)+{\phi }_k(y)-{\phi }_k\left({\Delta }_n^k{x}_n\right)+〈A_k{\Delta }_n^{k-1}{x}_n,y-{\Delta }_n^k{x}_n〉\\ +\frac{1}{r_{k,n}}〈y-{\Delta }_n^k{x}_n,{\Delta }_n^k{x}_n-{\Delta }_n^{k-1}{x}_n〉\ge 0.\end{array}$$

By (A2), we have

$$\begin{array}{c}{\phi }_k(y)-{\phi }_k\left({\Delta }_n^k{x}_n\right)+〈A_k{\Delta }_n^{k-1}{x}_n,y-{\Delta }_n^k{x}_n〉+\frac{1}{r_{k,n}}〈y-{\Delta }_n^k{x}_n,{\Delta }_n^k{x}_n-{\Delta }_n^{k-1}{x}_n〉\hfill \\ \ge {\Theta }_k(y,{\Delta }_n^k{x}_n).\hfill \end{array}$$

Let $z_t=ty+(1-t)w$ for all $t\in (0,1]$ and $y\in C$. This implies that $z_t\in C$. Then we have

$$\begin{array}{c}〈z_t-{\Delta }_n^k{x}_n,A_k{z}_t〉\hfill \\ \ge {\phi }_k\left({\Delta }_n^k{x}_n\right)-{\phi }_k(z_t)+〈z_t-{\Delta }_n^k{x}_n,A_k{z}_t〉-〈z_t-{\Delta }_n^k{x}_n,A_k{\Delta }_n^{k-1}{x}_n〉\hfill \\ -〈z_t-{\Delta }_n^k{x}_n,\frac{{\Delta }_n^k{x}_n-{\Delta }_n^{k-1}{x}_n}{r_{k,n}}〉+{\Theta }_k(z_t,{\Delta }_n^k{x}_n)\hfill \\ ={\phi }_k\left({\Delta }_n^k{x}_n\right)-{\phi }_k(z_t)+〈z_t-{\Delta }_n^k{x}_n,A_k{z}_t-A_k{\Delta }_n^k{x}_n〉\hfill \\ +〈z_t-{\Delta }_n^k{x}_n,A_k{\Delta }_n^k{x}_n-A_k{\Delta }_n^{k-1}{x}_n〉\hfill \\ -〈z_t-{\Delta }_n^k{x}_n,\frac{{\Delta }_n^k{x}_n-{\Delta }_n^{k-1}{x}_n}{r_{k,n}}〉+{\Theta }_k(z_t,{\Delta }_n^k{x}_n).\hfill \end{array}$$

(3.36)

By (3.25), we have $\parallel A_k{\Delta }_n^k{x}_n-A_k{\Delta }_n^{k-1}{x}_n\parallel \to 0$ as $n\to \mathrm{\infty }$. Furthermore, by the monotonicity of $A_k$, we obtain $〈z_t-{\Delta }_n^k{x}_n,A_k{z}_t-A_k{\Delta }_n^k{x}_n〉\ge 0$. Then by (A4) we obtain

$$〈z_t-w,A_k{z}_t〉\ge {\phi }_k(w)-{\phi }_k(z_t)+{\Theta }_k(z_t,w).$$

(3.37)

Utilizing (A1), (A4), and (3.37), we obtain

$$\begin{array}{rl}0& ={\Theta }_k(z_t,z_t)+{\phi }_k(z_t)-{\phi }_k(z_t)\\ \le t{\Theta }_k(z_t,y)+(1-t){\Theta }_k(z_t,w)+t{\phi }_k(y)+(1-t){\phi }_k(w)-{\phi }_k(z_t)\\ \le t[{\Theta }_k(z_t,y)+{\phi }_k(y)-{\phi }_k(z_t)]+(1-t)〈z_t-w,A_k{z}_t〉\\ =t[{\Theta }_k(z_t,y)+{\phi }_k(y)-{\phi }_k(z_t)]+(1-t)t〈y-w,A_k{z}_t〉,\end{array}$$

and hence

$$0\le {\Theta }_k(z_t,y)+{\phi }_k(y)-{\phi }_k(z_t)+(1-t)〈y-w,A_k{z}_t〉.$$

Letting $t\to 0$, we have, for each $y\in C$,

$$0\le {\Theta }_k(w,y)+{\phi }_k(y)-{\phi }_k(w)+〈y-w,A_{k}w〉.$$

This implies that $w\in GMEP({\Theta }_k,{\phi }_k,A_k)$ and hence $w\in {\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)$. Thus, $w\in \Omega ={\bigcap }_{n=1}^{\mathrm{\infty }}Fix(T_n)\cap {\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)\cap {\bigcap }_{m=1}^N\mathrm{I}(B_m,R_m)$.

