1 Introduction

Let X be an arbitrary nonempty set and f:XX be a mapping. A fixed point for f is a point xX such that fx=x. Many useful mathematical facts can be expressed by assertions that say that certain mappings have fixed points. Fixed point theory, one of the very active research areas in mathematics as well as quantitative sciences, focuses on maps and abstract spaces for which one can assure the existence and/or uniqueness of fixed points when they are put together. For example, fixed point theorems are vital for the existence and uniqueness of differential equations, matrix equations, and integral equations (see, e.g., [1, 2]). Moreover, it has applications in many fields such as chemistry, biology, statistics, economics, computer science and engineering (see, e.g., [36]). For example, fixed point results are incredibly useful when it comes to proving the existence of various types of Nash equilibria (see, e.g., [3]) in economics.

The classical contraction mapping principle of Banach is one of the most powerful theorems in fixed point theory because of its simplicity and usefulness. So, it has become a very popular tool for solving many problems in many branches of mathematical analysis and also in many other fields. Refer to [717] and references mentioned therein for certain extensions of this principle. In 2004, the Banach contraction principle was extended to metric spaces endowed with a partial ordering by Ran and Reurings [18]. They also gave some applications of their results to matrix equations. Afterwards, Nieto and Rodríguez-López [19] extended the results of Ran and Reurings for nondecreasing mappings and studied the existence and uniqueness of solutions for a first-order ordinary differential equation with periodic boundary conditions.

In 2006, Bhaskar and Lakshmikantham [20] introduced the concept of a mixed monotone property for the first time and gave their classical coupled fixed point theorems for mappings which satisfy the mixed monotone property. They also produced some applications in the existence and uniqueness of solutions for the periodic boundary value problem

u ( t ) = f ( t , u ( t ) ) , t [ 0 , T ] , u ( 0 ) = u ( T ) ,
(1.1)

where the function f satisfies certain conditions. Afterwards, Harjani et al. [21] and Luong and Thuan [22, 23] studied the existence and uniqueness of solutions of nonlinear integral equations as an application of coupled fixed points. Recently, Caballero et al. [24] have investigated the existence and uniqueness of positive solutions for the following singular fractional boundary value problem:

D 0 + α u ( t ) + f ( t , u ( t ) ) = 0 , 0 < t < 1 , u ( 0 ) = u ( 1 ) = 0 ,
(1.2)

where αR such that 1<α2. Here D 0 + α is the standard Riemann-Liouville differentiation. The function f:(0,1]×[0,)[0,) has the property lim t 0 + f(t,)= for all t(0,1] (i.e., f is singular at t=0). Very recently, motivated by the work of Caballero et al. [24], Jleli and Samet [25] discussed the existence and uniqueness of a positive solution for the singular nonlinear fractional differential equation boundary value problem

D 0 + α u ( t ) = f ( t , u ( t ) , u ( t ) ) , 0 < t < 1 , u ( a ) = u ( b ) = 0 , a , b { 0 , 1 } ,
(1.3)

where αR such that 3<α4. Above D 0 + α is also the Riemann-Liouville fractional derivative. The function f:(0,1]×[0,)×[0,)[0,) is continuous, lim t 0 + f(t,,)= for all t(0,1], and nondecreasing with respect to the first component, decreasing with respect to its second and third components.

Because of their important roles in the study of the existence and uniqueness of solutions of the periodic boundary value problems, nonlinear integral equations and the existence and uniqueness of positive solutions for the singular nonlinear fractional differential equations with boundary value, discussions on coupled fixed point theorems are of interest to many scientists. A considerable number of articles have been dedicated to the improvement and generalization of this topic (see [2633] and references therein).

On the other hand, Huang and Zhang [34] reintroduced the notion of cone metric spaces and established fixed point theorems for mappings in such spaces. In 2011, Cho et al. [35] introduced a new concept of a c-distance, a cone version of a w-distance of Kada et al. [36], in cone metric spaces and proved some fixed point theorems in partially ordered cone metric spaces using the notion of a c-distance. Afterwards, Sintunavarat et al. [37] (see also [38]) established fixed point theorems for some type of generalization of contraction mappings by using this concept.

