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Growth, income distribution, and the ‘entrepreneurial state’

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Abstract

In this paper, we introduce a twofold role for the public sector in the Goodwin (1967) model of the growth cycle. The government collects income taxes in order to: (a) invest in infrastructure capital, which directly affects the production possibilities of the economy; (b) finance publicly-funded research and development (R&D), which augments the growth rate of labor productivity. We study two versions of the model, with and without induced technical change; that is, with or without a feedback from the labor share to labor productivity growth. In both cases we show that: (i) provided that the output-elasticity of infrastructure is greater than the elasticity of labor productivity growth to public R&D, there exists a tax rate that maximizes the long-run labor share, and it is smaller than the growth-maximizing tax rate; (ii) the long-run share of labor is always increasing in the share of public spending in infrastructure; (iii) different taxation schemes can affect the stability of growth cycles.

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Notes

  1. Even though this feature can actually be micro-founded (Funk 2002), the reduced form specification (5) is very flexible and allows for the model to be solved analytically.

  2. We used Mathematica11 for the simulations. The code is available from the authors upon request.

  3. Guellec and Van Pottelsberghe (2004, p.366) conclude that the elasticity of productivity growth to public research is around 0.17. However, that estimation results from using the stock of R&D, measured as the cumulated value of past R&D investment, as independent variable. This measure is inconsistent with our model, which is concerned with R&D investment flows. Accordingly, we have based our calibration on estimations found in the section of the paper where R&D investment flows are considered (Appendix 2, Table ??).

  4. Observe that, given the small size of the two average values for government spending to match, the solution will return a pretty low tax rate (which is the variable that scales government spending in our model). This, however, is harmless, because in our framework the only two uses of government spending are infrastructure spending and public R&D. Thus, the values obtained for τ and 𝜃 using our calibration strategy are those consistent with an admittedly hypothetical government sector only performing these two roles and running a balanced budget.

  5. Observe finally that the simulated employment rate can, in principle, leave the unit square, even though under our calibration it does not. This is a well-known limitation of the Goodwin model, pointed out by Desai et al. (2006). Avoiding the issue altogether would imply to drastically modify the wage-Phillips curve, and would come at the expenses of the tractability of the model.

  6. The third eigenvalue is purely real and equal to − .02, implying convergence to the limit cycle.

  7. This fact becomes apparent when reminding that Eq. 12 is obtained substituting the steady state value for the labor share into Eq. 9.

  8. Even thoughωssis an endogenous variable in the model, its steady state value is determined implicitlyby an equation that is formally similar to Eq. 14. Thus, the threshold value\(\bar {\beta }\)is fully determined once the model is parameterized.

  9. While the dynamics become unfeasible in mathematical terms, neither the employment rate nor the labor share can escape the unit box. Thus, full instability means that there will be a limit cycle corresponding to the edges of the unit box in the (e,ω) plane.

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Acknowledgements

We wish to thank participants to: the Analytical Political Economy Workshop 2016 at Queen Mary University London; the Crisis 2016 conference in Ancona and Lisa Gianmoena and Mauro Gallegati in particular; URPE at ASSA 2017 Session E1; Leila Davis for helpful comments on a previous draft; and two anonymous referees. The usual disclaimer applies.

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Appendices

Appendix A: Proof of propositions 1 and 6

1.1 A.1 The model with public R&D only

Maximizing the labor share is equivalent to minimizing the natural logarithm of its complement (that is, the share of profits) 1 − ωss as written in the RHS of Eq. 11. We have that

$$\frac{\partial\ln(1-\omega_{ss})}{\partial\tau}=\frac{1}{1-\tau}-\left( \frac{\eta-\phi}{1-\eta}\right)\frac{1}{\tau}, $$

and

$$\frac{\partial^{2}\ln(1-\omega_{ss})}{\partial\tau^{2}}=\frac{1}{(1-\tau)^{2}}+\left( \frac{\eta-\phi}{1-\eta}\right)\frac{1}{\tau^{2}}>0. $$

