Abstract
A reaction of RhCl3·3H2O with P(CH2OH)3 (THP) and H2S in methanol results in the formation of a new trinuclear complex [Rh3(μ3-S)2(μ2-S)(μ2-Cl)2(THP)6]Cl (1) with a yield of 29%. The structure of 1 is determined by X-ray crystallography. With the same initial compounds with hexamethyldisilthiane as a sulfide source a binuclear [Rh2(μ2-S2)(μ2-S)(THP)6]2+ complex is obtained in which mono- and disulfide bridges are present simultaneously. The latter is isolated and structurally characterized as [Rh2(μ-S2)(μ2-S)(THP)6][Mo6Cl14]·0.6MeOH (2) with a yield of 12%. The compounds obtained are characterized by mass spectrometry and 31P NMR spectra.
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The work was supported by RFBR (grant 17-03-00663).
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Russian Text © The Author(s), 2019, published in Zhurnal Strukturnoi Khimii, 2019, Vol. 60, No. 7, pp. 1120-1127.
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Anyushin, A.V., Kompan’kov, N.B., Abramov, P.A. et al. Polynuclear Sulfide-Bridging Rh(III) Complexes with P(CH2OH)3. J Struct Chem 60, 1072–1079 (2019). https://doi.org/10.1134/S0022476619070072
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DOI: https://doi.org/10.1134/S0022476619070072