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Reduction of LnIII to LnII in reactions of LnCl3·6H2O (Ln = Eu, Yb, and Sm) with Bui 2AlH in THF. The formation of soluble luminescent complexes LnCl2·xTHF

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Abstract

Soluble luminescent complexes of divalent lanthanides, LnCl2·xTHF (Ln = Eu, Yb, and Sm), were obtained for the first time by reduction of LnIII to LnII in reactions of the lanthanide trichloride hexahydrates LnCl3·6H2O with Bui 2AlH in THF. The photoluminescence spectra and other spectral characteristics of LnCl2·xTHF were examined.

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Authors and Affiliations

  1. Institute of Petrochemistry and Catalysis, Russian Academy of Sciences, 141 prosp. Oktyabrya, 450075, Ufa, Russian Federation

    R. G. Bulgakov, S. M. Eliseeva & D. I. Galimov

Authors
  1. R. G. Bulgakov
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  2. S. M. Eliseeva
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  3. D. I. Galimov
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Correspondence to R. G. Bulgakov.

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Dedicated to Academician of the Russian Academy of Sciences M. P. Egorov on the occasion of his 60th birthday.

Published in Russian in Izvestiya Akademii Nauk. Seriya Khimicheskaya, No. 11, pp. 2345–2348, Novemer, 2013.

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Bulgakov, R.G., Eliseeva, S.M. & Galimov, D.I. Reduction of LnIII to LnII in reactions of LnCl3·6H2O (Ln = Eu, Yb, and Sm) with Bui 2AlH in THF. The formation of soluble luminescent complexes LnCl2·xTHF. Russ Chem Bull 62, 2345–2348 (2013). https://doi.org/10.1007/s11172-013-0340-6

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  • DOI: https://doi.org/10.1007/s11172-013-0340-6

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