Furthermore, let us show that $w\in \Gamma$. In fact, define

$$\tilde{T}v=\{\begin{array}{ll}\mathrm{\nabla }f(v)+N_{C}v,& \text{if }v\in C,\\ \mathrm{\varnothing },& \text{if }v\notin C,\end{array}$$

where $N_{C}v=\{u\in H:〈v-x,u〉\ge 0,\mathrm{\forall }x\in C\}$. Then $\tilde{T}$ is maximal monotone and $0\in \tilde{T}v$ if and only if $v\in VI(C,\mathrm{\nabla }f)$; see [29]. Let $(v,\tilde{v})\in G(\tilde{T})$. Then we have $\tilde{v}\in \tilde{T}v=\mathrm{\nabla }f(v)+N_{C}v$, and hence $\tilde{v}-\mathrm{\nabla }f(v)\in N_{C}v$. So, we have $〈v-x,\tilde{v}-\mathrm{\nabla }f(v)〉\ge 0$ for all $x\in C$. On the other hand, from $t_n=P_C(v_n-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n}(v_n))$ and $v\in C$, we get $〈v_n-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)-t_n,t_n-v〉\ge 0$, and hence,

$$〈v-t_n,\frac{t_n-v_n}{{\lambda }_n}+\mathrm{\nabla }{f}_{{\alpha }_n}(v_n)〉\ge 0.$$

Therefore, from $\tilde{v}-\mathrm{\nabla }f(v)\in N_{C}v$ and $t_{n_i}\in C$, we have

$$\begin{array}{rcl}〈v-t_{n_i},\tilde{v}〉& \ge & 〈v-t_{n_i},\mathrm{\nabla }f(v)〉\\ \ge & 〈v-t_{n_i},\mathrm{\nabla }f(v)〉-〈v-t_{n_i},\frac{t_{n_i}-v_{n_i}}{{\lambda }_{n_i}}+\mathrm{\nabla }{f}_{{\alpha }_{n_i}}(v_{n_i})〉\\ =& 〈v-t_{n_i},\mathrm{\nabla }f(v)〉-〈v-t_{n_i},\frac{t_{n_i}-v_{n_i}}{{\lambda }_{n_i}}+\mathrm{\nabla }f(v_{n_i})〉-{\alpha }_{n_i}〈v-t_{n_i},v_{n_i}〉\\ =& 〈v-t_{n_i},\mathrm{\nabla }f(v)-\mathrm{\nabla }f(t_{n_i})〉+〈v-t_{n_i},\mathrm{\nabla }f(t_{n_i})-\mathrm{\nabla }f(v_{n_i})〉\\ -〈v-t_{n_i},\frac{t_{n_i}-v_{n_i}}{{\lambda }_{n_i}}〉-{\alpha }_{n_i}〈v-t_{n_i},v_{n_i}〉\\ \ge & 〈v-t_{n_i},\mathrm{\nabla }f(t_{n_i})-\mathrm{\nabla }f(v_{n_i})〉-〈v-t_{n_i},\frac{t_{n_i}-v_{n_i}}{{\lambda }_{n_i}}〉-{\alpha }_{n_i}〈v-t_{n_i},v_{n_i}〉.\end{array}$$

Hence, it is easy to see that $〈v-w,\tilde{v}〉\ge 0$ as $i\to \mathrm{\infty }$. Since $\tilde{T}$ is maximal monotone, we have $w\in {\tilde{T}}^{-1}0$, and hence $w\in VI(C,\mathrm{\nabla }f)=\Gamma$. Consequently, $w\in {\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)\cap {\bigcap }_{i=1}^N\mathrm{I}(B_i,R_i)\cap Fix(T)\cap \Gamma =:\Omega$. This shows that ${\omega }_w(x_n)\subset \Omega$.

Step 5. We prove that $x_n\rightharpoonup x^{\ast }$ where $\{x^{\ast }\}=VI(\Omega ,\gamma S-\mu F)$.

