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- 1.$$ \mathrm{If}\kern0.24em \frac{{\mathrm{ft}}^3}{\sec }=\frac{1\kern0.24em \mathrm{gal}}{\min}\times \frac{1\kern0.24em \min }{60.0\kern0.24em \sec}\times \frac{1\kern0.24em {\mathrm{ft}}^3}{7.40\kern0.24em \mathrm{gal}}=2.25\times {10}^{-3}\kern0.24em \frac{{\mathrm{ft}}^3}{\sec}\mathrm{then}\kern0.24em \frac{1\kern0.24em \mathrm{gal}}{\min }=\frac{2.25\times {10}^{-3}\kern0.24em {\mathrm{ft}}^3}{1\kern0.24em \sec } $$
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Field, H.L., Long, J.M. (2018). Irrigation. In: Introduction to Agricultural Engineering Technology. Springer, Cham. https://doi.org/10.1007/978-3-319-69679-9_19
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DOI: https://doi.org/10.1007/978-3-319-69679-9_19
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