In Brechmann and Rendall (2018) it was investigated using the Poincaré compactification in which ways solutions of (9) and (10) can tend to infinity for large times. Here we want to carry out corresponding calculations for (7) and (8). A useful preliminary step is to introduce a new time coordinate T satisfying \(\frac{d\tau }{dT}=1+\nu y^\gamma (\beta +x)\). Then we get the system
$$\begin{aligned} \frac{dx}{dT}= & {} 1-xy^\gamma +\nu y^\gamma (\beta +x),\\ \frac{dy}{dT}= & {} \alpha [xy^\gamma -y-\nu y^{\gamma +1}(\beta +x)]. \end{aligned}$$
This makes the right hand side into a polynomial while leaving the phase portrait unchanged.
The phase portrait is more complicated than that in the case of mass action kinetics. A schematic picture of it is given in Fig. 3 and its properties are summarized in the following lemma which is the analogue of Lemma 2 in Brechmann and Rendall (2018).
Lemma 5
Suppose that \(\nu <1\). There is a smooth mapping of the closure of the positive quadrant into itself mapping the axes into themselves with the following properties. The restriction of \(\phi \) to the open quadrant is a diffeomorphism onto its image. This image is a region whose closure is a compact set bounded by intervals \([0,x_0]\) and \([0,y_0]\) on the x- and y-axes and four smooth curves \(\gamma _i, 1\le i\le 4\). The curve \(\gamma _1\) joins the point \(P_1=(0,y_0)\) with a point \(P_3\) in the positive quadrant. \(\gamma _2\) joins the point \(P_3\) with the point \(P_4\). For \(3\le i\le 4\) the curve \(\gamma _i\) joins the point \(P_{2i-2}\) with the point \(P_{2i}\) and \(P_8=(x_0,0)\). The image of the dynamical system can be rescaled so as to extend smoothly to the closure of the image of \(\phi \) in such a way that \(P_3\) and \(P_{2i}, 2\le i\le 4\), are steady states and the \(\gamma _i\) and the image of the x-axis under \(\phi \) are invariant manifolds. There are further steady states \(P_2\) and \(P_{2i+1}, 2\le i\le 3\), on the boundary belonging to the interior of \(\gamma _1\) and \(\gamma _{i+1}, 2\le i\le 3\), respectively.
The statements of Lemma 5 are proved in the remainder of this section. To analyse the case where x becomes large [Case 1 in the terminology of Brechmann and Rendall (2018)] introduce the variables \(Y=\frac{y}{x}\), \(Z=\frac{1}{x}\). Define a new time variable t satisfying \(\frac{dt}{dT}=Z^{-\gamma -1}\). The result of the transformation is
$$\begin{aligned} \frac{dY}{dt}= & {} \alpha Y^\gamma Z+Y^{\gamma +1}Z-\alpha YZ^{\gamma +1}-YZ^{\gamma +2}\\&-\,\nu Y^{\gamma +1}(\alpha +Z)(1+\beta Z),\nonumber \\ \frac{dZ}{dt}= & {} Y^\gamma Z^2-Z^{\gamma +3}-\nu Y^\gamma Z^2(1+\beta Z). \end{aligned}$$