Recently, Cho et al. [39] established new coupled fixed point theorems under contraction mappings by using the concept of the mixed monotone property and c-distance in partially ordered cone metric spaces as follows.

Theorem 1.1 ([39])

Let (X,) be a partially ordered set and suppose that (X,d) is a complete cone metric space. Let q be a c-distance on X and F:X×XX be a continuous function having the mixed monotone property such that

q ( F ( x , y ) , F ( x , y ) ) k 2 ( q ( x , x ) + q ( y , y ) )

for some k[0,1) and all x,y, x , y X with

( x x ) ( y y ) or ( x x ) ( y y ) .

If there exist x 0 , y 0 X such that

x 0 F( x 0 , y 0 )andF( y 0 , x 0 ) y 0 ,

then F has a coupled fixed point (u,v). Moreover, we have q(v,v)=θ and q(u,u)=θ.

Theorem 1.2 ([39])

In addition to the hypotheses of Theorem 1.1, suppose that any two elements x and y in X are comparable. Then the coupled fixed point has the form (u,u), where uX.

Theorem 1.3 ([39])

Let (X,) be a partially ordered set and suppose that (X,d) is a complete cone metric space. Let q be a c-distance on X and F:X×XX be a function having the mixed monotone property such that

q ( F ( x , y ) , F ( x , y ) ) k 4 ( q ( x , x ) + q ( y , y ) )

for some k(0,1) and all x,y, x , y X with

( x x ) ( y y ) or ( x x ) ( y y ) .

Also, suppose that X has the following properties:

(a) if ( x n ) is a non-decreasing sequence in X with x n x, then x n x for all nN;

(b) if ( x n ) is a non-increasing sequence in X with x n x, then x x n for all nN.

Assume there exist x 0 , y 0 X such that

x 0 F( x 0 , y 0 )andF( y 0 , x 0 ) y 0 .

If y 0 x 0 , then F has a coupled fixed point.

Very recently, Sintunavarat et al. [40] have weakened the condition of the mixed monotone property in results of Cho et al. [39] by using the concept of an F-invariant set (see the notion of an F-invariant set in Section 2).

Theorem 1.4 ([40])

Let (X,d) be a complete cone metric space. Let q be a c-distance on X, M be a nonempty subset of X 4 and F:X×XX be a continuous function such that

q ( F ( x , y ) , F ( x , y ) ) k 2 ( q ( x , x ) + q ( y , y ) )
(1.4)

for some k[0,1) and all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M.

If M is F-invariant and there exist x 0 , y 0 X such that

( F ( x 0 , y 0 ) , F ( y 0 , x 0 ) , x 0 , y 0 ) M,

then F has a coupled fixed point (u,v). Moreover, if (u,v,u,v)M, then q(v,v)=θ and q(u,u)=θ.

Theorem 1.5 ([40])

In addition to the hypotheses of Theorem 1.4, suppose that for any two elements x and y in X, we have

(y,x,x,y)Mor(x,y,y,x)M.

Then the coupled fixed point has the form (u,u), where uX.

Theorem 1.6 ([40])

Let (X,d) be a complete cone metric space. Let q be a c-distance on X, M be a subset of X 4 and F:X×XX be a function such that

q ( F ( x , y ) , F ( x , y ) ) k 4 ( q ( x , x ) + q ( y , y ) )
(1.5)

for some k[0,1) and all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M.

Also, suppose that

(i) there exist x 0 , y 0 X such that (F( x 0 , y 0 ),F( y 0 , x 0 ), x 0 , y 0 )M,

(ii) two sequences { x n }, { y n } with ( x n + 1 , y n + 1 , x n , y n )M for all nN and { x n }x, { y n }y, then (x,y, y n , x n )M and ( y n , x n ,y,x)M for all nN.

If M is an F-invariant set, then F has a coupled fixed point.

Inspired by the results of Sintunavarat et al. [40], we prove some coupled fixed point theorems in cone metric spaces by using the concept of an F-invariant set and give some example which is not applied to the existence of a coupled fixed point by the results of Sintunavarat et al. [40], but can be applied to our results. Moreover, we show that our results can be applied to the result in partially ordered cone metric spaces. We also consider an application to illustrate our result is useful (see Section 4).

