Large Deformations
Chapter
Abstract
Let z0 = R0ζ0 be half the length of the shape and z = R0ζ, ϱ = ϱ (ζ) be the dimensionless z-coordinate and the axially symmetric shape function in cylindrical coordinates, respectively, then the relevant quantities are calculated from multiple integrals (if not otherwise noted, integrals run from − ζ0 to + ζ0). In the natural units of Chap. 1,
$$ \begin{gathered} Q_l = \frac{{4\pi }}{{2l + 3}}\int {\text{d}\zeta (} \varrho ^2 + \zeta ^2 )^{l/2 + 1} [\text{P}_l (x) - \text{P}_{l + 2} (x)] \hfill \\ \text{Where}\,x = \frac{\zeta }{{\sqrt {\varrho ^2 + \zeta ^2 } }} \hfill \\ \end{gathered} $$
(7.1)
$$ \begin{gathered} Q = \frac{\pi }{2}\int {\text{d}\zeta \,\varrho ^\text{2} (4\zeta ^2 - \varrho ^2 )} \hfill \\ Q_4 = \frac{\pi }{4}\int {\text{d}\zeta \text{ }\varrho ^\text{2} (8\zeta ^4 - } 12\zeta ^2 \varrho ^2 + \varrho ^4 \hfill) \\ \end{gathered} $$
(7.2)
$$ \begin{gathered} r^2_\text{rms = }\frac{\text{3}}{\text{8}}\int {\text{d}\zeta \varrho ^2 \text{(2}\zeta ^\text{2} + \varrho ^2 } ) \hfill \\ \overline {(\delta r)^2 } = \frac{1}{2}\int {\text{d}\zeta } \varrho \frac{{e - \zeta \varrho \prime}}{{(\varrho ^2 + \zeta ^2 )^{3/2} }}\left( {\sqrt {\varrho ^2 + \zeta ^2 - 1} } \right)^2 \hfill \\ \end{gathered} $$
(7.3)
$$ \begin{gathered} J_\parallel = \frac{{15}}{{16}}\int {\text{d}\zeta \varrho ^\text{4} } \hfill \\ J_ \bot = \frac{{15}}{{32}}\int {\text{d}\zeta \varrho ^\text{2} (4\zeta ^2 + \varrho ^2 )} \hfill \\ \end{gathered} $$
(7.4)
$$\begin{gathered}
{B_{{\text{surf }}}}{\text{ = }}\frac{1}{2}\int {d\zeta } \varrho \sqrt {1 + \varrho {'^2}} {\text{ }} \hfill \\
{\text{ with }}\varrho ' = {\text{d}}\varrho (\zeta )/{\text{d}}\zeta {\text{.}} \hfill \\
\end{gathered} $$
(7.5)
Keywords
Natural Unit Coulomb Energy Volume Conservation Symmetric Shape Fission Barrier
These keywords were added by machine and not by the authors. This process is experimental and the keywords may be updated as the learning algorithm improves.
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© Springer-Verlag Berlin Heidelberg 1988