Appendix
A Proof of Proposition 3 and Corollary 5
Given the inverse demands (14), consumer surplus can be written as follows:
$$\begin{aligned} CS = \frac{1}{2} \cdot \left[ \gamma (q_1+q_2)^2 + (1-\gamma ) (q_1^2+q_2^2)\right] = q_1^2 + q_2^2 + 2 \gamma q_1q_2. \end{aligned}$$
(15)
In the second stage of the game, firm \(i \in \{1,2\}\) chooses \(q_i\) in order to maximize \(V_i=\pi _i + \theta _i CS\). For \(i,j \in \{1,2\}\), \(i \not = j\), the first-order conditions \(\frac{\partial V_i}{\partial q_i} = 0\) imply the reaction functionsFootnote 18
$$\begin{aligned} q_i = \frac{1-\gamma (1-\theta _i)q_j}{2-\theta _i}. \end{aligned}$$
(16)
Solving the system of equations (16) yields
$$\begin{aligned} q_i = \frac{(1-\gamma )+(1-\theta _j)+\gamma \theta _i}{2+(2-\gamma ^2)(1-\theta _j) -[1+(1-\gamma ^2)(1-\theta _j)]\theta _i} \end{aligned}$$
(17)
for \(i,j \in \{1,2\}\), \(i \not = j\). We now use (14) and (17) to compute the corresponding prices
$$\begin{aligned} p_i = \frac{(1-\gamma )+(1-\theta _j)-[1+(1-\gamma ^2)(1-\theta _j)]\theta _i}{2+(2-\gamma ^2)(1-\theta _j)-[1+(1-\gamma ^2)(1-\theta _j)]\theta _i}. \end{aligned}$$
(18)
In the first stage of the game, firm \(i \in \{1,2\}\) chooses \(\theta _i\) in order to maximize \(\pi _i=p_iq_i\). Using (17) and (18), the first-order conditions \(\frac{\partial \pi _i}{\partial \theta _i} = 0\) imply the reaction functions
$$\begin{aligned} \theta _i = \frac{\gamma ^2(1-\theta _j)(2-\theta _j-\gamma )}{[2-\theta _j-(1-\theta _j) \gamma ^2](2-\theta _j+\gamma )} \end{aligned}$$
(19)
for \(i,j \in \{1,2\}\), \(i \not = j\). Solving the system of equations (19) for \(i,j \in \{1,2\}\), \(i \not = j\) yields a unique feasible solution:Footnote 19
$$\begin{aligned} \theta _i = \frac{2(1+\gamma )+\gamma ^2-\sqrt{[2(1+\gamma )]^2+\gamma ^4}}{2(1+\gamma )} =: \theta _C^*(\gamma ) > 0. \end{aligned}$$
(20)
Using (20), it is straightforward to show that \(\frac{d\theta _C^*(\gamma )}{d\gamma } > 0\) for \(\gamma >0\), and \(\frac{d\theta _C^*(\gamma )}{d\gamma } < 0\) for \(\gamma <0\). This proves Proposition 3.
Finally, to prove Corollary 5, we use (20) and compute firm i’s equilibrium profit
$$\begin{aligned} \pi _i^* = \frac{2\left( \sqrt{[2(1+\gamma )]^2+\gamma ^4}-\gamma ^2-2\gamma )\right) }{\left( \sqrt{[2(1+\gamma )]^2+\gamma ^4}-\gamma ^2+2\right) ^2} \end{aligned}$$
whereas the regular Cournot profit without strategic CSR (\(\theta _1=\theta _2=0\)) equals \(\pi _i^C=\frac{1}{(2+\gamma )^2}\). A comparison shows that, in the relevant range, \(\pi _i^* > \pi _i^C\) if and only if \(-1< \gamma <0\).
