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Beckman-Quarles type theorems for mappings from \( \mathbb{R}^n \) to \( \mathbb{C}^n \)

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Let \( \varphi_{n} : \mathbb{C}^{n} \times \mathbb{C}^{n} \to \mathbb{C}, \varphi_{n}((x_{1}, \dots, x_{n}), (y_{1}, \dots, y_{n})) = (x_{1} - y_{1})^{2} + \dots + (x_{n} - y_{n})^{2}. \) We say that \( f : \mathbb{R}^{n} \to \mathbb{C}^{n} \) preserves the distance d ≥ 0 if for each \( x,y \in \mathbb{R}^n \, \varphi_{n}(x,y) = d^{2} \) implies \( \varphi_{n}(f(x), f(y)) = d^{2}. \) Let A n denote the set of all positive numbers d such that any map \( f : \mathbb{R}^{n} \to \mathbb{C}^{n} \) that preserves unit distance preserves also distance d. Let D n denote the set of all positive numbers d with the property: if \( x,y \in \mathbb{R}^n \) and \( |x - y| = d \) then there exists a finite set S xy with \( \{x,y\} \subseteq S_{xy} \subseteq \mathbb{R}^{n} \) such that any map \( f : S_{xy} \to \mathbb{C}^n \) that preserves unit distance preserves also the distance between x and y. Obviously, \( D_{n} \subseteq A_{n}. \) We prove: (1) \( A_{n} \subseteq \{d > 0 : d^{2} \in \mathbb{Q}\}, \) (2) for n ≥ 2 D n is a dense subset of \( (0, \infty). \) (2) implies that each mapping f from \( \mathbb{R}^n \) to \( \mathbb{C}^n \) (n ≥ 2) preserving unit distance preserves all distances, if f is continuous with respect to the product topologies on \( \mathbb{R}^n \) and \( \mathbb{C}^n. \)

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Correspondence to Apoloniusz Tyszka.

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Tyszka, A. Beckman-Quarles type theorems for mappings from \( \mathbb{R}^n \) to \( \mathbb{C}^n \) . Aequ. math. 67, 225–235 (2004). https://doi.org/10.1007/s00010-003-2719-1

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  • DOI: https://doi.org/10.1007/s00010-003-2719-1

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