Abstract
The solution of the exponential integral at linear heating for the general case that the activation energy linearly depends on temperature according toE(T)=E 0+RBT is
$$\frac{A}{q}\int\limits_0^T {T^B \exp \left( { - \frac{{E_0 }}{{RT}}} \right) dT = \frac{A}{q}\left( {\frac{{RT^{B + 2} }}{{E_0 + (B + 2)RT}}} \right)} \exp \left( { - \frac{{E_0 }}{{RT}}} \right).$$
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References
V. M. Gorbachev, J. Thermal Anal., 8 (1975) 349.
C. D. Doyle, Nature, 207 (1965) 290.
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Gorbachev, V.M. Algorism for the solution of the exponential integral in non-isothermal kinetics at linear heating. Journal of Thermal Analysis 10, 447–449 (1976). https://doi.org/10.1007/BF01909897
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DOI: https://doi.org/10.1007/BF01909897