Abstract
Recall [S, (12.1)] that an (F t ) stopping time, T, is a weak terminal time provided (i) for each t, \(t + T \circ {{\theta }_{t}} = T\) a.s. on t < T, and that T is exact if, in addition, (ii) \({{t}_{n}} + T \circ {{\theta }_{{{{t}_{n}}}}} \downarrow T\) a.s. whenever tn ↓↓ 0. If T is an exact weak terminal time, then according to [S, (55.20)] there exists an (F t ) stopping time S with S = T a.s. and such that (iii) t + S(θ t ω) = S(ω) for all t,ω with t < S(ω) and (iv) \(S(\omega ) = \downarrow \mathop{{\lim }}\limits_{{t \downarrow 0}} [t + S({{\theta }_{t}}\omega )]\) for every ω. It follows from (iii) and (iv) that t → t + S(θ t ω) is right continuous and increasing on [0, ∞[ for every ω. For simplicity we define a terminal time S to be an (Ft) stopping time that satisfies (iii), and we say that S is exact if, in addition, it satisfies (iv). In this language, [S, (55.20)] states that an exact weak terminal time is equal a.s. to an exact terminal. Note that if S is a terminal time, then (iii) implies that \(t \to t + S \circ {{\theta }_{t}}\) is increasing and one readily checks that \({{S}^{*}}: = \downarrow \mathop{{\lim }}\limits_{{t \downarrow 0}} (t + S \circ {{\theta }_{t}})\) is an exact terminal time called the exact regularization of S. Of course, if B ∈ εe then T B : = inf {t > 0: X t ∈ B} is an exact terminal time in the above sense, while D B : = inf {t ≥ 0: X t ∈ B} is a terminal time. Moreover T B is the exact regularization of D B .
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© 1990 Birkhäuser Boston
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Getoor, R.K. (1990). Balayage of Excessive Measures. In: Excessive Measures. Probability and Its Applications. Birkhäuser Boston. https://doi.org/10.1007/978-1-4612-3470-8_4
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DOI: https://doi.org/10.1007/978-1-4612-3470-8_4
Publisher Name: Birkhäuser Boston
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