As explained in the introduction, the proof of Theorem 1.1 is by induction. In this section we deal with its base case.
Let S be a surface with \(q(S)=0\) and \({\mathcal O}_S(h_S)\) a non–special very ample line bundle. If \(h^0\big (S,{\mathcal O}_S(K_S-h_S)\big )=0\), then Equality (2.3) yields \(h^0\big (S,{\mathcal O}_S(h_S)\big )=N+1\) where
$$\begin{aligned} N:=\frac{h^2_S-h_SK_S}{2}+p_g(S). \end{aligned}$$
(3.1)
In particular \({\mathcal O}_S(h_S)\) induces an embedding \(S\subseteq \mathbb {P}^{N}\).
Let X be any scheme. In what follows \(X^{[N+2]}\) denotes the Hilbert scheme of 0–dimensional subschemes of degree \(N+2\) inside X.
Construction 3.1
Let S be a surface with \(q(S)=0\), endowed with a non–special very ample line bundle \({\mathcal O}_S(h_S)\). Let \(S\subseteq \mathbb {P}^{N}\) be the induced embedding.
Since S is integral and non–degenerate in \(\mathbb {P}^{N}\), it follows the existence of an open non–empty subset \(\mathcal Z\subseteq S^{[N+2]}\) whose points correspond to schemes Z of \(N+2\) points in general linear position inside \(\mathbb {P}^{N}\). Each scheme Z corresponding to a point in \(\mathcal Z\) satisfies the hypothesis of Theorem 2.1 with respect to \({\mathcal O}_S(h_S)\), hence there is a rank 2 vector bundle \({\mathcal F}\) fitting into
$$\begin{aligned} 0\longrightarrow {\mathcal O}_S(K_S)\longrightarrow {\mathcal F}\longrightarrow {\mathcal I}_{Z\vert S}(h_S)\longrightarrow 0. \end{aligned}$$
(3.2)
Notice that
$$\begin{aligned} c_1({\mathcal F})=h_S+K_S,\qquad c_2({\mathcal F})=\frac{h_S^2+h_SK_S}{2}+\chi ({\mathcal O}_S)+1. \end{aligned}$$
By definition \(h^0\big (S,{\mathcal O}_S(h_S)\big )=N+1\), \({h}^0\big (Z,{\mathcal O}_Z\big )=N+2\) and \(h^1\big (S,{\mathcal O}_S(h_S)\big )=0\). Moreover, the choice of Z implies \(h^0\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )=0\). Thus the cohomology of the exact sequence
$$\begin{aligned} 0\longrightarrow {\mathcal I}_{Z\vert S}\longrightarrow {\mathcal O}_S\longrightarrow {\mathcal O}_Z\longrightarrow 0. \end{aligned}$$
(3.3)
tensored by \({\mathcal O}_S(h_S)\) and Equality (2.1) yield
$$\begin{aligned} \dim \mathrm {Ext}^1_S\big ({\mathcal I}_{Z\vert S}(h_S),{\mathcal O}_S(K_S)\big )=h^1\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )=1, \end{aligned}$$
(3.4)
i.e. \({\mathcal F}\) is uniquely determined by Z.
Lemma 3.2
Let S be a surface with \(\kappa (S)\ge 0\) and \(q(S)=0\), endowed with a non–special very ample line bundle \({\mathcal O}_S(h_S)\). Assume \(h^0\big (S,{\mathcal O}_S(K_S-h_S)\big )=0\).
Then
$$\begin{aligned} h^0\big (S,{\mathcal F}\big )=p_g(S),\qquad h^0\big (S,{\mathcal F}(-h_S)\big )=0,\qquad h^1\big (S,{\mathcal F}\big )=0 \end{aligned}$$
for the vector bundle \({\mathcal F}\) obtained from a scheme Z as in Construction (3.1).
Proof
Since \(h^0\big (S,{\mathcal I}_{Z\vert S}\big )=0\) and \(h^0\big (S,{\mathcal O}_S(K_S-h_S)\big )=0\), it follows that the cohomology of Sequence (3.2) tensored by \({\mathcal O}_S(-h_S)\) implies \(h^0\big (S,{\mathcal F}(-h_S)\big )=0\).
