Appendix A
Proof—Assume P and Q are two generalised fuzzified values with varying levels of confidence, such that \(\varepsilon_{P} { < }\varepsilon_{Q}\). Take \(\varepsilon = \min \left( {\varepsilon_{P} ,\varepsilon_{Q} } \right)\) i.e. ε = εP then α− cut of P and Q are.
$$P_{\alpha } = \left[ {p_{1} + \alpha \left( {\frac{{p_{2 } - p_{1 } }}{{\varepsilon_{P} }}} \right), p_{4} - \alpha \left( {\frac{{p_{4 } - p_{3 } }}{{\varepsilon_{P} }}} \right)} \right] \, ; \, \forall_{\alpha } \in \left[ {0, \varepsilon_{P} } \right] s.t. 0 \le \varepsilon_{P} \le 1$$
$$Q_{\alpha } = \left[ {q_{1} + \alpha \left( {\frac{{q_{2}^{*} - q_{1} }}{\varepsilon }} \right), q_{4} - \alpha \left( {\frac{{q_{4 } - q_{3}^{*} }}{\varepsilon }} \right)} \right] \, ; \, \forall_{\alpha } \in \left[ {0, \varepsilon } \right] s.t. 0 \le \varepsilon \le 1$$
Let, R=P+Q={x | x ∈ Rα} for all α ∈ [0, ε]. Here Rα=[RL(α), RU(α)] be its α− cuts such that, \({\text{R}}^{{\text{L}}} \, \, \left( { \, \alpha \, } \right) = {\text{P}}^{{\text{L}}} \left( { \, \alpha \, } \right) + {\text{Q}}^{{\text{L}}} \left( { \, \alpha \, } \right){\text{, and R}}^{{\text{U}}} \left( { \, \alpha \, } \right) = {\text{P}}^{{\text{U}}} \left( { \, \alpha \, } \right) + {\text{Q}}^{{\text{U}}} \left( { \, \alpha \, } \right)\) i.e.
$$R_{\alpha } = \left[ { P^{L} \left( \alpha \right) + Q^{L} \left( \alpha \right), P^{U} \left( \alpha \right) + Q^{U} \left( \alpha \right)} \right]$$
(57)
$$= \left[ {p_{1} + \alpha \left( {\frac{{p_{2 } - p_{1 } }}{{\varepsilon_{P} }}} \right) + q_{1} + \alpha \left( {\frac{{q_{2}^{*} - q_{1} }}{\varepsilon }} \right), p_{4} - \alpha \left( {\frac{{p_{4 } - p_{3 } }}{{\varepsilon_{P} }}} \right) + q_{4} - \alpha \left( {\frac{{q_{4 } - q_{3}^{*} }}{\varepsilon }} \right)} \right]$$
$$= \left[ { p_{1} + q_{1} + \alpha \left( {\frac{{p_{2 } - p_{1 } }}{{\varepsilon_{P} }} + \frac{{q_{2}^{*} - q_{1} }}{\varepsilon }} \right), p_{4} + q_{4} - \alpha \left( {\frac{{p_{4 } - p_{3 } }}{{\varepsilon_{P} }} + \frac{{q_{4 } - q_{3}^{*} }}{\varepsilon }} \right)} \right]$$
Now,
\(p_{1} + q_{1} + \alpha \left( {\frac{{p_{2 } - p_{1 } }}{{\varepsilon_{P} }} + \frac{{q_{2}^{*} - q_{1} }}{\varepsilon }} \right) - x = 0\) and
$$p_{4} + q_{4} - \alpha \left( {\frac{{p_{4 } - p_{3 } }}{{\varepsilon_{P} }} + \frac{{q_{4} - q_{3}^{*} }}{\varepsilon }} \right) - x = 0$$
As a result, R’s left and right membership functions are.
$${\text{f}}\frac{{\text{L}}}{{\text{R}}}\left( {\text{x}} \right) = \frac{{{\text{x}} - {\text{ p}}_{{1{ }}} - {\text{ q}}_{{1{ }}} { }}}{{\frac{{{\text{p}}_{{2{ }}} { } - {\text{ p}}_{{1{ }}} }}{{{\upvarepsilon }_{{\text{P}}} }}{ } - { }\frac{{{\text{q}}_{2}^{*} { } - {\text{q}}_{1} }}{{\upvarepsilon }}}}$$
(58)
$${\text{f}}\frac{{\text{L}}}{{\text{R}}}\left( {\text{x}} \right) = \frac{{{\text{p}}_{{4}} + { }_{{4}} - {\text{x}}}}{{\frac{{{\text{p}}_{{4 }} - {\text{p}}_{{3 }} }}{{{\upvarepsilon }_{{\text{P}}} }} + { }\frac{{{\text{q}}_{{4 }} - {\text{q}}_{{3}}^{*} }}{{\upvarepsilon }}}}$$
(59)
Since \(\varepsilon = \varepsilon_{P}\) and \(q_{2}^{*} = q_{1} + \varepsilon \left( {\frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }}} \right)\) and \(q_{3}^{*} = q_{4} - \varepsilon \left( {\frac{{q_{4} - q_{3} }}{{\varepsilon_{Q} }}} \right)\), Thus, above \({\text{f}}_{{\text{R}}}^{{\text{L}}}\) and \({\text{f}}_{{\text{R}}}^{{\text{R}}}\) becomes,
$$f\frac{L}{R}\left( x \right) = \frac{{x - p_{1 } - q_{1 } }}{{\frac{{p_{2 } - p_{1 } }}{{\varepsilon_{P} }} - \frac{{q_{2}^{*} - q_{1} }}{\varepsilon }}}$$
$$= \varepsilon \left( {\frac{{x - p_{1} - q_{1 } }}{{p_{2 } - p_{1} - q_{1} + q_{2}^{*} }}} \right)$$
$$= \varepsilon \left( { \frac{{x - ( p_{1 } + q_{1} )}}{{p_{2 } + q_{1} + \varepsilon \left( { \frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }} } \right) - ( p_{1} + q_{1} )}} } \right)$$
(60)
For, \(p_{1} + q_{1} \le x\, \le \,p_{2} + q_{1} + \varepsilon \left( { \frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }} } \right)\)Similarly,
$$f_{R}^{R} \left( x \right) = \varepsilon \left( { \frac{{ ( p_{4} + q_{4} ) - x}}{{q_{4 } + p_{3} - \varepsilon \left( { \frac{{q_{2} - q_{3} }}{{\varepsilon_{Q} }} } \right) - ( p_{4} + q_{4} )}} } \right)$$
(61)
For, \(q_{4} + p_{3} - \varepsilon \left( { \frac{{q_{2} - q_{3} }}{{\varepsilon_{Q} }} } \right) \le x\, \le \,( p_{4} + q_{4} )\)
Thus, adding two generalized fuzzy values is another generalized fuzzy, whose membership function is explained as,
$$\mu_{R} \left( x \right) = \left\{ \begin{gathered} \varepsilon \left( { \frac{{x - ( p_{1 } + q_{1} )}}{{p_{2 } + q_{1} + \varepsilon \left( { \frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }} } \right) - ( p_{1} + q_{1} )}} } \right) ;\quad p_{1} + q_{1} \le x \le p_{2 } + q_{1} + \varepsilon \left( { \frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }} } \right) \hfill \\ \varepsilon ;\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad p_{2 } + q_{1} + \varepsilon \left( { \frac{{q_{2} - q_{1} }}{{\varepsilon_{Q} }} } \right) \le x \le q_{4 } + p_{3} - \varepsilon \left( { \frac{{q_{2} - q_{3} }}{{\varepsilon_{Q} }} } \right) \hfill \\ \varepsilon \left( { \frac{{ ( p_{4} + q_{4} ) - x}}{{q_{4 } + p_{3} - \varepsilon \left( { \frac{{q_{2} - q_{3} }}{{\varepsilon_{Q} }} } \right) - ( p_{4} + q_{4} )}} } \right) ;\quad q_{4 } + p_{3} - \varepsilon \left( { \frac{{q_{2} - q_{3} }}{{\varepsilon_{Q} }} } \right) \le x \le ( p_{4} + q_{4} ) \hfill \\ 0; \quad \quad \quad \quad \quad \quad {\text{otherwise}} \hfill \\ \end{gathered} \right.$$
(62)
To put in another way, that’s the addition of two generalised fuzzy numbers, given by:
R = P + Q = (\({\mathrm{r}}_{1}, {\mathrm{ r}}_{2}, {\mathrm{ r}}_{3},{\mathrm{ r}}_{4} ;\upvarepsilon )=\) min (\({\upvarepsilon }_{\mathrm{P}}\),\({\upvarepsilon }_{\mathrm{Q}}\)) is a generalized fuzzy number where,
$$r_{1} = p_{1} \, + \,q_{1}$$
$$r_{2} = q_{1} + p_{2} \, + \,\frac{{\varepsilon \left( {q_{2} - q_{1} } \right) }}{{\varepsilon_{Q} }}$$
$$r_{3} = q_{4} \, + \,p_{3} - \frac{{\varepsilon \left( {q_{4} - q_{3} } \right) }}{{\varepsilon_{Q} }}$$
$$r_{4} = p_{4} \, + \,q_{4}$$
Appendix B
Proof—When k > 0, the α − cut for P’s membership function is.
