Abstract
Sia ϕ una funzione invertibile, continua e quasi ovunque differenziabile, da un aperto di IRn in IRn. Allora ϕ−1soddisfa alla condizione di Lusin (N) se e solo se lo Jacobiano di ϕ è quasi ovunque diverso da zero.
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Villani, A. On Lusin's condition for the inverse function. Rend. Circ. Mat. Palermo 33, 331–335 (1984). https://doi.org/10.1007/BF02844496
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DOI: https://doi.org/10.1007/BF02844496