Abstract
The kinetics of the Np(V) disproportionation in 0.1 M potassium hydrogen phthalate + 30 mM EDTA solutions at 25–45°C was studied by spectrophotometry. The reaction rate at pH in the range 3.0–5.0 is described by the equation −d[Np(V)]/dt = k[Np(V)]2, where k = k 0[H+]0.65. In solution with pH 4.01 at 25°C, k = 3.39 × 10−2 L mol−1 s−1. The complexes of NpO +2 with HY3− form a dimer, which forms an activated complex with the H+ ion. Decomposition of the activated complex yields Np(IV) and Np(VI). Neptunium(VI) bound with Y undergoes intramolecular reduction to Np(V).
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Original Russian Text © V.P. Shilov, A.M. Fedoseev, 2015, published in Radiokhimiya, 2015, Vol. 57, No. 4, pp. 348–351.
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Shilov, V.P., Fedoseev, A.M. Disproportionation of Np(V) in EDTA solutions in the presence of potassium hydrogen phthalate. Radiochemistry 57, 409–413 (2015). https://doi.org/10.1134/S1066362215040128
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DOI: https://doi.org/10.1134/S1066362215040128