Indeed, take an arbitrary $w\in {\omega }_w(x_n)$. Then there exists a subsequence $\{x_{n_i}\}$ of $\{x_n\}$ such that $x_{n_i}\rightharpoonup w$. Utilizing (3.16), we find that, for all $p\in \Omega$,

$$\begin{array}{c}{\parallel x_{n+1}-p\parallel }^2\hfill \\ \le (1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-\frac{{\beta }_n(1-{ϵ}_n\tau )}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉\hfill \\ \le {(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2+2{ϵ}_n{\delta }_n〈(\gamma Vp-\mu Fp),x_{n+1}-p〉\hfill \\ +2{ϵ}_n(1-{\delta }_n)〈(\gamma Sp-\mu Fp),x_{n+1}-p〉,\hfill \end{array}$$

which implies that

$$\begin{array}{c}〈(\mu F-\gamma S)p,x_n-p〉\hfill \\ \le 〈(\mu F-\gamma S)p,x_n-x_{n+1}〉+〈(\mu F-\gamma S)p,x_{n+1}-p〉\hfill \\ \le \parallel (\mu F-\gamma S)p\parallel \parallel x_n-x_{n+1}\parallel +\frac{{(\parallel x_n-p\parallel +{\alpha }_{n}b\parallel p\parallel )}^2-{\parallel x_{n+1}-p\parallel }^2}{2{ϵ}_n(1-{\delta }_n)}\hfill \\ +\frac{{\delta }_n}{1-{\delta }_n}〈(\gamma V-\mu F)p,x_{n+1}-p〉\hfill \\ \le \parallel (\mu F-\gamma S)p\parallel \parallel x_n-x_{n+1}\parallel \hfill \\ +\frac{(\parallel x_n-x_{n+1}\parallel +{\alpha }_{n}b\parallel p\parallel )(\parallel x_n-p\parallel +\parallel x_{n+1}-p\parallel +{\alpha }_{n}b\parallel p\parallel )}{2{ϵ}_n(1-{\delta }_n)}\hfill \\ +\frac{{\delta }_n}{1-{\delta }_n}\parallel (\gamma V-\mu F)p\parallel \parallel x_{n+1}-p\parallel .\hfill \end{array}$$

(3.38)

Since ${\alpha }_n\to 0$, $\frac{{\alpha }_n}{{\delta }_n}\to 0$, $\parallel x_n-x_{n+1}\parallel \to 0$, and

$$\underset{n\to \mathrm{\infty }}{lim}\frac{\parallel x_n-x_{n+1}\parallel +{\alpha }_{n}b\parallel p\parallel }{{ϵ}_n}=\underset{n\to \mathrm{\infty }}{lim}\frac{\parallel x_n-x_{n+1}\parallel +{\alpha }_{n}b\parallel p\parallel }{{\delta }_n}\cdot \frac{{\delta }_n}{{ϵ}_n}=0,$$

from (3.38) we conclude that

$$\begin{array}{rl}〈(\mu F-\gamma S)p,w-p〉& =\underset{i\to \mathrm{\infty }}{lim}〈(\mu F-\gamma S)p,x_{n_i}-p〉\\ \le \underset{n\to \mathrm{\infty }}{lim\hspace{0.17em}sup}〈(\mu F-\gamma S)p,x_n-p〉\\ \le 0,\mathrm{\forall }p\in \Omega ,\end{array}$$

that is,

$$〈(\mu F-\gamma S)p,w-p〉\le 0,\mathrm{\forall }p\in \Omega .$$

(3.39)

Since $\mu F-\gamma S$ is $(\mu \eta -\gamma )$-strongly monotone and $(\mu \kappa +\gamma )$-Lipschitz-continuous, by Minty’s lemma [39] we know that (3.39) is equivalent to the VIP

$$〈(\mu F-\gamma S)w,p-w〉\ge 0,\mathrm{\forall }p\in \Omega .$$

(3.40)

This shows that $w\in VI(\Omega ,\mu F-\gamma S)$. Taking into account $\{x^{\ast }\}=VI(\Omega ,\mu F-\gamma S)$, we know that $w=x^{\ast }$. Thus, ${\omega }_w(x_n)=\{x^{\ast }\}$; that is, $x_n\rightharpoonup x^{\ast }$.

Next we prove that ${lim}_{n\to \mathrm{\infty }}\parallel x_n-x^{\ast }\parallel =0$. As a matter of fact, utilizing (3.16) with $p=x^{\ast }$, we get