2 Preliminaries

Throughout this paper (X,) denotes a partially ordered set. By xy, we mean xy but xy. A mapping f:XX is said to be non-decreasing (non-increasing) if for all x,yX, xy implies f(x)f(y) (f(y)f(x) respectively).

Definition 2.1 ([20])

Let (X,) be a partially ordered set. A mapping F:X×XX is said to have the mixed monotone property if F is monotone non-decreasing in its first argument and is monotone non-increasing in its second argument; that is, for any x,yX,

x 1 , x 2 X, x 1 x 2 F( x 1 ,y)F( x 2 ,y)
(2.1)

and

y 1 , y 2 X, y 1 y 2 F(x, y 1 )F(x, y 2 ).
(2.2)

Definition 2.2 ([20])

Let X be a nonempty set. An element (x,y)X×X is called a coupled fixed point of mapping F:X×XX if

x=F(x,y)andy=F(y,x).

Next, we give some terminology of cone metric spaces and the concept of a c-distance in cone metric spaces due to Cho et al. [35] which is a generalization of a w-distance of Kada et al. [36].

Let (E, E ) be a real Banach space, θ be a zero element in E and P be a proper nonempty subset of E. Then P is called a cone if the following conditions are satisfied:

(1) P is closed and P{θ};

(2) a,b R + , x,yP implies ax+byP;

(3) xP(P) implies x=θ.

We shall always assume that the cone P has a nonempty interior (such cones are called solid). For the cone P, define the partial ordering ⪯ with respect to P by xy if and only if yxP. We write xy to indicate that xy but xy, while xy stand for yxint(P), where int(P) is an interior of P.

It can be easily shown that λint(P)int(P) for all positive scalars λ.

The cone P is called normal if there is a number K>0 such that for all x,yE,

0xy x E K y E .

The least positive number satisfying the above is called the normal constant of P. It is clear that K1.

In what follows, we always suppose that E is a real Banach space with the cone P.

Definition 2.3 ([34])

Let X be a nonempty set. Suppose that the mapping d:X×XE satisfies the following conditions:

(1) θd(x,y) for all x,yX and d(x,y)=θ if and only if x=y;

(2) d(x,y)=d(y,x) for all x,yX;

(3) d(x,y)d(x,z)+d(z,y) for all x,y,zX.

Then d is called a cone metric on X and (X,d) is called a cone metric space.

Definition 2.4 ([34])

Let (X,d) be a cone metric space. Let { x n } be a sequence in X and xX.

(1) If for any cX with θc, there exists NN such that d( x n ,x)c for all nN, then { x n } is said to be convergent to a point xX and x is the limit of { x n }. We denote this by lim n x n =x or x n x as n.

(2) If for any cE with θc, there exists NN such that d( x n , x m )c for all n,mN, then { x n } is called a Cauchy sequence in X.

(3) The space (X,d) is called a complete cone metric space if every Cauchy sequence is convergent.

Definition 2.5 ([35])

Let (X,d) be a cone metric space. Then a function q:X×XE is called a c-distance on X if the following are satisfied:

(q1) θq(x,y) for all x,yX;

(q2) q(x,y)q(x,z)+q(z,y) for all x,y,zX;

(q3) for any xX, if there exists u= u x P such that q(x, y n )u for each nN, then q(x,y)u whenever { y n } is a sequence in X converging to a point yX;

(q4) for any cE with θc, there exists eE with θe such that q(z,x)e and q(z,y)c imply d(x,y)c.

Remark 2.6 The c-distance q is a w-distance on X if we take (X,d) is a metric space, E= R + , P=[0,) and (q3) is replaced by the following condition:

For any xX, q(x,):X R + is lower semi-continuous.

Therefore, every w-distance is a c-distance. But the converse is not true in a general case. Therefore, the c-distance is a generalization of the w-distance.

Example 2.7 Let (X,d) be a cone metric space and P be a normal cone. Define a mapping q:X×XE by q(x,y)=d(x,y) for all x,yX. Then q is a c-distance.