Because the steady state profit share is a convex function of τ, the first order condition ln(1 − ωss)/τ = 0 is necessary and sufficient for a minimum. It has an interior solution in

$$\tau_{\omega}=\frac{\eta-\phi}{1-\phi}\in(0,1). $$

1.2 A.2 Public R&D and induced technical change

In order to prove the same result in the general model, totally differentiate Eq. 14 with respect to ω and τ to find

$$\left( \frac{(1-\omega_{ss})\beta+(1-\eta)\omega_{ss}}{\omega_{ss}^{1-\beta}(1-\omega_{ss})^{2-\eta}}\right)d\omega=\cfrac{s^{1-\eta}\theta^{\eta}}{\lambda(1-\theta)^{\phi}}\left( \cfrac{\eta-\phi-\tau(1-\phi)}{(1-\tau)^{\eta}\tau^{1-(\eta-\phi)}}\right)d\tau, $$

hence,

$$ \frac{d\omega}{d\tau}=\cfrac{s^{1-\eta}\theta^{\eta}}{\lambda(1-\theta)^{\phi}}\cfrac{\omega_{ss}^{1-\beta}\left( 1-\omega_{ss}\right)^{2-\eta}}{(1-\tau)^{\eta}\tau^{1-(\eta-\phi)}}\cfrac{[\eta-\phi-\tau(1-\phi)]}{[(1-\omega_{ss})\beta+(1-\eta)\omega_{ss}]}. $$
(16)

The denominator is always positive. It follows that \(Sign\frac {d\omega }{d\tau }=Sign[\eta -\phi -\tau (1-\phi )]\), which proves that the labor share is maximized by \(\tau _{\omega }=\frac {\eta -\phi }{1-\phi }.\)

Appendix B: Composition of public expenditure

1.1 B.1 The model with public R&D only

Start with

$$0\leq\frac{\lambda^{\frac{1}{1-\eta}}(1-\theta)^{\frac{\phi}{1-\eta}}}{s(1-\tau)\tau^{\frac{\eta-\phi}{1-\eta}}\theta^{\frac{\eta}{1-\eta}}}\leq1, $$

and re-write the second inequality as

$$\frac{(1-\theta)^{\frac{\phi}{1-\eta}}}{\theta^{\frac{\eta}{1-\eta}}}\equiv m(\theta)\leq(1-\tau)\tau^{\frac{\eta-\phi}{1-\eta}}s/\lambda^{\frac{1}{1-\eta}}\equiv h(\tau). $$

m(𝜃) is monotonically decreasing in 𝜃, with \(lim_{\theta \rightarrow 0^{+}}=\infty \), and m(1) = 0.h(τ) is hump-shaped, has a maximum in \(\tau _{\omega }=\frac {\eta -\phi }{1-\phi }\), with h(0) = h(1) = 0, and \(h(\tau _{\omega })=\frac {\eta -\phi }{1-\phi }^{\frac {\eta -\phi }{1-\phi }}\left (\frac {1-\eta }{1-\phi }\right )s/\lambda ^{\frac {1}{1-\eta }}\). We need \(m(\theta )\leq h(\tau )\leq \frac {\eta -\phi }{1-\phi }^{\frac {\eta -\phi }{1-\phi }}\left (\frac {1-\eta }{1-\phi }\right )s/\lambda ^{\frac {1}{1-\eta }},\) so that \(\theta \geq m^{-1}\left [\frac {\eta -\phi }{1-\phi }^{\frac {\eta -\phi }{1-\phi }}\left (\frac {1-\eta }{1-\phi }\right )s/\lambda ^{\frac {1}{1-\eta }}\right ]\equiv \bar {\theta }\). For any feasible \(\theta >\bar {\theta }\) there is a tax rate τmax(𝜃) such that m(𝜃) = h[τmax(𝜃)]. Since h(.) is decreasing in the relevant range, it follows that ττmax. Moreover, τmax(𝜃) is an increasing function because, for \(\theta \geq \bar {\theta }\), both m(.) and h(.) are decreasing functions.

1.1.1 B.1.1 Proof of proposition 2

i) Since \(\tau _{max}(\bar {\theta })=\tau _{\omega },\) then \(\tau _{g}(\bar {\theta })=\tau _{max}(\bar {\theta })=\tau _{\omega }.\) Next, ii) since \(\tau _{max}(\theta )\in (\tau _{\omega },1),\forall \theta >\bar {\theta }\), it follows that τg(𝜃) = τmax(𝜃) > τω.

