Expansion of the Gravitational Field Hamiltonian
Let us expand the gravitational field Hamiltonian in a series,
$$H = \frac{1}{{\sqrt \gamma }}\left( {{{\pi }_{{st}}}{{\pi }^{{st}}} - \frac{1}{2}{{\pi }^{2}}} \right) - \sqrt \gamma R{\kern 1pt} .$$
The leading order depends on the classical part alone and is a \(c\)-number,
$${{H}_{0}} = \frac{1}{{\sqrt F }}\left( {{{F}_{{{{n}_{{st}}}}}}F_{n}^{{st}} - \frac{1}{2}F_{n}^{2}} \right) - \sqrt F R(F),$$
and the next-to-leading order is linear with respect to quantum additions and derivatives with respect to them,
$$\begin{gathered} {{H}_{1}} = \frac{1}{{\sqrt F }}\left( {\frac{1}{2}\left( {{{F}_{{{{n}_{{kl}}}}}}F_{n}^{{kl}} - \frac{1}{2}F_{n}^{2}} \right)} \right.{{F}^{{st}}}{{{\hat {Q}}}_{{st}}} \\ \left. {\frac{{}}{{}} + \,\,\left( {{{{\hat {P}}}^{{st}}}{{F}_{{{{n}_{{st}}}}}} + F_{n}^{{st}}{{S}_{{st}}}} \right) - {{F}_{n}}\left( {{{{\hat {P}}}^{{st}}}{{F}_{{{{n}_{{st}}}}}} + {{{\hat {Q}}}_{{st}}}F_{n}^{{st}}} \right)} \right) \\ - \,\,\sqrt F \left( {\frac{1}{2}{{F}^{{st}}}{{R}_{{st}}}(F){{{\hat {Q}}}_{{st}}} - {{{\hat {Q}}}^{{st}}}{{R}_{{st}}}(F) + {{F}^{{st}}}{{R}_{{st}}}(F,\hat {Q})} \right). \\ \end{gathered} $$
Let us consider the term \(a\sqrt F {{F}^{{st}}}{{R}_{{st}}}(F,\hat {Q}).\) We recall that \(\Gamma _{{lt}}^{s} = {{\gamma }^{{sp}}}{{\Gamma }_{{ltp}}},\) and the Christoffel numbers are series,
$${{\Gamma }_{{ltp}}} = {{\Gamma }_{{ltp}}}(F) + \frac{1}{g}{{\Gamma }_{{ltp}}}(\hat {Q}) + \frac{1}{{{{g}^{2}}}}{{\Gamma }_{{ltp}}}(A),$$
so
$$\Gamma _{{lt}}^{s} = \Gamma _{{lt}}^{s}(F) + \frac{1}{g}\Gamma _{{lt}}^{s}(\hat {Q}),$$
where
$$\Gamma _{{lt}}^{s}(\hat {Q}) = \left( {{{F}^{{sp}}}{{\Gamma }_{{ltp}}}(\hat {Q}) - {{{\hat {Q}}}^{{sp}}}{{\Gamma }_{{ltp}}}(F)} \right).$$
Taking into account that
$${{\hat {Q}}_{{t{{p}_{{;l}}}}}} = {{\hat {Q}}_{{t{{p}_{{,l}}}}}} - \Gamma _{{lt}}^{m}(F){{\hat {Q}}_{{mp}}} - \Gamma _{{lp}}^{m}(F){{\hat {Q}}_{{mt}}},$$
we note that
$${{\Gamma }_{{ltp}}}(\hat {Q}) = \frac{1}{2}\left( {{{{\hat {Q}}}_{{tp{{;}_{l}}}}} + {{{\hat {Q}}}_{{lp{{;}_{t}}}}} - {{{\hat {Q}}}_{{lt{{;}_{p}}}}}} \right) - 2{{\hat {Q}}_{{mp}}} + \Gamma _{{lt}}^{m}(F),$$
and it can be stated that
$$\Gamma _{{lt}}^{s}(\hat {Q}) = \frac{1}{2}{{F}^{{sp}}}\left( {{{{\hat {Q}}}_{{tp{{;}_{l}}}}} + {{{\hat {Q}}}_{{lp{{;}_{t}}}}} - {{{\hat {Q}}}_{{lt{{;}_{p}}}}}} \right),$$
so the Ricci tensor is also a series,
$${{R}_{{st}}} = {{R}_{{st}}}(F) + \frac{1}{g}{{R}_{{st}}}(F,\hat {Q}) + \frac{1}{{{{g}^{2}}}}{{R}_{{st}}}(F,\hat {Q},A),$$