Example 2.8 Let E= C R 1 [0,1] with x E = x + x and P={xE:x(t)0 on [0,1]} (this cone is not normal). Let X=[0,) and define a mapping d:X×XE by

d(x,y)=|xy|φ

for all x,yX, where φ:[0,1]R such that φ(t)= e t . Then (X,d) is a cone metric space. Define a mapping q:X×XE by

q(x,y)=(x+y)φ

for all x,yX. Then q is a c-distance.

Example 2.9 Let (X,d) be a cone metric space and P be a normal cone. Define a mapping q:X×XE by

q(x,y)=d(u,y)

for all x,yX, where u is a fixed point in X. Then q is a c-distance.

Example 2.10 Let E=R and P={xE:x0}. Let X=[0,) and define a mapping d:X×XE by

d(x,y)=|xy|

for all x,yX. Then (X,d) is a cone metric space. Define a mapping q:X×XE by

q(x,y)=y

for all x,yX. Then q is a c-distance.

Remark 2.11 From Examples 2.9 and 2.10, we have the following important results for a c-distance q:

q(x,y)=q(y,x) does not necessarily hold.

q(x,y)=θ is not necessarily equivalent to x=y for all x,yX.

The following lemma is crucial in proving main results.

Lemma 2.12 ([35])

Let (X,d) be a cone metric space and q be a c-distance on X. Let { x n } and { y n } be sequences in X and x,y,zX. Suppose that { u n } is a sequence in P converging to θ. Then the following hold:

(1) If q( x n ,y) u n and q( x n ,z) u n , then y=z.

(2) If q( x n , y n ) u n and q( x n ,z) u n , then { y n } converges to a point zX.

(3) If q( x n , x m ) u n for each m>n, then { x n } is a Cauchy sequence in X.

(4) If q(y, x n ) u n , then { x n } is a Cauchy sequence in X.

Next, we give the concept of an F-invariant set in a cone version due to Sintunavarat et al. [40].

Definition 2.13 ([40])

Let (X,d) be a cone metric space and F:X×XX be a given mapping. Let M be a nonempty subset of X 4 . We say that M is an F-invariant subset of X 4 if and only if for all x,y,z,wX, we have

( F 1 ) (x,y,z,w)M(w,z,y,x)M;

( F 2 ) (x,y,z,w)M(F(x,y),F(y,x),F(z,w),F(w,z))M.

We obtain that the set M= X 4 is trivially F-invariant.

Next example plays a key role in the proof of our main results in a partially ordered set.

Example 2.14 ([40])

Let (X,d) be a cone metric space endowed with a partial order ⊑. Let F:X×XX be a mapping satisfying the mixed monotone property; that is, for all x,yX, we have

x 1 , x 2 X, x 1 x 2 F( x 1 ,y)F( x 2 ,y)

and

y 1 , y 2 X, y 1 y 2 F(x, y 1 )F(x, y 2 ).

Define the subset M X 4 by

M= { ( a , b , c , d ) : c a , b d } .

Then, M is F-invariant of X 4 .

3 Main results

First, we show the weakness of Theorem 1.4 with the following example.

Example 3.1 Let E= C R 1 [0,1] with x E = x + x and P={xE,x(t)0,t[0,1]}. Let X=[0,) (with usual order ⊑), and let d:X×XE be defined by d(x,y)(t)=|xy| 2 t . Then (X,d) is a complete cone metric space. Let, further, q:X×XE be defined by q(x,y)(t)=y 2 t . It is easy to check that q is a c-distance. Consider the mapping F:X×XX by

F(x,y)={ 3 5 ( x + y ) if  x y , 0 if  x < y .

Let M= X 4 and so M is an F-invariant subset of X. Now, we show that there is no k[0,1) for which (1.4) holds. To prove this, suppose the contrary; that is, there is k[0,1) such that

q ( F ( x , y ) , F ( x , y ) ) k 2 ( q ( x , x ) + q ( y , y ) )

for all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M.