1.1.2 B.1.2 Proof of proposition 3

Start with \(\tilde {g}_{A,ss}(\theta )=\lambda \left [(1-\theta )\tau _{g}(\theta )\right ]^{\phi }.\) Let G(𝜃) ≡ (1 − 𝜃)τg(𝜃), so that \(\tilde {g}_{A,ss}(\theta )=\lambda [G(\theta )]^{\phi }\) and \(\tilde {g}_{A,ss}^{\prime }(\theta )=\lambda \phi G^{\prime }(\theta )/[G(\theta )]^{1-\phi }\). We have \(sign(\tilde {g}_{A,ss}^{\prime })=sign(G^{\prime }),\) which implies that \(\tilde {g}_{A,ss}\) and G have the same stationary points. Let us now analyze \(G^{\prime }(\theta )=(1-\theta )\tau _{g}^{\prime }(\theta )-\tau _{g}(\theta ).\) All we know about \(\tau _{g}^{\prime }(\theta )\) is \(\tau _{g}^{\prime }(\theta )>0\), while we know that τg(𝜃) is an increasing function from τω to arbitrarily close to 1. This implies \(lim_{\theta \rightarrow 1^{-}}G^{\prime }(\theta )=-1\) so that gA(𝜃) is decreasing in a left neighborhood of − 1. Starting from − 1, a reduction in 𝜃 increases the growth rate \(\tilde {g}_{A,ss}\) as long as G(𝜃) < 0. There is no guarantee that G(𝜃) will go through 0 as 𝜃 moves from 1 to \(\bar {\theta }\). If it does, there is a stationary point 𝜃 that solves \((1-\theta ^{*})=\tau _{g}(\theta ^{*})/\tau _{g}^{\prime }(\theta ^{*})\) and it is a maximum; if it does not, growth is maximized by the lowest admissible composition of public expenditure \(\bar {\theta }.\)

1.2 B.2 Public R&D and induced technical change

1.2.1 B.2.1 Proof of proposition 7

Taking logs in Eq. 5 evaluated at the steady state, we have \(\ln g_{A}=\ln \left [\lambda (1-\theta )^{\phi }\tau ^{\phi }\omega (\tau ,\theta )_{ss}^{\beta }\right ]=\ln \lambda +\phi \ln (1-\theta )+\phi \ln \tau +\beta \ln \omega (\tau ,\theta )_{ss}.\) Hence, \(\frac {d\ln g_{A}}{d\tau }=\cfrac {\phi }{\tau }+\cfrac {\beta }{\omega }\frac {d\omega }{d\tau }\). Setting \(\frac {d\ln g_{A}}{d\tau }= 0,\) while using Eq. 16 we have

$$\cfrac{1}{\tau}\left[\phi+\cfrac{\beta}{\lambda}\cfrac{\left( 1-\omega_{ss}\right)^{2-\eta}}{\omega_{ss}^{\beta}}\cfrac{s^{1-\eta}\theta^{\eta}}{(1-\theta)^{\phi}}\cfrac{\tau_{g}^{\eta-\phi}}{(1-\tau_{g})^{\eta}}\cfrac{[\eta-\phi-\tau_{g}(1-\phi)]}{[(1-\omega_{ss})\beta]+(1-\eta)\omega_{ss}]}\right]= 0, $$

or

$$\phi=\cfrac{\beta}{\lambda}\cfrac{\left( 1-\omega_{ss}\right)^{2-\eta}}{\omega_{ss}^{\beta}}\cfrac{s^{1-\eta}\theta^{\eta}}{(1-\theta)^{\phi}}\cfrac{\tau_{g}^{\eta-\phi}}{(1-\tau_{g})^{\eta}}\cfrac{[\tau_{g}(1-\phi)-(\eta-\phi)]}{[(1-\omega_{ss})\beta+(1-\eta)\omega_{ss}]}, $$

which requires τg(1 − ϕ) > ηϕ, or \(\tau _{g}>\frac {\eta -\phi }{1-\phi }.\)

1.2.2 B.2.2 Growth-maximizing composition of public expenditure

With respect to the growth-maximizing composition of public expenditure (𝜃), totally differentiate Eq. 14 with respect to ω and τ to find

$$\cfrac{d\omega}{d\theta}=\left( \cfrac{[s(1-\tau)]^{1-\eta}\tau^{\eta-\phi}}{\lambda}\right)\left( \cfrac{\eta-\theta(\eta-\phi)}{\theta^{1-\eta}(1-\theta)^{1+\phi}}\right)\left( \frac{\omega_{ss}^{\beta-1}\left( 1-\omega_{ss}\right)^{2-\eta}}{(1-\omega_{ss})\beta+(1-\eta)\omega_{ss}]}\right). $$

Next, set \(\frac {d\ln g_{A}}{d\theta }=\cfrac {-\phi }{1-\theta }+\cfrac {\beta }{\omega }\frac {d\omega }{d\theta }= 0\), to find

$$\cfrac{[s(1-\tau)]^{1-\eta}\tau^{\eta-\phi}}{\lambda}\cfrac{\eta-\theta^{*}(\eta-\phi)}{[(1-\omega_{ss})\beta+(1-\eta)\omega_{ss}]}\frac{\left( 1-\omega_{ss}\right)^{2-\eta}}{\omega_{ss}^{2-\beta}}=\cfrac{\phi}{\beta}\theta^{*(1-\eta)}(1-\theta^{*})^{\phi}. $$