Both axes are invariant under the flow and the flow there is towards the origin. The linearization of the system about the origin is identically zero. Thus we do a quasihomogeneous directional blow-up. An appropriate transformation can be obtained by using a Newton polygon as in Dumortier et al. (2006). The coefficients are \({\tilde{\alpha }}=\gamma \) and \({\tilde{\beta }}=\gamma -1\). (These are the same values as occurred in the blow-up of the corresponding point for the model (9) and (10). The notation has been changed compared to that of the sources quoted by the addition of a tilde to avoid confusion with other uses of the same letters elsewhere in the present paper.) Thus we use variables \({\bar{y}}\) and \({\bar{z}}\) satisfying \((Y,Z)=({\bar{y}}^\gamma ,{\bar{y}}^{\gamma -1}{\bar{z}})\). In addition we introduce a new time coordinate s satisfying \(\frac{ds}{dt}=\gamma ^{-1}{\bar{y}}^{\gamma ^2-1}\). The system becomes
$$\begin{aligned} \frac{d{\bar{y}}}{ds}= & {} \alpha {\bar{y}}{\bar{z}}+{\bar{y}}^{\gamma +1}{\bar{z}} -\alpha {\bar{y}}{\bar{z}}^{\gamma +1}-{\bar{y}}^\gamma {\bar{z}}^{\gamma +2}\\&-\,\nu (\alpha +{\bar{y}}^{\gamma -1}{\bar{z}}){\bar{y}}^2(1+\beta {\bar{y}}^{\gamma -1}{\bar{z}}),\\ \frac{d{\bar{z}}}{ds}= & {} -\alpha (\gamma -1){\bar{z}}^2+{\bar{y}}^{\gamma }{\bar{z}}^2 +\alpha (\gamma -1){\bar{z}}^{\gamma +2}-{\bar{y}}^{\gamma -1}{\bar{z}}^{\gamma +3}\\&+\,\nu [(\gamma -1)\alpha -{\bar{y}}^{\gamma -1}{\bar{z}}]{\bar{y}}{\bar{z}} (1+\beta {\bar{y}}^{\gamma -1}{\bar{z}}). \end{aligned}$$
Both axes are invariant under the flow. There is a steady state at the origin and one at the point (0, 1), which corresponds to \(P_7\). The linearization at the origin is identically zero.
Next the centre manifold of \(P_7\) will be studied. Introducing \(w={\bar{z}}-1\) moves the steady state to origin. The centre subspace is given \(w=\rho {\bar{y}}\) with \(\rho =\frac{1-\alpha \nu }{2\alpha }\) for \(\gamma =2\) and \(\rho =-\frac{\nu }{\gamma }\) for \(\gamma >2\).
Lemma 6
The relation \({{\bar{y}}}'=-\frac{\gamma }{\gamma -1}{\bar{y}}^\gamma +o({\bar{y}}^\gamma )\) holds on the centre manifold of \(P_7\) for all \(\gamma \ge 2\).
Proof
In the case \(\gamma =2\) we have
$$\begin{aligned} {{\bar{y}}}'=\alpha {\bar{y}}{\bar{z}}-\alpha {\bar{y}}{\bar{z}}^3 -\alpha \nu {\bar{y}}^2-{\bar{y}}^2+O({\bar{y}}^3). \end{aligned}$$
Substituting the relation \({\bar{z}}=1+\rho {\bar{y}}+O({\bar{y}}^2)\) which holds on the centre manifold into this relation gives
$$\begin{aligned} {{\bar{y}}}'=\alpha \rho {\bar{y}}^2-3\alpha \rho {\bar{y}}^2 -\alpha \nu {\bar{y}}^2-{\bar{y}}^2 +O({\bar{y}}^3)=-2{\bar{y}}^2+O({\bar{y}}^3) \end{aligned}$$
and this completes the proof for \(\gamma =2\). For \(\gamma >2\) we use the relation
$$\begin{aligned} {{\bar{z}}}'=-{\bar{y}}^{\gamma -1} +(\gamma -1)[-\alpha {\bar{z}}^2+\alpha {\bar{z}}^{\gamma +2} +\alpha \nu {\bar{y}}{\bar{z}}]+O({\bar{y}}^\gamma ). \end{aligned}$$
Substituting this into the evolution equation for \({\bar{y}}\) gives
$$\begin{aligned} {{\bar{y}}}'=-\frac{\gamma }{\gamma -1}{\bar{y}}^{\gamma } -\frac{1}{\gamma -1}{\bar{y}}{\bar{z}}^{-1}{{\bar{z}}}'+O({\bar{y}}^{\gamma +1}). \end{aligned}$$
Suppose that we know that \({{\bar{y}}}'=O({\bar{y}}^k)\) for some k with \(2\le k\le \gamma -1\). Then it follows that \({{\bar{z}}}'=O({\bar{y}}^{k+1})\). Hence \({{\bar{y}}}'=O({\bar{y}}^{k+1})\). After finitely many steps we get the conclusion of the lemma for \(\gamma >2\). \(\square \)