Take x=0, y=1, x =1 and y =0. Then

q ( F ( 0 , 1 ) , F ( 1 , 0 ) ) (t) k 2 ( q ( 0 , 1 ) + q ( 1 , 0 ) ) (t).

This implies

F(1,0) 2 t = 3 5 2 t k 2 2 t .

Hence, k 6 5 is a contradiction. Therefore, there is no k for which (1.4) holds.

Moreover, for y 1 = 1 3 and y 2 = 1 2 , we have for x=1, we get y 1 = 1 3 1 2 = y 2 but

F(x, y 1 )= 4 5 9 10 =F(x, y 2 ).

So, the mapping F does not satisfy the mixed monotone property. Therefore, main theorems of Cho et al. [39] cannot be used to reach this conclusion.

The following theorem is the extension of Theorem 1.4

Theorem 3.2 Let (X,d) be a complete cone metric space. Let q be a c-distance on X, M be a nonempty subset of X 4 and F:X×XX be a continuous function such that

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )
(3.1)

for some k[0,1) and all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M.

If M is F-invariant and there exist x 0 , y 0 X such that

( F ( x 0 , y 0 ) , F ( y 0 , x 0 ) , x 0 , y 0 ) M,

then F has a coupled fixed point (u,v). Moreover, if (u,v,u,v)M, then q(u,u)=θ and q(v,v)=θ.

Proof Since F(X×X)X, we can construct two sequences { x n } and { y n } in X such that

x n =F( x n 1 , y n 1 )and y n =F( y n 1 , x n 1 )for all nN.
(3.2)

Since (F( x 0 , y 0 ),F( y 0 , x 0 ), x 0 , y 0 )=( x 1 , y 1 , x 0 , y 0 )M and M is an F-invariant set, we get

( F ( x 1 , y 1 ) , F ( y 1 , x 1 ) , F ( x 0 , y 0 ) , F ( y 0 , x 0 ) ) =( x 2 , y 2 , x 1 , y 1 )M.

Again, using the fact that M is an F-invariant set, we have

( F ( x 2 , y 2 ) , F ( y 2 , x 2 ) , F ( x 1 , y 1 ) , F ( y 1 , x 1 ) ) =( x 3 , y 3 , x 2 , y 2 )M.

By repeating the argument similar to the above, we get

( F ( x n 1 , y n 1 ) , F ( y n 1 , x n 1 ) , x n 1 , y n 1 ) =( x n , y n , x n 1 , y n 1 )M

for all nN. From (3.1), we have

q ( x n , x n + 1 ) + q ( y n , y n + 1 ) q ( F ( x n 1 , y n 1 ) , F ( x n , y n ) ) + q ( F ( y n 1 , x n 1 ) , F ( y n , x n ) ) k ( q ( x n 1 , x n ) + q ( y n 1 , y n ) ) .
(3.3)

We repeat the above process for n-times, we get

q( x n , x n + 1 )+q( y n , y n + 1 ) k n ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .
(3.4)

From (3.4), we can conclude that

q( x n , x n + 1 ) k n ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )
(3.5)

and

q( y n , y n + 1 ) k n ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .
(3.6)

Let m,nN with m>n. Since

and 0k<1, we have

q( x n , x m ) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )

and

q( y n , y m ) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .

Using Lemma 2.12(3), we have { x n } and { y n } are Cauchy sequences in (X,d). By completeness of X, we get x n u and y n v as n for some u,vX.

Since F is continuous, taking n in (3.2), we get

lim n x n + 1 = lim n F( x n , y n )=F ( lim n x n , lim n y n ) =F(u,v)

and

lim n y n + 1 = lim n F( y n , x n )=F ( lim n y n , lim n x n ) =F(v,u).

By the uniqueness of the limits, we get u=F(u,v) and v=F(v,u). Therefore, (u,v) is a coupled fixed point of F.

Finally, we assume that (u,v,u,v)M. By (3.1), we have

q(u,u)+q(v,v)=q ( F ( u , v ) , F ( u , v ) ) +q ( F ( v , u ) , F ( v , u ) ) k ( q ( u , u ) + q ( v , v ) ) .

