Abstract
We prove bounds on the number of incidences between a set of algebraic curves in \({\mathbb C}^2\) and a Cartesian product \(A\times B\) with finite sets \(A,B\subset {\mathbb C}\). Similar bounds are known under various restrictive conditions, but we show that the Cartesian product assumption leads to a simpler proof and lets us remove these conditions. This assumption holds in a number of interesting applications, and with our bound these applications can be extended from \({\mathbb R}\) to \({\mathbb C}\). We also obtain more precise information in the bound, which is used in several recent papers (Raz et al., 31st international symposium on computational geometry (SoCG 2015), pp 522–536, 2015, [17], Valculescu, de Zeeuw, Distinct values of bilinear forms on algebraic curves, 2014, [25]). Our proof works via an incidence bound for surfaces in \({\mathbb R}^4\), which has its own applications (Raz, Sharir, 31st international symposium on computational geometry (SoCG 2015), pp 569–583, 2015, [15]). The proof is a new application of the polynomial partitioning technique introduced by Guth and Katz (Ann Math 181: 155–190, 2015, [11]).
The first author was supported by ERC Advanced Research Grant no. 321104, by Hungarian National Research Grant NK 104183, and by NSERC. The second author was partially supported by Swiss National Science Foundation Grants 200020-144531 and 200021-137574. Part of this research was performed while the authors visited the Institute for Pure and Applied Mathematics (IPAM) in Los Angeles, which is supported by the National Science Foundation.
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Notes
- 1.
This could fail if a cutting point were a singularity (although even then the number of branches could be controlled with some more effort).
- 2.
This fact can be obtained more directly using Lemma 6 below, by noting that the union of the lines is a curve defined by a polynomial f of degree O(r), so \(C\backslash Z(f)\) has O(dr) connected components. However, we have used the argument above because it will play a crucial role in the proof of our main theorem.
- 3.
Note that the dimension of a reducible variety is the maximum of the dimensions of its components, so a curve can have zero-dimensional components. The degree of a reducible variety is the sum of the degrees of its components, so a curve of degree d with k zero-dimensional components has a purely one-dimensional component of degree \(d-k\).
- 4.
Here too a curve may have zero-dimensional components (isolated points), but in \({\mathbb R}^2\) a point (a, b) is defined by a single polynomial \((x-a)^2+(y-b)^2\).
- 5.
Note that \(X_1\times {\mathbb R}^2\) is defined by a polynomial g of degree \(2|X_1|=O(r^2)\). Thus, applying Lemma 6 to \(S_1\backslash Z_{{\mathbb R}^4}(g)\) gives \(O(d^2r\cdot r^2)\), which is too large. This is why we need a more refined argument, using the specific nature of \(X_1\times {\mathbb R}^2\).
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Solymosi, J., de Zeeuw, F. (2018). Incidence Bounds for Complex Algebraic Curves on Cartesian Products. In: Ambrus, G., Bárány, I., Böröczky, K., Fejes Tóth, G., Pach, J. (eds) New Trends in Intuitive Geometry. Bolyai Society Mathematical Studies, vol 27. Springer, Berlin, Heidelberg. https://doi.org/10.1007/978-3-662-57413-3_16
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