$$\begin{array}{c}{\parallel x_{n+1}-x^{\ast }\parallel }^2\hfill \\ \le (1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){(\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel )}^2-\frac{{\beta }_n(1-{ϵ}_n\tau )}{1-{\beta }_n}{\parallel y_n-x_n\parallel }^2\hfill \\ +2{ϵ}_n{\delta }_n〈(\gamma V{x}^{\ast }-\mu F{x}^{\ast }),x_{n+1}-x^{\ast }〉+2{ϵ}_n(1-{\delta }_n)〈(\gamma S{x}^{\ast }-\mu F{x}^{\ast }),x_{n+1}-x^{\ast }〉\hfill \\ \le (1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){(\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel )}^2+2{ϵ}_n{\delta }_n\parallel (\gamma V-\mu F)x^{\ast }\parallel \parallel x_{n+1}-x^{\ast }\parallel \hfill \\ +2{ϵ}_n(1-{\delta }_n)〈(\gamma S-\mu F)x^{\ast },x_{n+1}-x^{\ast }〉\hfill \\ =(1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau })[{\parallel x_n-x^{\ast }\parallel }^2+{\alpha }_{n}b\parallel x^{\ast }\parallel (2\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel )]\hfill \\ +2{ϵ}_n{\delta }_n\parallel (\gamma V-\mu F)x^{\ast }\parallel \parallel x_{n+1}-x^{\ast }\parallel +2{ϵ}_n(1-{\delta }_n)〈(\gamma S-\mu F)x^{\ast },x_{n+1}-x^{\ast }〉\hfill \\ \le (1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){\parallel x_n-x^{\ast }\parallel }^2+2{ϵ}_n{\delta }_n\parallel (\gamma V-\mu F)x^{\ast }\parallel \parallel x_{n+1}-x^{\ast }\parallel \hfill \\ +2{ϵ}_n(1-{\delta }_n)〈(\gamma S-\mu F)x^{\ast },x_{n+1}-x^{\ast }〉+{\alpha }_{n}b\parallel x^{\ast }\parallel (2\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel )\hfill \\ =(1-{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }){\parallel x_n-x^{\ast }\parallel }^2+{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }\cdot \frac{2\tau }{{\tau }^2-{\gamma }^2}[{\delta }_n\parallel (\gamma V-\mu F)x^{\ast }\parallel \parallel x_{n+1}-x^{\ast }\parallel \hfill \\ +(1-{\delta }_n)〈(\gamma S-\mu F)x^{\ast },x_{n+1}-x^{\ast }〉]+{\alpha }_{n}b\parallel x^{\ast }\parallel (2\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel ).\hfill \end{array}$$

(3.41)

Since ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n=\mathrm{\infty }$, and ${lim}_{n\to \mathrm{\infty }}〈(\gamma S-\mu F)x^{\ast },x^{\ast }-x_{n+1}〉=0$ (due to $x_n\rightharpoonup x^{\ast }$), we deduce that ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_{n}b\parallel x^{\ast }\parallel (2\parallel x_n-x^{\ast }\parallel +{\alpha }_{n}b\parallel x^{\ast }\parallel )<\mathrm{\infty }$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n\frac{{\tau }^2-{\gamma }^2}{\tau }=\mathrm{\infty }$, and

$$\underset{n\to \mathrm{\infty }}{lim}\frac{2\tau }{{\tau }^2-{\gamma }^2}[{\delta }_n\parallel (\gamma V-\mu F)x^{\ast }\parallel \parallel x_{n+1}-x^{\ast }\parallel +(1-{\delta }_n)〈(\gamma S-\mu F)x^{\ast },x_{n+1}-x^{\ast }〉]=0.$$

Therefore, applying Lemma 2.8 to (3.41) we infer that ${lim}_{n\to \mathrm{\infty }}\parallel x_n-x^{\ast }\parallel =0$. This completes the proof. □

In Theorem 3.1, putting $M=1$ and $N=2$, we obtain the following.

Corollary 3.1 Let C be a nonempty closed convex subset of a real Hilbert space H. Let $f:C\to \mathbf{R}$ be a convex functional with L-Lipschitz-continuous gradient ∇f. Let ${\Theta }_1$ be a bifunction from $C\times C$ to R satisfying (A1)-(A4), ${\phi }_1:C\to \mathbf{R}\cup \{+\mathrm{\infty }\}$ be a proper lower semicontinuous and convex function with restriction (B1) or (B2), and $A_1:H\to H$ be ${\mu }_1$-inverse-strongly monotone. Let $R_i:C\to 2^H$ be a maximal monotone mapping and $B_i:C\to H$ be ${\eta }_i$-inverse-strongly monotone, for $i=1,2$. Let $T:C\to C$ be a ξ-strictly pseudocontractive mapping, $S:H\to H$ be a nonexpansive mapping and $V:H\to H$ be a ρ-contraction with coefficient $\rho \in [0,1)$. Let $F:H\to H$ be κ-Lipschitzian and η-strongly monotone with positive constants $\kappa ,\eta >0$ such that $0\le \gamma <\tau$ and $0<\mu <\frac{2\eta }{{\kappa }^2}$ where $\tau =1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}$. Assume that $\Omega :=GMEP({\Theta }_1,{\phi }_1,A_1)\cap \mathrm{I}(B_2,R_2)\cap \mathrm{I}(B_1,R_1)\cap Fix(T)\cap \Gamma \ne \mathrm{\varnothing }$. Let $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$, $\{{\alpha }_n\}\subset (0,\mathrm{\infty })$ with ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$, $\{{ϵ}_n\},\{{\delta }_n\},\{{\beta }_n\},\{{\gamma }_n\},\{{\sigma }_n\}\subset (0,1)$ with ${\beta }_n+{\gamma }_n+{\sigma }_n=1$, and $\{r_{1,n}\}\subset [c_1,d_1]\subset (0,2{\mu }_1)$, $\{{\lambda }_{i,n}\}\subset [a_i,b_i]\subset (0,2{\eta }_i)$ for $i=1,2$. For arbitrarily given $x_0\in H$, let $\{x_n\}$ be a sequence generated by

