Abstract
We consider the two-particle Schrodinger operator H(k) on the one-dimensional lattice ℤ. The operator H(π) has infinitely many eigenvalues zm(π) = v(m), m ∈ ℤ+. If the potential v increases on ℤ+, then only the eigenvalue z0(π) is simple, and all the other eigenvalues are of multiplicity two. We prove that for each of the doubly degenerate eigenvalues zm(π), m ∈ ℕ, the operator H(π) splits into two nondegenerate eigenvalues z −m (k) and z +m (k) under small variations of k ∈ (π − δ, π). We show that z −m (k) < z +m (k) and obtain an estimate for z +m (k) − z −m (k) for k ∈ (π − δ, π). The eigenvalues z0(k) and z −1 (k) increase on [π − δ, π]. If (Δv)(m) > 0, then z ±m (k) for m ≥ 2 also has this property.
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Translated from Teoreticheskaya i Matematicheskaya Fizika, Vol. 145, No. 2, pp. 212–220, November, 2005.
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Abdullaev, J.I. Perturbation Theory for the Two-Particle Schrodinger Operator on a One-Dimensional Lattice. Theor Math Phys 145, 1551–1558 (2005). https://doi.org/10.1007/s11232-005-0182-y
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DOI: https://doi.org/10.1007/s11232-005-0182-y