1 Erratum to: Eur. Phys. J. C (2019) 79:679 https://doi.org/10.1140/epjc/s10052-019-7189-2

  1. 1.

    The Eq. (45) should read

    $$\begin{aligned} s=s_0\rho ^{1-\frac{1}{2w_2}}r^{-\frac{1+w_2}{w_2}}\sqrt{\frac{1-2m/r}{1-2\bar{m}/r}}, \end{aligned}$$
    (1)

    where \(\bar{m}=m-M\).

  2. 2.

    Contrary to the Lagrangian (37) which is deduced from the first principle, there is no guarantee that the trial Lagrangian (39) represents the true entropy for \(w_1=-1\) although it matches well for \(w_1\ne -1\) cases.

    The Lagrangian corresponding to ab in Eq. (44) is

    $$\begin{aligned} \mathcal {L}~\propto ~ (\bar{m}')^{1-\frac{1}{2w_2}}r^{-1}/\sqrt{1-2\bar{m}/r}. \end{aligned}$$
    (2)

    However, if the solutions are analytic around \(w_1=-1\), the \(w_1\rightarrow -1\) limit of the Lagrangian (37) gives

    $$\begin{aligned} \lim _{w_1\rightarrow -1}\mathcal {L}~\propto ~ (m')^{1-\frac{1}{2w_2}}r^{-1}, \end{aligned}$$
    (3)

    which is different from the above Lagrangian. Thus, one should be cautious in using the entropy density for \(w_1=-1\).

    Therefore, the exact form of the entropy density for \(w_1=-1\) should be derived by taking \(w_1\rightarrow -1\) limit of the entropy function Eq. (47). The entropy density so obtained has the form

    $$\begin{aligned} s=s_0\rho ^{1-\frac{1}{2w_2}}r^{-\frac{1+w_2}{w_2}}\sqrt{1-2m/r}. \end{aligned}$$
    (4)