where
$$\begin{gathered} {{R}_{{st}}}(F,\hat {Q}) = \Gamma _{{st{{;}_{l}}}}^{l}(\hat {Q}) - \Gamma _{{st{{;}_{t}}}}^{l}(\hat {Q}) \\ + \,\,\Gamma _{{st}}^{l}(\hat {Q})\Gamma _{{lm}}^{m}(F) + \Gamma _{{st}}^{l}(F)\Gamma _{{lm}}^{m}(\hat {Q}) \\ - \,\,\Gamma _{{sl}}^{m}(\hat {Q})\Gamma _{{mt}}^{l}(F) - \Gamma _{{sl}}^{m}(F)\Gamma _{{mt}}^{l}(F), \\ \end{gathered} $$
so that
$${{R}_{{st}}}(F,\hat {Q}) = {{\left( {\Gamma _{{st}}^{l}(\hat {Q})} \right)}_{{;l}}} - {{\left( {\Gamma _{{sl}}^{l}(\hat {Q})} \right)}_{{;t}}},$$
and the considered term is equal to
$$\begin{gathered} a\sqrt F {{F}^{{st}}}{{R}_{{st}}}(F,\hat {Q}) = \sqrt F \left( {a{{F}^{{st}}}\Gamma _{{st}}^{l}(\hat {Q})} \right){{,}_{l}} \\ - \,\,\sqrt F \left( {a{{F}^{{st}}}\Gamma _{{sl}}^{l}(\hat {Q})} \right){{,}_{t}} + \sqrt F {{F}^{{st}}}{{a}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}) \\ - \,\,\sqrt F {{F}^{{st}}}{{a}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}); \\ \end{gathered} $$
here,
$${{c}^{s}} = {{a}_{{;t}}}{{F}^{{st}}}.$$
Let us consider the form
$$\sqrt F {{F}^{{st}}}{{a}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}) = \sqrt F {{c}^{s}}\frac{1}{2}{{F}^{{lp}}}\left( {{{{\hat {Q}}}_{{sp{{;}_{l}}}}} + {{{\hat {Q}}}_{{lp{{;}_{s}}}}} - {{{\hat {Q}}}_{{sl{{;}_{p}}}}}} \right).$$
We take into account that the following expression is zero:
$${{F}^{{lp}}}\left( {{{{\hat {Q}}}_{{sp{{;}_{l}}}}} - {{{\hat {Q}}}_{{sl{{;}_{p}}}}}} \right) = 0,$$
since it contains the product \({\text{of}}\) the symmetric and antisymmetric tensors. Similarly,
$$\sqrt F {{F}^{{st}}}{{a}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}) = \frac{1}{2}{{\left( {\sqrt F {{c}^{s}}{{F}^{{lp}}}{{{\hat {Q}}}_{{lp}}}} \right)}_{{;s}}} - \frac{1}{2}\sqrt F {{F}^{{lp}}}{{\hat {Q}}_{{lp}}}c_{{;s}}^{s}$$
and
$$\sqrt F {{F}^{{st}}}{{a}_{{;l}}}\Gamma _{{st}}^{l}(\hat {Q}) = {\text{Div}} + \frac{1}{2}\sqrt F {{F}^{{lp}}}{{\hat {Q}}_{{lp}}}c_{{;s}}^{s} - \sqrt F {{F}^{{sl}}}{{\hat {Q}}_{{lp}}}c_{{;s}}^{p},$$
and finally, the terms take the form
$$a\sqrt F {{F}^{{st}}}{{R}_{{st}}}(F,\hat {Q}) = {\text{Div}} + \sqrt F {{\hat {Q}}_{{st}}}\left( {{{F}^{{sp}}}c_{{;p}}^{t} - {{F}^{{st}}}c_{{;p}}^{p}} \right).$$
Similarly, it can be stated that
$$a\sqrt F {{F}^{{st}}}{{R}_{{st}}}(F,\hat {Q},A) = {\text{Div}} + \sqrt F {{A}_{{st}}}\left( {{{F}^{{sp}}}c_{{;p}}^{t} - {{F}^{{st}}}c_{{;p}}^{p}} \right).$$
Let us consider the following order of these terms:
