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Some mistakes has slipped in on Page 184:

In the first line it should read instead of “2L” only “L”.

We will focus again on the one-dimensional case with domain size L (Fig. 6.2).

In the second sentence in the paragraph after Eq. (6.11) the term “(-L)” should be “(0) = ”.

This system of first-order differential equations must then be solved under the boundary conditions T + (L) = 0 and T - (0) = 0.

$$\left\langle T \right\rangle = T\left( {x_0 } \right) = \frac{{2x_0 \left( {L - x_0 } \right)}}{D} + \frac{L}{\upsilon }$$
(6.13)

In Eq. (6.13) the numerator should read “2x 0(L - x 0)” and the denominator is “D”.

In Eq. (6.14) the denominator in both lines is “D

$$\begin{array}{*{20}c} {\left\langle {T_ + } \right\rangle \equiv T_ + \left( {x_0 } \right) = \frac{{x_0 \left( {L - x_0 } \right)}}{D} + \frac{{L - x_0 }}{\upsilon }} \\ {\left\langle {T_ - } \right\rangle \equiv T_ - \left( {x_0 } \right) = \frac{{x_0 \left( {L - x_0 } \right)}}{D} + \frac{{x_0 }}{\upsilon }.} \\\end{array}$$
(6.14)