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On x 6 + x + a in Characteristic Three

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Abstract

Let F be a field of characteristic 3 and 0 ≠ aF. We show that the 10 ways to factor x 6 + x + a into two cubics over the algebraic closure F are in natural Galois bijection with the 10 roots of x 10 + ax + 1. We use this to (1) prove the two polynomials have the same splitting field; (2) prove that a difference set constructed by Arasu and Player using the polynomial x 6 + x + a is isomorphic to a difference set constructed by Dillon using the polynomial x 10 + x + a; (3) obtain a natural realization for the accidental isomorphism between the alternating group A 6 and the special linear group PSL2(9); and (4) characterize how x 6 + x + a factors when F = GF (3m) with m odd. For example, x 6 + x + a is irreducible if and only if a can be written as δ− 36 + δ4 with δ ∈ F × and Tr(δ5) ≠ 0.

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Bluher, A.W. On x 6 + x + a in Characteristic Three. Designs, Codes and Cryptography 30, 85–95 (2003). https://doi.org/10.1023/A:1024711426896

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  • DOI: https://doi.org/10.1023/A:1024711426896

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