Abstract
Relativistic quantum chemistry investigations are carried out to tackle the puzzling oxidation state problem in a series of MO -3 trioxide anions of all d- and f-block elements with five valence electrons. We have shown here that while the oxidation states of V, Nb, Ta, Db, Pa are, as usual, all +V with divalent oxygen O(-II) in MO -3 anions, the lanthanide elements Pr and Gd cannot adopt such high +V oxidation state in similar trioxide anions. Instead, lanthanide element Gd retains its usual +III oxidation state, while Pr retains a +IV oxidation state, thus forcing oxygen into a non-innocent ligand with an uncommon monovalent radical (O•) of oxidation state -I. A unique Pr• - •(O)3 biradical with highly delocalized unpairing electron density on Pr(IV) and three O atoms is found to be responsible for stabilizing the monovalent-oxygen species in PrO -3 ion, while GdO -3 ion is in fact an OGd+(O 2-2 ) complex with Gd(III). These results show that a naïve assignment of oxidation state of a chemical element without electronic structure analysis can lead to erroneous conclusions.
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Su, J., Hu, S., Huang, W. et al. On the oxidation states of metal elements in MO3 - (M=V, Nb, Ta, Db, Pr, Gd, Pa) anions. Sci. China Chem. 59, 442–451 (2016). https://doi.org/10.1007/s11426-015-5481-z
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DOI: https://doi.org/10.1007/s11426-015-5481-z