Abstract
In a quantum many-body system where the Hamiltonian and the order operator do not commute, it often happens that the unique ground state of a finite system exhibits long-range order (LRO) but does not show spontaneous symmetry breaking (SSB). Typical examples include antiferromagnetic quantum spin systems with Néel order, and lattice boson systems which exhibits Bose–Einstein condensation. By extending and improving previous results by Horsch and von der Linden and by Koma and Tasaki, we here develop a fully rigorous and almost complete theory about the relation between LRO and SSB in the ground state of a finite system with continuous symmetry. We show that a ground state with LRO but without SSB is inevitably accompanied by a series of energy eigenstates, known as the “tower” of states, which have extremely low excitation energies. More importantly, we also prove that one gets a physically realistic “ground state” by taking a superposition of these low energy excited states.
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Notes
These energy eigenstates must not be confused with the spin-wave excitations. See the remark at the end of Sect. 3.3.
Here we mean the standard textbook treatment of superconductivity where dynamical electromagnetic field is not included.
It seems that people started observing the tower structure numerically in the early 90s when sufficiently advanced computers became available. We find, for example, partial data for the tower in Table I of [8], and a complete tower structure in Table I of [9], both for the \(S=1/2\) antiferromagnetic Heisenberg model on the square lattice.
The quotation marks indicated that they are not ground states in the standard definition in quantum mechanics.
The commutation relation \([\hat{\mathcal{O}}_L^{(1)},\hat{\mathcal{O}}_L^{(2)}]=i\hat{C}_L\) makes our discussion considerably simple, but may not be necessary. We expect that one can prove basically the same results (with much more effort) without assuming it.
The constants depend only on \(o_0\), \(h_0\), \(\zeta \), and \(q_0\). See the proof, for example (4.56), for explicit dependences.
The condition \(M_L=0\) can be replaced by the condition that \(|M_L|\) is bounded by a constant independent of L.
To be more precise it is crucial that the excitation is spread almost uniformly over the whole lattice in the state \(|\Gamma _L^M\rangle \). A state obtained by, for example, exciting a single spin from the ground state satisfies a similar bound as (3.9), but it is regarded as an excited state.
The existence of the limit \(L\uparrow \infty \), on the other hand, is not guaranteed in general (although it is very much expected). One may take a subsequence or replace \(\lim \) with \(\limsup \) or \(\liminf \) if necessary.
The order of the limits is essential here. If one takes the limit \(k\uparrow \infty \) for finite L one simply gets the maximum possible value S, which does not reflect the properties of the ground state.
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Acknowledgements
It is a pleasure to thank Hosho Katsura for his essential contribution in the derivation of (4.43), which considerably simplified the proof, and for useful comments. I also thank Tohru Koma and Haruki Watanabe for indispensable discussions and comments which made the present work possible, and Masaki Oshikawa and Masafumi Udagawa for useful discussions. The present work was supported by JSPS Grants-in-Aid for Scientific Research no. 16H02211.
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Tasaki, H. Long-Range Order, “Tower” of States, and Symmetry Breaking in Lattice Quantum Systems. J Stat Phys 174, 735–761 (2019). https://doi.org/10.1007/s10955-018-2193-8
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DOI: https://doi.org/10.1007/s10955-018-2193-8