We see that the flow on the centre manifold is towards \(P_7\) and since the non-zero eigenvalue of the linearization at that point is positive \(P_7\) is a topological saddle. In fact the flow on the boundary is everywhere away from \(P_7\). We next blow up the origin in the coordinates \(({\bar{y}},{\bar{z}})\). This time the procedure described in Dumortier et al. (2006) leads to the choice of coefficients \({\tilde{\alpha }}={\tilde{\beta }}=1\). Blow-ups in the two coordinate directions are required. The only terms in the resulting equations which will be written explicitly are those which have a direct influence on the analysis which follows. In the first transformed system, with \({\bar{y}}={\tilde{y}}_1\) and \({\bar{z}}={\tilde{y}}_1{\tilde{z}}_1\), the equations are
$$\begin{aligned} {{\tilde{y}}_1}'= & {} {\tilde{y}}_1[-\alpha (\nu -{\tilde{z}}_1){\tilde{y}}_1+\cdots ],\\ {{\tilde{z}}_1}'= & {} {\tilde{y}}_1[\gamma \alpha (\nu -{\tilde{z}}_1){\tilde{z}}_1+\cdots ]. \end{aligned}$$
A change of time coordinate eliminates the common factor \({\tilde{y}}_1\). On the boundary there is a steady state at the point \((0,\nu )\), which corresponds to \(P_5\). The origin of this coordinate system corresponds to \(P_4\). The terms which have been retained suffice to determine the steady states on the boundary and the linearization of the system at those points. The point \(P_5\) also appears in the second transformed system but since it can be analysed in the chart corresponding to the first transformed system the second transformed system, with \({\bar{y}}={\tilde{y}}_2{\tilde{z}}_2\) and \({\bar{z}}={\tilde{z}}_2\), is only needed to analyse the steady state \(P_6\) at the origin of that coordinate system. For this purpose the only terms which need to be retained are
$$\begin{aligned} {{\tilde{y}}_2}'= & {} {\tilde{z}}_2[\gamma \alpha {\tilde{y}}_2+\cdots ],\\ {{\tilde{z}}_2}'= & {} {\tilde{z}}_2[-\alpha (\gamma -1){\tilde{z}}_2+\cdots ]. \end{aligned}$$
The common factor \({\tilde{z}}_2\) can be eliminated by a change of time coordinate. The origin of this coordinate system corresponds to \(P_6\). We see that in both cases, after a suitable change of time coordinate, the origin is a hyperbolic saddle.
Next the centre manifold of \(P_5\) will be studied in the case \(\gamma =2\). We do not expect that the case \(\gamma >2\) is essentially different but since the algebra becomes significantly more complicated only the case \(\gamma =2\) has been worked out. The centre subspace is parallel to the \({\tilde{y}}_1\)-axis. We have \({{\tilde{z}}_1}'=O({\tilde{y}}_1^3)\) on the centre manifold and this implies that if \({\tilde{z}}_1=\nu +w\) then
$$\begin{aligned} 2\alpha \nu w=[\nu ^2(1-\nu )+2\alpha \nu ^4+2\alpha \beta \nu ^3]{\tilde{y}}_1^2+\ldots \end{aligned}$$
It follows that provided \(\nu <1\) the flow on the centre manifold of \(P_5\) is away from \(P_5\). For the rest of the discussion we return to the case of general \(\gamma \).