Appendix: C: Uniqueness of the steady state in the model with induced technical change

Rewrite Eq. 14 as

$$\omega_{ss}^{\beta}=\cfrac{\left[s(1-\tau)\right]^{1-\eta}\tau^{\eta-\phi}\theta^{\eta}}{\lambda(1-\theta)^{\phi}}\left( 1-\omega_{ss}\right)^{1-\eta}\equiv{\Gamma}(\tau,\theta)\left( 1-\omega_{ss}\right)^{1-\eta}, $$

where Γ(τ,𝜃) > 0. Raise both sides of the equation to the power 1/β and rearrange to find:

$$\omega_{ss}-\left( {\Gamma}(\tau,\theta)\right)^{\frac{1}{\beta}}\left( 1-\omega_{ss}\right)^{\frac{1-\eta}{\beta}}= 0. $$

The left hand side is the difference between two continuous functions of ω, with ω ∈ [0, 1]. The first one increases linearly from 0 to 1; the second one is a power function decreasing from \(\left ({\Gamma }(\tau ,\theta )\right )^{\frac {1}{\beta }}\)to 0. Therefore, the left hand side is a continuous function that starts from \(-\left ({\Gamma }(\tau ,\theta )\right )^{\frac {1}{\beta }}\)and increases monotonically to 1: it crosses the horizontal axis once and only once. By Eqs. 12 and 13, both χss and ess are monotonic functions of the labor share: if the steady state value of the latter is unique, so are the former.

Appendix D: Stability analysis

1.1 D.1 Proof of proposition 8 - income tax with induced technical change

Linearization of the system formed by Eqs. 67 and 8 around its steady state position, when β ∈ (0, 1), yields the following Jacobian matrix:

$$\begin{array}{ll} J(\chi_{ss},e_{ss},\omega_{ss}) & =\left[\begin{array}{ccc} J_{11} & 0 & J_{13}\\ 0 & 0 & J_{23}\\ 0 & J_{32} & J_{33} \end{array}\right], \end{array} $$

with

$$\begin{array}{ll} J_{11} & =-\tau\theta\chi_{ss}^{\eta-1}<0;\\ J_{13} & =s(1-\tau)\chi_{ss}^{1+\eta}>0;\\ J_{23} & =-e_{ss}\left\{ (1-\eta)s(1-\tau)\chi_{ss}^{\eta}+\lambda\beta[(1-\theta)\tau]^{\phi}\omega^{\beta-1}\right\} <0;\\ J_{32} & =\delta^{-1}e_{ss}^{\frac{1-\delta}{\delta}}\omega_{ss}>0;\\ J_{33} & =-\lambda\beta\left( (1-\theta)\tau\right)^{\phi}\omega_{ss}^{\beta}<0. \end{array} $$

The Routh-Hurwitz necessary and sufficient conditions for stability of the steady state require that:

  1. 1.

    TrJ < 0. We have that TrJ = J11 + J33 < 0 as required.

  2. 2.

    DetJ < 0. We have that DetJ = J11 × (−J23J32) < 0 as required.

  3. 3.

    PmJ > 0, where PmJ denotes the sum of the principal minors of J. In fact, PmJ = −J23J32 + J11J33 > 0 as required.

  4. 4.

    Finally, we need to check that − PmJ + DetJ/TrJ < 0. Since TrJ < 0, the condition can be rewritten as DetJ > TrJ(PmJ). We have \(-J_{11}J_{23}J_{32}>\left (J_{11}+J_{33}\right )\left [-J_{23}J_{32}+J_{11}J_{33}\right ]=-J_{11}J_{23}J_{32}-J_{33}J_{23}J_{32}+J_{11}^{2}J_{33}+J_{11}J_{33}^{2}\), ⇔\(0>J_{33}\left (-J_{23}J_{32}+J_{11}^{2}+J_{11}J_{33}\right ),\) which is always true.

Notice that the stability conditions hold for any value of the main parameters of the model s ∈ (0, 1],τ ∈ (0, 1),𝜃 ∈ (0, 1],η ∈ [0, 1).