$$\{\begin{array}{l}\Theta (u_n,y)+\phi (y)-\phi (u_n)+〈A{x}_n,y-u_n〉+\frac{1}{r_n}〈y-u_n,u_n-x_n〉\ge 0,\mathrm{\forall }y\in C,\\ v_n=J_{R_2,{\lambda }_{2,n}}(I-{\lambda }_{2,n}{B}_2)J_{R_1,{\lambda }_{1,n}}(I-{\lambda }_{1,n}{B}_1)u_n,\\ y_n={\beta }_n{x}_n+{\gamma }_n{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n+{\sigma }_{n}T{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n,\\ x_{n+1}={ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(I-{ϵ}_n\mu F)y_n,\mathrm{\forall }n\ge 0,\end{array}$$

(3.42)

where $\mathrm{\nabla }{f}_{{\alpha }_n}={\alpha }_{n}I+\mathrm{\nabla }f$ for all $n\ge 0$. Suppose that

(C1) ${lim}_{n\to \mathrm{\infty }}{ϵ}_n=0$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n=\mathrm{\infty }$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|=0$;

(C2) ${lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}\frac{{\delta }_n}{{ϵ}_n}<\mathrm{\infty }$, ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|=0$;

(C3) ${lim}_{n\to \mathrm{\infty }}\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C4) ${lim}_{n\to \mathrm{\infty }}\frac{|r_{1,n}-r_{1,n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_{i,n}-{\lambda }_{i,n-1}|}{{ϵ}_n{\delta }_n}=0$ for $i=1,2$;

(C5) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n-{\lambda }_{n-1}|}{{ϵ}_n{\delta }_n}=0$, ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n{\alpha }_n-{\lambda }_{n-1}{\alpha }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$;

(C6) $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, ${lim}_{n\to \mathrm{\infty }}\frac{{\alpha }_n}{{\delta }_n}=0$ and ${lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\sigma }_n>0$.

Then we have:

• (i) ${lim}_{n\to \mathrm{\infty }}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0$;

• (ii) ${\omega }_w(x_n)\subset \Omega$;

• (iii) $\{x_n\}$ converges strongly to a minimizer $x^{\ast }$ of the CMP (1.2), which is a unique solution $x^{\ast }$ in Ω to the HVIP

  $$〈(\mu F-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0,\mathrm{\forall }p\in \Omega .$$

In Theorem 3.1, putting $M=N=1$, we obtain the following.

Corollary 3.2 Let C be a nonempty closed convex subset of a real Hilbert space H. Let $f:C\to \mathbf{R}$ be a convex functional with L-Lipschitz-continuous gradient ∇f. Let ${\Theta }_1$ be a bifunction from $C\times C$ to R satisfying (A1)-(A4), ${\phi }_1:C\to \mathbf{R}\cup \{+\mathrm{\infty }\}$ be a proper lower semicontinuous and convex function with restriction (B1) or (B2), and $A_1:H\to H$ be ${\mu }_1$-inverse-strongly monotone. Let $R_1:C\to 2^H$ be a maximal monotone mapping and $B_1:C\to H$ be ${\eta }_1$-inverse-strongly monotone. Let $T:C\to C$ be a ξ-strictly pseudocontractive mapping, $S:H\to H$ be a nonexpansive mapping and $V:H\to H$ be a ρ-contraction with coefficient $\rho \in [0,1)$. Let $F:H\to H$ be κ-Lipschitzian and η-strongly monotone with positive constants $\kappa ,\eta >0$ such that $0\le \gamma <\tau$ and $0<\mu <\frac{2\eta }{{\kappa }^2}$ where $\tau =1-\sqrt{1-\mu (2\eta -\mu {\kappa }^2)}$. Assume that $\Omega :=GMEP({\Theta }_1,{\phi }_1,A_1)\cap \mathrm{I}(B_1,R_1)\cap Fix(T)\cap \Gamma \ne \mathrm{\varnothing }$. Let $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$, $\{{\alpha }_n\}\subset (0,\mathrm{\infty })$ with ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$, $\{{ϵ}_n\},\{{\delta }_n\},\{{\beta }_n\},\{{\gamma }_n\},\{{\sigma }_n\}\subset (0,1)$ with ${\beta }_n+{\gamma }_n+{\sigma }_n=1$, and $\{r_{1,n}\}\subset [c_1,d_1]\subset (0,2{\mu }_1)$, $\{{\lambda }_{1,n}\}\subset [a_1,b_1]\subset (0,2{\eta }_1)$. For arbitrarily given $x_0\in H$, let $\{x_n\}$ be a sequence generated by