B Proof of Proposition 4
The inverse demand functions (14) imply the following direct demands
$$\begin{aligned} q_i = \frac{1-\gamma - p_i + \gamma p_j}{1-\gamma ^2} \end{aligned}$$
(21)
for \(i,j \in \{1,2\}\), \(i\ne j\). Using (15) and (21), consumer surplus can be expressed in terms of prices:
$$\begin{aligned} CS = \frac{2(1-\gamma )(1-p_1-p_2) - 2\gamma p_1p_2 + p_1^2 +p_2^2}{2(1-\gamma ^2)}. \end{aligned}$$
In the second stage of the game, firm \(i \in \{1,2\}\) chooses \(p_i\) in order to maximize \(V_i=\pi _i + \theta _i CS\). For \(i,j \in \{1,2\}\), \(i \not = j\), the first-order conditions \(\frac{\partial V_i}{\partial p_i} = 0\) imply the reaction functionsFootnote 20
$$\begin{aligned} p_i = \frac{(1-\theta _i)(1 - \gamma + \gamma p_j)}{2-\theta _i}. \end{aligned}$$
(22)
Solving the system of equations (22) yields
$$\begin{aligned} p_i =\frac{(1-\gamma )(1-\theta _i)[2-\theta _j+\gamma (1-\theta _j)]}{(2-\theta _i)(2-\theta _j)-(1-\theta _i)(1-\theta _j)\gamma ^2} \end{aligned}$$
(23)
for \(i,j \in \{1,2\}\), \(i \not = j\). We now use (21) and (23) to compute the corresponding profits
$$\begin{aligned} \pi _i = p_iq_i = \frac{(1-\gamma )(1-\theta _i)[2-\theta _j+\gamma (1-\theta _j)]^2}{(1+\gamma ) [(2-\theta _i)(2-\theta _j)-(1-\theta _i)(1-\theta _j)\gamma ^2]^2}. \end{aligned}$$
(24)
In the first stage of the game, firm \(i \in \{1,2\}\) chooses \(\theta _i\) in order to maximize \(\pi \). Using (24), it is straightforward to show that for \(i,j \in \{1,2\}\), \(i \not = j\)
$$\begin{aligned} \frac{\partial \pi _i}{\partial \theta _i} = - \frac{(1-\gamma )[(2-\theta _j)\theta _i+(1-\theta _i)(1-\theta _j)\gamma ^2] [2-\theta _j+\gamma (1-\theta _j)]^2}{(1+\gamma )[(2-\theta _i)(2-\theta _j) -(1-\theta _i)(1-\theta _j)\gamma ^2]^3} < 0 \end{aligned}$$
(25)
for all \(0<|\gamma |<1\). Consequently, each firm \(i \in \{1,2\}\) will choose the lowest CSR level possible, i.e., \(\theta _i=0=:\theta ^*_B(\gamma )\).
C Proof of Proposition 5
At the second stage, the objective functions of the two firms are given by
$$\begin{aligned} V_1&=p(q_1+q_2)q_1+\theta _1CS(q_1+q_2),\\ V_2&=p(q_1+q_2)q_2+\theta _2CS(q_1+q_2). \end{aligned}$$
The maximizing quantities satisfy the first-order conditions
$$\begin{aligned} \dfrac{\partial V_1}{\partial q_1}&=p'(q_1+q_2)q_1+p(q_1+q_2)+\theta _1CS'(q_1+q_2)=0, \end{aligned}$$
(26)
$$\begin{aligned} \dfrac{\partial V_2}{\partial q_2}&=p'(q_1+q_2)q_2+p(q_1+q_2)+\theta _2CS'(q_1+q_2)=0, \end{aligned}$$
(27)
as well as the second order conditions \(\dfrac{\partial ^2 V_i}{\partial q_i^2} < 0\). Using \(CS(q_1+q_2)=\int _0^{q_1+q_2}[p(q)-p(q_1+q_2)]dq\) and thus \(CS'(q_1+q_2)=-(q_1+q_2)p'(q_1+q_2)\), we rewrite Eqs. (26) and (27):
$$\begin{aligned}{}[(1-\theta _1)q_1-\theta _1q_2]p'(q_1+q_2)+p(q_1+q_2)&=0, \end{aligned}$$
(28)
$$\begin{aligned} p'(q_1+q_2)+p(q_1+q_2)&=0. \end{aligned}$$
(29)
Denote the left-hand side of Eqs. (28) and (29) by \(F_1(\theta _1,\theta _2,q_1,q_2)\) and \(F_2(\theta _1,\theta _2, q_1,q_2)\), respectively.