\({\text{P}}_{{\upalpha }} = [{\text{p}}_{1} +\)α(\(\frac{{{\text{p}}_{{2{ }}} { } - {\text{ p}}_{{1{ }}} }}{{{\upvarepsilon }_{{\text{P}}} }}\)), \({\text{p}}_{4} -\)α(\(\frac{{{\text{p}}_{{4{ }}} { } - {\text{ p}}_{{3{ }}} }}{{{\upvarepsilon }_{{\text{P}}} }}\))] ; \(\forall_{{\upalpha }}\) ∈ [0, \({\upvarepsilon }_{{\text{P}}}\)] s.t. 0 ≤ \({\upvarepsilon }_{{\text{P}}}\) ≤ 1
This is,therefore,
$$x \in \left[ {p_{1} + \alpha \left( {\frac{{p_{2} - p_{1} }}{{\varepsilon_{p} }}} \right),p4 - \alpha \left( {\frac{{p_{4} - p_{3} }}{{\varepsilon_{p} }}} \right)} \right]$$
$$y = kx \in \left[ { kp_{1} + \alpha \left( { \frac{{kp_{2 } - kp_{1 } }}{{\varepsilon_{P} }} } \right), kp_{4} - \alpha \left( { \frac{{kp_{4} - kp_{3 } }}{{\varepsilon_{P} }} } \right) } \right]$$
(63)
As a conclusion, the scalar product’s membership function is:
$${\upmu }_{{{\text{kP}}}} \left( {\text{x}} \right) = \left\{ \begin{gathered} {\upvarepsilon }_{{\text{P }}} \left( {{ }\frac{{{\text{x}} - {\text{kp}}_{{1 }} }}{{{\text{kp}}_{{2 }} - {\text{kp}}_{{1 }} }}{ }} \right)\,{;}\quad {\text{if kp}}_{{1 }} \le {\text{x }} \le {\text{ kp}}_{{2 }} \hfill \\ {\upvarepsilon }_{{\text{P }}} ;\quad \quad \quad \quad \quad \quad \quad {\text{if kp}}_{{2 }} \le {\text{x}} \le {\text{kp}}_{{3 }} \hfill \\ {\upvarepsilon }_{{\text{P }}} \left( {{ }\frac{{{\text{kp}}_{{4 }} - {\text{x}}}}{{{\text{kp}}_{{4 }} - {\text{kp}}_{{3 }} }}{ }} \right){;}\quad {\text{if kp}}_{{3 }} \le {\text{x}} \le {\text{kp}}_{{4 }} \hfill \\ {0;}\quad \quad \quad \quad \quad \quad \quad \,{\text{otherwise}} \hfill \\ \end{gathered} \right.$$
Appendix C
Proof—Because there are two distinct fuzzy numbers with confidence levels, \({\upvarepsilon }_{\mathrm{P}}\) and \({\upvarepsilon }_{\mathrm{q}}\) defined as \({\upvarepsilon }_{\mathrm{P}}\) ≤\({\upvarepsilon }_{\mathrm{q}}\). So, first of all we’ll turn the fuzzy Q into \({\text{Q*}} = {\text{Q}} = (q_{1} , q_{2}^{*} , q_{3}^{*} , q_{4} ; \varepsilon\), where.
\(q_{2}^{*} = q_{1} + \varepsilon \left( {\frac{{q_{2 } - q_{1 } }}{{\varepsilon_{Q} }}} \right){\text{and }}q_{3}^{*} = q_{4} - \varepsilon \left( {\frac{{q_{4 } - q_{3 } }}{{\varepsilon_{Q} }}} \right)\), Now the α − cuts that suit P and Q* are equivalent to.
$$P_{\alpha } = \left[ {p_{1} + \alpha \left( {\frac{{p_{2} - p_{1 } }}{{\varepsilon_{P} }}} \right), p_{4} - \alpha \left( {\frac{{p_{4} - p_{3 } }}{{\varepsilon_{P} }}} \right)} \right]\quad ;\quad \forall_{\alpha } \in \left[ {0, \, \varepsilon_{P} } \right] \, s.t. \, 0 \le \varepsilon_{P} \le 1$$
$$Q_{\alpha }^{*} = \left[ {q_{1} + \alpha \left( {\frac{{q_{2}^{*} - q_{1 } }}{\varepsilon }} \right), q_{4} - \alpha \left( {\frac{{q_{4} - q_{3}^{*} }}{\varepsilon }} \right)} \right]\quad ;\quad \forall_{\alpha } \in \left[ {0, \, \varepsilon_{P} } \right] \, s.t. \, 0 \le \varepsilon \le 1$$
Suppose \(R = P \times Q = \left\{ {x| x \in R_{\alpha } } \right\}\) for all \({\upalpha } \in \left[ {0, \, \varepsilon } \right]\). Here \(R_{\alpha } = \left[ {R_{\alpha }^{L} , R_{\alpha }^{U} } \right]\) be its α − cuts such that \(R_{\alpha }^{L} = P_{\alpha }^{L} Q_{\alpha }^{*L}\) and \(R_{\alpha }^{U} = P_{\alpha }^{U} Q_{\alpha }^{*U}\) i.e.
$$R_{\alpha } = \left[ {P_{\alpha }^{L} Q_{\alpha }^{*L} , P_{\alpha }^{U} Q_{\alpha }^{*U} } \right]$$
$$= \left[ {\left\{ {p_{1} + \alpha \left( {\frac{{p_{2} - p_{1 } }}{{\varepsilon_{P} }}} \right)} \right\}, \left\{ {q_{1} + \alpha \left( {\frac{{q_{2}^{*} - q_{1 } }}{\varepsilon }} \right)} \right\}, \left\{ {p_{4} - \alpha \left( {\frac{{p_{4 } - p_{3 } }}{{\varepsilon_{P} }}} \right)} \right\} \left\{ {q_{4} - \alpha \left( {\frac{{q_{4} - q_{3}^{*} }}{\varepsilon }} \right)} \right\}} \right]$$
$$= \left[ {p_{1 } q_{1} + \alpha \left( {\frac{{p_{1 } \left( {q_{2}^{*} - q_{1} } \right) + q_{1 } \left( {p_{2 } - p_{1} } \right)}}{\varepsilon }} \right) + \frac{{\alpha^{2} }}{{\varepsilon^{2} }} \left( {p_{2} - p_{1} } \right) \left( {q_{2}^{*} - q_{1} } \right)} \right]$$
$$\left[ {p_{4 } q_{4} + \alpha \left( {\frac{{p_{4 } \left( { q_{4} - q_{3}^{*} } \right) + q_{1 } \left( { p_{4} - p_{3 } } \right)}}{\varepsilon }} \right) + \frac{{\alpha^{2} }}{{\varepsilon^{2} }} \left( {p_{4} - p_{3} } \right)\left( {q_{4} - q_{3}^{*} } \right)} \right]$$
Therefore,
$$p_{1 } q_{1} + \alpha \left( {\frac{{p_{1 } \left( { q_{2}^{*} - q_{1 } } \right) + q_{1 } \left( { p_{2 } - p_{1 } } \right)}}{\varepsilon }} \right) + \frac{{\alpha^{2} }}{{\varepsilon^{2} }} \left( {p_{2 } - p_{1} } \right)\left( {q_{2}^{*} - q_{1} } \right) - x = {\text{0, and}}$$
\(p_{4 } q_{4} + \alpha \left( {\frac{{p_{4 } \left( { q_{4 } - q_{3}^{*} } \right) + q_{1 } \left( { p_{4 } - p_{3 } } \right)}}{\varepsilon }} \right) + \frac{{\alpha^{2} }}{{\varepsilon^{2} }} \left( {p_{4} - p_{3} } \right)\left( {q_{4} - q_{3}^{*} } \right) - x = 0\)
Which are the quadratic functions in the α and therefore its roots give the left as well as right membership of R,
$$f_{R}^{L} \left( x \right) = \frac{{ - N_{1} + \sqrt {N_{1}^{2} + 4M_{1} \left( { x - J_{1} } \right)} }}{{2M_{1} }}; \, r_{1} \le x \le r_{2}$$
(64)
$$f_{R}^{U} \left( x \right) = \frac{{ - N_{2} + \sqrt {N_{2}^{2} + 4M_{2} \left( { x - J_{2} } \right)} }}{{2M_{2} }}; \, r_{3} \le x \le r_{4}$$
(65)
Where, \(N_{1} = \frac{{p_{1 } \left( { q_{2}^{*} - q_{1 } } \right) + q_{1 } \left( { p_{2 } - p_{1 } } \right)}}{\varepsilon }\), \(N_{2} = \frac{{p_{4 } \left( { q_{4 } - q_{3}^{*} } \right) + q_{1 } \left( { p_{4 } - p_{3 } } \right)}}{\varepsilon }\), \(M_{1} = \frac{{\left( { p_{2 } - p_{1 } } \right) \left( { q_{2}^{*} - q_{1 } } \right) }}{{\varepsilon^{2} }}\), \(M_{2} = \frac{{\left( { p_{4 } - p_{3 } } \right) \left( {q_{4 } - q_{3}^{*} } \right) }}{{\varepsilon^{2} }}\), \(J_{1} = p_{1 } q_{1} , J_{2} = p_{4 } q_{4}\)
By Substituting the value of \({\mathrm{q}}_{2}^{*}\) and \({\mathrm{q}}_{3}^{*}\), we get.