Since 0k<1, we conclude that q(u,u)+q(v,v)=θ and hence q(u,u)=θ and q(v,v)=θ. This completes the proof. □

Remark 3.3 We obtain that the mapping F in Example 3.1 has a coupled fixed point. Indeed, for all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M

we have

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) 3 5 ( q ( x , x ) + q ( y , y ) ) .

Also, we note that there exists points 0,1X such that (F(0,1),F(1,0),0,1)M. Thus, by Theorem 3.2, we have F has a coupled fixed point that is a point (0,0).

Theorem 3.4 In addition to the hypotheses of Theorem 3.2, suppose that for any two elements x and y in X, we have

(y,x,x,y)Mor(x,y,y,x)M.

Then the coupled fixed point has the form (u,u), where uX.

Proof As in the proof of Theorem 3.2, there exists a coupled fixed point (u,v)X×X. Hence,

u=F(u,v)andv=F(v,u).

Moreover, q(u,u)=θ and q(v,v)=θ if (u,v,u,v)M.

From the additional hypothesis, we have (u,v,v,u)M or (v,u,u,v)M. By (3.1), we get

q(u,v)+q(v,u)=q ( F ( u , v ) , F ( v , u ) ) +q ( F ( v , u ) , F ( u , v ) ) k ( q ( u , v ) + q ( v , u ) ) .

Since 0k<1, we get q(u,v)+q(v,u)=θ. Therefore, q(u,v)=θ and q(v,u)=θ.

Let u n =θ and x n =u. Then

q( x n ,u) u n

and

q( x n ,v) u n .

From Lemma 2.12(1), we have u=v. Therefore, the coupled fixed point of F has the form (u,u). This completes the proof. □

Theorem 3.5 Let (X,d) be a complete cone metric space. Let q be a c-distance on X, M be a subset of X 4 and F:X×XX be a function such that

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )
(3.7)

for some k[0,1) and all x,y, x , y X with

( x , y , x , y ) Mor ( x , y , x , y ) M.

Also, suppose that

(i) there exist x 0 , y 0 X such that (F( x 0 , y 0 ),F( y 0 , x 0 ), x 0 , y 0 )M,

(ii) two sequences { x n }, { y n } with ( x n + 1 , y n + 1 , x n , y n )M for all nN and { x n }x, { y n }y, then (x,y, x n , y n )M for all nN.

If M is an F-invariant set, then F has a coupled fixed point. Moreover, if (u,v,u,v)M, then q(u,u)=θ and q(v,v)=θ.

Proof As in the proof of Theorem 3.2, we can construct two Cauchy sequences { x n } and { y n } in X such that

( x n , y n , x n 1 , y n 1 )M

for all nN. Moreover, we have that { x n } converges to a point uX and { y n } converges to vX,

q( x n , x m ) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )

and

q( y n , y m ) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )

for each m>n1. By (q3), we have

q( x n ,u) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )
(3.8)

and

q( y n ,v) k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )
(3.9)

and so

q( x n ,u)+q( y n ,v) 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .
(3.10)

By the assumption (ii), we have (u,v, x n , y n )M. From (3.7) and (3.10), we have

q ( x n , F ( u , v ) ) + q ( y n , F ( v , u ) ) = q ( F ( x n 1 , y n 1 ) , F ( u , v ) ) + q ( F ( y n 1 , x n 1 ) , F ( v , u ) ) k ( q ( x n 1 , u ) + q ( y n 1 , v ) ) k 2 k n 1 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) = 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .

Therefore, we have

q ( x n , F ( u , v ) ) 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )
(3.11)

and

q ( y n , F ( v , u ) ) 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .
(3.12)

From (3.10), we get

q( x n ,u) 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) )
(3.13)

and

q( y n ,v) 2 k n 1 k ( q ( x 0 , x 1 ) + q ( y 0 , y 1 ) ) .
(3.14)

Since (3.11), (3.12), (3.13) and (3.14) hold, by using Lemma 2.12(1), we get u=F(u,v) and v=F(v,u). Therefore, (u,v) is a coupled fixed point of F. The proof of q(u,u)=θ and q(v,v)=θ is the same as the proof in Theorem 3.2. This completes the proof. □

The following theorem can be proved in the same way as Theorem 3.4.