$$\{\begin{array}{l}\Theta (u_n,y)+\phi (y)-\phi (u_n)+〈A{x}_n,y-u_n〉+\frac{1}{r_n}〈y-u_n,u_n-x_n〉\ge 0,\mathrm{\forall }y\in C,\\ v_n=J_{R_1,{\lambda }_{1,n}}(I-{\lambda }_{1,n}{B}_1)u_n,\\ y_n={\beta }_n{x}_n+{\gamma }_n{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n+{\sigma }_{n}T{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n,\\ x_{n+1}={ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(I-{ϵ}_n\mu F)y_n,\mathrm{\forall }n\ge 0,\end{array}$$

(3.43)

where $\mathrm{\nabla }{f}_{{\alpha }_n}={\alpha }_{n}I+\mathrm{\nabla }f$ for all $n\ge 0$. Suppose that

(C1) ${lim}_{n\to \mathrm{\infty }}{ϵ}_n=0$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n=\mathrm{\infty }$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|=0$;

(C2) ${lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}\frac{{\delta }_n}{{ϵ}_n}<\mathrm{\infty }$, ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|=0$;

(C3) ${lim}_{n\to \mathrm{\infty }}\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C4) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_{1,n}-{\lambda }_{1,n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|r_{1,n}-r_{1,n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C5) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n-{\lambda }_{n-1}|}{{ϵ}_n{\delta }_n}=0$, ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n{\alpha }_n-{\lambda }_{n-1}{\alpha }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$;

(C6) $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, ${lim}_{n\to \mathrm{\infty }}\frac{{\alpha }_n}{{\delta }_n}=0$ and ${lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\sigma }_n>0$.

Then we have:

• (i) ${lim}_{n\to \mathrm{\infty }}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0$;

• (ii) ${\omega }_w(x_n)\subset \Omega$;

• (iii) $\{x_n\}$ converges strongly to a minimizer $x^{\ast }$ of the CMP (1.2), which is a unique solution $x^{\ast }$ in Ω to the HVIP

  $$〈(\mu F-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0,\mathrm{\forall }p\in \Omega .$$

In Theorem 3.1, putting $M=N=1$, $\mu =2$, and $F\equiv \frac{1}{2}I$ where I is the identity mapping on H, we obtain the following.

Corollary 3.3 Let C be a nonempty closed convex subset of a real Hilbert space H. Let $f:C\to \mathbf{R}$ be a convex functional with L-Lipschitz-continuous gradient ∇f. Let ${\Theta }_1$ be a bifunction from $C\times C$ to R satisfying (A1)-(A4), ${\phi }_1:C\to \mathbf{R}\cup \{+\mathrm{\infty }\}$ be a proper lower semicontinuous and convex function with restriction (B1) or (B2), and $A_1:H\to H$ be ${\mu }_1$-inverse-strongly monotone. Let $R_1:C\to 2^H$ be a maximal monotone mapping and $B_1:C\to H$ be ${\eta }_1$-inverse-strongly monotone. Let $T:C\to C$ be a ξ-strictly pseudocontractive mapping, $S:H\to H$ be a nonexpansive mapping and $V:H\to H$ be a ρ-contraction with coefficient $\rho \in [0,1)$. Assume that $\Omega :=GMEP({\Theta }_1,{\phi }_1,A_1)\cap \mathrm{I}(B_1,R_1)\cap Fix(T)\cap \Gamma \ne \mathrm{\varnothing }$. Let $0\le \gamma <1$, $\{{\lambda }_n\}\subset [a,b]\subset (0,\frac{2}{L})$, $\{{\alpha }_n\}\subset (0,\mathrm{\infty })$ with ${\sum }_{n=0}^{\mathrm{\infty }}{\alpha }_n<\mathrm{\infty }$, $\{{ϵ}_n\},\{{\delta }_n\},\{{\beta }_n\},\{{\gamma }_n\},\{{\sigma }_n\}\subset (0,1)$ with ${\beta }_n+{\gamma }_n+{\sigma }_n=1$, and $\{r_{1,n}\}\subset [c_1,d_1]\subset (0,2{\mu }_1)$, $\{{\lambda }_{1,n}\}\subset [a_1,b_1]\subset (0,2{\eta }_1)$. For arbitrarily given $x_0\in H$, let $\{x_n\}$ be a sequence generated by