$$N_{1} = \frac{{\left( {p_{2} - p_{1 } } \right) \left( { q_{2} - q_{1 } } \right)}}{{\varepsilon \varepsilon_{Q} }} \, ; \, N_{2} = \frac{{\left( {p_{4} - p_{3 } } \right) \left( { q_{4} - q_{3 } } \right)}}{{\varepsilon \varepsilon_{Q} }}$$
(66)
$$M_{1} = \frac{{ p_{1 } \left( { q_{2} - q_{1 } } \right)}}{{\varepsilon_{Q} }} + \frac{{q_{1 } \left( { p_{2} - p_{1 } } \right) }}{\varepsilon } \, ; \, M_{2} = \frac{{ p_{4 } \left( { q_{4} - q_{3 } } \right)}}{{\varepsilon_{Q} }} + \frac{{q_{4 } \left( { p_{4} - p_{3 } } \right) }}{\varepsilon }$$
(67)
As an outcome, the product of two generalised fuzzy numbers is a fuzzy number with the membership,
$$\mu_{R} \left( x \right) = \left\{ {\begin{array}{*{20}c} {\frac{{ - N_{1} + \sqrt {N_{1}^{2} + 4M_{1} \left( { x - J_{1} } \right)} }}{{2M_{1} }}\quad ;\quad r_{1 } \le x \le r_{2 } } \\ {\varepsilon \quad \quad \quad \quad \quad \quad \quad ; \quad r_{2 } \le x \le r_{3 } } \\ {\frac{{ - N_{2} + \sqrt {N_{2}^{2} + 4M_{2} \left( { x - J_{2} } \right)} }}{{2M_{2} }}\quad ; \quad r_{3 } \le x \le r_{4 } } \\ \end{array} } \right.$$
(68)
where,
$$r_{2} = \frac{{\varepsilon \left( {p_{2} q_{2} - p_{2} q_{1} } \right) }}{{\varepsilon_{Q} }} + p_{2} q_{1}$$
$$r_{3} = \frac{{\varepsilon \left( {p_{3} q_{3} - p_{3} q_{4} } \right) }}{{\varepsilon_{Q} }} + p_{3} q_{4}$$
Appendix D
Proof—Consider the membership of two parabolic fuzzy numbers, X and Y be.
$$\mu_{X} \left( x \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( x \right){\text{; if }}p_{1 } \le x < p_{2,} } \\ {\varepsilon_{1} {\text{; if }}x = p_{2,} } \\ {\varepsilon_{1} R_{1} \left( x \right){\text{; if }}p_{2} \le x < p_{3} } \\ { \quad \quad 0{;}\quad {\text{if otherwise}}} \\ \end{array} } \right.$$
And,
$$\mu_{Y} \left( y \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( y \right){;}\quad {\text{if }}q_{1 } \le y < q_{2,} } \\ {\varepsilon_{1} {;}\quad {\text{if }}y = q_{2,} } \\ {\varepsilon_{1} R_{1} \left( y \right){;}\quad {\text{if }}q_{2} \le y < q_{3} } \\ { \quad 0{;}\quad \quad {\text{if otherwise}}} \\ \end{array} } \right.$$
To add the fuzzy numbers \({\text{X}}\) and \({\text{Y}}\), the next fuzzy number of them, \({\text{Z}} = {\text{X}} + {\text{Y}}\)
Implies \(Z = \left[ {p_{1} + q_{1} ,p_{2} + q_{2} ,p_{3} + q_{3} } \right]\)
As \(z = x + y\) at \(y = \varphi_{1} \left( {\text{x}} \right)\) and \(\varphi_{2} \left( {\text{x}} \right)\) we get,
\(z = x + \varphi_{1} \left( x \right)\) and \({\text{z}} = {\text{x}} + \varphi_{2} \left( {\text{x}} \right)\) respectively.that specifies that \(x = \varphi_{1} \left( z \right)\) and \(x = \varphi_{2} \left( z \right)\) where
$$x = \varphi_{1} \left( z \right) = \frac{{z - \frac{{p_{2} q_{1} }}{{p_{2} - p_{1} }} + \frac{{p_{1} q_{2} }}{{p_{2} - p_{1} }}}}{{1 + \frac{{ \left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}}}$$
(69)
Hence, \(\eta_{1} \left( z \right) = \left( {\frac{2}{{ (p_{2} - p_{1} )^{2} }}} \right)\left( {\frac{{z - p_{1} - q_{1} }}{{1 + \frac{{\left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}}}} \right)\), \(m_{1} \left( z \right) = 1 + \frac{{\left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}\)so, the left sided distribution function
$$\mathop \smallint \limits_{{p_{1} + q_{1} }}^{X} \eta_{1} \left( z \right)m_{1} \left( z \right)dz = \mathop \smallint \limits_{{p_{1} + q_{1} }}^{X} \left( {\frac{2}{{ (p_{2} - p_{1} )^{2} }}} \right) \left( {\frac{{z - p_{1} - q_{1} }}{{1 + \frac{{ \left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}}}} \right) \times \left( {\frac{1}{{1 + \frac{{ \left( {q_{2} - q_{1} } \right)1}}{{p_{2} - p_{1} }}}}} \right)dz$$
$$= \left( {\frac{2}{{ (p_{2} - p_{1} )^{2} }}} \right) \left( {\frac{1}{{1 + \frac{{ \left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}}})^{2} \times \mathop \smallint \limits_{{p_{1} + q_{1} }}^{X} (z - p_{1} - q_{1} } \right)dz = (\frac{1}{{p_{2} - p_{1} }})^{2} (\frac{{x - \left( {p_{1} + q_{1} } \right)}}{{1 + \frac{{\left( {q_{2} - q_{1} } \right)}}{{p_{2} - p_{1} }}}})^{2}$$
$$= (\frac{{x - \left( {p_{1} + q_{1} } \right)}}{{p_{2} + q_{2} - p_{1} - q_{1} }})^{2} \, ; \, p_{1} + q_{1} \le x < p_{2} + q_{2}$$
Similarly, if \({\text{y}} = \phi_{2} { }\left( {\text{x}} \right)\) then \({\text{z}} = {\text{x}} + {\text{y}}\) becomes \({\text{x}} = \varphi_{2} { }\left( {\text{z}} \right)\) where
$$\varphi_{2} \left( x \right) = \frac{{z + \frac{{ - p_{2} q_{3} }}{{p_{3} - p_{2} }} + \frac{{p_{3} q_{2} }}{{p_{3} - p_{2} }}}}{{1 + \frac{{q_{3} - q_{2} }}{{p_{3} - p_{2} }}}}$$
(70)
Here, in this case
$$\eta_{2} \left( x \right) = \left( {\frac{ - 2}{{ (p_{3} - p_{2} )^{2} }}} \right) \left( {\frac{{p_{3} + q_{3} - z}}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}}} \right)$$
(71)
so, the right sided distribution function,
$$\mathop \smallint \limits_{{p_{3} + q_{3} }}^{X} \eta_{2} \left( z \right)m_{2} \left( z \right)dz = \mathop \smallint \limits_{{p_{3} + q_{3} }}^{X} \left( {\frac{ - 2}{{ (p_{3} - p_{2} )^{2} }}} \right) \left( {\frac{{p_{3} + q_{3} - z}}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}}} \right) \times \left( {\frac{1}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}}} \right)dz$$
(72)
$$= \left( {\frac{ - 2}{{ (p_{3} - p_{2} )^{2} }}} \right) \left( {\frac{1}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}})^{2} \times \mathop \smallint \limits_{{p_{3} + q_{3} }}^{X} (p_{3} + q_{3} - z} \right)dz$$
$$= \left( {\frac{ - 2}{{ (p_{3} - p_{2} )^{2} }}} \right) (\frac{1}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}})^{2} \times \frac{{ (p_{3} + q_{3} - x)^{2} }}{ - 2}$$
