Abstract
We introduce a \({{\mathbb {Z}}}_2\)-index for time reversal invariant Hamiltonians with unique gapped ground state on quantum spin chains. We show this is an invariant of a \(C^1\)-classification of gapped Hamiltonians. Analogous results hold for more general on-site finite group symmetry, with the 2-cohomology class as the invariant.
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Notes
We show that, for any \(C^1\)-path of interactions with the required symmetry and for any \(C^1\)-path of boundary conditions without symmetry, there must be a point at which the energy gap of a finite chain vanishes as the length of the chain increases.
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Acknowledgements
The author is grateful to Hal Tasaki for fruitful discussion which was essential for the present work. This work was supported by JSPS KAKENHI Grant Number 16K05171. Part of this paper was written during the visit of the author to CRM, with the support of CRM-Simons program “Mathematical challenges in many-body physics and quantum information”.
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Appendices
Proof of Lemma 5.1 and Lemma 5.2
In this section we prove Lemma 5.1 and Lemma 5.2. The proof is based on arguments and tools in [BMNS]. For M in Condition B, we may and will assume that \(M>2\) . Let us first recall the Lieb–Robinson bound. Fix some \(a>0\) (throughout this appendix), and define a positive function \(F_a(r)\) on \({{\mathbb {R}}}_{\ge 0}\) by \(F_a(r):=(1+r)^{-2}e^{-ar}\). For a path of interactions satisfying Definition 3.4, there exist positive constants \(C_{1,a}\), \(v_a\) satisfying the following.: For any \(X,Y\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), \(A\in {{\mathcal {A}}}_X\), \(B\in {{\mathcal {A}}}_Y\), \(k\in {\mathbb {N}}\), \(s\in [0,1]\) and \(t\in {{\mathbb {R}}}\), we have
(The inequality means that each of the left hand side can be bounded by the same value written on the right hand side. We use this way of writing below as well.) As in the proof of Theorem 2.2 [NOS], perturbation of dynamics can be estimated by the use of the Lieb–Robinson bound. In particular, by the Lieb–Robinson bound (57) and 2. of Defintion 3.4, for the fixed \(a>0\) above, there exists a constant \(C_{2,a}\) such that
for all \(t\in {{\mathbb {R}}}\), \(s\in [0,1]\), \(n\in {\mathbb {N}}\), \(Y\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), and \(A\in {{\mathcal {A}}}_Y\). Here, \(v_a\) is the same constant as in (57). Similarly, we have
for all \(t\in {{\mathbb {R}}}\), \(s\in [0,1]\), \(k\in {\mathbb {N}}\), \(Y\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), and \(A\in {{\mathcal {A}}}_Y\).
Taking \(n\rightarrow \infty \) limit in (58), we obtain
for all \(t\in {{\mathbb {R}}}\), \(s\in [0,1]\), \(Y\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), and \(A\in {{\mathcal {A}}}_Y\). This estimate tells us that if A is far away from the origin of \({{\mathbb {Z}}}\) compared to |t|, the difference between the dynamics given by \(\Phi (s)\) and \({\tilde{\Phi }}(s)\) is small.
By the same argument as in (58), for the fixed \(a>0\), there exists a positive constant \(C_{3,a}\) such
for all \(n,m\in {\mathbb {N}}\), \(n>m\), \(t\in {{\mathbb {R}}}\), \(s\in [0,1]\), \(Y\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), and \(A\in {{\mathcal {A}}}_Y\). Here, \(v_a\) is the same constant as in (57). For each \(k\in {\mathbb {N}}\), we denote by \(m_k\) the the smallest integer less than or equal to \(n_k/2\).
Proof of Lemma 5.1
We first show that
for any \(l\in {\mathbb {N}}\) and \(A\in {{\mathcal {A}}}_{\Lambda _l}\). Fix any \(l\in {\mathbb {N}}\) and \(A\in {{\mathcal {A}}}_{\Lambda _l}\). We may and we will assume that \(n_k\ge 4(M+R+l)\) for each \(k\in {\mathbb {N}}\). For each \(k\in {\mathbb {N}}\), we have
We claim
To show this, we split \(\left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \) into two parts. For each k, we denote by \(L_k\), the smallest integer less than or equal to \(\frac{n_k}{4}\). Recall also that \(m_k\) is the smallest integer less than or equal to \(\frac{n_k}{2}\). From [BMNS] proof of Theorem 4.5 and Lemma 3.2, \(\left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \) can be decomposed into an element \(\Pi _{L_k}\left( \left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \right) \) in \({{\mathcal {A}}}_{L_k}\) with \(\left\| \Pi _{L_k}\left( \left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \right) \right\| \le \left\| A\right\| \), and the rest, which is bounded from above as
The function \({\tilde{u}}(r)\), \(r>0\) on the right hand side satisfies \({\tilde{u}}(r)\rightarrow 0\), as \(r\rightarrow \infty \).