$$\begin{gathered} a\sqrt F {{F}^{{st}}}{{F}^{{st}}}{{{\hat {Q}}}_{{st}}}{{R}_{{st}}}(F,\hat {Q}) \\ {\text{ = Div}} + \sqrt F {{F}^{{st}}}{{\left( {a\hat {Q}} \right)}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}) \\ - \,\,\sqrt F {{F}^{{st}}}{{\left( {a\hat {Q}} \right)}_{{;l}}}\Gamma _{{st}}^{l}(\hat {Q}). \\ \end{gathered} $$
We introduce the following notation:
$${{r}^{s}} = {{\left( {a\hat {Q}} \right)}_{{;t}}}{{F}^{{st}}},$$
and then direct calculation shows that
$$\begin{gathered} a\sqrt F {{F}^{{st}}}\hat {Q}{{R}_{{st}}}(F,\hat {Q}) = \sqrt F \hat {Q}\left( {{{F}^{{sp}}}r_{{;p}}^{t} - {{F}^{{st}}}r_{{;p}}^{p}} \right) \\ = \sqrt F \left( {{{F}^{{sp}}}c_{{;p}}^{t} - {{F}^{{st}}}c_{{;p}}^{p}} \right){{{\hat {Q}}}_{{st}}}{{{\hat {Q}}}_{{st}}}{{F}^{{st}}} \\ + \,\,a\sqrt F {{F}^{{st}}}\left( {{{F}^{{sp}}}{{F}^{{tr}}} - {{F}^{{st}}}{{F}^{{pr}}}} \right){{{\hat {Q}}}_{{st{{,}_{{pr}}}}}}, \\ \end{gathered} $$
and it can be stated that these terms have the form
$$\begin{gathered} a\sqrt F {{{\hat {Q}}}^{{st}}}{{R}_{{st}}}(F,\hat {Q}) = \sqrt F {{\left( {a{{{\hat {Q}}}^{{st}}}} \right)}_{{;t}}}\Gamma _{{sl}}^{l}(\hat {Q}) \\ - \,\,\sqrt F {{\left( {a{{{\hat {Q}}}^{{st}}}} \right)}_{{;l}}}\Gamma _{{st}}^{l}(\hat {Q}) = \sqrt F \left( {{{F}^{{sp}}}{{a}_{{;tp}}}{{{\hat {Q}}}^{{st}}} - {{F}^{{st}}}{{a}_{{;tp}}}{{{\hat {Q}}}^{{pt}}}} \right) \\ \times \,\,{{{\hat {Q}}}_{{st}}} + a\sqrt F {{F}^{{st}}}\left( {{{F}^{{sp}}}\hat {Q}_{{;tp}}^{{st}} - {{F}^{{st}}}\hat {Q}_{{;tp}}^{{pt}}} \right){{{\hat {Q}}}_{{st}}}. \\ \end{gathered} $$
Therefore,
$$\begin{gathered} {{S}_{1}} = {{{\hat {P}}}^{{st}}}(x{\kern 1pt} '){{F}_{{{{n}_{{st}}}}}}(x{\kern 1pt} ') + F_{n}^{{st}}(x{\kern 1pt} '){{{\hat {Q}}}_{{{{n}_{{st}}}}}}(x{\kern 1pt} ') + a{{H}_{1}}(F,\hat {Q}) \\ = \int\limits_\Sigma {{A}_{{st}}}(x{\kern 1pt} '){{{\hat {P}}}^{{st}}}(x{\kern 1pt} ') + {{B}^{{st}}}(x{\kern 1pt} '){{{\hat {Q}}}_{{st}}}(x{\kern 1pt} '), \\ \end{gathered} $$
$${{A}_{{st}}} = \frac{{2a}}{{\sqrt F }}\left( {{{F}_{{{{n}_{{st}}}}}} - \frac{1}{2}{{F}_{n}}{{F}_{{st}}}} \right),$$
$$\begin{gathered} {{B}^{{st}}} = \frac{a}{{2\sqrt F }}\left( {{{F}_{{{{n}_{{kl}}}}}}F_{n}^{{kl}} - \frac{1}{2}F_{n}^{2}} \right){{F}^{{st}}} \\ - \,\,\frac{{2a}}{{\sqrt F }}\left( {F_{n}^{{st}}F_{n}^{{kl}}{{F}_{{{{n}_{{st}}}}}} - \frac{1}{2}{{F}_{n}}F_{n}^{{st}}} \right) \\ - \,\,a\sqrt F \left( {{{R}^{{st}}} - \frac{1}{2}{{F}^{{st}}}R} \right) - \sqrt F \left( {{{F}^{{sl}}}c_{{;l}}^{t} - {{F}^{{st}}}c_{{;l}}^{l}} \right). \\ \end{gathered} $$