Abstract
For α satisfying 0 < α < π, suppose that C 1 and C 2 are rays from the origin, C 1: z = re i(π−α) and C 2: z = re i(π+α), r ≥ 0, and that D = {z: | arg z − π| < α}. Let u be a nonconstant subharmonic function in the plane and define B(r, u) = sup|z|=r u(z) and A D (r, u) = \( \inf _{z \in \bar D_r } \) u(z), where D r = {z: z ∈ D and |z| = r}. If u(z) = (1 + o(1))B(|z|, u) as z → ∞ on C 1 ∪ C 2 and A D (r, u) = o(B(r, u)) as r → ∞, then the lower order of u is at least π/(2α).
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The second author was supported in part by the Department of Mathematics and Statistics at the University of Otago. He would like to thank them for their hospitality.
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Fenton, P.C., Rossi, J. A reverse Denjoy theorem II. JAMA 110, 385–395 (2010). https://doi.org/10.1007/s11854-010-00010-7
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DOI: https://doi.org/10.1007/s11854-010-00010-7