1.2 D.2 Proof of proposition 4 - income tax with public R&D only

Linearization of the system formed by Eqs. 67 and 8 around its steady state position, evaluated at β = 0, yields the following Jacobian matrix:

$$\begin{array}{ll} J(\chi_{ss},e_{ss},\omega_{ss}) & =\left[\begin{array}{ccc} J_{11} & 0 & J_{13}\\ 0 & 0 & J_{23}\\ 0 & J_{32} & 0 \end{array}\right], \end{array} $$

with

$$\begin{array}{ll} J_{11} & =-\tau\theta\chi_{ss}^{\eta-1}<0;\\ J_{13} & =s(1-\tau)\chi_{ss}^{1+\eta}>0;\\ J_{23} & =-(1-\eta)s(1-\tau)\chi_{ss}^{\eta}e_{ss}<0;\\ J_{32} & =\delta^{-1}e_{ss}^{\frac{1-\delta}{\delta}}\omega_{ss}>0. \end{array} $$

The Routh-Hurwitz necessary and sufficient conditions for stability of the steady state require that:

  1. 1.

    TrJ < 0. We have that TrJ = J11 < 0 as required.

  2. 2.

    DetJ < 0. We have that DetJ = J11 × (−J23J32) < 0 as required.

  3. 3.

    PmJ > 0, where PmJ denotes the sum of the principal minors of J. It is easy to check that, in fact, PmJ = −J23J32 > 0 as required.

  4. 4.

    Finally, we need to check that − PmJ + DetJ/TrJ < 0. This condition is violated. In fact, DetJ/TrJ = Pm1J = PmJ, so we have − PmJ + PmJ = 0. As illustrated by Julius (2006), when the fourth condition goes from negative (see the previous appendix) through zero, the Hopf bifurcation theorem implies that the system has a family of closed orbits in a neighborhood of the steady state. This is happening as β goes from positive to zero.

Notice that, as long as β = 0, the above properties are not sensitive to alternative parametric specifications: the entries of the Jacobian matrix will not change signs as long as s ∈ (0, 1],τ ∈ (0, 1),𝜃 ∈ (0, 1],η ∈ [0, 1). Thus, the limit cycle is robust in the parameter space.

1.3 D.3 Proof of proposition 9 - profit tax

The Jacobian matrix evaluated at the steady state has the following structure:

$$\begin{array}{ll} J(\chi_{ss},e_{ss},\omega_{ss}) & =\left[\begin{array}{ccc} J_{11} & 0 & 0\\ 0 & 0 & J_{23}\\ 0 & J_{32} & J_{33} \end{array}\right], \end{array} $$

with

$$\begin{array}{ll} J_{11} & =-\tau\theta(1-\omega)\chi_{ss}^{\eta-1}<0;\\ J_{23} & =-\frac{e_{ss}}{\omega_{ss}(1-\omega)_{ss}}g_{A,ss}[\omega_{ss}(1-\phi)+\beta(1-\omega_{ss})]<0;\\ J_{32} & =\delta^{-1}e_{ss}^{\frac{1-\delta}{\delta}}\omega_{ss}>0;\\ J_{33} & =-\frac{g_{A,ss}}{1-\omega_{ss}}[\beta(1-\omega_{ss})-\phi\omega_{ss}]. \end{array} $$

With \(\beta \in [0,\frac {\phi \omega _{ss}}{1-\omega _{ss}})\), J33 > 0 and the steady state is unstable. With \(\beta =\frac {\phi \omega _{ss}}{1-\omega _{ss}},J_{33}= 0\), which is the limit cycle case. With \(\beta >\frac {\phi \omega _{ss}}{1-\omega _{ss}},J_{33}<0\), and the steady state is stable.

1.4 D.4 Wage tax with public R&D only

The Jacobian matrix evaluated at the steady state has the following structure:

$$\begin{array}{ll} J(\chi_{ss},e_{ss},\omega_{ss}) & =\left[\begin{array}{ccc} J_{11} & 0 & J_{13}\\ 0 & 0 & J_{23}\\ 0 & J_{32} & J_{33} \end{array}\right], \end{array} $$

with

$$\begin{array}{ll} J_{11} & =-\tau\theta\omega\chi_{ss}^{\eta-1}<0;\\ J_{23} & =\frac{e_{ss}}{\omega_{ss}(1-\omega)_{ss}}g_{A,ss}[\eta-\omega_{ss}-(1-\omega_{ss})(\phi+\beta)];\\ J_{32} & =\delta^{-1}e_{ss}^{\frac{1-\delta}{\delta}}\omega_{ss}>0;\\ J_{33} & =-\frac{g_{A,ss}}{\omega}[\beta+\phi]<0. \end{array} $$

The condition η < ωss is sufficient for J23 < 0, which ensures local stability. This condition is verified under our parameterization: as mentioned in Section 3.3, estimates for η are around 15%, way below the long-run value of the labor share.

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Tavani, D., Zamparelli, L. Growth, income distribution, and the ‘entrepreneurial state’. J Evol Econ 30, 117–141 (2020). https://doi.org/10.1007/s00191-018-0555-7

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