$$= (\frac{1}{{p_{3} - p_{2} }})^{2} (\frac{{ \left( {p_{3} + q_{3} } \right) - x}}{{1 + \frac{{ \left( {q_{3} - q_{2} } \right)}}{{p_{3} - p_{2} }}}})^{2}$$
$$= (\frac{{ \left( {p_{3} + q_{3} } \right) - x}}{{p_{3} - p_{2} + q_{3} - q_{2} }})^{2} ; p_{2} + q_{2} \le x < p_{3} + q_{3}$$
(73)
so, the membership functions of the fuzzy variable \({\text{Z}} = {\text{X}} + {\text{Y}}\) is,
$$\mu_{Z} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon (\frac{{x - \left( {p_{1} + q_{1} } \right)}}{{p_{2} - p_{1} + q_{2} - q_{1} }})^{2} } \hfill & {;\quad p_{1} + q_{1} \le x < p_{2} + q_{2} } \hfill \\ \varepsilon \hfill & {;\quad x = p_{2} + q_{2} } \hfill \\ {\varepsilon (\frac{{ \left( {p_{3} + q_{3} } \right) - x}}{{p_{3} - p_{2} + q_{3} - q_{2} }})^{2} } \hfill & {;\quad p_{2} + q_{2} \le x < p_{3} + q_{3} } \hfill \\ 0 \hfill & {;\quad otherwise} \hfill \\ \end{array} } \right.$$
(74)
where \(\upvarepsilon =\mathrm{ min }({\upvarepsilon }_{1}, {\upvarepsilon }_{2})\)
Appendix E
Proof—Using the change z = kx, we receive x = z/k as well as x = z/k and thus \(\varphi { }\left( {\text{z}} \right) = \frac{{\text{z}}}{{\text{k}}}\)
so, \(\left| {\frac{dx}{{dz}}} \right| = \frac{1}{k} = m \left( z \right)\).
Therefore,
$$\mathop \smallint \limits_{{kp_{1} }}^{X} \eta_{1} \left( z \right)m \left( z \right)dz = \mathop \smallint \limits_{{kp_{1} }}^{X} (\frac{{2 \left( {z - kp_{1} } \right)}}{{k (p_{2} - p_{1} )^{2} }}) \left( \frac{1}{k} \right)dz = (\frac{{x - kp_{1} }}{{kp_{2} - kp_{1} }})^{2}$$
(75)
$$\mathop \smallint \limits_{{kp_{3} }}^{X} \eta_{2} \left( z \right)m \left( z \right)dz = \mathop \smallint \limits_{{kp_{3} }}^{X} (\frac{{ - 2 \left( {kp_{3} - z} \right)}}{{k (p_{3} - p_{2} )^{2} }}) \left( \frac{1}{k} \right)dz = (\frac{{kp_{3} - x}}{{kp_{3} - kp_{2} }})^{2}$$
Therefore, \(\mathrm{at}\) \(\mathrm{k}>0\) is
$$\mu_{kX} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon_{1} (\frac{{x - kp_{1} }}{{kp_{2} - kp_{1} }})^{2} } \hfill & {;\quad kp_{1} \le x < kp_{2} } \hfill \\ {\varepsilon_{1} } \hfill & {;\quad x = kp_{2} } \hfill \\ {\varepsilon_{1} (\frac{{kp_{3} - x}}{{kp_{3} - kp_{2} }})^{2} } \hfill & {;\quad kp_{2} \le x < kp_{3} } \hfill \\ 0 \hfill & {;\quad otherwise} \hfill \\ \end{array} } \right.$$
(76)
Also, at \({\text{k}} < 0\) is
$$\mu_{kX} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon_{1} (\frac{{x - kp_{3} }}{{kp_{2} - kp_{3} }})^{2} } \hfill & {;\quad kp_{3} \le x < kp_{2} } \hfill \\ {\varepsilon_{1} } \hfill & {;\quad x = kp_{2} } \hfill \\ {\varepsilon_{1} (\frac{{kp_{1} - x}}{{kp_{1} - kp_{2} }})^{2} } \hfill & {;\quad kp_{2} \le x < kp_{1} } \hfill \\ 0 \hfill & {;\quad otherwise} \hfill \\ \end{array} } \right.$$
(77)
Appendix F
Proof—Because X and Y have a parabolic membership,
$$\mu_{x} \left( x \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( x \right)\quad ;\quad if \, p_{1 } \le x < p_{2,} } \\ {\varepsilon_{1} \quad ;\quad if \, x = p_{2.} } \\ {\varepsilon_{1} R_{1} \left( x \right)\quad ;\quad if \, p_{2} \le x < p_{3} } \\ { 0\quad \quad \quad ;\quad if \, otherwise} \\ \end{array} } \right.$$
And,
$$\mu_{Y} \left( y \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( y \right) \quad ;\quad if\quad q_{1 } \le y < q_{2,} } \\ {\varepsilon_{1} ; \quad if\quad y = q_{2,} } \\ {\varepsilon_{1} R_{1} \left( y \right)\quad ; \quad if\quad q_{2} \le y < q_{3} } \\ { 0\quad \quad \quad ;\quad if\quad otherwise} \\ \end{array} } \right.$$
Therefore, to find the membership functions\({\text{Z}} = {\text{XY}}\)
at \({\text{y}} = \emptyset_{1} { }\left( {\text{x}} \right),\) \({\text{z}} = {\text{xy}}\) gives
$$x = \frac{{ \left( {p_{1} q_{2} - p_{2} q_{1} } \right) \pm \sqrt { (p_{1} q_{2} - p_{2} q_{1} )^{2} + 4 \left( {q_{2} - q_{1} } \right) \left( {p_{2} - p_{1} } \right)z} }}{{2 \left( {q_{2} - q_{1} } \right)}} = \varphi_{1} \left( z \right)$$
(78)
Take,
$$P_{1} = \left( {p_{2} - p_{1} } \right) \left( {q_{2} - q_{1} } \right)$$
$$Q_{1} = p_{1} \left( {q_{2} - q_{1} } \right) + q_{1} \left( {p_{2} - p_{1} } \right)$$
Hence,
$$\eta_{1} \left( z \right) = \frac{2}{{ (p_{2} - p_{1} )^{2} }} \times \left[ {\frac{{ - p_{1} q_{2} - p_{2} q_{1} + 2p_{1} q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2 \left( {q_{2} - q_{1} } \right)}}\left] { = \frac{1}{{p_{2} - p_{1} }}} \right[\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{P_{1} }}} \right]$$
$$m \left( z \right) = \left| {\frac{dx}{{dz}}} \right| = \frac{{p_{2} - p_{1} }}{{\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}$$
(79)
therefore,
$$\mathop \smallint \limits_{{p_{1} b_{1} }}^{X} \eta_{1} \left( z \right)m_{1} \left( z \right)dz = \mathop \smallint \limits_{{p_{1} b_{1} }}^{X} \frac{1}{{p_{2} - p_{1} }}\left[ {\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{P_{1} }}} \right] \times \frac{{p_{2} - p_{1} }}{{\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}dz = \mathop \smallint \limits_{{p_{1} b_{1} }}^{X} \frac{1}{{P_{1} }}\left[ {\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} }}} \right]dz$$
$$= \mathop \smallint \limits_{{p_{1} b_{1} }}^{X} \frac{1}{{P_{1} }}\left[ {\frac{{ - Q_{1} }}{{\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }} + 1\left] {dz = \frac{1}{{P_{1} }}} \right[\frac{{ ( - Q_{1} )^{2} - Q_{1} \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} + 2P_{1} x - 2P_{1} R_{1} }}{{2P_{1} }}} \right]$$
$$= [\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} }}{{2P_{1} }}]^{2} \, ; \, p_{1} q_{1} \le x < p_{2} q_{2}$$
(80)
Similarly, by taking.
