Abstract
Given a ring extension \(R\subset S\) of integral domains, it is shown that if each proper subring of \(S\) containing \(R\) is integrally closed, then \(S\) is integrally closed. As an application, we show that if each proper subring of \(S\) containing \(R\) is a valuation (resp., Prüfer, resp. Principal ideal) domain, then so is \(S\).
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The authors extend their thanks to the referee for his/her valuable suggestions.
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Communicated by Marco Fontana.
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Jarboui, N., Toumi, M.E.I. & Trabelsi, S. Some questions concerning proper subrings. Ricerche mat. 64, 51–55 (2015). https://doi.org/10.1007/s11587-014-0188-6
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DOI: https://doi.org/10.1007/s11587-014-0188-6
Keywords
- Integral domain
- Intermediate ring
- Overring
- Ring extension
- Integral extension
- Integrally closed
- Prüfer domain
- Dedekind domain
- Valuation domain
- Noetherian ring