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Notes
- 1.
The number of times an element appears in a segment l in an i.i.d. sequence follows a Poisson distribution, as deduced in Sect. 21.5. A Poisson distribution is characterized by its mean and variance being equal. If l is made k times larger, then its mean obviously becomes k times larger as well, and so does the variance. Therefore, ν = 1 for an i.i.d. sequence. Section 21.6 gives a more formal explanation.
- 2.
For fitting Fig. 9.1, the least-squares method was applied (cf. Sect. 21.1) to the plots for l ∝ a k, with k = 1, 2, 3, …, a = 1.8. ε = 0.0797 for Moby Dick, whereas ε = 0.00936 for the shuffled text. As introduced in Sect. 3.5, the shuffled text used here is word shuffled, and therefore, the order of the characters within words is maintained. Nevertheless, ν ≈ 1.
- 3.
ε = 0.0541.
- 4.
The choice of l is arbitrary but must be sufficiently smaller than the text length to accurately calculate the mean and standard deviation. Among different values of l taken from logarithmic bins, a maximum l that could apply to all texts was adopted here. This resulted in a choice of l around 5000 words, specifically l = 5620 ≈ 103.75.
- 5.
- 6.
Previously, the corresponding value for the EN method was 1. Taylor analysis uses the standard deviation, so the i.i.d. case has α = 0.5. Section 21.6 gives a more formal explanation.
- 7.
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Tanaka-Ishii, K. (2021). Fluctuation. In: Statistical Universals of Language. Mathematics in Mind. Springer, Cham. https://doi.org/10.1007/978-3-030-59377-3_9
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