$$P_{2} = \left( {p_{3} - p_{2} } \right) \left( {q_{3} - q_{2} } \right)$$
$$Q_{2} = - p_{3} \left( {q_{3} - q_{2} } \right) - q_{3} \left( {p_{3} - p_{2} } \right)$$
the membership function for the corresponding dispersal functions as.
$$\mathop \smallint \limits_{{p_{3} q_{3} }}^{X} \eta_{1} \left( z \right)m_{1} \left( z \right)dz = [\frac{{ - Q_{2} + \sqrt {Q_{2}^{2} - 4P_{2} \left( {R_{2} - x} \right)} }}{{2P_{2} }}]^{2} ; p_{2} q_{2} \le x < p_{3} q_{3}$$
(81)
As a result, the fuzzy variable Z’s membership is given by:
$$\mu_{XY} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon (\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} }}{{2P_{1} }})^{2} } \hfill & {p_{1} q_{1} \le x < p_{2} q_{2} } \hfill \\ \varepsilon \hfill & {x = p_{2} q_{2} } \hfill \\ {\varepsilon (\frac{{ - Q_{2} + \sqrt {Q_{2}^{2} - 4P_{2} \left( {R_{2} - x} \right)} }}{{2P_{2} }})^{2} } \hfill & {p_{2} q_{2} \le x < p_{3} q_{3} } \hfill \\ 0 \hfill & {otherwise} \hfill \\ \end{array} } \right.$$
(82)
where, Z = XY.
Appendix G
Proof—let a fuzzy inconstant be \(X = \left[ {p_{1} , p_{2} , p_{3} , \varepsilon_{1} } \right]\) whose membership is given in.
$$\mu_{x} \left( x \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( x \right) ;\quad if\quad p_{1 } \le x < p_{2,} } \\ {\varepsilon_{1} ; \quad if\quad x = p_{2,} } \\ {\varepsilon_{1} R_{1} \left( x \right) ; \quad if\quad p_{2} \le x < p_{3} } \\ { \quad 0\quad ; \quad if\quad otherwise} \\ \end{array} } \right.$$
Then let \({\text{z}} = \frac{1}{{\text{X}}}\) so that \(\left| {\frac{{{\text{dx}}}}{{{\text{dz}}}}} \right| = \frac{1}{{{\text{z}}^{2} }}\). So, for \({\text{X}}^{ - 1}\)
$$\mathop \smallint \limits_{X}^{{p_{1}^{ - 1} }} \eta_{1} \left( z \right)m \left( z \right)dz = \mathop \smallint \limits_{X}^{{p_{1}^{ - 1} }} (\frac{2}{{ (p_{2} - p_{1} )^{2} }} \left( {\frac{1}{z} - p_{1} } \right)) \left( {\frac{1}{{z^{2} }}} \right)dz = (\frac{{1 - p_{{1^{X} }} }}{{x \left( {p_{2} - p_{1} } \right)}})^{2}$$
And,
$$\mathop \smallint \limits_{{p_{3}^{ - 1} }}^{X} \eta_{2} \left( z \right)m \left( z \right)dz = \mathop \smallint \limits_{{p_{3}^{ - 1} }}^{X} (\frac{2}{{ (p_{3} - p_{2} )^{2} }} \left( {\frac{1}{z} - p_{3} } \right)) \left( {\frac{1}{{z^{2} }}} \right)dx = (\frac{{xp_{3} - 1}}{{x \left( {p_{3} - p_{2} } \right)}})^{2}$$
So, constructed on the distribution, fuzzy membership of \({\text{X}}^{ - 1}\) is
$$\mu_{{X^{ - 1} }} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon_{1} (\frac{{xp_{3} - 1}}{{x \left( {p_{3} - p_{2} } \right)}})^{2} } \hfill & {if\quad p_{3}^{ - 1} \le x < p_{2}^{ - 1} } \hfill \\ {\varepsilon_{1} } \hfill & {if\quad x = p_{2}^{ - 1} } \hfill \\ {\varepsilon_{1} (\frac{{1 - p_{{1^{X} }} }}{{x \left( {p_{2} - p_{1} } \right)}})^{2} } \hfill & {if\quad p_{2}^{ - 1} \le x < p_{1}^{ - 1} } \hfill \\ 0 \hfill & {otherwise} \hfill \\ \end{array} } \right.$$
(83)
Appendix H
Proof—Deliberate two fuzzy Sigmoid numbers X and Y having membership function as,
$$\mu_{X} \left( x \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( x \right) ; \quad if\quad p_{1 } \le x < p_{2,} } \\ {\varepsilon_{1} ;\quad if\quad x = p_{2,} } \\ {\varepsilon_{1} R_{1} \left( x \right) ; \quad if\quad p_{2} \le x < p_{3} } \\ { \quad 0 ;\quad if\quad otherwise} \\ \end{array} } \right.$$
And,
$$\mu_{Y} \left( y \right) = \left\{ {\begin{array}{*{20}c} {\varepsilon_{1} L_{1} \left( y \right) ;\quad if\quad q_{1 } \le y < q_{2,} } \\ {\varepsilon_{1} ;\quad if\quad y = q_{2,} } \\ {\varepsilon_{1} R_{1} \left( y \right) ; \quad if\quad q_{2} \le y < q_{3} } \\ { 0 ;\quad if\quad otherwise} \\ \end{array} } \right.$$
We have Z = X + Y = \(\left( {{\text{p}}_{1} + {\text{ q}}_{{1{ }}} ,{\text{ p}}_{2} + {\text{ q}}_{{2{ }}} ,{\text{ p}}_{3} + {\text{ q}}_{3} } \right)\) as the result of combining these fuzzy sigmoid numbers, and if we let z = x + y, we obtain z = x + \({\mathrm{\varnothing }}_{1}\) (x) and z = x + \({\mathrm{\varnothing }}_{2}\) (x) which means x = \({\upxi }_{1}\) (z) and x = \({\upxi }_{2}\) (z) where,
$${\text{x}} = {\upxi }_{1} { }\left( {\text{z}} \right) = \frac{{({\text{ p}}_{2} - {\text{ p}}_{1} ){\text{ z }} - { }\left( {{\text{q}}_{{1{ }}} {\text{p}}_{2} { } - {\text{ p}}_{1} {\text{ q}}_{{2{ }}} } \right){ }}}{{{\text{p}}_{2} + {\text{ q}}_{{2{ }}} - {\text{ p}}_{1} - {\text{ q}}_{1} }}$$
hence,
$${\text{m}}_{1} \left( {\text{z}} \right) = \frac{{\text{d}}}{{{\text{dz}}}}{ }\left( {{\upxi }_{1} { }\left( {\text{z}} \right)} \right) = \frac{{({\text{ p}}_{2} - {\text{ p}}_{1} )}}{{{ }({\text{ p}}_{2} - {\text{ p}}_{1} + {\text{ q}}_{{2{ }}} - {\text{ q}}_{{1{ }}} )}}$$
As in addition,
$$n_{1} \left( z \right) = \frac{d}{dz} \left( {L_{1} } \right) {\text{ at }} x = \xi_{1} \left( z \right)$$
$$= \frac{10}{{ \left( {p_{2} - p_{1} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}} \left[ {\varphi \left( { x - \frac{{p_{1 } + p_{2} }}{2} } \right) \left( { \frac{10}{{p_{2} - p_{1} }} } \right)} \right]$$
$$\times \left[ {1 - \varphi \left( { x - \frac{{p_{1 } + p_{2} }}{2} } \right) \left( { \frac{10}{{p_{2} - p_{1} }} } \right)} \right]_{{x = \xi_{1} \left( z \right)}}$$
By solving above equation by part
$$\varphi \left( {x - \frac{{p_{1} + p_{2} }}{2}} \right)\left( {\frac{10}{{p_{2} - p_{1} }}} \right) = \varphi \left( { \frac{{ (p_{2} - p_{1} ) z - \left( {q_{1 } p_{2} - p_{1} q_{2 } } \right) }}{{p_{2} + q_{2} - p_{1} - q_{1 } }} - \frac{{p_{1} + p_{2} }}{2}} \right)\left( { \frac{10}{{p_{2} - p_{1} }}} \right)$$
$$= \varphi \left( {\frac{{2( p_{2} - p_{1} ) z - 2 \left( {q_{1 } p_{2} - p_{1} q_{2 } } \right) - \left( {p_{1} + p_{2} } \right) \left( {p_{2} + q_{2} - p_{1 } + q_{1} } \right) }}{{2 \left( {p_{2} + q_{2 } - p_{1} - q_{1 } } \right)}} - \frac{{p_{1 } + p_{2} }}{2}} \right)\left( { \frac{10}{{p_{2} - p_{1} }}} \right)$$
$$= \varphi \left( {\frac{{2(p_{2} - p_{1} )z + (p_{1} + p_{2} )(p_{1} - p_{2} ) + q_{2} (\left( {p_{1} - p_{2} } \right) + q_{1} ((p_{1} - p_{2} ))}}{{2(p_{2} + q_{2} - p_{1} - q_{1} )}} - \frac{{p_{1} + p_{2} }}{2}} \right)\left( {\frac{10}{{p_{2} - p_{1} }}} \right)$$
$$= \varphi \left( {\frac{{2z - (p_{1} + p_{2} + q_{1} + q_{2} )}}{{2(p_{2} + q_{2} - p_{1} - q_{1} )}}} \right)$$
$$= \varphi \left( {z - \frac{{\left( {p_{1} + p_{2} + q_{1} + q_{2} } \right)}}{2}} \right)\left( {\frac{10}{{\left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right)$$
Thus,
$$n_{1} \left( z \right) = \frac{10}{{ \left( {p_{2} - p_{1} } \right)\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}} \times \varphi \left( {z - \frac{{ \left( {p_{1} + p_{2} + q_{1} + q_{2 } } \right)}}{2}} \right)\left( {\frac{10}{{ \left( {p_{2} + q_{2 } - p_{1} - q_{1 } } \right)}}} \right)$$