The difference \(-D_k(s)+{\hat{D}}_{k,o}(s)\) is localized at the boundary of \(\Lambda _{n_k}\). Therefore, by Lieb–Robinson bound, it almost commutes with \(\Pi _{L_k}\left( \left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \right) \) for k large enough. For simplicity, let us introduce a notation
for \(X\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), \(t\in {{\mathbb {R}}}\), \(s\in [0,1]\), and \(k\in {{\mathbb {N}}}\). We have
Set
for each \(k\in {\mathbb {N}}\) and \(X\in {{\mathfrak {S}}}_{{\mathbb {Z}}}\). We split the summation of \(X\subset \Lambda _{n_k}\) in the first term of (67) into \(X\subset \Lambda _{m_k}\) and \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \). For \(X\subset \Lambda _{m_k}\), we split the integration into \(|t|\le T_X^{k}\) part and \(|t|\ge T_X^{k}\) part. For \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \), we split the integration into \(|t|\le S_X^{k}\) part and \(|t|\ge S_X^{k}\) part.
First we consider \(X\subset \Lambda _{m_k}\) and \(|t|\le T_X^{k}\) part. From (59), and Definition 3.42., we have
Note that for \(X\subset \Lambda _{m_k}\), the distance between X and \(\left( \Lambda _{n_k-R}\right) ^c\) is at least \(n_k-R-m_k\). This is used in the equality in the second line. Recall that \(n_k-m_k-R\ge 1\) as we assumed \(n_k\ge 4(M+R+l)\) in the beginning of the proof. In the last inequality, we used the fact that for any \(j\ge 1\), the number of \(X\subset \Lambda _{m_k}\) with \(\mathop {\mathrm {diam}}\nolimits (X)<M\) such that \(d\left( X,\left( \Lambda _{n_k-R}\right) ^c\right) =j\) is at most \(2^{M}\). Note that the last line of (69) is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \).
Next we estimate the first term of (67) corresponding to \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \) and \(|t|\le S_X^{k}\) part. The corresponding part of \(-D_k(s)+{\hat{D}}_{k,o}(s)\) is not necessarily small, but it is localized at the edge of \(\Lambda _{n_k}\). Therefore, the commutator with \(\Pi _{L_k}\left( \left( {\hat{\alpha }}_s^{(k,o)}\right) ^{-1}\left( A\right) \right) \) is small. From the Lieb–Robinson bound (57), by the same kind of argument as in (69)
As we assumed that k is large enough so that \(n_k\ge 4(M+R+l)\), we have \(m_k-M-L_k\ge 1\). Therefore, in the last inequality, the number of \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \) with \(\mathop {\mathrm {diam}}\nolimits X<M\) and \(d(X,\Lambda _{L_k})=j\ge 1\) is bounded by \(2^{M}\). The last line is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \).
For \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \), and \(|t|\ge S_X^{k}\) part, we have
In the first inequality we used \(B(X,s,t,k)\le 2C_1\) and (20) and the oddness of \(W_\gamma (t)\). As we assumed that k is large enough so that \(n_k\ge 4(M+R+l)\), we have \(m_k-M-L_k\ge 1\). Therefore, in the second inequality, the number of \(X\cap \left( \Lambda _{m_k}\right) ^c\ne \emptyset \) with \(\mathop {\mathrm {diam}}\nolimits X<M\) and \(d(X,\Lambda _{L_k})=j\ge 1\) is bounded by \(2^{M}\). The right hand side is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \).
Similary, we may estimate \(X\subset \Lambda _{m_k}\) and \(|t|\ge T_X^{k}\) part.
The last line is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \).
Hence we have shown
The latter part of (67) can be estimated analogously. We divide the integral into \(|t|\le S_{X}^k\) part and \(|t|\ge S_X^{k}\) part. The \(|t|\le S_{X}^k\) part can be treated as in (70) and we have
The last line is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \). The \(|t|\ge S_{X}^k\) part can be treated as in (71) and we have
The last line is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \).