The vanishing \(h^0\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )=0\) implies \(h^0\big (S,{\mathcal F}\big )=p_g(S)\). The equality \(h^2\big (S,{\mathcal F}\big )=h^0\big (S,{\mathcal F}(-h_S)\big )=0\), the cohomology of Sequence (3.2) and the vanishing \(h^0\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )=0\) yield the exact sequence
$$\begin{aligned} 0\longrightarrow H^1\big (S,{\mathcal F}\big )\longrightarrow H^1\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )\longrightarrow H^2\big (S,{\mathcal O}_S(K_S)\big )\longrightarrow 0, \end{aligned}$$
hence \(h^1\big (S,{\mathcal F}\big )= h^1\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )- h^2\big (S,{\mathcal O}_S(K_S)\big )\). Since \(h^2\big (S,{\mathcal O}_S(K_S)\big )=1\), it follows that \(h^1\big (S,{\mathcal F}\big )=0\), thanks to Equality (3.4). \(\square \)
In the next proposition we deal with the properties of the point corresponding to \({\mathcal F}\) in the moduli spaces \(Spl_S(2;c_1({\mathcal F}),c_2({\mathcal F}))\) and \(M_S(2;c_1({\mathcal F}),c_2({\mathcal F}))\).
To this purpose, we denote by \(\mathcal Z_0\) the open subset of \(\mathcal Z\) of points corresponding to schemes Z such that \(h^0\big (S,{\mathcal I}_{Z\vert S}(K_S)\big )=0\). Trivially, \(\mathcal Z_0\ne \emptyset \) if \(N+2\ge p_g(S)\). It is immediate to check that such an inequality is equivalent to \(h_S^2+4\ge h_SK_S\) if \(h^0\big (S,{\mathcal O}_S(K_S-h_S)\big )=0\).
Finally, let \(\mathcal Z_1:=S_0^{[N+2]}\cap \mathcal Z\). As pointed out in Remark 2.3, \(\mathcal Z_1\) could be empty, but if k is uncountable and \(\kappa (S)\ge 0\), then it is certainly dense inside \(S^{[N+2]}\).
Proposition 3.3
Let S be a surface with \(q(S)=0\) and \(p_g(S)\ge 1\), endowed with a non–special very ample line bundle \({\mathcal O}_S(h_S)\). Assume \(h^0\big (S,{\mathcal O}_S(K_S-h_S)\big )=0\).
Then the following properties hold for the vector bundle \({\mathcal F}\) obtained from a scheme \(Z\in \mathcal Z\) as in Construction (3.1)
-
(1)
\({\mathcal F}\) is simple.
-
(2)
\(p_g(S)\le \dim \mathrm {Ext}_S^2\big ({\mathcal F},{\mathcal F}\big )\le p_g(S)+h^0\big (S,{\mathcal O}_S(2K_S-h_S)\big )\) if \(h_S^2+4\ge h_SK_S\) and \(Z\in \mathcal Z_0\).
-
(3)
\({\mathcal F}\) is \(\mu \)–stable if \(h_S^2> h_SK_S\) and \(Z\in \mathcal Z_1\).
Proof
In order to prove assertion (1), applying \(\mathrm {Hom}_S\big ({\mathcal F},-\big )\) to Sequences (3.3) tensored by \({\mathcal O}_S(h_S)\) and (3.2), taking into account of Lemma 3.2 we obtain
$$\begin{aligned} \mathrm {Hom}_S({\mathcal F},{\mathcal F}\big )\subseteq \mathrm {Hom}_S({\mathcal F},{\mathcal I}_{Z\vert S}(h_S)\big )\subseteq \mathrm {Hom}_S({\mathcal F},{\mathcal O}_S(h_S)\big )\cong H^0\big (S,{\mathcal F}(-K_S)\big ). \end{aligned}$$
Tensoring the cohomology of Sequence (3.2) by \({\mathcal O}_S(-K_S)\) we obtain
$$\begin{aligned} h^0\big (S,{\mathcal F}(-K_S)\big )\le 1+h^0\big (S,{\mathcal I}_{Z\vert S}(h_S-K_S)\big ). \end{aligned}$$
The choice of Z and the hypothesis \(p_g(S)\ge 1\) imply
$$\begin{aligned} h^0\big (S,{\mathcal I}_{Z\vert S}(h_S-K_S)\big )\le h^0\big (S,{\mathcal I}_{Z\vert S}(h_S)\big )=0, \end{aligned}$$
hence \({\mathcal F}\) is simple.