$$\{\begin{array}{l}\Theta (u_n,y)+\phi (y)-\phi (u_n)+〈A{x}_n,y-u_n〉+\frac{1}{r_n}〈y-u_n,u_n-x_n〉\ge 0,\mathrm{\forall }y\in C,\\ v_n=J_{R_1,{\lambda }_{1,n}}(I-{\lambda }_{1,n}{B}_1)u_n,\\ y_n={\beta }_n{x}_n+{\gamma }_n{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n+{\sigma }_{n}T{P}_C(I-{\lambda }_n\mathrm{\nabla }{f}_{{\alpha }_n})v_n,\\ x_{n+1}={ϵ}_n\gamma ({\delta }_{n}V{x}_n+(1-{\delta }_n)S{x}_n)+(1-{ϵ}_n)y_n,\mathrm{\forall }n\ge 0,\end{array}$$

(3.44)

where $\mathrm{\nabla }{f}_{{\alpha }_n}={\alpha }_{n}I+\mathrm{\nabla }f$ for all $n\ge 0$. Suppose that

(C1) ${lim}_{n\to \mathrm{\infty }}{ϵ}_n=0$, ${\sum }_{n=0}^{\mathrm{\infty }}{ϵ}_n=\mathrm{\infty }$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|1-\frac{{\delta }_{n-1}}{{\delta }_n}|=0$;

(C2) ${lim\hspace{0.17em}sup}_{n\to \mathrm{\infty }}\frac{{\delta }_n}{{ϵ}_n}<\mathrm{\infty }$, ${lim}_{n\to \mathrm{\infty }}\frac{1}{{ϵ}_n}|\frac{1}{{\delta }_n}-\frac{1}{{\delta }_{n-1}}|=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{1}{{\delta }_n}|1-\frac{{ϵ}_{n-1}}{{ϵ}_n}|=0$;

(C3) ${lim}_{n\to \mathrm{\infty }}\frac{|{\beta }_n-{\beta }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|{\gamma }_n-{\gamma }_{n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C4) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_{1,n}-{\lambda }_{1,n-1}|}{{ϵ}_n{\delta }_n}=0$ and ${lim}_{n\to \mathrm{\infty }}\frac{|r_{1,n}-r_{1,n-1}|}{{ϵ}_n{\delta }_n}=0$;

(C5) ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n-{\lambda }_{n-1}|}{{ϵ}_n{\delta }_n}=0$, ${lim}_{n\to \mathrm{\infty }}\frac{|{\lambda }_n{\alpha }_n-{\lambda }_{n-1}{\alpha }_{n-1}|}{{ϵ}_n{\delta }_n}=0$ and $({\gamma }_n+{\sigma }_n)\xi \le {\gamma }_n$ for all $n\ge 0$;

(C6) $\{{\beta }_n\}\subset [c,d]\subset (0,1)$, ${lim}_{n\to \mathrm{\infty }}\frac{{\alpha }_n}{{\delta }_n}=0$ and ${lim\hspace{0.17em}inf}_{n\to \mathrm{\infty }}{\sigma }_n>0$.

Then we have:

• (i) ${lim}_{n\to \mathrm{\infty }}\frac{\parallel x_{n+1}-x_n\parallel }{{\delta }_n}=0$;

• (ii) ${\omega }_w(x_n)\subset \Omega$;

• (iii) $\{x_n\}$ converges strongly to a minimizer $x^{\ast }$ of the CMP (1.2), which is a unique solution $x^{\ast }$ in Ω to the HVIP

  $$〈(I-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0,\mathrm{\forall }p\in \Omega .$$

