Abstract
If X is a regular hereditary Souslin space and x ∈X then either there exists a sequence {xn: n=1, 2, ...} ⊂ X{x} such that x ∈ [{xn∶n=1, 2, ...}], or the pseudocharacter of x in X is no greater than countable. In other words, if X is a hereditary Souslin bicompactum which is a χ-space, then X is a Frechet-Urysohn space.
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Translated from Matematicheskie Zametki, Vol. 15, No. 2, pp. 281–288, February, 1974.
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Shapirovskii, B.É. Spaces with a Souslin and a shanin condition. Mathematical Notes of the Academy of Sciences of the USSR 15, 161–164 (1974). https://doi.org/10.1007/BF02102399
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DOI: https://doi.org/10.1007/BF02102399