$$\times \left[ {1 - \varphi \left( {z - \frac{{ \left( {p_{1} + p_{2} + q_{1} + q_{2 } } \right) }}{2}} \right) \left( {\frac{10}{{ \left( {p_{2} + q_{2 } - p_{1} - q_{1 } } \right)}} } \right)} \right]_{{x = \xi_{1} \left( z \right)}}$$
Therefore,
$$L_{1} \left( x \right) = \mathop \smallint \limits_{{p_{1} + q_{1} }}^{X} m_{1} \left( z \right)\eta_{1} \left( z \right)dz$$
$$= \mathop \smallint \limits_{{p_{1} + q_{1} }}^{X} \frac{{10 \left( {p_{2} - p_{1} } \right)}}{{ \left( {p_{2} - p_{1} + q_{2} - q_{1} } \right)\left( {p_{2} - p_{1} } \right)\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( \cdot \right)\left( {1 - \varphi \left( \cdot \right)} \right)} \right]dz$$
where \(\varphi \left( \cdot \right) = \varphi \left( {z - \frac{{ \left( {p_{1} + p_{2} + q_{1} + q_{2 } } \right) }}{2}} \right) \left( {\frac{10}{{ \left( {p_{2} + q_{2 } - p_{1} - q_{1 } } \right)}}} \right)\)
$$= \frac{1}{{ \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {\left\{ {z - \frac{{p_{1} + p_{2} + q_{1} + q_{2} }}{2}} \right\}\frac{10}{{ \left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right)} \right]_{{p_{1} + q_{1} }}^{X}$$
$$= \frac{1}{{ \left( {\varphi \left( 5 \right) - \psi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} + q_{1} + q_{2} }}{2}} \right\}\frac{10}{{ \left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right)} \right.$$
$$- \left. {\varphi \left( {\left\{ {p_{1} + q_{1} - \frac{{p_{1} + p_{2} + q_{1} + q_{2} }}{2}} \right\}\frac{10}{{ \left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right)} \right]$$
$$= \frac{1}{{ \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} + q_{1} + q_{2} }}{2}} \right\}\frac{10}{{ \left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right) - \varphi \left( { - 5} \right)} \right]$$
So, the distribution function of left side fuzzy number Z = X + Y is;
$$L_{1} \left( z \right) = \frac{{\varphi \left( {\left\{ {z - \frac{{p_{1} + p_{2} + q_{1} + q_{2} }}{2}} \right\}\frac{10}{{\left( {p_{2} + q_{2} - p_{1} - q_{1} } \right)}}} \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}$$
Likewise, if \(y = \varphi_{2} \left( x \right)\), then \({\text{x}} = {\text{x}} + {\text{y}}\) becomes \({\text{x}} = {\upxi }_{2} { }\left( {\text{z}} \right)\), where
$$\xi_{2} \left( z \right) = \frac{{ \left( {p_{3} - p_{2} } \right)z - \left( {q_{2} p_{3} - p_{2} q_{3} } \right)}}{{ \left( {p_{3} - p_{2} } \right) + \left( {q_{3} - q_{2} } \right)}}$$
Thus, \(m_{2} \left( z \right) = \frac{{d \left( {\xi_{2} \left( z \right)} \right)}}{dx} = \frac{{p_{3} - p_{2} }}{{ \left( {p_{3} - p_{2} } \right) + \left( {q_{3} - q_{2} } \right)}}\)
and,
$$\eta_{2} \left( x \right) = \frac{d}{dx} \left( {R_{1} \left( x \right)} \right) at x = \xi_{2} \left( z \right)$$
$$= \frac{ - 10}{{ \left( {p_{3} - p_{2} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\varphi \times \left( {\left\{ {x - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right) \times \left( {1 - \varphi \left( {\left\{ {x - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right)} \right)$$
At \(x = \xi_{2} \left( z \right) = \frac{{\left( {p_{3} - p_{2} } \right)z - \left( {q_{2} p_{3} - p_{2} q_{3} } \right)}}{{\left( {p_{3} - p_{2} } \right) + \left( {q_{3} - q_{2} } \right)}}, {\text{we have}}\)
By solving above equation by part
$$\varphi \left( {\left\{ {x - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right) = \varphi \left( {\left\{ {\frac{{ \left( {p_{3} - p_{2} } \right)x - \left( {q_{2} p_{3} - p_{2} q_{3} } \right)}}{{ \left( {p_{3} - p_{2} } \right) + \left( {q_{3} - q_{2} } \right)}} - \frac{{p_{2} + p_{3} }}{2}} \right\} \times \frac{10}{{p_{3} - p_{2} }}} \right)$$
$$= \varphi \left( {\frac{{2 \left( {p_{3} - p_{2} } \right)x - 2 \left( {q_{2} p_{3} - p_{2} q_{3} } \right) - \left( {p_{2} + p_{3} } \right) \left( {p_{3} + q_{3} - p_{2} - q_{2} } \right)}}{{2 \left( {p_{3} + q_{3} - p_{2} - q_{2} } \right)}} \times \frac{10}{{p_{3} - p_{2} }}} \right)$$
$$= \varphi \left( {\frac{{2 \left( {p_{3} - p_{2} } \right)x + \left( {p_{2} + p_{3} } \right) \left( {p_{2} - p_{3} } \right) + q_{2} \left( {p_{2} - p_{3} } \right) + q_{3} \left( {p_{2} - p_{3} } \right)}}{{2 \left( {p_{3} + q_{3} - p_{2} - q_{2} } \right)}} \times \frac{10}{{p_{3} - p_{2} }}} \right)$$
$$= \varphi \left( {\left\{ {\frac{{2x - \left( {p_{2} + p_{3} + q_{2} + q_{3} } \right)}}{{2 \left( {p_{3} + q_{3} - p_{2} - q_{2} } \right)}}} \right\} \times 10} \right)$$
$$= \varphi \left( {\left\{ {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)$$
$$\begin{gathered} \eta_{2} { }\left( z \right) = \frac{10}{{{ }\left( {p_{3} - p_{2} } \right){ }\left( {\varphi { }\left( 5 \right) - \varphi { }\left( { - 5} \right)} \right)}}\varphi { }\left( {\left\{ {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right) \hfill \\ \times \left[ {1 - \varphi { }\left( {\left\{ {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)} \right] \hfill \\ \end{gathered}$$
Therefore,
$$R_{1} { }\left( x \right) = \mathop \smallint \limits_{x}^{{p_{3} + q_{3} }} \eta_{2} { }\left( z \right)m_{2} { }\left( z \right)dz$$
$$= \mathop \smallint \limits_{x}^{{p_{3} + q_{3} }} \frac{{10 \left( {p_{3} - p_{2} } \right)}}{{ \left( {p_{3} - p_{2} + q_{3} - q_{2} } \right)\left( {p_{3} - p_{2} } \right)\left( {\psi \left( 5 \right) - \psi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( \cdot \right)\left( {1 - \varphi \left( \cdot \right)} \right)} \right]dz$$
where
$$\varphi \left( \cdot \right) = \varphi \left( {\left\{ {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)$$
$$= \frac{1}{{\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {{ }\left( {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right)\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)} \right]_{x}^{{p_{3} + q_{3} }}$$
$$= \frac{1}{{\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {{ }\left( {p_{3} + q_{3} - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right)\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)} \right.$$
$$\left. { - \varphi \left( {\left( {x - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right)\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)} \right]$$
$$= \frac{{\varphi { }\left( 5 \right) - \varphi { }\left( {\left\{ {x - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)}}{{\varphi { }\left( 5 \right) - \varphi { }\left( { - 5} \right)}}$$
As a result, the right-side fuzzy number (Z = X + Y)’s distribution function is;
Similarly, the non-complementary function \({R}_{1} (z)\), gives.