First, we compute the sign of \(dq_1/d\theta _1\). Treating \(\theta _2\) as fixed and applying the implicit function theorem yields
$$\begin{aligned} \dfrac{dq_1}{d\theta _1}= \dfrac{-\dfrac{\partial F_1}{\partial \theta _1}\dfrac{\partial F_2}{\partial q_2}}{\dfrac{\partial F_1}{\partial q_1}\dfrac{\partial F_2}{\partial q_2}-\dfrac{\partial F_1}{\partial q_2}\dfrac{\partial F_2}{\partial q_1}}. \end{aligned}$$
(30)
Notice that \(\partial F_1/\partial \theta _1=-(q_1+q_2)p'(q_1+q_2)>0\). Moreover, \(\partial F_i/\partial q_i=\partial ^2V_i/\partial q_i^2<0\) for \(i \in \{1,2\}\), as implied by the second order conditions on the solution of the maximization problem. Thus the numerator of (30) is positive. Taking the respective derivatives, using the symmetry \(\theta _1=\theta _2=\theta \) in equilibrium, writing \(q_1+q_2=Q\), and simplifying terms, we compute the denominator
$$\begin{aligned} \dfrac{\partial F_1}{\partial q_1}\dfrac{\partial F_2}{\partial q_2}-\dfrac{\partial F_1}{\partial q_2}\dfrac{\partial F_2}{\partial q_1}=p'(Q)[(3-2\theta )p'(Q)+(1-2\theta )Qp''(Q)]. \end{aligned}$$
(31)
Due to \(p'(Q)<0\), an increase in a firm’s CSR level will increase its output, i.e., \(dq_1/d\theta _1>0\), if and only if
$$\begin{aligned} (3-2\theta )p'(Q)+(1-2\theta )Qp''(Q)<0. \end{aligned}$$
(32)
Next, we compute the sign of \(d q_1/d \theta _2\). Treating \(\theta _1\) as fixed now and applying the implicit function theorem yields
$$\begin{aligned} \dfrac{dq_1}{d\theta _2}= \dfrac{\dfrac{\partial F_2}{\partial \theta _2}\dfrac{\partial F_1}{\partial q_2}}{\dfrac{\partial F_1}{\partial q_1}\dfrac{\partial F_2}{\partial q_2}-\dfrac{\partial F_1}{\partial q_2}\dfrac{\partial F_2}{\partial q_1}}. \end{aligned}$$
(33)
The denominator of (33) equals that of (30). Again due to the symmetry in equilibrium, the numerator simplifies to
$$\begin{aligned} \dfrac{\partial F_2}{\partial \theta _2}\dfrac{\partial F_1}{\partial q_2}=-Qp'(Q)[(1-\theta )p'(Q)+(1-2\theta )Qp''(Q)]. \end{aligned}$$
(34)
Due to \(-Qp'(Q)>0\), an increase in a firm’s CSR level will decrease its rival’s output, \(dq_1/d\theta _2<0\), if and only if
$$\begin{aligned} (3-2\theta )p'(Q)+(1-2\theta )Qp''(Q) \end{aligned}$$
(35)
and
$$\begin{aligned} (1-\theta )p'(Q)+(1-2\theta )Qp''(Q) \end{aligned}$$
(36)
are either both positive or both negative, such that either the numerator of (33) is positive and the denominator of (33) is negative or vice versa. Note that (35) < (36) and thus we obtain the condition that \(dq_1/d\theta _2<0\) if and only if either
$$\begin{aligned} (3-2\theta )p'(Q)+(1-2\theta )Qp''(Q)>0 \end{aligned}$$
(37)
or
$$\begin{aligned} (1-\theta )p'(Q)+(1-2\theta )Qp''(Q)<0. \end{aligned}$$
(38)
Finally, notice that (37) and (32) can never both be fulfilled at the same time and that (38) already implies (32).