In the case where x gets large it remains to do one further quasihomogeneous directional blow-up of the origin in the (Y, Z) coordinate system. In this case \((Y,Z)=({\bar{y}}{\bar{z}}^{\gamma },{\bar{z}}^{\gamma -1})\). The time coordinate is transformed using the relation \(\frac{ds}{dt}=\frac{1}{\gamma -1} {\bar{z}}^{\gamma ^2-1}\). The resulting system is
$$\begin{aligned} {\bar{y}}'= & {} (\gamma -1)[\alpha {\bar{y}}^\gamma -\alpha {\bar{y}} -\alpha \nu {\bar{y}}^{\gamma +1}{\bar{z}}(1+\beta {\bar{z}}^{\gamma -1})\nonumber \\&+\,{\bar{y}}^{\gamma +1}{\bar{z}}^\gamma -{\bar{y}}{\bar{z}}^{\gamma -1} -\nu {\bar{y}}^{\gamma +1}{\bar{z}}^\gamma (1+\beta {\bar{z}}^{\gamma -1})]\nonumber \\&-\,\gamma [{\bar{y}}^{\gamma +1}{\bar{z}}^\gamma -{\bar{y}}{\bar{z}}^{\gamma -1}-\nu {\bar{y}}^{\gamma +1}{\bar{z}}^\gamma (1+\beta {\bar{z}}^{\gamma -1})], \end{aligned}$$
(16)
$$\begin{aligned} {\bar{z}}'= & {} {\bar{y}}^\gamma {\bar{z}}^{\gamma +1} -{\bar{z}}^\gamma -\nu {\bar{y}}^\gamma {\bar{z}}^{\gamma +1} (1+\beta {\bar{z}}^{\gamma -1}). \end{aligned}$$
(17)
There is a steady state at the point (1, 0) but since it is just another representation of \(P_7\) it does not need to be analysed further. The origin of this coordinate system corresponds to \(P_8\). The \({\bar{z}}\)-axis is a centre manifold for \(P_8\) and the flow there is towards \(P_8\). Since the non-zero eigenvalue of the linearization at \(P_8\) is negative it can be concluded that \(P_8\) is a sink.
Having completed the analysis of the case where x gets large we now turn to the case where where y gets large [Case 2 in the terminology of Brechmann and Rendall (2018)], with new variables \(X=\frac{x}{y}\) and \(Z=\frac{1}{y}\). The result is
$$\begin{aligned} \frac{dX}{dT}= & {} \frac{1}{Z^{\gamma +1}}[Z^{\gamma +2}-XZ+\nu Z(X+\beta Z)\\&-\,\alpha X^2Z+\alpha XZ^{\gamma +1}+\alpha \nu X (X+\beta Z)],\\ \frac{dZ}{dT}= & {} \frac{1}{Z^{\gamma +1}} [-\alpha XZ^2+\alpha Z^{\gamma +2}+\alpha \nu Z(X+\beta Z)]. \end{aligned}$$
The common factor \(\frac{1}{Z^{\gamma +1}}\) can be removed by a suitable change of time coordinate satisfying \(\frac{dt}{dT}=Z^{-\gamma -1}\). The linearization of the resulting system about the origin is identically zero so that it is again necessary to do a blow-up. In this case a calculation using a Newton polygon gives the exponents \({\tilde{\alpha }}=1\) and \({\tilde{\beta }}=1\). The transformation in the X direction uses the relation \((X,Z)=({\bar{x}}_1,{\bar{x}}_1{\bar{z}}_1)\). The resulting system is
$$\begin{aligned} \frac{d{\bar{x}}_1}{dt}= & {} {\bar{x}}_1[{\bar{x}}_1^{\gamma +1}{\bar{z}}_1^{\gamma +2} -{\bar{x}}_1{\bar{z}}_1 +\nu {\bar{x}}_1{\bar{z}}_1 (1+\beta {\bar{z}}_1)\\&-\,\alpha {\bar{x}}_1^2{\bar{z}}_1+\alpha {\bar{x}}_1^{\gamma +1}{\bar{z}}_1^{\gamma +1} +\alpha \nu {\bar{x}}_1 (1+\beta {\bar{z}}_1)],\\ \frac{d{\bar{z}}_1}{dt}= & {} {\bar{x}}_1[-{\bar{x}}_1^{\gamma }{\bar{z}}_1^{\gamma +3}+{\bar{z}}_1^2 -\nu {\bar{z}}_1^2 (1+\beta {\bar{z}}_1)]. \end{aligned}$$
The origin of this coordinate system corresponds to \(P_3\). By a change of time coordinate we can remove the factor \({\bar{x}}_1\). The linearization of the system which results at the origin has one positive eigenvalue and the \({\bar{z}}_1\)-axis is invariant and defines a centre manifold at that point. It can be concluded that \(P_3\) is a source. If \(\nu <1\) there is a steady state at the point \(\left( 0,\frac{1-\nu }{\beta \nu }\right) \) which corresponds to the point \(P_2\). That point is a hyperbolic saddle whose stable manifold is the \({\bar{z}}_1\)-axis.