$$R_{1} { }\left( z \right) = \frac{{\varphi \left( 5 \right) - \varphi \left( {\left\{ {z - \frac{{p_{3} + p_{2} + q_{2} + q_{3} }}{2}} \right\}\frac{10}{{p_{3} + q_{3} - p_{2} - q_{2} }}} \right)}}{{\varphi \left( 5 \right) - \varphi { }\left( { - 5} \right)}}$$
As a result, the fuzzy variable Z = X + Y membership is given by
$$\mu_{z} { }\left( {\text{Z}} \right) = \left\{ \begin{gathered} \varepsilon { }\frac{{\varphi { }\left[ {{ }\left( {{ }z{ } - { }\frac{{p_{{1{ }}} + { }p_{2} + { }q_{{1{ }}} + { }q_{2} }}{2}{ }} \right){ }\left( {{ }\frac{10}{{p_{2} { } + { }q_{2} { } - { }p_{1} - { }q_{{1{ }}} }}{ }} \right){ }} \right]{ } - { }\varphi { }\left( { - 5} \right){ }}}{{{ }\varphi { }\left( 5 \right){ } - { }\varphi { }\left( { - 5} \right)}}\quad \quad ;\quad if\quad p_{1} + { }q_{{1{ }}} \le z < p_{2} + { }q_{{2{ }}} \hfill \\ \varepsilon { }\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad ;\quad if\quad z{ } = { }p_{{\begin{array}{*{20}c} {2 } \\ \\ \end{array} }} + { }q_{2} \hfill \\ \varepsilon { }\frac{{\varphi { }\left( 5 \right){ } - { }\varphi { }\left[ {{ }\left( {{ }z{ } - { }\frac{{p_{{2{ }}} + { }p_{3} { } + { }q_{{2{ }}} + { }q_{3} }}{2}{ }} \right){ }\left( {{ }\frac{10}{{p_{3} { } + { }q_{3} { } - { }p_{2} - { }q_{2} { }}}{ }} \right){ }} \right]{ }}}{{{ }\varphi { }\left( 5 \right){ } - { }\varphi { }\left( { - 5} \right)}}\quad \, ;\quad if\quad p_{2} + { }q_{{2{ }}} { } \le z < p_{3} + { }q_{3} \hfill \\ 0\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad ;\quad \quad otherwise \hfill \\ \end{gathered} \right.$$
(84)
Appendix I
Proof—By the use of transformation given by z = kx, we get x = \(\frac{\mathrm{z}}{\mathrm{k}}\), which can be written as \(\upxi (\mathrm{z})\)
so, \(\left| {\frac{{{\text{dx}}}}{{{\text{dz}}}}} \right| = \frac{1}{{\text{k}}} = {\text{m }}\left( {\text{z}} \right)\). Then, at \({\text{x}} = {\xi }\left( {\text{z}} \right)\)
$$\varphi \left( z \right) = \varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{ \left( {p_{2} - p_{1} } \right)}}} \right)$$
In addition, we have.
$${\upeta }_{1} { }\left( {\text{z}} \right) = \frac{{\text{d}}}{{{\text{dx}}}}{ }\left( {{\text{L}}_{1} } \right){\text{ at x}} = {\upxi }_{1} { }\left( {\text{z}} \right) = \frac{{\text{z}}}{{\text{k}}}$$
$$= \frac{10}{{ \left( {p_{2} - p_{1} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}} \times \left( {\varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right) \times \left( {1 - \varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right)$$
Hence,
$$L_{1} \left( x \right) = \mathop \smallint \limits_{{kp_{1} }}^{x} \eta_{1} \left( z \right)m \left( z \right)dz$$
$$= \mathop \smallint \limits_{{kp_{1} }}^{x} \left[ \begin{gathered} \frac{10}{{k \left( {p_{2} - p_{1} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}} \left( {\varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right) \hfill \\ \times \left( {1 - \varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right) \hfill \\ \end{gathered} \right]dz$$
$$= \frac{{\varphi \left( {\left\{ {x - \frac{{kp_{1} + kp_{2} }}{2}} \right\}\frac{10}{{ \left( {kp_{2} - kp_{1} } \right)}}} \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}$$
(85)
\(\eta_{2} \left( z \right) = \frac{d}{dx} \left( {R_{1} \left( x \right)} \right)\) at \(x = \xi \left( z \right) = \frac{z}{k}\)
$$= \frac{10}{{ \left( {p_{3} - p_{2} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right) \times \left( {1 - \varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right)} \right)$$
And therefore,
$$R_{1} \left( x \right) = \mathop \smallint \limits_{X}^{{kp_{3} }} \eta_{2} \left( z \right)m \left( z \right)dx$$
$$= \mathop \smallint \limits_{X}^{{kp_{3} }} \left[ {\frac{10}{{ \left( {p_{3} - p_{2} } \right) \left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}} \times \left( {\varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right)} \right) \times \left( {1 - \varphi \left( {\left\{ {\frac{z}{k} - \frac{{p_{2} + p_{3} }}{2}} \right\}\frac{10}{{p_{3} - p_{2} }}} \right)} \right)} \right]dz$$
$$= \frac{{\varphi \left( 5 \right) - \varphi \left( {\left\{ {x - \frac{{kp_{2} + kp_{3} }}{2}} \right\}\frac{10}{{ \left( {kp_{3} - kp_{2} } \right)}}} \right)}}{{\varphi \left( 5 \right) - \psi \left( { - 5} \right)}}$$
The membership for the fuzzy number \({\text{kX}}\) at \({\text{k}} > 0\) is:
$$\mu_{kX} \left( x \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon_{1} \frac{{\varphi \left( {\left\{ {x - \frac{{kp_{1} + kp_{2} }}{2}} \right\}\frac{10}{{ \left( {kp_{2} - kp_{1} } \right)}}} \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}};} \hfill & {kp_{1} \le x < kp_{2} } \hfill \\ {\varepsilon_{1} ;} \hfill & {x = kp_{2} } \hfill \\ {\varepsilon_{1} \frac{{\varphi \left( 5 \right) - \varphi \left( {\left\{ {x - \frac{{kp_{2} + kp_{3} }}{2}} \right\}\frac{10}{{ \left( {kp_{3} - kp_{2} } \right)}}} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}};} \hfill & {kp_{2} \le x < kp_{3} .} \hfill \\ \end{array} } \right.$$
Likewise, the membership for the fuzzy number kX at k < 0, is:
$$\mu_{kX} \left( x \right) = \left\{ \begin{gathered} \varepsilon_{1} \frac{{\varphi \left( {\left\{ {x - \frac{{kp_{2} + kp_{3} }}{2}} \right\}\frac{10}{{ \left( {kp_{2} - kp_{3} } \right)}}} \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}};\quad kp_{3} \le x < kp_{2} \hfill \\ \varepsilon_{1} ; \quad \quad \quad \quad \quad \quad \quad \quad x = kp_{2} \hfill \\ \varepsilon_{1} \frac{{\varphi \left( 5 \right) - \varphi \left( {\left\{ {x - \frac{{kp_{1} + kp_{2} }}{2}} \right\}\frac{10}{{ \left( {kp_{1} - kp_{2} } \right)}}} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}; \quad kp_{2} \le x < kp_{1} \hfill \\ \end{gathered} \right.$$
Appendix J
Proof—The fuzzy number \(Z = XY\), associate \(L_{1} \left( x \right)\) with \(L_{1} \left( y \right)\) and \(R_{1} \left( x \right)\) with \(R_{2} \left( y \right)\) and get \(y = \emptyset_{1} \left( x \right)\) and \(y = \emptyset_{2} \left( x \right)\),
Where,\(\emptyset_{1} \left( x \right) = \frac{{q_{1} + q_{2} }}{2} + \frac{{q_{2} - q_{1} }}{{a_{2} - a_{1} }}\left( {x - \frac{{a_{1} + a_{2} }}{2}} \right)\);\(\emptyset_{2} \left( x \right)\)\(= \frac{{q_{2} + q_{3} }}{2} + \frac{{q_{3} - q_{2} }}{{a_{3} - a_{2} }}\left( {x - \frac{{a_{2} + a_{3} }}{2}} \right)\).
