Abstract
The reaction of neodymium diiodide NdI2 with excess methanol in acetonitrile produced the tetranuclear neodymium cluster [Nd4(μ2-I)1.1(μ3-I)(μ2-OMe)4.9(μ4-O)(MeCN)12]I3 (1). In the latter, the isomorphic substitution of one methoxy group by an I− anion with site occupancies (%) of 90 and 10, respectively, was observed. Due to the isomorphic substitution in the crystal, cluster 1 can be considered as a superposition of two complexes, [Nd4(μ2-I)(μ3-I)(μ2-OMe)5(μ4-O)(MeCN)12]I3 and [Nd4(μ2-I)2(μ3-I)(μ2-OMe)4(μ4-O)(MeCN)12]I3. The characteristic feature of cluster 1 is that the center of the Nd4 cage is occupied by the μ4-coordinated O2− anion, which is indicative of the partial O-C bond cleavage in methanol. The reaction of NdI2 with an equimolar amount of MeOH in an acetonitrile solution produced methoxide NdI2(OMe)(MeCN)4 in 49% yield.
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Dedicated to Professor W. J. Evans on the occasion of his 60th birthday.
Published in Russian in Izvestiya Akademii Nauk. Seriya Khimicheskaya, No. 10, pp. 1894–1897, October, 2007.
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Kuzyaev, D.M., Fukin, G.K., Baranov, E.V. et al. Reaction of neodymium diiodide with methanol in acetonitrile. Structure of the cluster [Nd4(μ2-I)1.1(μ3-I)(μ2-OMe)4.9(μ4-O)(MeCN)12]I3 . Russ Chem Bull 56, 1960–1963 (2007). https://doi.org/10.1007/s11172-007-0305-8
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DOI: https://doi.org/10.1007/s11172-007-0305-8