Abstract
We show that a surface corresponding to a first-order ODE is minimal in three-dimensional Riemannian manifold which is determined by the first prolongation of \({\text {d}}y/\mathrm{d}x=p(x,y)\) if and only if \(p_{yy}=0\). Accordingly, any linear first-order ODE describes a minimal surface which is not necessarily totally geodesic.
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Bayrakdar, T., Ergin, A.A. Minimal Surfaces in Three-Dimensional Riemannian Manifold Associated with a Second-Order ODE. Mediterr. J. Math. 15, 183 (2018). https://doi.org/10.1007/s00009-018-1229-2
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DOI: https://doi.org/10.1007/s00009-018-1229-2