Therefore, at \(y = \emptyset_{1} \left( x \right),\) \(z = xy\) becomes
$$x = \frac{{p_{1} q_{2} - p_{2} q_{1} \pm \sqrt {(p_{1} q_{2} - p_{2} q_{1} )^{2} + 4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)x} }}{{2\left( {q_{2} - q_{1} } \right)}} = \xi_{1} \left( z \right)$$
Therefore,
$$m_{1} \left( z \right) = |\frac{dx}{{dz}}|_{{x = \xi_{1} \left( z \right)}} = \frac{{4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)}}{{4\left( {q_{2} - q_{1} } \right)\sqrt {(p_{1} q_{2} - p_{2} q_{1} )^{2} + 4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)z} }}$$
$$= \frac{{p_{2} - p_{1} }}{{\sqrt {(p_{1} q_{2} - p_{2} q_{1} )^{2} + 4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)z} }} = \frac{{p_{2} - p_{1} }}{{\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}$$
where \(P_{1} = \left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)\); \(Q_{1} = p_{1} \left( {q_{2} - q_{1} } \right) +\);\(R_{1} = p_{1} q_{1}\).and in addition,
$$\eta_{1} \left( z \right) = \frac{d}{dx}\left( {L_{1} } \right){\text{ at, }}x = \xi_{1} \left( z \right)$$
$$= \frac{10}{{\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)dx}}\left( {\varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{\left( {p_{2} - p_{1} } \right)}}} \right)} \right)$$
$$= \frac{10}{{\left( {p_{2} - p_{1} } \right)\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{\left( {p_{2} - p_{1} } \right)}}} \right) \times \left( {1 - \varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{\left( {p_{2} - p_{1} } \right)}}} \right)} \right)$$
At,
$$X = \xi_{1} \left( z \right) = \frac{{p_{1} q_{2} - p_{2} q_{1} \pm \sqrt {(p_{1} q_{2} - p_{2} q_{1} )^{2} + 4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)z} }}{{2\left( {q_{2} - q_{1} } \right)}}$$
$$\varphi \left( {\left\{ {x - \frac{{p_{1} + p_{2} }}{2}} \right\}\frac{10}{{\left( {p_{2} - p_{1} } \right)}}} \right) = \varphi \left( {\left\{ {\frac{{p_{1} q_{2} - p_{2} q_{1} \pm \sqrt {\left( {p_{1} q_{2} - p_{2} q_{1} } \right)^{2} + 4\left( {p_{2} - p_{1} } \right)\left( {q_{2} - q_{1} } \right)z} p_{1} + p_{2} }}{{2\left( {q_{2} - q_{1} } \right)2}}} \right\} \times \frac{10}{{p_{2} - p_{1} }}} \right)$$
$$= \varphi \left( {\left\{ {\frac{{p_{1} q_{2} - p_{2} q_{1} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} p_{1} + p_{2} }}{{2\left( {q_{2} - q_{1} } \right)2}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)$$
$$= \varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2\left( {q_{2} - q_{1} } \right)}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)$$
Hence
$$\eta_{1} \left( z \right) = \frac{10}{{\left( {p_{2} - p_{1} } \right)\left( {\psi \left( 5 \right) - \psi \left( { - 5} \right)} \right)}}\varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2\left( {q_{2} - q_{1} } \right)}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)$$
$$\times \left[ {1 - \varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2\left( {q_{2} - q_{1} } \right)}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right]$$
Therefore,
$$L_{1} \left( x \right) = \mathop \smallint \limits_{{p_{1} q_{1} }}^{X} m_{1} \left( z \right)\eta_{1} \left( z \right)dz = \mathop \smallint \limits_{{p_{1} q_{1} }}^{X} \frac{10}{{\left( {\varphi \left( 5 \right) - \psi \left( { - 5} \right)} \right)\sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}\varphi \left( \cdot \right)\left( {1 - \varphi \left( \cdot \right)} \right)dz$$
where \(\varphi \left( \cdot \right) = \varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2\left( {q_{2} - q_{1} } \right)}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)\)
$$= \frac{1}{{\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} }}{{2\left( {q_{2} - q_{1} } \right)}}} \right\}\frac{10}{{p_{2} - p_{1} }}} \right)} \right]_{{p_{1} b_{1} }}^{X}$$
$$= \frac{1}{{\left( {\varphi \left( 5 \right) - \varphi \left( { - 5} \right)} \right)}}\left[ {\varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {(Q_{1} )^{2} - 4P_{1} \left( {R_{1} - x} \right)} }}{{2\left( {q_{2} - q_{1} } \right)\left( {p_{2} - p_{1} } \right)}}} \right\}10} \right)} \right. - \varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {Q_{1} - p_{1} q_{1} } \right)} }}{{2\left( {q_{2} - b_{1} } \right)\left( {p_{2} - p_{1} } \right)}}} \right\}} \right.$$
$$= \frac{{\varphi \left( {\left\{ {\frac{{p_{1} q_{1} - p_{2} q_{2} \pm \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} }}{{2\left( {q_{2} - q_{1} } \right)\left( {p_{2} - p_{1} } \right)}}} \right\}10} \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}$$
\(= \frac{{\varphi \left( {\tau_{1} } \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}\), where, \(\tau_{1} = 10\left( {\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - x} \right)} - P_{1} }}{{2P_{1} }}} \right)\).
By taking, \(P_{2} = \left( {p_{3} - p_{2} } \right)\left( {q_{3} - q_{2} } \right)\); \(Q_{2} = - p_{3} \left( {q_{3} - q_{2} } \right) - q_{3} \left( {p_{3} - p_{2} } \right)\); \(R_{2} = p_{3} q_{3}\),
We're having the accurate membership of \(Z = XY\) as:
\(R_{1} \left( x \right) = l^{{p_{3} q_{3} }} \eta_{2} \left( z \right)m_{2} \left( z \right)dz = \frac{{\varphi \left( 5 \right) - \varphi \left( {\tau_{2} } \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}}\), where \(\tau_{2} = 10\left( {\frac{{ - Q_{2} - \sqrt {Q_{2}^{2} - 4P_{2} \left( {R_{2} - x} \right)} + P_{2} }}{{2P_{2} }}} \right)\)consequently, the membership of the fuzzy number \(Z = XY\) is:
$$\mu_{XY} \left( z \right) = \left\{ {\begin{array}{*{20}l} {\varepsilon \frac{{\varphi \left( {\tau_{1} } \right) - \varphi \left( { - 5} \right)}}{{\varphi \left( 5 \right) - \varphi \left( { - 5} \right)}};} \hfill & {p_{1} q_{1} \le z < p_{2} q_{2} } \hfill \\ {\varepsilon ;} \hfill & {z = p_{2} q_{2} } \hfill \\ {\varepsilon \frac{{\varphi \left( 5 \right) - \varphi \left( {\tau_{2} } \right)}}{{ \varphi \left( 5 \right) - \varphi \left( { - 5} \right)}};} \hfill & {p_{2} q_{2} \le z < p_{3} q_{3} } \hfill \\ \end{array} } \right.$$
(86)
where \(\tau_{1} = 10\left( {\frac{{ - Q_{1} + \sqrt {Q_{1}^{2} - 4P_{1} \left( {R_{1} - z} \right)} - P_{1} }}{{2P_{1} }}} \right)\) and \(\tau_{2} = 10\left( {\frac{{ - Q_{2} - \sqrt {Q_{2}^{2} - 4P_{2} \left( {R_{2} - z} \right)} + P_{2} }}{{2P_{2} }}} \right)\)