Remark 3.1 It is obvious that our iterative scheme (3.1) is very different from Xu’s iterative one (1.4) and Yao et al.’s iterative one (1.8). Here, Xu’s iterative scheme in [[20], Theorem 5.2] is extended to develop our four-step iterative scheme (3.1) for the CMP (1.2) with constraints of finite many GMEPs, finite many variational inclusions and the fixed point problem of a strict pseudocontraction by combining Korpelevich’s extragradient method, the viscosity approximation method, the hybrid steepest-descent method, Mann’s iteration method, and the gradient-projection method (GPM) with regularization. It is worth pointing out that under the lack of the assumptions similar to those in [[21], Theorem 3.2], e.g., $\{x_n\}$ is bounded, $Fix(T)\cap intC\ne \mathrm{\varnothing }$ and $\parallel x-Tx\parallel \ge kDist(x,Fix(T))$, $\mathrm{\forall }x\in C$ for some $k>0$, the sequence $\{x_n\}$ generated by (3.1) converges strongly to a point $x^{\ast }\in {\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)\cap {\bigcap }_{i=1}^N\mathrm{I}(B_i,R_i)\cap Fix(T)\cap \Gamma =:\Omega$, which is a unique solution of the HVIP (over the fixed point set of strictly pseudocontractive mapping T), i.e., $〈(\mu F-\gamma S)x^{\ast },p-x^{\ast }〉\ge 0$, $\mathrm{\forall }p\in \Omega$.

Remark 3.2 Our Theorem 3.1 improves, extends, supplements, and develops Xu [[20], Theorem 5.2] and Yao et al. [[21], Theorems 3.1 and 3.2] in the following aspects:

• (a) Our HVIP with the unique solution $x^{\ast }\in \Omega$ satisfying

  $$x^{\ast }=P_{{\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)\cap {\bigcap }_{i=1}^N\mathrm{I}(B_i,R_i)\cap Fix(T)\cap \Gamma }(I-(\mu F-\gamma S))x^{\ast }$$

  is more general than the problem of finding a point $\tilde{x}\in C$ satisfying $\tilde{x}=P_{Fix(T)}S\tilde{x}$ in [21] and very different from the problem of finding a point $x^{\ast }\in \Gamma$ satisfying $x^{\ast }=P_{\Gamma }V{x}^{\ast }$ in [[20], Theorem 5.2]. It is worth emphasizing that the nonexpansive mapping T in [[21], Theorems 3.1 and 3.2] is extended to the strict pseudocontraction T and the CMP in [[20], Theorem 5.2] is generalized to the setting of finitely many GMEPs, finitely many variational inclusions and the fixed point problem of a strict pseudocontraction T.

• (b) Our four-step iterative scheme (3.1) for the CMP with constraints of several problems is more flexible, more advantageous and more subtle than Xu’s one-step iterative one (1.4) and than Yao et al.’s two-step iterative one (1.8) because it can be used to solve two kinds of problems, e.g., the HVIP (over the fixed point set of strictly pseudocontractive mapping T), and the problem of finding a common point of four sets: ${\bigcap }_{k=1}^{M}GMEP({\Theta }_k,{\phi }_k,A_k)$, ${\bigcap }_{i=1}^N\mathrm{I}(B_i,R_i)$, $Fix(T)$ and Γ. In addition, our Theorem 3.1 also drops the crucial requirements in [[21], Theorem 3.2(v)] that $Fix(T)\cap intC\ne \mathrm{\varnothing }$ and $\parallel x-Tx\parallel \ge kDist(x,Fix(T))$, $\mathrm{\forall }x\in C$ for some $k>0$.

• (c) The techniques for the argument in our Theorem 3.1 are very different from [[21], Theorems 3.1 and 3.2] and from [[20], Theorem 5.2] because we make use of the properties of strictly pseudocontractive mappings (see Lemmas 2.3 and 2.4), the ones of resolvent operators and maximal monotone mappings (see Proposition 2.2, Remark 2.2, and Lemmas 2.9-2.13), the ones of averaged mappings (see Propositions 2.3 and 2.4), the inclusion problem $0\in \tilde{T}v$ ($\iff v\in VI(C,A)$ for maximal monotone operator $\tilde{T}$) (see (2.2)), and the contractive coefficient estimates for the contractions associated with nonexpansive mappings (see Lemma 2.7).

• (d) Compared with the restrictions on the parameter sequences of [[21], Theorem 3.2] and [[20], Theorem 5.2], respectively, the hypotheses (C3)-(C6) in our Theorem 3.1 are added because our Theorem 3.1 involves the quite complex problem, i.e., the HVIP (over the fixed point set of strictly pseudocontractive mapping T) with constraints of several problems: CMP (1.2), finitely many GMEPs and finitely many variational inclusions.