Abstract
Alkylation of 3-methyl-1Н-acenaphtho[5,6]pyridazine with methyl and propyl iodides as well as with benzyl chloride in alkaline medium leads to the formation of the corresponding both N- and С-substituted pyridazine derivatives and also to the dimerization product of the initial compound. The ratio of obtained compounds depends on the used hydride, reaction temperature, and solvent.
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Original Russian Text © N.I. Omelichkin, L.G. Minyaeva, V.V. Mezheritskii, 2017, published in Zhurnal Organicheskoi Khimii, 2017, Vol. 53, No. 2, pp. 261–264.
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Omelichkin, N.I., Minyaeva, L.G. & Mezheritskii, V.V. Alkylation of 3-methyl-1H-acenaphtho[5,6-de]pyridazine. Russ J Org Chem 53, 258–262 (2017). https://doi.org/10.1134/S1070428017020208
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DOI: https://doi.org/10.1134/S1070428017020208