Theorem 3.6 In addition to the hypotheses of Theorem 3.5, suppose that for any two elements x and y in X, we have

(y,x,x,y)Mor(x,y,y,x)M.

Then the coupled fixed point has the form (u,u), where uX.

Remark 3.7 Since the relations (1.4) and (1.5) imply (3.1), we can apply Theorems 3.2, 3.4 and 3.5 to the main result of Sintunavarat et al. [40].

Next, we apply Theorems 3.2, 3.4, 3.5 and 3.6 to the results in a partially ordered cone metric spaces.

Corollary 3.8 Let (X,) be a partially ordered set and suppose that (X,d) is a complete cone metric space. Let q be a c-distance on X and F:X×XX be a continuous function having the mixed monotone property such that

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )
(3.15)

for some k[0,1) and all x,y, x , y X with

( x x ) ( y y ) or ( x x ) ( y y ) .

If there exist x 0 , y 0 X such that

x 0 F( x 0 , y 0 )andF( y 0 , x 0 ) y 0 ,

then F has a coupled fixed point (u,v). Moreover, we have q(v,v)=θ and q(u,u)=θ.

Proof Let M={(a,b,c,d):ca,bd} X 4 . We obtain that M is an F-invariant set. By (3.15), we have

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )

for some k[0,1) and all x,y, x , y X with (x,y, x , y )M or ( x , y ,x,y)M. Now, all the hypotheses of Theorem 3.2 hold. Thus, F has a coupled fixed point. □

Corollary 3.9 In addition to the hypotheses of Corollary 3.8, suppose that for any two elements x and y in X, we have x and y are comparable. Then the coupled fixed point has the form (u,u), where uX.

Proof This result is obtained by Theorem 3.4. □

Corollary 3.10 Let (X,) be a partially ordered set and suppose that (X,d) is a complete cone metric space. Let q be a c-distance on X and F:X×XX be a function having the mixed monotone property such that

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )
(3.16)

for some k[0,1) and all x,y, x , y X with

( x x ) ( y y ) or ( x x ) ( y y ) .

Also, suppose that X has the following properties:

(a) if { x n } is a non-decreasing sequence in X with x n x, then x n x for all nN;

(b) if { y n } is a non-increasing sequence in X with y n y, then y y n for all nN.

If there exist x 0 , y 0 X such that

x 0 F( x 0 , y 0 )andF( y 0 , x 0 ) y 0 ,

then F has a coupled fixed point (u,v). Moreover, we have q(v,v)=θ and q(u,u)=θ.

Proof Let M={(a,b,c,d):ca,bd} X 4 . We obtain that M is an F-invariant set. By (3.16), we have

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k ( q ( x , x ) + q ( y , y ) )

for some k[0,1) and all x,y, x , y X with (x,y, x , y )M or ( x , y ,x,y)M. From assumptions (a) and (b), we get two sequences { x n }, { y n }, with { x n } being a non-decreasing sequence in X with x n x and { y n } being a non-increasing sequence in X with y n y,

x 0 x 1 x n x

and

y 0 y 1 y n y

for all nN. Therefore, we get the condition (ii) in Theorem 3.5 holds. Now, all the hypotheses of Theorem 3.5 hold. Thus, F has a coupled fixed point. □

Corollary 3.11 In addition to the hypotheses of Corollary 3.10, suppose that for any two elements x and y in X, we have x and y are comparable. Then the coupled fixed point has the form (u,u), where uX.

4 Applications

In this section, we apply our theorem to the existence theorem for a solution of the following integral equations:

x ( t ) = 0 T f ( t , x ( s ) , y ( s ) ) d s , t [ 0 , T ] ; y ( t ) = 0 T f ( t , y ( s ) , x ( s ) ) d s , t [ 0 , T ] ,
(4.1)

where T>0 and f:[0,T]×R×RR.

In what follows, we always let C([0,T],R) denote the class of ℝ-valued continuous functions on the interval [0,T], where T is a real number such that T>0.