The transformation in the Z direction uses the relation \((X,Z)=({\bar{x}}_2{\bar{z}}_2,{\bar{z}}_2)\). The resulting system is
$$\begin{aligned} \frac{d{\bar{x}}_2}{dt}= & {} {\bar{z}}_2[{\bar{z}}_2^{\gamma }-{\bar{x}}_2 +\nu (\beta +{\bar{x}}_2)],\\ \frac{d {\bar{z}}_2}{dt}= & {} -\alpha XZ^2+\alpha Z^{\gamma +2}+\alpha \nu Z(X+\beta Z)\\= & {} {\bar{z}}_2[-\alpha {\bar{x}}_2{\bar{z}}_2^2+\alpha {\bar{z}}_2^{\gamma +1} +\alpha \nu {\bar{z}}_2(\beta +{\bar{x}}_2)]. \end{aligned}$$
The origin of this coordinate system is \(P_1\). By a change of time coordinate we can remove the factor \({\bar{z}}_2\). In the system which results there is inflow on the \({\bar{z}}_2\)-axis while the \({\bar{x}}_2\)-axis is invariant and corresponds to the \({\bar{z}}_1\)-axis in the previous system. Note that the point \(P_1\) is not a steady state.
The facts which have now been collected imply strong restrictions on the possible \(\omega \)-limit sets of solutions. The only points of the boundary which they can contain are those on the part connecting \(P_5\) and \(P_7\). Poincaré–Bendixson theory implies that the \(\omega \)-limit set of a positive solution must be either a point (which can only be the positive steady state, \(P_7\) or \(P_8\)), a periodic solution or a heteroclinic cycle joining \(P_5\) and \(P_7\). The last of these can only occur if the centre manifolds of \(P_5\) and \(P_7\) coincide. Note that any periodic solution or heteroclinic cycle must contain the positive steady state in its interior.
We have the following analogue of Theorem 1 of Brechmann and Rendall (2018).
Theorem 3
There exists a positive number \(\epsilon >0\) such that any solution of the Michaelis–Menten system (7) and (8) with initial data \(x(0)=x_0\) and \(y(0)=y_0\) which satisfies \(x_0>\epsilon ^{-1}\) and \(x_0y_0^\gamma <\epsilon \) has the late-time asymptotics
$$\begin{aligned} x(\tau )= & {} \tau (1+o(1)),\\ y(\tau )= & {} y_1e^{-\alpha \tau }(1+o(1)). \end{aligned}$$
for a constant \(y_1\). There exists a solution, unique up to time translation, which has the asymptotic behaviour
$$\begin{aligned} x(\tau )= & {} \tau (1+o(1)),\\ y(\tau )= & {} \tau ^{-\frac{1}{\gamma -1}}(1+o(1)). \end{aligned}$$
Proof
The proof of this theorem is very similar to that of Theorem 1 of Brechmann and Rendall (2018), whose basic structure we now recall. Any solution which starts close enough to the point \(P_8\) converges to that point as \(t\rightarrow \infty \). Using this information in the system (16) and (17) allows these equations for \({\bar{y}}(s)\) and \({\bar{z}}(s)\) to be integrated to leading order in the limit \(s\rightarrow \infty \). The resulting asymptotic expressions can then be transformed back to the original variables \(x(\tau )\) and \(y(\tau )\). The only extra element is that, while in the original proof only one change of time coordinate was required, in the present case we must first transform from s to T and then from T to \(\tau \). Since for this type of solution the time coordinates \(\tau \) and T are asymptotically equal this extra element does not change the final answer. In particular, the parameter \(\nu \) does not contribute to the leading order asymptotics. This gives the first statement of the theorem. The solution mentioned in the second statement of the theorem is a solution on the centre manifold of \(P_7\). Integrate the equation for \({\bar{y}}\) in Lemma 6 in leading order in the limit \(s\rightarrow \infty \) and substitute the result into the equation for \({\bar{z}}\). This provides asymptotic expressions for \({\bar{y}}(s)\) and \({\bar{z}}(s)\). Transforming these back to the variables \(x(\tau )\) and \(y(\tau )\) gives the second part of the theorem. \(\square \)