Let us prove assertion (2). The choice of Z implies \(h^0\big (S,{\mathcal I}_{Z\vert S}(K_S)\big )=0\), then the cohomology of Sequence (3.2) tensored by \({\mathcal O}_S(K_S-h_S)\) yields
$$\begin{aligned} h^0\big (S,{\mathcal F}(K_S-h_S)\big )=h^0\big (S,{\mathcal O}_S(2K_S-h_S)\big ). \end{aligned}$$
The cohomology of the same exact sequence tensored by \({\mathcal F}(-h_S)\cong {\mathcal F}^\vee (K_S)\) returns
$$\begin{aligned} \dim \mathrm {Ext}_S^2\big ({\mathcal F},{\mathcal F}\big )= & {} {h}^0\big (S,{\mathcal F}\otimes {\mathcal F}^\vee (K_S)\big )\\\le & {} {h}^0\big (S,{\mathcal F}\otimes {\mathcal I}_{Z\vert S}\big )+h^0\big (S,{\mathcal O}_S(2K_S-h_S)\big ). \end{aligned}$$
The obvious inclusion \({\mathcal F}\otimes {\mathcal I}_{Z\vert S}\subseteq {\mathcal F}\) yields \(h^0\big (S,{\mathcal F}\otimes {\mathcal I}_{Z\vert S}\big )\le p_g(S)\) thanks to Lemma 3.2, hence
$$\begin{aligned} \dim \mathrm {Ext}_S^2\big ({\mathcal F},{\mathcal F}\big )\le p_g(S)+h^0\big (S,{\mathcal O}_S(2K_S-h_S)\big ). \end{aligned}$$
Assertion (2) follows by combining Inequality (2.2) with the above inequality.
Let us prove assertion (3). Thanks to [43, Theorem II.1.2.2], if \({\mathcal F}\) is not \(\mu \)–stable, then there should exist a sheaf \(\mathcal M\subseteq {\mathcal F}\) of rank 1 such that \({\mathcal F}/{\mathcal M}\) is torsion–free and
$$\begin{aligned} \mu (\mathcal M)\ge \mu ({\mathcal F})=\frac{h_S^2+h_SK_S}{2}. \end{aligned}$$
The sheaf \({\mathcal M}\) is trivially torsion–free and it is also normal (see [43, Lemma II.1.1.16]). Thus it is a line bundle, because it has rank 1 (see [43, Lemmas II.1.1.12 and II.1.1.15]). It follows that \({\mathcal M}\cong {\mathcal O}_S(E)\) for some divisor E on S.
We have
$$\begin{aligned} (K_S-E)h_S\le \frac{h_SK_S-h_S^2}{2}<0. \end{aligned}$$
The Nakai criterion then implies
$$\begin{aligned} h^0\big (S,{\mathcal O}_S(K_S-E)\big )=0, \end{aligned}$$
(3.5)
hence \({\mathcal O}_S(E)\) is not contained in the kernel \(\mathcal {K}\cong {\mathcal O}_S(K_S)\) of the map \({\mathcal F}\rightarrow {\mathcal I}_{Z\vert S}(h_S)\) in Sequence (3.2) and the composition \({\mathcal O}_S(E)\subseteq {\mathcal F}\rightarrow {\mathcal I}_{Z\vert S}(h_S)\) is necessarily non–zero. In particular \({h}^0\big (S,{\mathcal I}_{Z\vert S}(h_S-E)\big )\ge 1\), hence there is \(A\in \vert h_S-E\vert \) through Z.