Hence we have shown
We also bound \(-D_k(s)+{\hat{D}}_{k,o}(s)\) itself. From (59)
In the second inequality, we used the fact that \(T_X^k=0\) if \(d(X,\left( \Lambda _{n_k-R}\right) ^c))=0\). The last line is finite and independent of \(s\in [0,1]\) and \(k\in {\mathbb {N}}\). Combining this with (65), we obtain
From (76) and (78), we obtain (64).
for any \(l\in {\mathbb {N}}\) and \(A\in {{\mathcal {A}}}_{\Lambda _l}\). Hence we have
for any \(A\in {{\mathcal {A}}}\). As we also have
for any \(A\in {{\mathcal {A}}}\) from [BMNS], we obtain
for any \(A\in {{\mathcal {A}}}\). From this, we have
for any \(A\in {{\mathcal {A}}}\). Hence we have proven the Lemma.
Proof of Lemma 5.2
First we prove
To prove this, for each \(X\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\) and \(k\in {\mathbb {N}}\) we set
With this \(S_X^{(k)}\), we divide the integral into \(|t|\le S_X^{(k)}\) part and \(|t|\ge S_X^{(k)}\) part. By (61) and Definition 3.42., \(|t|\le S_X^{(k)}\) part is bounded as
Here \(C_{4,a}\) is a positive constant which is independent of k, s. The right hand side is indepenednt of \(s\in [0,1]\) and converges to 0 as \(k\rightarrow \infty \). The \(|t|\ge S_X^{(k)}\) part
Here, we used Definition 3.42. for the second inequality. In the third line, we recalled the definition of \(S_X^{(k)}\) (85) and used the fact that for any finite set X in \(\Lambda _{m_k}\) with \(\mathop {\mathrm {diam}}\nolimits (X)<M\), the distance between X and \(\Lambda _{n_k}^c\) is at least \(n_k-m_k\). We also used the fact that for any \(l\ge n_k-m_k\), the number of \(X\subset \Lambda _{m_k}\) with \(\mathop {\mathrm {diam}}\nolimits (X)<M\) such that \(d(X,\Lambda _{n_k}^c)=l\) is at most \(2^{M}\). The right hand side of (87) is independent of \(s\in [0,1]\) goes to 0 as \(k\rightarrow \infty \), because of (19). Hence we have shown (84). Similarly, we have
Next we show
To prove this, for each \(X\in {{\mathfrak {S}}}_{{{\mathbb {Z}}}}\), we set
With this \(T_X\), we divide the integral into \(|t|\le T_X\) part and \(|t|\ge T_X\) part. We then have
The first part (93) is bounded by use of the (60) as
In the last line, we used \(R_X\le d(X,\{0,-1\})\le d(\{x\},\{0\})\) for all \(x\in X\) and \(d(X,\{0\})-M\le d(X,[-M,M])\le R_X\). (Recall we assumed \(M>2\) in the beginning of this section.) We also used the fact that the number of X with \(\mathop {\mathrm {diam}}\nolimits X<M\) and \(d(X,\{0\})=l\) is bounded by \(2^{M}\), and introduced a new constant \(C_{5,a}:=2^{M}M \left\| W_\gamma \right\| _1 C_1C_{2,a}e^{\frac{a}{2}{M}}\). The right hand side is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \). The second term (94) is 0 for k large enough. The third term (95) can be evaluated as in (87). We have for \(m_k>2M\),
Here we used \(d(X,\{0\})-M\le R_X\), for the second inequality.
The right hand side is independent of \(s\in [0,1]\) and goes to 0 as \(k\rightarrow \infty \). Hence we have shown (89). Similarly, we obtain
From (89), we have
Therefore, we may define
and from (84), (88), (89), (97), we obtain (27).\(\quad \square \)
On-site Group Symmetry
For a Hilbert space \({{\mathcal {K}}}\), we denote by \({{\mathcal {U}}}({{\mathcal {K}}})\) the set of all unitaries on \({{\mathcal {K}}}\). Let G be a finite group and \(w:G\rightarrow {{\mathcal {U}}}({{\mathbb {C}}}^{2S+1})\) a unitary representation of G on \({{\mathbb {C}}}^{2S+1}\). Then there is an action \(T:G\rightarrow {\mathrm {Aut}}{{\mathcal {A}}}\) of G on \({{\mathcal {A}}}\) such that
for any finite interval I of \({{\mathbb {Z}}}\). A state \(\varphi \) on \({{\mathcal {A}}}\) is G-invariant if \(\varphi \circ T_g=\varphi \) for any \(g\in G\). As \(T_g ({{\mathcal {A}}}_R)={{\mathcal {A}}}_R\), the restriction \(T_{g,R}:=\left. T_g\right| _{{{\mathcal {A}}}_R}\) is a \(*\)-automorphism on \({{\mathcal {A}}}_R\).