Definition 4.1 An element α,βC([0,T],R)×C([0,T],R) is called a coupled lower and upper solution of the integral equation (4.1) if α(t)β(t) and

α(t) 0 T f ( t , α ( s ) , β ( s ) ) ds

and

β(t) 0 T f ( t , β ( s ) , α ( s ) ) ds

for all t[0,T].

Now, we consider the following assumptions:

(a) f:[0,T]×R×RR is continuous;

(b) for all t[0,T] and for all x,y, x , y R for which x x and y y , we have

0f(t,x,y)f ( t , x , y ) 1 T φ ( x x + y y 2 ) ,

where φ:[0,)[0,) is continuous non-decreasing and satisfies: there exists 0k<1 such that

φ(r)krr0.

Next, we give the existence theorem for a solution of the integral equations (4.1).

Theorem 4.2 Suppose that assumptions (a) and (b) hold. Then the existence of a coupled lower and upper solution for (4.1) provides the existence of a solution (u,v)C([0,T],R)×C([0,T],R) for the integral equations (4.1).

Proof Let E= R 2 and PE be the cone defined by

P= { ( x , y ) R 2 | x 0 , y 0 } .

We endow X with the cone metric d:X×XE defined by

d(x,y)= ( sup t [ 0 , T ] | x ( t ) y ( t ) | , sup t [ 0 , T ] | x ( t ) y ( t ) | ) ,u,vX.

It is clear that (X,d) is a complete cone metric space. Let q(x,y)=d(x,y) for all x,yX. Then, q is a c-distance.

Define the self-mapping F:C([0,T],R)×C([0,T],R)C([0,T],R) by

F(x,y)(t)= 0 T f ( t , x ( s ) , y ( s ) ) ds,x,yC ( [ 0 , T ] , R ) ,t[0,T].

Let M={(x,y, x , y ) X 4 : x (t)x(t) and y(t) y (t) for all t[0,T]}.

Next, we prove that M is an F-invariant subset of X 4 . It obvious that M satisfies ( F 1 ). Now, we show that ( F 2 ) holds. Let (x,y, x , y )M and then x (t)x(t) and y(t) y (t) for all t[0,T]. By (b), for all t[0,T], we have

0f ( t , x ( t ) , y ( t ) ) f ( t , x ( t ) , y ( t ) )
(4.2)

and

0f ( t , y ( t ) , x ( t ) ) f ( t , y ( t ) , x ( t ) ) .
(4.3)

From (4.2), we get

f ( t , x ( t ) , y ( t ) ) f ( t , x ( t ) , y ( t ) )

and so

0 T f ( t , x ( s ) , y ( s ) ) ds 0 T f ( t , x ( s ) , y ( s ) ) ds.

This implies that

F ( x , y ) (t)F(x,y)(t).
(4.4)

Similarly, from (4.3), we get

F(y,x)(t)F ( y , x ) (t).
(4.5)

From (4.4) and (4.5), we get (F(x,y),F(y,x),F( x , y ),F( y , x ))M, and thus M satisfies ( F 2 ). Therefore, M is an F-invariant subset of X 4 .

Now, let (x,y, x , y )M and so x (t)x(t) and y(t) y (t) for all t[0,T]. Using (b), for all t[0,T], we have

which implies that

(4.6)

Similarly, we can get

(4.7)

Adding up (4.6) and (4.7), we get

Thus,

q ( F ( x , y ) , F ( x , y ) ) +q ( F ( y , x ) , F ( y , x ) ) k [ q ( x , x ) + q ( y , y ) ]

for all (x,y, x , y )M. This implies that the condition (3.7) of Theorem 3.5 is satisfied.

Now, let (α,β) be a coupled lower and upper solution of the integral equations (4.1), then we have α(t)F(α,β)(t) and β(t)F(β,α)(t) for all t[0,T], that is, αF(α,β) and βF(β,α). Therefore, (F(α,β),F(β,α),α,β)M, and then the condition (i) in Theorem 3.5 is satisfied. Moreover, it is easy to see that the condition (ii) in Theorem 3.5 is also satisfied.

Finally, applying our Theorem 3.5, we get the desired result. □