We claim that \(Ah_S\ge N+1\). Assuming the claim, Equality (3.1) yields
$$\begin{aligned} \frac{h_S^2-h_SK_S}{2}+p_g(S)+1\le Ah_S=(h_S-E)h_S\le \frac{h_S^2-h_SK_S}{2}, \end{aligned}$$
a contradiction. We deduce that a sheaf \({\mathcal M}\) as above does not exist, hence \({\mathcal F}\) is \(\mu \)–stable.
It remains to prove the claim. To this purpose, let \(C_1,\dots , C_s\) be the integral components of A intersecting Z and B their union. Since \(Z\subseteq S_0\), it follows that \(p_a(C_i)\ge 1\). It is well known that \(p_a(C_i\cup C_j)=p_a(C_i)+p_a(C_j)+C_iC_j-1\) for each \(i, j\in \{\ 1,\dots , s\ \}\), \(i\ne j\) (e.g. see [28, Exercise V.1.3 (c)]): by combining these remarks with an easy induction on s we then deduce
$$\begin{aligned} p_a(B)\ge \sum _{i=1}^sp_a(C_i)-s+1\ge 1. \end{aligned}$$
(3.6)
On the one hand, the cohomology of
$$\begin{aligned} 0\longrightarrow {\mathcal O}_S(h_S-B)\longrightarrow {\mathcal O}_S(h_S)\longrightarrow {\mathcal O}_B(h_B)\longrightarrow 0 \end{aligned}$$
yields \(h^1\big (B,{\mathcal O}_B(h_B)\big )\le h^2\big (S,{\mathcal O}_S(h_S-B)\big )\). Vanishing (3.5) then implies
$$\begin{aligned} h^2\big (S,{\mathcal O}_S(h_S-B)\big )= & {} h^0\big (S,{\mathcal O}_S(B-h_S+K_S)\big )\\\le & {} h^0\big (S,{\mathcal O}_S(A-h_S+K_S)\big )=h^0\big (S,{\mathcal O}_S(K_S-E)\big )=0, \end{aligned}$$
hence \(h^1\big (B,{\mathcal O}_B(h_B)\big )=0\). Thus the Riemann–Roch theorem for the curve B and Inequality (3.6) above yield \(h^0\big (B,{\mathcal O}_B(h_B)\big )\le Bh_S\). On the other hand, the curve B is not contained in any hyperplane inside \(\mathbb {P}^{N}\), because it contains Z, hence \(h^0\big (B,{\mathcal O}_B(h_B)\big )\ge N+1\).
We then deduce that \(Ah_S\ge Bh_S\ge N+1\), hence the claim is proved and the proof of assertion (3) is complete. \(\square \)
Remark 3.4
Construction 3.1 makes sense also in the case \(p_g(S)=0\). Indeed it is the method we used in [13, 14] for proving the existence of special Ulrich bundles when \(p_g(S)=q(S)=0\). Notice that in this case the inequality \(h^2_S> h_SK_S\) is for free.
On the one hand, the proof of Lemma 3.2 can be carried over word by word to this case. On the other hand, the proof of assertion (1) of Proposition 3.3 cannot be extended to the case \(p_g(S)=0\). Moreover, the proof of assertion (3) is alternative to [13, 14, Theorem 1.2] when \(\mathcal Z_1\ne \emptyset \): in particular, it certainly needs \(\kappa (S)\ge 0\).
One of the hypothesis of [13, 14, Theorem 1.2] is that k is uncountable. Thus, the above proof and [36] extend such a result when \(\kappa (S)=2\) also to the case of a countable base field. When \(p_g(S)=0\) and \(\kappa (S)\le 1\), as in the case \(p_g(S)\ge 1\), the condition \(\mathcal Z_1\ne \emptyset \) is not immediate: e.g. there exist Enriques surfaces containing infinitely many rational curves (see [19]).