In [M2], Matsui introduced the projective representation of G associated to pure split G-invariant states. As in Theorem 2.2, it is unique up to unitary conjugacy and a phase, and the cohomology class is independent of the choice of the projective representation.
Theorem B.1
Let \(\varphi \) be a G-invariant pure state on \({{\mathcal {A}}}\), which satisfies the split property. Let \(\varphi _R\) be the restriciton of \(\varphi \) to \({{\mathcal {A}}}_R\), and \(({{\mathcal {H}}}_{\varphi _R},\pi _{\varphi _R},\Omega _{\varphi _R})\) be the GNS triple of \(\varphi _R\). Then there are a Hilbert space \({{\mathcal {K}}}_\varphi \), a \(*\)-isomorphism \(\iota _\varphi : \pi _{\varphi _R}\left( {{\mathcal {A}}}_R\right) {''}\rightarrow B({{\mathcal {K}}}_{\varphi })\), and a projective unitary representation \(U_\varphi :G\rightarrow {{\mathcal {U}}}({{\mathcal {K}}}_\varphi )\) on \({{\mathcal {K}}}_{\varphi }\) such that
These \({{\mathcal {K}}}_\varphi \), \(\iota _\varphi \), \(U_{\varphi }\) are unique in the following sense.: If a Hilbert space \({\tilde{{{\mathcal {K}}}}}_\varphi \), a \(*\)-isomorphism \({\tilde{\iota }}_\varphi : \pi _{\varphi _R}\left( {{\mathcal {A}}}_R\right) {''}\rightarrow B({\tilde{{{\mathcal {K}}}}}_{\varphi })\), and a projective unitary representation \({\tilde{U}}_\varphi :G\rightarrow {{\mathcal {U}}}({\tilde{{{\mathcal {K}}}}}_\varphi )\) on \({\tilde{{{\mathcal {K}}}}}_{\varphi }\) satisfy
then there is a unitary \(W:{{\mathcal {K}}}_\varphi \rightarrow {\tilde{{{\mathcal {K}}}}}_\varphi \) and \(c: G\rightarrow {{\mathbb {T}}}\) such that
In particular, the cohomology class of \(U_\varphi \) is equal to that of \({\tilde{U}}_{\varphi }\).
The same argument as the proof of Theorem 2.6 shows that the cohomology class is an invariant of factorizable automorphic equivalence, preserving G-symmetry.
Theorem B.2
Let \(\varphi _1,\varphi _2\) be G-invariant pure states satisfying the split property. Suppose that there exists an automorphism \(\alpha \) on \({{\mathcal {A}}}\) such that
Furthermore, assume that there are automorphisms \(\alpha _R\), \(\alpha _L\) on \({{\mathcal {A}}}_R\), \({{\mathcal {A}}}_L\) respectively, and a unitary W in \({{\mathcal {A}}}\) such that
and
Then the the cohomology class of the associated projective representations of \(\varphi _1\) and \(\varphi _2\) are equal.
From this, we can show that the cohomology class is invariant of \(C^1\)-classification.
Theorem B.3
Let \(\Phi :[0,1]\ni s \rightarrow \Phi (s):=\{\Phi (X;s)\}_{X\in {{\mathfrak {S}}}_{{\mathbb {Z}}}}\in {{{\mathcal {B}}}_f}\) be a \(C^1\)-path of interactions, satisfying the Condition B with
6’. For each \(s\in [0,1]\), \(\Phi (s)\) is G-invariant i.e.,
instead of 6. Then the cohomology class of the associated representation of the ground state does not change along the path.
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Ogata, Y. A \({{\mathbb {Z}}}_2\)-Index of Symmetry Protected Topological Phases with Time Reversal Symmetry for Quantum Spin Chains. Commun. Math. Phys. 374, 705–734 (2020). https://doi.org/10.1007/s00220-019-03521-5
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DOI: https://doi.org/10.1007/s00220-019-03521-5